- ti os6 truy~n.
1.PhaD los.ti thea tioh nAng su d\1Dg
'. a) MAy xuc xAy d1,1ng chl;lY hanh xfeb, Mnh 16p cO tht1 deb g,iu xuc tit 0,25 + 2 m3. b) May xuc dung trang cOng nghi~p khai thAc m6 l¢ thi~n co th~ deb gliu Xu.c tu
4,6 + 8 m3,
e) May xllc b6c din d:i co the' deb gliu xuc tu 4 + 35 m3. d) May xllc gliu ngol;lm co the' deh gl1u xuc tu 4 + 80 m 3. 2. PhAn los,ti thea CD cAu b6c x6c
a) MAy xllc co co cA:u Me xuc lA gfiu xllc thu~n : gdu xuc di chuy~n vila dll't da thea h1.Umg til: mAy xuc ra phis tr110c du:Oi tAc dl,lDg cua hai h,':c k~t hQP cua co cfIu nAng vA 00 cilu da':y tay g4u (hlnh 4 - la).
b) M~y xuc co cO ci1u b6c xiic ki~u g4u cAo di chuyen thea huO'ng til: tay gl1u vAa mAy xuc theo rn$t phAng nhm ngang (hlnh 4 - Ib).
c) May xuc cO co cI1u b6c xuc k.i~u g4u treo tr@n dAy : g~u di chuyen theo huO'ng tit: phia ngoAi vAo may xuc duO'i tAc dl,lDg cua hrc k~t hQp cua hai cO ci1u : cO ci1u keo vA 00 ci1u nang (hlnh 4-1c).
d) May xuc co cO ci1u b6c xuc ki~u g4u ngoQ.m : qua trlnh b6c xuc di1t da thl,lc hi~n
bAng cach kMp kIn da':n hai ntia thAnh g4u ngo~m dueJi Mc d .... ng ly:c keo cua cO c~u keo. (xern hlnh 4 - Id).
d) May xuc co co et'lu b6c xuc ki~u g!1u quay. G!1u quay lA mOt Mnh xe, g!1u xuc dUQc ga l@n Mnh xe thea ebu vi (hlnh 4 - Id).
e) MAy xuc co co cliu Mc xuc ki~u mAng cAo nhMu g!1Q.. xuc (xem hlnh 4 - Ie). J. PhAn lo~i theo thi tich g'hu x6c
a) MAy xuc cOng sui1t nM, cO th~ deb gfiu xuc tit: 0,25 d~n 2 rn3 b) May xiic cOng su~t trung blnh, co th~ deb pu xuc til: 2 d~n 6 m 3 c) May xiic cOng sui1t Ibn cd th~ dch gl1u xuc tit: 6 d~n 80 m 3,
'.
b)
C)
d) e)
Hlnh 4-1. Cae dl;lllg may xUc.
4. Ph.lin IOQ,i theo cO cAu truyen Ivc
a} MAy xuc dung cd du truyAn !l,te Iii. dOng co d6t trong b) MAy xuc dung 00 dIu truy~n h,te IS. dOng 00 di~n. 5. Phin loti theo cAn tQ,o CUB cO cAll di chuyen
a) MAy x(ic ch~y bAnh x(ch