the prime minister and i episode 1 eng sub full

Metal Machining - Theory and Applications Episode 1 Part 10 ppt

Metal Machining - Theory and Applications Episode 1 Part 10 ppt

... view of chip formation Z′ is parallel to z and z′, still in the cutting direction, but X′ is normal to, and Y′ is in, the plane containing the cutting and chip velocities In terms of the chip ... indicate the positions 1, 2, 3, etc in Figure 6 .15 at which the quantities are calculated, or else the subscripted quantities are defined in the figure Further details of the values of the quantities ... value of the uncut chip thickness is t1e and the accompanying chip thickness is t2e The subscript e stands for effective and emphasizes that the plane of the figure is the Uwork–Uchip plane The rake...

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Metal Machining - Theory and Applications Episode 1 Part 9 pptx

Metal Machining - Theory and Applications Episode 1 Part 9 pptx

... known (p1 = +k in this case) and if the directions of the slip-lines f1, f2 and f3 at points 1, and are known (point is the intersection of the a and b lines connecting points and 3) Then, the normal ... Annals CIRP 26 (1) , 21 26 Kakino, K (19 84) Monitoring of metal cutting and grinding processes by acoustic emission J Acoustic Emission 3, 10 8 11 6 Miwa, Y., Inasaki, I and Yonetsu, S (19 81) In-process ... slip-line is determined by force equilibrium requirements If the directions of the slip-lines at a point are defined by the anticlockwise rotation f of one of the lines from some fixed direction...

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Metal Machining - Theory and Applications Episode 1 Part 8 ppsx

Metal Machining - Theory and Applications Episode 1 Part 8 ppsx

... thermocouple calibration set-up Childs Part 28:3:2000 3 :11 pm Page 15 1 Temperatures in machining 15 1 Fig 5 .17 A detail of the hot junction and the associated measurement circuit Fig 5 .18 Calibration ... ring (Figure 5.9) is loaded radially there is zero strain at the positions B and B′, ± 39.9˚ from the point of application of the radial load; likewise when the ring is loaded tangentially, there ... from the cutting edges, and the work and its holder have higher inertia than the tool and its holder in turning The quick-stop must be synchronized with the intermittent cutting action There...

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Metal Machining - Theory and Applications Episode 1 Part 7 ppt

Metal Machining - Theory and Applications Episode 1 Part 7 ppt

... alumina ceramic tools when machining steel Carbon, silicon and nitrogen all diffuse easily in iron at elevated temperatures; and silicon nitride and silicon carbide dissolve readily in hot iron Thermal ... changes in sliding conditions In machining, the tool damage mode and the rate of damage are similarly very sensitive to changes in the cutting operation and the cutting conditions While tool ... coated with PVD TiN, TiCN or TiAlN Chromium nitride, boron nitride and boron carbide coatings are also under investigation TiN and TiC coatings have also been found to be useful on silicon nitride...

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Metal Machining - Theory and Applications Episode 1 Part 6 pdf

Metal Machining - Theory and Applications Episode 1 Part 6 pdf

... it will lose the toughening reinforcement that it gains from its substrate The tensile thermal strain resulting from its thermal mismatch with the substrate will further contribute to its failure ... conductivity was emphazied as influencing the steady state temperature rise in machining In transient conditions, heat capacity is also important because, with conductivity, it determines thermal diffusivity ... cubic boron nitride (single crystal diamonds are also used for the finishing of IT mirror and disc substrate products) Details of the various materials within these groups are given in Appendix...

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Metal Machining - Theory and Applications Episode 1 Part 5 potx

Metal Machining - Theory and Applications Episode 1 Part 5 potx

... stresses (which are between two and three times the average stress) in the range k to 3k This is in line with the estimates in Chapter 2, Figure 2 .15 The different thermal diffusivities of the five metals ... spanning the range as far as tool stressing is concerned Their intermediate thermal conductivities and diffusivities result in their spanning the range with respect to temperature rise per unit ... temperature rises in machining At the other extreme, austenitic steels, nickel and titanium alloys have medium to high shear stresses and work hardening rates and low thermal diffusivities They are likely...

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Metal Machining - Theory and Applications Episode 1 Part 4 pot

Metal Machining - Theory and Applications Episode 1 Part 4 pot

... caused by the heating Given that the primary shear acts on the workpiece, these simple considerations point to the possibility of workpiece thermal damage when machining aluminium and titanium alloys, ... Chapter 1) Small variations in mechanical characteristics can lead to large variations in economic life It is the economic pressure to use cutting edges at their limit that drives the study of machining ... heating of the chip and tool due to friction is considered next 2.3.2 Heating due to friction The size of the friction stress t between the chip and the tool has been discussed in Section 2.2.5 It...

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Metal Machining - Theory and Applications Episode 1 Part 3 pot

Metal Machining - Theory and Applications Episode 1 Part 3 pot

... chip still, but its friction coefficient is marginally increased too Comparing Figures 2.8(b) and 2.7(b), changes in work hardening and friction coefficient have similar influences on chip thickness ... create them The role of mechanics in this context is more to aid the description than to be predictive First, Section 2.2 .1 describes how chip formation in all machining processes (turning, milling, ... formed is thick and straight Adding a lubricating fluid causes the chip to become thinner and curled In this case, adding the lubricant caused the friction coefficient between the chip and tool...

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Metal Machining - Theory and Applications Episode 1 Part 2 pps

Metal Machining - Theory and Applications Episode 1 Part 2 pps

... Ct is the initial price of the tool, plus all the reconditioning costs, divided by the number of times it is reconditioned It is less than the purchase price (if it were more, reconditioning would ... Table 1. 1 (cutting tool data) and equations (1. 10) and (1. 11) for cost rates Childs Part 28:3:2000 2:35 pm Page 31 Economic optimization of machining 31 Table 1. 7 Assumptions for milling time and ... is continuously removing metal Equations (1. 12) and (1. 13) can be used with a = For the example concerned, the time and cost of removing material by drilling is negligible It is the loading and...

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Metal Machining - Theory and Applications Episode 1 Part 1 potx

Metal Machining - Theory and Applications Episode 1 Part 1 potx

... loading and unloading systems (see Section 1. 2) The prices in Figure 1. 10(b) not include such external materials handling devices 1. 1.2 Milling and drilling machines Up to this point, the description ... retrieval system, without either prior permission in writing from the publishers or a licence permitting restricted copying In the United Kingdom such licences are issued by the Copyright Licensing ... non-productive cycle time, relative to its pre -19 70 levels This halving of time is indicated in Figure 1. 5(a) (Figure 1. 5(b) is considered in Section 1. 1.2) A further halving of non-productive cycle time...

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Wiley the official guide for GMAT Episode 1 Part 10 pps

Wiley the official guide for GMAT Episode 1 Part 10 pps

... in their participation in the job market (as compared with men’s) and thus reduces their opportunities to acquire training for highly skilled work In addition, the human capital theory explains ... first clarifying goals, assessing the problem, formulating options, estimating likelihoods of success, making a decision, and only then taking action to implement the decision Rather, in their day-by-day ... cases disputing the traditional diversion and use of water by Pueblo Indians (E) Arizona v California applies the criteria derived from the Winters doctrine only to federal lands other than American...

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Wiley the official guide for GMAT Episode 1 Part 9 potx

Wiley the official guide for GMAT Episode 1 Part 9 potx

... 14 0 is divided by 11 0, the quotient is R30 However, 250 divided by 11 0 yields a quotient of R30, and 360 divided by 11 0 gives a quotient of R30 Since there is no consistency in the tens digit, ... line segment XC and if point S is the midpoint of line segment YC, what is the area of triangular region RCS ? 11 0 The product of the units digit, the tens digit, and the hundreds digit of the ... determined; NOT sufficient The correct answer is A; statement alone is sufficient 10 9 In triangle ABC, point X is the midpoint of side AC and point Y is the midpoint of side BC If point R is the midpoint...

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Wiley the official guide for GMAT Episode 1 Part 8 potx

Wiley the official guide for GMAT Episode 1 Part 8 potx

... B 14 7 C C 43 E 78 C 11 3 D 14 8 B A 44 C 79 E 11 4 D 14 9 A 10 B 45 D 80 D 11 5 D 15 0 A 11 A 46 B 81 C 11 6 A 15 1 D 12 B 47 A 82 B 11 7 D 15 2 B 13 D 48 C 83 C 11 8 E 15 3 D 14 C 49 B 84 D 11 9 E 15 4 A 15 ... First- and second-degree equations Taking (1) and (2) together, if k < n and the median of the list is 10 , then 12 and 17 are to the right of the median and the list in ascending order is either ... region ABX is 32 The length of one of the altitudes of triangle ABC is 11 0 The product of the units digit, the tens digit, and the hundreds digit of the positive integer m is 96 What is the units...

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Wiley the official guide for GMAT Episode 1 Part 7 ppsx

Wiley the official guide for GMAT Episode 1 Part 7 ppsx

... standard deviation to least standard deviation in which of the following? (A) I, II, III (B) I, III, II (C) II, III, I (D) III, I, II (E) III, II, I Arithmetic Statistics The data set with the ... received grades of A, B, or C 242 x2 – x (A) I only (B) III only (C) I and II (D) I and III (E) II and III Algebra Simplifying algebraic expressions Investigate each of the functions to determine ... an integer 5.5 Problem Solving Answer Explanations (A) I only (B) II only (C) I and II only (D) II and III only (E) I, II, and III 1. 25wH = wh (new wage)(new hours) = (original wage)(original...

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Wiley the official guide for GMAT Episode 1 Part 6 ppt

Wiley the official guide for GMAT Episode 1 Part 6 ppt

... = 11 0 The first integer in the sequence is 11 0, so the next integers are 11 1, 11 2, 11 3, and 11 4 From this, the last integers in the sequence, and thus their sum, can be determined The sum of the ... mathematically inclined, if n is divisible by 3, then the expression in each answer choice is divisible by Assume, then, that n is not divisible by If the remainder when n is divided by is 1, then ... + 1, n + 3, and n + is divisible by Therefore, if the remainder when n is divided by is 1, only the expressions in answer choices A, B, and E are divisible by On the other hand, if the remainder...

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Wiley the official guide for GMAT Episode 1 Part 5 pptx

Wiley the official guide for GMAT Episode 1 Part 5 pptx

... what is the number of green marbles in Jar R ? 18 0 (A) I, II, III (B) I, III, II (C) II, III, I (D) III, I, II (E) III, II, I 5.3 Problem Solving Sample Questions 200 Of the 50 researchers in a ... the quantities is increased by 5, what is the ratio of these two new quantities? x (A) x2 – x (B) (A) I only (B) III only (C) I and II (D) I and III (E) II and III (C) (D) (E) 18 19 23 24 It cannot ... C 216 B 12 7 A 15 7 B 18 7 A 217 D 12 8 A 15 8 E 18 8 E 218 D 12 9 D 15 9 D 18 9 B 219 E 13 0 E 16 0 D 19 0 E 220 B 13 1 E 16 1 E 19 1 C 2 21 D 13 2 D 16 2 B 19 2 E 222 C 13 3 E 16 3 E 19 3 D 223 B 13 4 B 16 4 D 19 4...

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Wiley the official guide for GMAT Episode 1 Part 4 ppt

Wiley the official guide for GMAT Episode 1 Part 4 ppt

... perpendicular vertical line is called the y-axis The point at which these two axes intersect, designated O, is called the origin The axes divide the plane into four quadrants, I, II, III, and IV, ... inscribed in the circle and the circle is circumscribed about the polygon If each side of a polygon is tangent to a circle, then the polygon is circumscribed about the circle and the circle is ... circle so that one of its sides is a diameter of the circle, then the triangle is a right triangle 13 3 The Official Guide for GMAT® Review 12 th Edition Y X Z O In the circle above, XZ is a diameter...

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Wiley the official guide for GMAT Episode 1 Part 3 ppt

Wiley the official guide for GMAT Episode 1 Part 3 ppt

... the right) ( + = digits to the right) Division of decimals To divide a number (the dividend) by a decimal (the divisor), move the decimal point of the divisor to the right until the divisor is ... but 15 is not, since 15 has four different positive divisors, 1, 3, 5, and 15 The number is not a prime number since it has only one positive divisor Every integer greater than either is prime ... pirates copying and distributing (E) to distribute songs and full- length recordings on the Internet and it will protect copyright holders and foiling the many audio pirates who copy and distribute...

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Wiley the official guide for GMAT Episode 1 Part 1 doc

Wiley the official guide for GMAT Episode 1 Part 1 doc

... multiple of 6, then xy must be a multiple of which of the following? (B) I (C) II 12 (D) III 18 (A) I and II only (C) I and III only (D) II and III only (E) (E) II only (B) I, II, and III Algebra ... measurements The quotient is the variance and the positive square root of the variance is the standard deviation (1) If the variance is 4, then the standard , which is less than 3; deviation SUFFICIENT ... sufficient Taking (1) and (2) together, since k is divisible by both 10 and 15 , it must be divisible by their different positive prime factors of 2, 3, and Thus k has at least different positive prime factors...

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Wiley the official guide for GMAT Episode 1 Part 2 pdf

Wiley the official guide for GMAT Episode 1 Part 2 pdf

... following? I II 12 (A) III 18 (B) 1: 1 (C) :1 (A) II only (B) I and II only (D) I and III only (E) (D) II and III only (E) 21 (C) I, II, and III 2 :1 John deposited $10 ,000 to open a new savings account ... production by Wiley Publishing, Inc Composition Services Charles Forster, Designer Mike Wilson, Production Designer Table of Contents 1. 0 1. 1 1. 2 1. 3 1. 4 1. 5 1. 6 1. 7 1. 8 1. 9 1. 10 What Is the GMAT®? ... jogging and walking? $10 ,10 1 (C) 22 $10 ,10 0 24 A container in the shape of a right circular cylinder is full of water If the volume of water in the container is 36 cubic inches and the height...

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