movers 4 for teacher and parents

**1 Have you heard the one about ...?** **Two-line jokes** 1. What was the tortoise doing on the motorway? Answer: About ten metres an hour 2. What did the big chimney say to the little chimney? Answer: You're too young to smoke 3. What did the traffic light say to the car? Answer: Don't look now, I'm changing 4. What's worse than finding a worm in an apple? Answer: Finding half a worm 5. Do you know that it takes three sheep to knit a sweater? Answer: One to hold on to the needles, one to do the knitting, and one to pull the wool over everyone's eyes 6. How do you know when there's an elephant under the bed? Answer: Your nose touches the ceiling 7. I say, driver, do you stop at the Ritz Hotel? Answer: What, on my wages? 8. I broke my arm in three places. Answer: Well, you ought to stay out of those places then! 9. How can you tell a British workman by his hands? Answer: They're always in his pocket 10. What do you call a crocodile at the North Pole? Answer: Lost 11. Do you write with your left hand or your right hand? Answer: Neither — I use a ballpoint pen 12. You've put your shoes on the wrong feet. Answer: But these are the only feet I've got, Mum! 13. How do you get a man to stop biting his nails? Answer: Make him wear his shoes 14. Why were the two flies playing football in a saucer? Answer: They were practising for the cup 15. Why do golfers take an extra pair of trousers with them? Answer: In case they get a hole in one

Ngày tải lên: 11/03/2014, 03:28

... Evaluating Traffic Capacity and Improvements to Geometry Technical Paper Number 74 The World Bank ,Washington D.C, USA Moavenzadeh, F., Stafford J.H., Suhbrier J., and Alexander J (1971) Highway Design ... 75 -4 Massachusetts Institute of Technology, Cambridge, USA Kerali H.R and V Mannisto (1999) Prioritization Methods for Strategic Planning and Road Work Programming in a New Highway Development and ... Transportation Research Record 1655, pp 49 - 54 PIARC (2001) Highway Development and Management System HDM -4 World Road Association, ISOHDM, PIARC, Paris, France RNIP (20 04) Dự án Nâng cấp Mạng lới Đờng

Ngày tải lên: 08/08/2022, 12:45

... mole Al2(SO4)3 is 27*2 + (32 + 64) * = 342 g From the equation, mole of H2SO4 required to produce one mole of Al2(SO4)3 98 * g H2SO4 produce 342 g Al2(SO4)3 X g H2SO4 produce g Al2(SO4)3 X = 9g ... the equation, one mole of H2SO4 produces one mole of K2SO4 98 g H2SO4 produce 1 74 g of K2SO4 9.8 g H2SO4 produce X g K2SO4 X = 9.8 g * 1 74 g / 98 g = 17 .4 g K2SO4 Answer: 11.2 g KOH is required ... 35 = 74 g of KCl From the equation, mole of KClO3 produce mole of O2 and mole of KCl 122*2= 244 g of KClO3 produce 16*3 =48 g of O2 X g of KClO3 produce 4. 29 g of O2 X = 244 g * 4. 29 g / 48 g =

Ngày tải lên: 11/09/2022, 20:51

... billed for the remaining 50% of the price of the tuition Eligible students are responsible for paying for fees and the cost of books and supplies Please reference Senate Bill 740 for more information ... the fall and spring semesters of their high school career Eligible students are responsible for paying for fees and the cost of books and supplies unless they are approved for free and reduced ... requirements for Maryland and standards of rigor for BCPS The Dual Credit Program in partnership with CCBC offers select, pre-approved college courses that provide both high school and college credit for

Ngày tải lên: 23/10/2022, 07:15

... Performance Stress Sleep Disorders and Sleep Deprivation Addictions: Drugs and Games Cognitive-Enhancing Drugs The Aging Brain 142 ! 144 ! 146 ! 146 ! 147 ! 150! 151! Brain Science for Educators and ... reach for autonomy Parents, stepparents, and other relatives form one group, and surrogate parents form the other group Teachers, coaches, and youth program directors are examples of surrogate parents ... brain science is specifically designed for preservice and inservice K-12 teachers, for teachers of these teachers, and for parents Here are two important and unifying questions addressed throughout

Ngày tải lên: 01/11/2022, 20:01

... pp. 342 1- 343 6, ISSN: 0020-7 543 Foster, S.T. (2008). Towards an understanding of supply chain quality management. Journal of Operations Management, Vol. 26, No .4, (July 2008), pp. 46 1? ?46 7, ISSN: ... environment as “the quality chain” and use three layers as basic, technical, and operating environment, highlighting the need for the integration of information, standards and organisation with business ... information integration and implementation platform. An internal quality information integration model is suggested on top of this structure, defining the subsystems and the critical data and

Ngày tải lên: 19/06/2014, 15:20

... ton, and Nevada (Figure 4. 2). The investigators evaluated water movement through soil covers for 4? ??17 years (Nyhan et al. 1990; Anderson et al. 1993; Waugh et al. 19 94; Anderson 1997; Andraski ... poor-to-unacceptable perfor- mance. The soil in an ET cover should have low density. 4. 3 CONCEPT BACKGROUND AND PROOF The principles and technology that form the basis for the ET landll cover are well ... that region. 4. 3.3 .4 Texas High Plains Aronovici (1971) measured soil water content, chloride, and salt movement in soil proles under native grasslands, dryland wheat and sorghum, and irrigated

Ngày tải lên: 20/06/2014, 00:20

... fH ¼ and fP ¼ Àaexp(ÀaP); these need to be evaluated at the steady states and the coefficients a, b, c, and d in Eq (4. 9) evaluated so that we can then determine and Exercise 4. 3 (M/H) For NicholsonBailey ... the condition becomes | | ỵ ( 2 /4) > ( 2 /4) and this simplifies to ỵ > | | Our first condition was ! and we have agreed that | | < so that < Therefore, > ! 4 , so that > or > ỵ When we combine ... parameters and k is k/, it would be sensible for this to be the average value of the attack rate so that a ¼ k/; we choose ¼ k/a We then multiply top and bottom of the right hand side of Eq (4. 14)

Ngày tải lên: 06/07/2014, 13:20

... Linguistics (22) 4: 40 5 -43 8 Ruiz-Garrido, M.F (2006) Conceptualising and teaching business reports In Gillaerts, P and P Shaw (eds) The Map and the Landscape: Norms and. .. 4th International ... Orlando, Florida, 21- 24 September Le Maistre, C and A Paré (20 04) Learning in two communities: The challenge for universities and workplaces, Journal of Workplace Learning (16) 1/2: 44 ... perspective, Information Processing and Management (44 ) 2: 702-737 Schryer, C.F (19 94) The lab vs the clinic: Sites of competing genres In Freedman, A and P Medway (eds) Genre and the New

Ngày tải lên: 22/07/2014, 04:21

... x and an increasing √ √ √ function of δ for positive x and δ Thus for any fixed δ, the maximum value of x + δ − x is bounded by δ √ √ √ Therefore on the interval (0, 1), a sufficient condition for ... ln2 x dx 102 Figure 4. 1: Plot of ln |x| and 1/x Note the absolute value signs This is because this d dx ln |x| = 1 x for x = 0 In Figure 4. 1 is a plot of ln |x| and Example 4. 1.1 Consider I= (x2 ... (x) is called the integrand 122 f(ξ1 ) a x1 x2 x3 ∆ x n-2 x n-1 b xi Figure 4. 2: Divide -and- Conquer Strategy for Approximating a Definite Integral 4. 2.2 Properties Linearity and the Basics Because

Ngày tải lên: 06/08/2014, 01:21

... the ratio test k 4 /4k k→∞ (k + 1 )4 /4k+1 k4 = 4 lim k→∞ (k + 1 )4 24 = 4 lim k→∞ 24 =4 R = lim The series converges absolutely for |z| < 4 1 Since the integrand is analytic inside and on the contour ... at z = 0 and z = −1 Let C1 and C2 be contours around z = 0 and z = −1 See Figure 11.6 We deform C onto C1 and C2 = C + C1 520 C2 4 2 -4 C1 C2 2 -2 C 4 -2 -4 Figure 11.5: The contours for (z 3 ... 2 The integrand has singularities at z = 0 and z = 4 Only the singularity at z = 0 lies inside the contour We use 518 4 2 C2 -4 -6 C C1 -2 C3 2 4 6 -2 -4 Figure 11 .4: The contours for z z 3 −9

Ngày tải lên: 06/08/2014, 01:21

... R(x)y = 0 (16 .4) An exact equation can be written in the form: d [a(x)y + b(x)y] = 0 dx If Equation 16 .4 is exact, then we can write it in the form: d [P (x)y + f (x)y] = 0 dx for some function ... intervals (−∞ 0) and (0 ∞) 2 x(x − 1)y + 3xy + 4y = 2 3 4 2 y + y + y= x−1 x(x − 1) x(x − 1) Unique solutions exist on the intervals (−∞ 0), (0 1) and (1 ∞) 9 24 3 ex y + x2 y + y ... solutions of the form, xitα , xitα log t + ηtα , xitα (log t)2 + ηtα log t + ζtα , ., analogous to the form of the solutions for a constant coefficient system, xi eατ , xiτ eατ +η eατ , 4 Method 1 Now

Ngày tải lên: 06/08/2014, 01:21

... 2)(n − 4) · · · (1) For the even terms, a2 = 1 2 a4 = 2 22 a6 = 42 an = 2(n−2)/2 (n − 2)(n − 4) · · · (2) Thus an = 2(n 1) /2 (n−2)(n 4) ··· (1) 2(n−2)/2 (n−2)(n 4) ···(2) 11 83 for odd ... polynomial are 1 − 3 /4 3 = , 2 4 Thus our two series solutions will be of the form 1 = 1+ α2 = 1 ∞ w1 = z 3 /4 1 − 3 /4 1 = 2 4 ∞ an z n , w2 = z 1 /4 n=0 bn z n n=0 Substituting ... express the formula form the n th element in terms of rational numbers. 1182 [...]... yields the difference equation 1 1 an (α) + an 1 (α) = 0 4 4 n(n + 1) α(α − 1) 1 + + an 1 (α) 4 4 16

Ngày tải lên: 06/08/2014, 01:21

... α = 1 /4 in the recurrence formula, an−1 an (α1 ) = − 2 + 2( n + 1 /4) − 1 8(n + 1 /4) an−1 an (α1 ) = − 2n(4n + 3) Thus the first solution is ∞ w1 = z 1 /4 an (α1 )z n = a0 z 1 /4 1 − n=0 ... (x)P1 (x) dx = x dx = 3 −1 −1 1 2 1 1 1 1 9x4 − 6x2 + 1 dx = 4 4 P2 (x)P2 (x) dx = −1 −1 1 1 P3 (x)P3 (x) dx = −1 −1 1 1 25 x6 − 30x4 + 9x2 dx = 4 4 = −1 5 2 3 9x − 2x3 + x 5 7 1 = −1 25 ... )) = 0 (2a2 x + 6a3 x2 ) + (2x + 4a2 x2 ) + (6x + 6(1 + a2 )x2 ) = O(x3 ) = 0 17 a2 = 4, a3 = 3 17 y1 = x − 4x2 + x3 + O(x4 ) 3 Now we... , n ≥ 0 n +2 n≥0 a0 and a1 are arbitrary We determine

Ngày tải lên: 06/08/2014, 01:21

... one term is best for x 2, the ten term is best for 2 x 4, and the twenty term is best for 4 x This leads us to the concept... 1268 1 2 3 4 5 6 -20 -40 -60 Figure 24. 3: log(error ... n!(2x)2n+1 x 1 2 3 4 5 6 7 8 9 10 erfc(x) 0.157 0.0 046 8 2.21 × 10−5 1. 54 × 10−8 1. 54 × 10−12 2.15 × 10−17 4. 18 × 10− 23 1.12 × 10−29 4. 14 × 10 37 2.09 × 10 45 One Term Relative ... cos(πx) , Pn |Pn 1285 yields 15 45 (2π 2 − 21) P2 (x) + P4 (x) π2 4 105 = 4 [ (31 5 − 30 π 2 )x4 + ( 24 2 − 270)x2 + (27 − 2π 2 )] 8π cos(πx) ≈ − The cosine and this polynomial... by parts,

Ngày tải lên: 06/08/2014, 01:21

... = π 4( −1)n = n2 a0 = Thus the Fourier series is ∞ π2 (−1)n x = +4 cos(nx) for x ∈ (−π π) n2 n=1 ∞ n=1 n4 We apply Parseval’s theorem for this series to find the value of ∞ 2π 1 + 16 = n4 π ... 16 = n4 π n=1 ∞ π x4 dx −π 2π 2π + 16 = n4 n=1 ∞ n=1 ? ?4 = n4 90 1375 Now we integrate the series for f (x) = x2 x ξ2 − ∞ π2 3 dξ = n=1 ∞ (−1)n n2 x cos(nξ) dξ x π (−1)n − x =4 sin(nx) 3 n3 n=1 ... there is no value of a for which both cos a and sin a vanish, the system is not orthogonal for any interval of length π First note that π cos nx dx = for n ∈ N If n = m, n ≥ and m ≥ then π cos nx

Ngày tải lên: 06/08/2014, 01:21

... eigenvalues and eigenfunctions for: d4 φ = λφ, dx4 φ(0) = φ (0) = 0, φ(1) = φ (1) = 0 Hint, Solution 144 2 29.5 Hints Hint 29.1 Hint 29.2 Hint 29.3 Hint 29 .4 Write the problem in Sturm-Liouville form... ... µy, for a ≤ x ≤ b, α 1 y(a) + α 2 y  (a) = 0, β 1 y(b) + β 2 y  (b) = 0, where the p j are real and continuous and p 2 > 0 on [a, b], and the α j and β j are real can be written in the form ... y (0)) − n2 yn + αyn = fn π Unfortunately we don’t know the values of y (0) and y (π) CONTINUE HERE 143 8 29 .4 Exercises Exercise 29.1 Find the eigenvalues and eigenfunctions of y + 2αy

Ngày tải lên: 06/08/2014, 01:21

... cosh(λ1 /4 x) + c3 sin(λ1 /4 x) + c4 sinh(λ1 /4 x) Applying the condition φ(0) = 0 we obtain φ = c1 (cos(λ1 /4 x) − cosh(λ1 /4 x)) + c2 sin(λ1 /4 x) + c3 sinh(λ1 /4 x) The condition φ (0) ... 1 /4 x). The left boundary condition gives us y = c e x/2 sin(  λ − 1 /4 x). 145 7 The right boundary condition demands that  λ − 1 /4 = nπ, n = 1, 2, . . . Thus we see that the eigenvalues and ... c1 sin(λ1 /4 x) + c2 sinh(λ1 /4 x) We substitute the solution into the two right boundary conditions c1 sin(λ1 /4 ) + c2 sinh(λ1 /4 ) = 0 −c1 λ1/2 sin(λ1 /4 ) + c2 λ1/2 sinh(λ1 /4 ) = 0...

Ngày tải lên: 06/08/2014, 01:21

... Hint 31 .4 If... = f (s − c) for s > c + α Solution 31 .4 First consider the Laplace transform of t0 f (t) ˆ L[t0 f (t)] = f (s) 1510 Now consider the Laplace transform of tn f (t) for n ... Laplace transform has the behavior ˆy(s) ∼ 1 s + 2 s 2 + O(s −3 ), as s → +∞. 149 4 31.5 Systems of Constant Coefficient Differential Equations The Laplace transform can be used to transform a system ... c) for s > c + α. 149 7 Hint, Solution Exercise 31 .4 Show that L[t n f(t)] = (−1) n d n ds n [ ˆ f(s)] for n = 1, 2, . . . Hint, Solution Exercise 31.5 Show that if  β 0 f(t) t dt exists for

Ngày tải lên: 06/08/2014, 01:21

... problem y  + 4y  + 4y = 4 e −t , y(0) = 2, y  (0) = −3 1537 We take the Laplace transform of the differential equation and solve for ˆy(s). s 2 ˆy −sy(0) − y  (0) + 4sˆy −4y(0) + 4? ?y = 4 s + 1 s ... −2s + 3 + 4sˆy −8 + 4? ?y = 4 s + 1 ˆy = 4 (s + 1)(s + 2) 2 + 2s + 5 (s + 2) 2 ˆy = 4 s + 1 − 2 s + 2 − 3 (s + 2) 2 We take the inverse Laplace transform to determine the solution. y = 4 e −t −(2 ... 1 + 5x2 + 4 is to first expand the function in partial fractions f (x) = 1/3 1/3 − 2 +1 x +4 x2 1 2 1 4 F[f (x)] = F 2 − F 2 6 x +1 12 x +4 1 −|ω| 1 −2|ω| = e − e 6 12 32 .4. 4 Parseval’s

Ngày tải lên: 06/08/2014, 01:21