... xin trõn trng cm n PGS.TS Phan Huy Khi, ngi thy ó trc tip ging dy, hng dn v to mi iu kin giỳp t i hon thnh lun ny T i xin trõn trng cm n Ban giỏm hiu, Phũng o to sau i hc Trng i hc Khoa hc i ... hc i hc Th i Nguyờn v cỏc thy giỏo, cụ giỏo ó trc tip ging dy, giỳp t i sut quỏ trỡnh hc ti trng T i xin by t lũng bit n n cha m, ngi thõn, bn bố v tt c nhng ngi ó giỳp , ng viờn t i sut quỏ ... 2 2 sin b + sin g sin g + sin a sin a + sin b S húa bi Trung tõm Hc liu i hc Th i Nguyờn http://www.Lrc-tnu.edu.vn (*) 14 Bi gii D thy: cos2 a + cos b + cos2 g = (1) ị sin a + sin b + sin g...
... xin trõn trng cm n PGS.TS Phan Huy Khi, ngi thy ó trc tip ging dy, hng dn v to mi iu kin giỳp t i hon thnh lun ny T i xin trõn trng cm n Ban giỏm hiu, Phũng o to sau i hc Trng i hc Khoa hc i ... hc i hc Th i Nguyờn v cỏc thy giỏo, cụ giỏo ó trc tip ging dy, giỳp t i sut quỏ trỡnh hc ti trng T i xin by t lũng bit n n cha m, ngi thõn, bn bố v tt c nhng ngi ó giỳp , ng viờn t i sut quỏ ... 2 2 sin b + sin g sin g + sin a sin a + sin b S húa bi Trung tõm Hc liu i hc Th i Nguyờn http://www.Lrc-tnu.edu.vn (*) 14 Bi gii D thy: cos2 a + cos b + cos2 g = (1) ị sin a + sin b + sin g...
... www.VNMATH.com LI CM N T i xin trõn trng cm n PGS.TS Phan Huy Khi, ngi thy ó trc tip ging dy, hng dn v to mi iu kin giỳp t i hon thnh lun ny T i xin trõn trng cm n Ban giỏm hiu, Phũng o to sau i hc Trng i ... Khoa hc i hc Th i Nguyờn v cỏc thy giỏo, cụ giỏo ó trc tip ging dy, giỳp t i sut quỏ trỡnh hc ti trng T i xin by t lũng bit n n cha m, ngi thõn, bn bố v tt c nhng ngi ó giỳp , ng viờn t i sut ... g - cos b - cos a + + Ê sin b + sin g sin g + sin a sin a + sin b sin g + sin b -1 sin a + sin g - sin a + sin b - + + Ê sin b + sin g sin a + sin g sin b + sin a ổ 1 1ử 1 3-ỗ + + ữ Ê + + ...
... 146 LI CM N T i xin trõn trng cm n PGS.TS Phan Huy Khi, ngi thy ó trc tip ging dy, hng dn v to mi iu kin giỳp t i hon thnh lun ny T i xin trõn trng cm n Ban giỏm hiu, Phũng o to sau i hc Trng i ... cos g - cos b - cos a + + Ê sin b + sin g sin g + sin a sin a + sin b sin g + sin b -1 sin a + sin g - sin a + sin b - + + Ê sin b + sin g sin a + sin g sin b + sin a ổ 1 1ử 1 - ỗỗ + + ữữữ Ê ... Khoa hc i hc Th i Nguyờn v cỏc thy giỏo, cụ giỏo ó trc tip ging dy, giỳp t i sut quỏ trỡnh hc ti trng T i xin by t lũng bit n n cha m, ngi thõn, bn bố v tt c nhng ngi ó giỳp , ng viờn t i sut...
... - I (y -k!a) k=O (n+l) k II II g(k)(a) S g (y - ay+l, Vy ~ a (n + I) ! 00 Ta cling bi€t rang (2.18) cho mQt danh gia tITcong thuc khai tri€n Taylor c6 di€n xung quanh di€m x =a ma cling bi€t iif ... @LieWil~iJuU! (n+l) = II II g [(x-ay+l +(Y_Xy+l] 00 (n + I) ! (n+l) II II S g 00 (n + I) ! (y-aY+\ do, bit d~ng thuc sail cling cua (2.16) du
... (n +I) !' \:IxE [O,y] Han mIa, n6u chon x = Y , ta co y n-l (4.4 ) ( I) k + - eY -I- elI k=O < eYyn+l -2n(n +I) !' yk+l (k + I) ! 2k+l \:Iy:2:0 4.2 Ham g(x) = lux Ta xet ham g: (0,+00)~ IR, g(x)= Inx, ... = sinx, khid6 g(k)(X) = sin(x + k ;), \:Jk E Z+ va (4.17) Ilg(n +I) IL = a~t~y suplg(n+J)(t)1 ~ Ap dl;lng b~t dAngthuc (2.16), ta thu duQc (4.18) Isiny-sina-! nI( y-x )k+l + ( l)k ( - (k + I) ! ... x-a )k+1 sin x+(k+l) ( < - (n+l)![(y-x)n+1 +(x-ay +I] < (y-ay+l > (n + I) ! ' Y - a Truong hQp rieng, n€u chQn a = (4.18), ta duQc n -I (4.19) siny- I k=O n ( - X ) k+1 + ( -I ) k Xk+1 y sin x+(k+l)(...
... - I (y -k!a) k=O (n+l) k II II g(k)(a) S g (y - ay+l, Vy ~ a (n + I) ! 00 Ta cling bi€t rang (2.18) cho mQt danh gia tITcong thuc khai tri€n Taylor c6 di€n xung quanh di€m x =a ma cling bi€t iif ... @LieWil~iJuU! (n+l) = II II g [(x-ay+l +(Y_Xy+l] 00 (n + I) ! (n+l) II II S g 00 (n + I) ! (y-aY+\ do, bit d~ng thuc sail cling cua (2.16) du