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ccna final exam answers 2013 version 4 0

Tài liệu Take Assessment - ENetwork Final Exam - Network Fundamentals (Version 4.0) pdf

Tài liệu Take Assessment - ENetwork Final Exam - Network Fundamentals (Version 4.0) pdf

Quản trị mạng

... allows 5 10 hosts given the IP address 172. 30. 0 .0? 255.255 .0. 0255.255. 248 .0 255.255.252 .0 255.255.2 54. 0 255.255.255 .0 255.255.255.128 30 file:///C:/Users/Martinos/Desktop/cisco/HTML /exam. htm 14 van ... 255.255.255. 248 ; Default Gateway: 192.168. 100 .18IP address: 192.168. 100 .22; Subnet Mask: 255.255.255. 2 40 ; Default Gateway: 10. 1.1.5IP address: 192.168. 100 . 30; Subnet Mask: 255.255.255. 2 40 ; Default ... 192.168.1.1IP address: 192.168. 100 .31; Subnet Mask: 255.255.255. 2 40 ; Default Gateway: 192.168. 100 .189 file:///C:/Users/Martinos/Desktop/cisco/HTML /exam. htm11 van 15 10/ 01/ 200 8 20: 03Refer to the exhibit....
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Tài liệu CCNA Semester 4 - Skills Based Final Exam - Student Training Instructor Guidelines - Exam Overview and Administration doc

Tài liệu CCNA Semester 4 - Skills Based Final Exam - Student Training Instructor Guidelines - Exam Overview and Administration doc

Quản trị mạng

... Ip route 172. 50. 2 .0 255.255.255 .0 172. 50. 1.2 Ip route 172.16 .0. 0 255.255 .0. 0 202 .168. 10. 2 ip route 0. 0 .0. 0 0. 0 .0. 0 202 .168. 10. 1 ip access-list 101 deny tcp any 172. 50. 1 .0 0 .0. 0.255 eq telnet ... Semester 4 Skills Based Final – Part 1 Router Configuration Student Training – Frame Relay Scenario – ( 60 pts) HeadQuartersMainOfficeSerial 202 .168. 10. 0/ 24 172. 50. 1 .0/ 24 HQ NetworkS0/.1(DCE)S0/.2E0S1Frame ... NetworkS0/.1(DCE)S0/.2E0S1Frame RelayNetworkRemoteOffice172.16.1.99/ 24 DLCI 201 172.16.1.88/ 24 DLCI 101 Configuring theHeadquarters RouterSalesOfficeE0 E1172. 50. 2 .0/ 24 Sales NetworkSwitchSwitchE1Switch172.16 .0. 0/16MainOffice...
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CCNA LAB GUIDE Version 4.0

CCNA LAB GUIDE Version 4.0

Công nghệ thông tin

... chỉ IP Ví dụ 1: 172.16 .0. 0 0. 0.255.255 172.16 .0. 0 = 101 01 100 .00 0 100 00. 000 000 00. 000 000 00 0. 0.255.255 = 00 000 000 .00 000 000 .11111111.11111111 result = 101 01 100 .00 0 100 00. xxxxxxxx.xxxxxxxx 172.16.x.x ... IP nằm trong khoảng từ 172.16 .0. 0 và 172.16.255.255 sẽ tương ứng với ví dụ này) Ví dụ 2: 172.16.8 .0 0 .0. 7.255 172.168.8 .0 = 101 01 100 .00 0 100 00. 000 0 100 0 .00 000 000 Created by: Dương Văn Toán ... Interface-type 0/ port fa0 /0 & fa0/1 gi0 /0 & gi0/1 Slot 0 HWIC/HWICD/ WIC/VWIC/ VIC Interface-type 0/ slot/ port s0 /0/ 0 & s0 /0/ 1 fa0 /0/ 0 & 0/ 0/1 Slot 1 HWIC/HWICD/...
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CCNA Semester 3 - Skills Based Final Exam - Student Training Instructor Guidelines - Exam Overview and Administration

CCNA Semester 3 - Skills Based Final Exam - Student Training Instructor Guidelines - Exam Overview and Administration

Quản trị mạng

... 1 171.17 .0. 65 - 171.17 .0. 126 16 171.17 .4. 1 - 171.17 .4. 62 2 171.17 .0. 129 – 171.17 .0. 1 90 17 171.17 .4. 65 - 171.17 .4. 126 3 171.17 .0. 193 – 171.17 .0. 2 54 18 171.17 .4. 129 - 171.17 .4. 1 90 4 171.17.1.1 ... Interface S0: 171.17.255.66 – 171.17.255.126 Interface S0: 171.17.2 54. 1 94 –171.17.2 54. 2 54 Interface S1: 171.17.255.2 – 171.17.255.62 Interface S1: 171.17.2 54. 1 30 –171.17.2 54. 1 90 4. LAN ... Interface Ethernet 0 IP addr: 171.17.255.1 30 CCNA Semester 3 - Skills Based Final Exam - Student Training Instructor Guidelines - Exam Overview and Administration – Cont. Exam Part 2 - Troubleshooting...
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Tài liệu TestKing''''s Designing Cisco Network Service Architectures Exam Version 4.1 doc

Tài liệu TestKing''''s Designing Cisco Network Service Architectures Exam Version 4.1 doc

Chứng chỉ quốc tế

... Answer: A, B, D, F QUESTION NO: 64 What is the device weight limit per CallManager in a Cisco IP phone configuration? A. 2 500 B. 300 0 C. 500 0 D. 6 500 Answer: C QUESTION NO: ... B. Set the MTU higher than 1 500 bytes. C. Turn off pre-fragmentation for IPSec. D. Set the MTU value to 1 40 0 bytes. Answer: C, D QUESTION NO: 50 642 - 871 Leading the way in ... standard provides backward compatibility with 802 .11b? A. 802 .11a B. 802 .1q C. 802 .11g D. 802 .11p Answer: C QUESTION NO: 73 642 - 871 Leading the way in IT testing and certification...
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Tài liệu Chapter 5 - OSI Network Layer CCNA Exploration version 4.0 ppt

Tài liệu Chapter 5 - OSI Network Layer CCNA Exploration version 4.0 ppt

Quản trị mạng

... known as routing. 4. DecapsulationHọc viện mạng Bách khoa - Website: www.bkacad.com 4 ( Refer to 5.1.1 ) Network Layer FieldsHọc viện mạng Bách khoa - Website: www.bkacad.com 14 ã 8 bitsã Specifies ... www.bkacad.com 17ã 3 bits(R, DF. MF) R(reserved): set to 0. DF(Dont fragment): ã 0: Fragment if necessary.ã 1: Do not fragment. MF(More fragment):ã 0: This is the last fragment.ã 1: More fragment ... www.bkacad.com 44 Hierarchical Addressingã Hierarchical addressing solves the problem of devices communicating across networks of networks.Học viện mạng Bách khoa - Website: www.bkacad.com 34 ...
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Tài liệu Chapter 4 - OSI Transport Layer CCNA Exploration version 4.0 docx

Tài liệu Chapter 4 - OSI Transport Layer CCNA Exploration version 4.0 docx

Quản trị mạng

... SummaryHọc viện mạng Bách khoa - Website: www.bkacad.com 45 Chapter 4 - OSI Transport Layer CCNA Exploration version 4. 0CCNA Exploration version 4. 0 Flow ControlWhen datagrams arrive too quickly ... indicator to the sender to stop sending data. Học viện mạng Bách khoa - Website: www.bkacad.com 40 sender to stop sending data. When the receiver can handle additional data, the receiver sends ... indicator. When this indicator is received, the sender can resume the segment transmission. Labs 44 Học viện mạng Bách khoa - Website: www.bkacad.com Managing TCP SessionsHọc viện mạng Bách khoa...
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Tài liệu CCNA LAB GUIDE Version 4.0 P2 docx

Tài liệu CCNA LAB GUIDE Version 4.0 P2 docx

Quản trị mạng

... http://www.vnexperts.net 40 0. 0 .0. 7.255 = 00 000 000 .00 000 000 .00 000 111.11111111 result = 101 01 100 .00 0 100 00. 000 01xxx.xxxxxxxx 00 001 xxx = 00 001 000 to 00 001 111 = 8–15 xxxxxxxx = 00 000 000 to 11111111 = 0 255 Mọi ... chỉ IP Ví dụ 1: 172.16 .0. 0 0. 0.255.255 172.16 .0. 0 = 101 01 100 .00 0 100 00. 000 000 00. 000 000 00 0. 0.255.255 = 00 000 000 .00 000 000 .11111111.11111111 result = 101 01 100 .00 0 100 00. xxxxxxxx.xxxxxxxx 172.16.x.x ... IP nằm trong khoảng từ 172.16 .0. 0 và 172.16.255.255 sẽ tương ứng với ví dụ này) Ví dụ 2: 172.16.8 .0 0 .0. 7.255 172.168.8 .0 = 101 01 100 .00 0 100 00. 000 0 100 0 .00 000 000 Created by: Dương Văn Toán...
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Tài liệu CCNA LAB GUIDE Version 4.0 P1 pptx

Tài liệu CCNA LAB GUIDE Version 4.0 P1 pptx

Quản trị mạng

... Interface-type 0/ slot/ port s0 /0/ 0 & s0 /0/ 1 fa0 /0/ 0 & 0/ 0/1 Slot 1 HWIC/HWICD/ WIC/VWIC/ VIC Interface-type 0/ slot/ port s0/1 /0 & s0/1/1 fa0/1 /0 & 0/ 1/1 NME slot ... Interface-type 0/ slot/port S0 /0/ 0 và s0 /0/ 1 Slot 1 HWIC/WIC/VWIC Interface-type 0/ slot/port S0/1 /0 và s0/1/1 2 801 On board Fast Ethernet Interface-type 0/ port Fa0 /0 và fa0/1 Slot 0 VIC /VWIC ... Interface-type 0/ port Fa0 /0 và fa0/1 Slot 0 WIC (serial) Interface-type 0/ port S0 /0 và S0/1 1 841 On board Fast Ethernet Interface-type 0/ port Fa0 /0 và fa0/1 Slot 0 High-speed WAN Interface...
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Tài liệu Cisco: CCNA® 3.0 (Cisco® Certified Network Associate 3.0) Exam 640-607 - Version 6.0 docx

Tài liệu Cisco: CCNA® 3.0 (Cisco® Certified Network Associate 3.0) Exam 640-607 - Version 6.0 docx

Chứng chỉ quốc tế

... Signaling channel (D). Reference: Cisco CCNA Exam # 6 40 - 607 Certification Guide. (Cisco Press: 200 2) page 549 . Q.36 Access-list 122 permit ip 131. 107 . 30. 0 0. 0 .0. 255 any You apply the access-list ... Press: 200 0) pages 41 5 – 41 6. Q .47 Which hardware device enables high-speed data exchange on a LAN? A. Hub B. Bridge C. Switch D. Repeater 6 40 - 607 16 21certify.com D. 00 -00 -12- 34- FE-AA ... Cisco: CCNA 3 .0 (Ciscođ Certified Network Associate 3 .0) Exam 6 40 - 607 Version 6 .0 Jun. 17th, 200 3 6 40 - 607 7 21certify.com ...
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Tài liệu CCNA Semester 1 - Skills Based Final Exam - Student Training Guidelines - Exam Overview and Administration docx

Tài liệu CCNA Semester 1 - Skills Based Final Exam - Student Training Guidelines - Exam Overview and Administration docx

Quản trị mạng

... routing protocol service network 152. 20. 0 .0 Enables RIP advertisements to be broadcast and received for network 152. 20. 0 .0 (on interface E1) network 193.5.5 .0 Enables RIP advertisements to be ... 193.5.5 .0 (on interface E0) int e0 Selects interface E0 for configuration ip address 193.5.5.1 255.255.255 .0 Sets IP address and subnet mask for E0 no shutdown Brings up interfaces E0 int ... Scored: ____________ CCNA Semester 1 - Skills Based Final Exam - Student Training Guidelines - Exam Overview and Administration This exam is for use with regular CCNA classes taught by...
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Tài liệu CCNA Semester 2 - Skills Based Final Exam - Student Training Instructor Guidelines - Exam Overview and Administration doc

Tài liệu CCNA Semester 2 - Skills Based Final Exam - Student Training Instructor Guidelines - Exam Overview and Administration doc

Quản trị mạng

... ____________ CCNA Semester 2 - Skills Based Final Exam - Student Training Instructor Guidelines - Exam Overview and Administration This exam is for use with regular CCNA classes taught ... CCNA Semester 2 - Skills Based Final Exam - Student Training Instructor Guidelines - Exam Overview and Administration – Cont. Exam Part 2 – Troubleshooting ... working on Part 3, the Network Concepts portion of the exam. Exam Part 1 – Router Configuration – (Practical hands-on, Max. time 40 min., 60 Points) Objective: Configure the standard 5-router...
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CCNA Lab Book version 4  - Access Control List

CCNA Lab Book version 4 - Access Control List

Quản trị mạng

... Phiên bản tiếng Việt Trang 2/7 CCNA Lab Book version 4 VDC Training Center 4. Cấu hình Extend ACL trên R1, chặn dữ liệu từ 192.168. 10. 0/ 24 đến 209 .165. 200 .255, cho phép các phần còn lại. ... Trang 4/ 7 CCNA Lab Book version 4 VDC Training Center Phiên bản tiếng Việt Trang 6/7 CCNA Lab Book version 4 VDC Training Center YZ Phiên bản tiếng Việt Trang 7/7 CCNA Lab Book version ... mạng 10. 2.2 .0/ 252, 192.168. 30. 0/ 24 b. Gán ACL vào line vty c. Kiểm tra kết quả - Thực hiện telnet tới R2 từ R1, ta có kết quả như bên dưới (chú ý, R1 sẽ lấy IP nguồn là 10. 1.1.1...
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