4 2 methods for environmental valuation
Tài liệu Statistical Methods for Environmental Pollution Monitoring pdf
... 10 11 12 10 11 12 1 1 1 1 1 2 2 2 2 2 2 3 3 3 n = 48 STATION 6 .29 6.11 5.66 5.16 4. 75 6.79 4. 51 1.37 4. 95 5 .22 5.73 6. 72 7 . 42 7.56 6.13 6. 24 5.07 1.95 4. 59 5 .22 5.13 5.69 6 .41 7.53 7. 02 6.93 ... 10 11 12 48 S~ATIOW 6. 32 6.08 5.16 1.17 1.13 3.65 3 .48 3.78 3. 94 4 .40 4. 94 5. 32 5. 82 5.76 4. 88 4. 84 4.87 4. 13 3.51 1. 32 1.06 1 .47 5.05 5 .20 5.83 5.65 5. 32 5.33 4. 20 3.85 1 .45 STIT~OU WUlBfR OF ... 1. 645 Hence, , C = 1. 645 [VAR(S)]'" = 1. 645 [58.IJ1" = 12. 54 where the value for VAR(S) was obtained fmm Example 16.3 Since N' = 24 , we have M, = ( 24 12. 54) /2 = 5.73 and M2 I = ( 24 + 12. 54) 12...
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ENCYCLOPEDIA OF ENVIRONMENTAL SCIENCE AND ENGINEERING - STATISTICAL METHODS FOR ENVIRONMENTAL SCIENCE potx
... (10) (11) © 20 06 by Taylor & Francis Group, LLC C019_0 04_ r03.indd 11 24 11/18 /20 05 1:30:56 PM 1 125 STATISTICAL METHODS FOR ENVIRONMENTAL SCIENCE 1.0 0.6 0.8 F(X) 0.6 0 .4 0 .4 0 .2 0.0 –3 2 –1 X(σ ... frequency for samples from that population Flower color Red Number of plants Pink White expected 25 50 25 observed 28 48 24 © 20 06 by Taylor & Francis Group, LLC C019_0 04_ r03.indd 1 127 11/18 /20 05 ... variables to predict the variable of interest The formula for three variables is r1 .23 ϭ 2 r 12 ϩ r13 Ϫ 2r 12 r13r23 1Ϫ r23 ( 32) Generalizations are available for larger numbers of variables If the variables...
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Advanced Mathematical Methods for Scientists and Engineers Episode 2 Part 4 ppsx
... , C2 and C2 C z dz = z3 − C1 z− + √ C2 z− C3 z− + = 2 + 2 + 2 z− √ √ √ z− z− z √ dz e 2 /3 z − e− 2 /3 z √ √ dz 2 /3 z − 9e z − e− 2 /3 z √ √ dz z − e 2 /3 z − e− 2 /3 z− 9 √ z e 2 /3 ... C2 -4 -6 C C1 -2 C3 -2 -4 Figure 11 .4: The contours for z z −9 the Cauchy Integral Formula to evaluate the integral C d sin z sin z dz = 2 − 4) dz z − z=0 cos z sin z = 2 − z − (z − 4) 2 ... continuously deformed to C2 on the domain where the integrand is analytic Thus the integrals have the same value 5 14 -4 -2 -2 -4 Figure 11 .2: The contours and the singularities of 3z +1 -6 -4 -2 -2 -4 -6...
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Advanced Mathematical Methods for Scientists and Engineers Episode 4 Part 2 pps
... + x + x2 /2 + O(x3 ))(x + a2 x2 + a3 x3 + O(x4 )) = (2a2 x + 6a3 x2 ) + (2x + 4a2 x2 ) + (6x + 6(1 + a2 )x2 ) = O(x3 ) = 17 a2 = 4, a3 = 17 y1 = x − 4x2 + x3 + O(x4 ) Now we see if the second ... yields z= t dz = − dt t d d = −t2 dz dt w + d2 d d = −t2 −t2 dz dt dt d d = t4 + 2t3 dt dt 1 24 0 The equation for u is then t4 u + 2t3 u + (2t + 3t2 )(−t2 )u + t2 u = u + −3u + u = t We see that ... − a0 (2n)(2n − 2) · · · · a0 = (−1)n n , n≥0 m=1 2m = (−1)n a2n−1 2n + a2n−3 = (2n + 1)(2n − 1) a2n+1 = − a1 (2n + 1)(2n − 1) · · · · a1 = (−1)n n , n≥0 m=1 (2m + 1) = (−1)n If {w1 , w2 } is...
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Tài liệu ESSAY OUTLINE ( FOR IELTS ) TOPIC 4-2 doc
... figuring out budgets are all good practice for life after graduation -> grow into adulthood - A better perspective on what is going on around them 22 You have been told that dormitory rooms at ... that going to classes should be optional for students Which point of view you agree with? Use specific reasons and details to explain your answer TOEFL 14 - Why should attend the class? - Personal ... to absorb information and apply what they’ve learned to other situations - Teach them how to work with the other members of the class - Teach students responsibility and discipline 20 Some people...
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METHODS IN ENVIRONMENTAL BIOTECHNOLOGY FOR ENVIRONMENTALISTS pot
... 190 .41 Total 21 8 .28 46 Proposed land use – 20 01 Use Area in km Residential 66. 72 Commercial 4. 18 Industrial 18.37 Educational 6.31 Public and semi pub 1 .48 Agricultural 121 .19 Total 21 8 .28 As ... = 28 C1 C2 C3 C C5 C6 C7 C8 1§ 0 0.6 0.1 0 .2 0 .4 0.8 0.1 · ¨ ¸ 2 0 0 0 0 ¸ 3¨ 0 0 0 0 ¸ ¨ ¸ 4 0 0 0 0 ¸ 5¨ 0 0 0.1 0 .2 0.1 ¸ ¨ ¸ ¨ 0.1 0 0 .2 0.3 0.5 0.7 0 .2 ¸ ¨ 0 .2 0.1 0 0.1 0.3 0 .2 ¸ ¨ ¸ ¨ ... 0 .2 ¸ ¨ ¸ ¨ 0.3 0.3 0 0 .2 0.6 0.1 ¸ ¨ ¸ ¨ 0.5 0 0 0.5 0 .4 0.1 ¸ 10 ¨ 0.1 0.3 0 0.7 0 .2 ¸ ¨ ¸ 11 ¨ 0 0 0 0.6 ¸ 12 ¨ 0 0 0 0 ¸ ¨ ¸ 13 ¨ 0 0 .2 0 0.8 ¸ 14 ¨ 0 0 0.3 0 .2 0.6 0 .2 ¸ ¨ ¸ 15 ¨ 0 0 0 0 ¸...
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Handbook of Residue Analytical Methods for Agrochemicals VOLUME 1 and VOLUME 2 doc
... study findings 21 1 21 2 21 3 21 3 21 3 21 5 21 5 21 5 21 6 21 8 21 8 21 9 22 3 2 24 2 24 2 24 22 6 22 7 22 7 22 7 22 8 23 0 23 0 23 1 23 1 23 1 23 2 23 3 2 34 23 5 23 6 23 7 23 8 23 9 23 9 24 0 24 1 24 1 24 2 24 2 24 3 24 5 Contents of ... 121 3 121 3 121 3 12 14 12 14 12 14 121 5 121 5 121 6 121 6 121 6 121 7 121 7 121 7 121 7 121 8 121 9 121 9 121 9 121 9 122 0 122 1 122 1 122 2 122 2 122 2 122 3 122 3 122 3 12 24 12 24 122 5 122 5 122 5 122 6 122 6 122 6 122 7 122 7 ... 122 8 122 8 122 8 122 9 122 9 123 0 123 0 123 0 123 0 123 1 123 1 123 1 123 2 123 2 123 2 123 3 123 3 12 34 12 34 123 5 123 5 123 5 123 5 123 6 123 6 123 6 123 7 123 8 123 8 123 9 1 24 0 1 24 1 1 24 2 1 24 2 1 24 3 1 24 3 1 24 3 1 24 3 1 24 4 ...
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UNIT 2. FORMATS FOR ELECTRONIC DOCUMENTS AND IMAGES LESSON 4. PORTABLE DOCUMENT FORMAT (PDF)NOTE potx
... necessarily the best format for dissemination of documents Formats for electronic documents and images - Portable document format (pdf) – page When to use PDF? Portable Document Format (PDF) is a ... format to use for its dissemination… The best format for document delivery depends on what you’re doing with the document To create and edit a document, Microsoft Word can be an appropriate format ... objects Formats for electronic documents and images - Portable document format (pdf) – page Summary • PDF (Portable Document Format ) is a procedural mark-up language that allows page-formatted...
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Báo cáo hóa học: " Comparison of four different methods for reliability evaluation of ecotoxicity data: a case study of non-standard test data used in environmental risk assessments of pharmaceutical substances" pdf
... Ågerstrand et al Environmental Sciences Europe 20 11, 23 :17 http://www.enveurope.com/content /23 /1/17 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 European and Global Challenges Edited ... Toxicology 20 02, 60 :28 5 -29 9 Mattson B: A voluntary environmental classification system for pharmaceutical substances Drug Information Journal 20 07, 41 (2) :187-191 Ågerstrand M, Rudén C: Evaluation ... Toxicology 20 02, 43 :22 9 -23 5 Robinson AA, Belden JB, Lydy MJ: Toxicity of fluoroquinolone antibiotics to aquatic organisms Environmental toxicology and Chemistry 20 05, 24 ( 2) : 42 3 -43 0 Schmitt-Jansen...
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Báo cáo hóa học: "Research Article Time-Frequency and Time-Scale-Based Fragile Watermarking Methods for Image Authentication Braham Barkat1 and Farook Sattar (EURASIP Member)2 1 Department 2 Faculty" pdf
... 0.1880 0.0313 0 .2 847 0.0781 0. 341 3 0.1357 0 . 42 14 0 .21 68 0 .46 34 l=1 0 .45 87 0 .48 02 0 .48 32 0.50 34 0 .49 95 0 .49 78 Table 3: Bit error rate (BER) values of the extracted watermarks obtained for other types ... Comp 0. 120 2 Salt-and-pepper noise Actual PSNR Quality Assessment (QF) (dB) MSE 45 .97 2. 0 025 ×10−5 45 .35 5. 146 0 ×10 4 32. 89 98% 44 .41 0.00 14 28 .69 95% 41 .53 0.0101 19.95 90% 38.83 0. 026 7 15. 74 80% ... 15. 74 80% 35. 94 0.0 641 11.93 70% 34. 41 0.0956 10.19 60% 33. 34 0.1061 9. 74 50% 32. 56 0. 122 7 9.11 w mag (i) − , Nw i=1 given by 26 7, 26 8, 28 3, 2 84, 29 9, 300, 315, 316, 331, and 3 32, exactly match...
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Quantitative Methods for Business chapter 2 doc
... by elimination: (a) 3x ϩ 2y ϭ xϩ yϭ3 (c) 2x ϩ 7y ϭ 4x ϩ 3y ϭ 17 (d) 6x ϩ 6y ϭ 27 4x ϩ 5y ϭ 22 2 .4 (b) 5x ϩ 3y ϭ 19 2x Ϫ y ϭ (e) 3x Ϫ 2y ϭ x ϩ 4y ϭ 26 (f) 12x ϩ 4y ϭ 2x Ϫ y ϭ Following a crash, ... chartered) 120 100 80 Cargo 60 Passenger 40 20 0 20 40 60 x (Lotkas chartered) 80 100 80 100 Figure 2. 22 The feasible region in Example 2. 23 y (Soodnas chartered) 120 100 80 60 40 A 20 0 20 40 60 x ... Quantitative methods for business Cost/Revenue (£m) 48 Chapter 16 14 12 10 0 20 40 60 Output (000) 80 100 120 Figure 2. 11 Total cost and total revenue lines in Example 2. 11 In Figure 2. 11 the steeper...
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Quantitative Methods for Business chapter 4 doc
... 2 4. 11 5 2 4 4 4 Arrange these data into a frequency distribution The ages of 28 applicants for a graduate management trainee post are: 21 23 21 21 23 21 24 22 21 24 21 26 23 22 21 22 23 21 22 ... 6 .48 4. 90 4. 52 5.11 5. 94 5. 82 7. 14 7 .28 8.15 7. 04 4.67 6.90 5.85 5.65 5.50 4. 12 5 .27 5 .25 6 .43 4. 65 5.37 4. 24 6 .45 4. 70 5.09 4. 82 6 .23 5 .40 5 .26 Construct a grouped frequency distribution for ... 35 53 72 50 70 49 58 35 62 47 55 87 54 38 64 39 44 67 44 79 70 40 67 57 64 85 63 34 52 89 59 38 The marks for the staff from Southampton were: 51 85 29 4. 20 65 78 49 74 75 68 24 46 81 45 28 66...
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Quantitative Methods for Ecology and Evolutionary Biology (Cambridge, 2006) - Chapter 2 pptx
... partial differential equations 140 Figure 2. 9 The bifurcation plot of N(500) versus r; see text for details 120 N(500) 100 80 60 40 20 1 .2 1 .4 1.6 1.8 r 2. 2 2 .4 2. 6 2. 8 How we understand what is ... 15 20 25 30 35 40 45 50 Time, t (d) 150 150 Population size, N (t ) Population size, N (t ) 50 10 15 20 25 30 35 40 45 50 Time, t (c) 100 50 0 100 50 10 15 20 25 30 35 40 45 50 Time, t (e) 10 20 ... Expected reproductive success 120 30 Size (cm) 25 20 15 10 0 10 15 Age (yr) 20 25 30 100 80 60 40 20 0 10 15 Age (yr) 20 25 Figure 2. 2 (a) von Bertalanffy growth for an organism with asymptotic...
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Quantitative Methods for Ecology and Evolutionary Biology (Cambridge, 2006) - Chapter 4 pot
... size 143 40 30 40 30 20 20 10 10 0 50 100 150 Generation 20 0 25 0 300 0 50 100 150 Generation 20 0 25 0 300 (c) 70 60 Population size 50 40 30 20 10 0 50 100 150 Generation 20 0 25 0 300 Figure 4. 7 ... 0 10 15 Generation 20 25 30 10 15 Generation 20 25 30 (c) 160 Hosts Population size 140 120 100 80 Parasitoids 60 40 20 0 10 15 Generation 20 25 30 Figure 4. 6 Allowing for variation in the attack ... 141 1 42 The evolutionary ecology of parasitoids (a) (b) 70 50 45 Hosts 60 35 Population size Population size 40 30 25 20 15 40 30 Parasitoids 20 10 10 Parasitoids Hosts 50 0 10 15 Generation 20 ...
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Advanced Mathematical Methods for Scientists and Engineers Episode 1 Part 2 ppt
... |a · b| 44 The area of the quadrilateral is then, 1 1 |(3i + j) · (i + 2j)| + |(i − 5j) · (−i − 4j)| = (5) + (19) = 12 2 2 y (3,7) (2, 3) (4, 2) (1,1) x Figure 2. 15: Quadrilateral Solution 2. 7 The ... b2 (−i) = (a2 b3 − a3 b2 )i − (a1 b3 − a3 b1 )j + (a1 b2 − a2 b1 )k Next we evaluate the determinant i j k a a a a a a a1 a2 a3 = i − j + k b2 b3 b1 b3 b1 b2 b1 b2 b3 = (a2 b3 − a3 b2 )i − (a1 ... + a2 j + a3 k) × (b1 i + b2 j + b3 k) = a1 i × (b1 i + b2 j + b3 k) + a2 j × (b1 i + b2 j + b3 k) + a3 k × (b1 i + b2 j + b3 k) = a1 b2 k + a1 b3 (−j) + a2 b1 (−k) + a2 b3 i + a3 b1 j + a3 b2...
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Advanced Mathematical Methods for Scientists and Engineers Episode 1 Part 4 pptx
... − sin2 x = lim x→0 24 cos2 x − 8x2 cos2 x − 64x cos x sin x − 24 sin2 x + 8x2 sin2 x = = lim It is easier to use a Taylor series expansion lim csc2 x − x→0 x2 x2 − sin2 x x→0 x2 sin2 x x2 − (x ... x→0 2x cos x sin x + 2x sin2 x − cos2 x + sin2 x = lim x→0 2x cos2 x + 8x cos x sin x + sin2 x − 2x2 sin2 x cos x sin x = lim x→0 12x cos2 x + 12 cos x sin x − 8x2 cos x sin x − 12x sin2 x cos2 ... , (2y(x) − x)3 105 Solution 3.15 a f (x) = ( 12 − 2x )2 + 2x( 12 − 2x)( 2) = 4( x − 6 )2 + 8x(x − 6) = 12( x − 2) (x − 6) There are critical points at x = and x = f (x) = 12( x − 2) + 12( x − 6) = 24 ( x...
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Advanced Mathematical Methods for Scientists and Engineers Episode 2 Part 1 pps
... are ux = vy and uy = −vx −(x − 1) + y −(x − 1 )2 + y 2( x − 1)y 2( x − 1)y = and = ((x − 1 )2 + y )2 ((x − 1 )2 + y )2 ((x − 1 )2 + y )2 ((x − 1 )2 + y )2 2 The Cauchy-Riemann equations are each identities ... satisfied for z = Note that the form fx = −ıfy will be far more convenient than the form ux = v y , uy = −vx 40 4 for this problem fx = 4( x + ıy)−5 e−(x+ıy) −ıfy = − 4( x + ıy)−5 ı e−(x+ıy) 4 4 = 4( x ... lim = lim z→0 cos (z ) =1 379 − 4z sin (z ) lim z→(nπ)1 /2 z − (nπ)1 /2 = lim 2) 1 /2 2z cos (z ) sin (z z→(nπ) = 1 /2 (−1)n 2( nπ) Example 8 .4. 4 e1/z is singular at z = The function is not analytic...
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Advanced Mathematical Methods for Scientists and Engineers Episode 2 Part 2 pptx
... function Recall that for analytic functions f , f = fx = −ıfy So that fx + ıfy = 2 2 + = ∂u2 ∂v dw dz −1 dw dz 2 2 dw + = 2 ∂u ∂v dz −1 2 2 2 + ∂x2 ∂y 2 2 + ∂x2 ∂y Solution 8.16 ... analytic 42 3 We calculate the first partial derivatives of u and v u x = ex −y uy = 2 e (x cos(2xy) − y sin(2xy)) x2 −y (y cos(2xy) + x sin(2xy)) vx = e x2 −y (y cos(2xy) + x sin(2xy)) vy = e x2 −y ... velocity field v= v= φ 2x(x + y − 1) 2y(x2 + y + 1) ˆ ˆ x+ y x4 + 2x2 (y − 1) + (y + 1 )2 x + 2x2 (y − 1) + (y + 1 )2 43 1 Figure 8.9: Velocity field and velocity direction field for φ = ln r − θ The...
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Advanced Mathematical Methods for Scientists and Engineers Episode 2 Part 3 ppt
... θ0 + π] z2 − dz ≤ z2 + z2 − |dz| C z +1 θ0 +π R2 e 2 −1 ≤ |R dθ| R2 e 2 +1 θ0 θ0 +π R2 + dθ R2 − θ0 R2 + = πr R −1 ≤R 49 0 Solution 10.6 f (z) dz = C √ π eıθ /2 ı eıθ dθ + r dr + 2 = + − −ı ... of the integral z = eıθ , θ ∈ [−π /2 π /2] 48 9 Log z dz ≤ |Log z| |dz| C C π /2 | ln + ıθ |2 dθ = −π /2 π /2 (ln + |θ|) dθ 2 −π /2 π /2 =4 (ln + θ) dθ π (π + ln 2) = We parameterize the contour and ... 2 ) 2 eınθ ı eıθ dθ (z − z0 )n dz = C = 2 eı(n+1)θ n+1 [ıθ ]2 for n = −1 = for n = −1 2 for n = −1 for n = −1 We parameterize the contour and the integration z − z0 = 2 + eıθ , 2 ...
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Tìm thêm: xác định các nguyên tắc biên soạn khảo sát các chuẩn giảng dạy tiếng nhật từ góc độ lí thuyết và thực tiễn khảo sát chương trình đào tạo của các đơn vị đào tạo tại nhật bản khảo sát chương trình đào tạo gắn với các giáo trình cụ thể xác định thời lượng học về mặt lí thuyết và thực tế tiến hành xây dựng chương trình đào tạo dành cho đối tượng không chuyên ngữ tại việt nam điều tra đối với đối tượng giảng viên và đối tượng quản lí khảo sát thực tế giảng dạy tiếng nhật không chuyên ngữ tại việt nam xác định mức độ đáp ứng về văn hoá và chuyên môn trong ct phát huy những thành tựu công nghệ mới nhất được áp dụng vào công tác dạy và học ngoại ngữ mở máy động cơ lồng sóc mở máy động cơ rôto dây quấn các đặc tính của động cơ điện không đồng bộ hệ số công suất cosp fi p2 đặc tuyến mômen quay m fi p2 đặc tuyến tốc độ rôto n fi p2 đặc tuyến dòng điện stato i1 fi p2 động cơ điện không đồng bộ một pha thông tin liên lạc và các dịch vụ từ bảng 3 1 ta thấy ngoài hai thành phần chủ yếu và chiếm tỷ lệ cao nhất là tinh bột và cacbonhydrat trong hạt gạo tẻ còn chứa đường cellulose hemicellulose