2 alkoxy 5 4h oxazolone formation and disproportionation

... and 22 2.3 The former ion showed fragment peaks with m/z 161.3, 149 .2 and 1 35 .2, the latter provided peaks with m/z 20 5 .2, 193 .2 and 176 .2 in the respective MS/MS spectra The peak with m/z 22 2.3 ... those with m/z 178.1 and 25 7.1 there were three more peaks with m/z 334.3 (fragmentation: m/z 317.3, 3 05 .2, 29 1.1, 25 3 .2 and 24 0.1), 350 .2 (fragmentation: m/z 333 .2 and 307.1) and 431.3 (fragmentation: ... values and elemental composition of ions: 161.11 (C10H13N2), 149.11 (C9H13N2), 1 35. 09 (C8H11N2), 109.08 (C6H9N2), 95. 06 (C5H7N2) and 82. 06 (C5H8N) Ó FEBS 20 04 4704 Z Lamplot et al (Eur J Biochem 27 1)...

Ngày tải lên: 19/02/2014, 16:20

... Biochem Parasitol 78, 24 9 25 7 14 Verschuur, A.C., Van Gennip, A.H., Leen, R., Voute, P.A., Brinkman, J & Van Kuilenburg, A.B (20 02) Cyclopentenyl 21 22 23 24 25 26 27 28 29 30 31 32 cytosine increases ... (AAC33441.1), Azospirillum brasilense (P2 859 5), Campylobacter jejuni (CAB 7 25 20.1), Heliobacter pylori (O 251 16), Borrelia burgdorferi (O51 52 2 ), Cricetulus griseus (P5 054 7), Mus musculus (P70698), Homo ... of % 25 and % 28 kDa In the presence of ATP and UTP (10 mM each) (B), and CTP (2. 5 mM) (C), only production of the 10- and 53 -kDa cleavage fragments is observed In the presence of GTP (2. 5 mM)...

Ngày tải lên: 23/03/2014, 17:22

... 0,45g N4 (0,0015mol) - 0 ,20 7g K2CO3 (0,0015mol) - 0, 322 g (0,0015mol) 2- chloro-N-(4-nitrophenyl)acetamide - Acetone c) Cách tiến hành Tương tự tổng hợp N5 thay 2- chloro-N-(p-tolyl)acetamide 2- chloroN-(4-nitrophenyl)acetamide ... 2- {4-amino -5- [(4,6-dimethylpyrimidin -2- ylthio)methyl] -4H1 ,2, 4-triazol-3-ylthio}-N-(4-metylphenyl)acetamide (N5) a) Phương trình phản ứng b) Hóa chất - 0,45g N4 (0,0015mol) - 0 ,20 7g K2CO3 (0,0015mol) - 0 ,27 5g (0,0015mol) 2- chloro-N-(p-tolyl)acetamide - Acetone c) Cách tiến hành Hòa tan 0,45g N4 ... III .2 Tổng hợp 4-amino -5[ (4,6-dimethylpyrimidine -2- ylthio)methyl]-1 ,2, 4triazole-3-thiol/thione (N4) .51 III .2. 1 Cơ chế phản ứng .51 III .2. 2 Phân tích phổ 52 IV...

Ngày tải lên: 12/05/2014, 23:15

... textual, and image content, the MetaMedia multimedia database platform is used to account for both metadata and content, and a browsing and searching interface is developed where all the various and ... description, transcription and image content,” C Calistru et al propose an indexing and retrieval environment for the integrated management of the vast and heterogeneous information often associated ... content descriptors by its curators, and generic users can access and browse the document center, searching the structured information in the descriptors and annotations, or finding documents...

Ngày tải lên: 21/06/2014, 18:20

... E-Commerce Project using ASP.NET 3 .5 in C# 20 08 and SQLServer 20 05 position: absolute; top: 16px; right: 10px; width: 180px; height: 80px; padding: 2px 2px 2px 2px; font-size: 9px; } /* Phần Theme ... E-Commerce Project using ASP.NET 3 .5 in C# 20 08 and SQLServer 20 05 22 Tạo thư mục App_Code:  Right-click project : KimSoft  Chọn : Add ASP.NET Folder  App_Code 23 Tạo lớp Helpers  Right-Click ... – longnamit@yahoo.com Page 22 Building CMS / E-Commerce Project using ASP.NET 3 .5 in C# 20 08 and SQLServer 20 05 GVHD: Dương Ngọc Long Nam – longnamit@yahoo.com Page 23 Building CMS / E-Commerce...

Ngày tải lên: 02/07/2014, 00:20

... sentence ? III Practice : Ss practice in pairs using the information in the grid Example exchange : S1 : Did her neighbor make the dress ? S2 : Yes, she did S1 : Did Hoa buy the material ? S3 : No, ... Yesterday, I went to and I bought (a/ some) _ Did you go to (name of a place / a shop) ? Did you buy _ (thing) ? IV Homework : Retell what you did yesterday ? (5 sentences) ...

Ngày tải lên: 03/07/2014, 21:20

... GRAMMAR: CHAPTER BE GOING TO, WILL, and THE PRESENT CONTINUOUS  Be going to and the Present Continuous as FUTURE: A INTENTIONS AND PLANS: Use BE GOING TO and THE PRESENT CONTINUOUS to talk about ... FUTURE with WILL and BE GOING TO: A Predictions with WILL and BE GOING TO + Use WILL or BE GOING TO to make predictions You can also use PROBABLY and other adverbs with WILL and BE GOING TO to ... statements and YES/NO questions It comes at the end of a sentence For example: They haven’t arrived yet / Have you met him yet? + STILL means “UP TO NOW” STILL is used in negative statements and comes...

Ngày tải lên: 04/07/2014, 03:21

Ngày tải lên: 10/07/2014, 22:20

... 1.9 2. 1 2. 2 2. 3 2. 4 2. 5 5.0000E-01 ###### 0.01 6.0365E-03 7.9762E-03 1.0444E- 02 1. 355 3E- 02 1.7 429 E- 02 2 .22 16E- 02 2.8067E- 02 3 .51 48E- 02 4.3633E- 02 5. 3699E- 02 6 .5 52 2 E- 02 7. 927 0E- 02 9 .50 98E- 02 1.1314E-01 ... 3.6693E-01 4. 051 7E-01 4.4433E-01 4.8405E-01 0. 05 5.3861E-03 7.1 428 E-03 9.3867E-03 1 .22 25E- 02 1 .57 78E- 02 2.0182E- 02 2 .55 88E- 02 3 .21 57 E- 02 4.0 059 E- 02 4.9471E- 02 6. 057 1E- 02 7.3 52 9 E- 02 8. 850 8E- 02 1. 056 5E-01 ... 8. 424 2E-03 1.1011E- 02 1. 426 2E- 02 1.8309E- 02 2. 329 6E- 02 2.9379E- 02 3.6 727 E- 02 4 .55 14E- 02 5. 5917E- 02 6.8112E- 02 8 .22 64E- 02 9.8 52 5 E- 02 1.1702E-01 1.3786E-01 1.6109E-01 1.8673E-01 2. 1476E-01 2. 451 0E-01...

Ngày tải lên: 21/07/2014, 15:20

... stresses and temperatures; and for VB = 0 .5 mm) to be 0.00 65 mm/min at a cutting speed of 100 m/min and 0. 024 mm/min at 20 0 m/min, and its change as VB increased could be followed Childs Part 31:3 :20 00 ... et al., 19 92) (C5) f2 Ra = ——— ≤ Ra, max 31.3rn (9 .22 ) where Ra,max is the required surface finish Chatter Chatter limits (C6) have been given by equation (9.15b), (9.15c) or (9.15e), and are often ... gi (x) (9.32a) Childs Part 31:3 :20 00 10:38 am Page 29 2 29 2 Process selection, improvement and control Fig 9. 12 Fuzzy optimization of cutting conditions; only three constraints 1, and 10 are considered...

Ngày tải lên: 21/07/2014, 17:20

... STUDENTS’ ACTIVITIES Activity 1: (3’) Warm up and review Work in pair: -Calls Ss to make a dialogue Activity 2: ( 10’) 1.Look, listen and repeat 1.Look, listen and repeat a- Pre listening T says about ... class Other listen carefully and remar b- White- listen Reads times c- Post-listen Call some Ss read again Activity3(10’) Look and say Look and say - Read follow teacher (2- 3 times Guide Ss to say ... listen and repeat go straight ahead Listen and repeat sentence by turn right sentence turn left on your right on your left You’re welcome Grammar Ss work in pair Guide Ss use question and answer...

Ngày tải lên: 23/07/2014, 14:22

... a v) 20 0 4oo 120 0 1400- 1600- 1800- 20 00- w (3 22 00 24 00 - 26 00 - 28 00 - 3000 Figure 9 .2 9.1 .5 Design chart for gear lubrication Lubrication Factor for Surface Durability Most gear rating and ... Chapter 24 Godfrey, D., NACA Technical Note No 20 39, 1 950 25 Wright, K H., Proc Inst Mech Engrs, London, l B , 19 52 , p 55 6 26 Row, C N., “Wear - Corrosion and Erosion, Interdisciplinary Approach to ... Technology,” NASA, SP-3 18, 1973 27 Almen, J O., “Lubricants and False Brinelling of Ball and Roller Bearings,” Mech Eng., 1937, Vol 59 , pp 4 15 422 28 Temlinson, G A., Thorpe, P L., and Gough, J H., “An Investigation...

Ngày tải lên: 05/08/2014, 09:20

... Tooth No £ *: Tooth No - 25 0 (0 4) 0, Tooth No -300 - 350 l>^ s > * r " , ^ - Tooth No Tooth No 10 50 100 150 Time in minutes -100 - 150 -20 0 - 25 0 -300 150 Time in minutes Fig 15. 4 Test results from ... rattle and give noise and there are fewer high speed shafts so lubrication and churning losses are lower Lower tooth frequencies generally give lower noise Chapter 14 22 6 50 100 150 20 0 25 0 Fig ... rl = (brl*psil - brl*tan(phi2))/(pi*cos(phio)); r2 = (br2*psi2 - br2*tan(phi2))/(pi*cos(phio)); conratio = rl + r2; disp(f angle rl r2 contact ratio') disp([ phi2 rl r2 conratio ]) phi3 = input('enter...

Ngày tải lên: 05/08/2014, 09:20

... Tooth No £ *: Tooth No - 25 0 (0 4) 0, Tooth No -300 - 350 l>^ s > * r " , ^ - Tooth No Tooth No 10 50 100 150 Time in minutes -100 - 150 -20 0 - 25 0 -300 150 Time in minutes Fig 15. 4 Test results from ... rattle and give noise and there are fewer high speed shafts so lubrication and churning losses are lower Lower tooth frequencies generally give lower noise Chapter 14 22 6 50 100 150 20 0 25 0 Fig ... rl = (brl*psil - brl*tan(phi2))/(pi*cos(phio)); r2 = (br2*psi2 - br2*tan(phi2))/(pi*cos(phio)); conratio = rl + r2; disp(f angle rl r2 contact ratio') disp([ phi2 rl r2 conratio ]) phi3 = input('enter...

Ngày tải lên: 05/08/2014, 09:20

... http://www.estec.esa.nl/wmwww/EMS/ARTESpresentation.htm, accessed May 22 , 20 04 [11] http://www.probeit.org.uk, accessed December 12, 20 04 [ 12] Demir, C., et al., “FCD for Urban Areas: Method and Analysis of Practical Realizations,” ... ReisezeitschÃtzung, day of notification: 12. 20 .20 02 [14] “Ford And Minnesota DOT Kickoff Road-Vehicle Communications Project,” IVsource.net, June 11, 20 04 [ 15] “Ford Launches Intelligent Highway ... accessed September 22 , 20 04 [18] “Floating Car Data: Zoom Information Systems Enters the Fray,” http://www.IVsource.net, August 20 04 [19] Private communication with Richard Weiland, Weiland Consulting...

Ngày tải lên: 05/08/2014, 11:20

... application must be clean, and chip and splinter proof Figure 7 -54 Keep unboxed bearings covered until ready for mounting  426 Machinery Component Maintenance and Repair Figure 7 -55 Cover subassemblies, ... preload depends upon the speed of the spindle and required operating temperatures and rigidity requirements  422 Machinery Component Maintenance and Repair Preloaded Replacement Bearings Normally ... characteristics Figure 7 -53 Check internal contact surfaces by turning outer ring slowly while holding inner ring Ball Bearing Maintenance and Replacement 4 25 such as internal fit, type and material of...

Ngày tải lên: 05/08/2014, 12:20

... cluster 6, application: p2p down ( 12% ) x 10 20 0 30 Typical day 12 20 Global p2p down 0.6 0 Typical customer p2p up 0.8 10 11 12 13 14 volume (in byte) 10 15 20 25 15 20 25 global mean 10 x 10 0 ... 0.6 0 80 20 0.8 10 11 12 13 14 0 volume (in byte) 10 15 20 25 15 20 25 Global mean 2. 5 x 10 1 .5 0 .5 0 10 Fig Profile of another cluster of customers (top left) and mean profile (bottom) and profiles ... value pid lid name 423 alias max (sugg) learner inst kernel inst default 15 64 0 . 25 15 64 C conf threshold false false 0 . 25 0.01 0.99 15 65 15 65 M nr inst/leaf false false 2 20 Learner inst Learner...

Ngày tải lên: 05/08/2014, 21:21

... Design 24 7 [20 ] A Efthymiou and J.D Garside, “Adaptive Pipeline Structures for Speculation Control”, Proceedings of Async'03, Vancouver, May 20 03, pp 46 55 ISBN 0-76 95- 1898 -2 ISSN 1 52 2 -8681 [21 ] ... Clockless 32- Bit Processor Core”, IEEE Micro, March 20 07, Vol 27 , No 2, pp 58 –68 ISSN: 027 2-17 32 [9] I Sutherland, “Micropipelines”, Communications of the ACM, June 1989, Vol 32, No 6, pp. 720 –738 ... UK, 20 02 [19] A Efthymiou and J.D Garside, “Adaptive Pipeline Depth Control for Processor Power-Management”, Proceedings of ICCD' 02, Freiburg, September 20 02, pp 454 – 457 ISBN 0-76 95 1700 -5 ISSN...

Ngày tải lên: 06/08/2014, 01:21

... n=0 ln (2n ) ln (3n ) + 1 ln(n + 20 ) 4n + 3n − ∞ (Logπ 2) n n=0 ∞ n =2 ∞ 10 n =2 n2 − n4 − n2 (ln n)n ∞ (−1)n ln 11 n =2 ∞ 12 n =2 ∞ 13 n =2 n (n! )2 (2n)! 3n + 4n + 5n − 4n − 5 62 ∞ 14 n =2 ∞ 15 n =2 ∞ 16 ... z +2 z + 5z + 1 √ =√ + z/3 + z /2 −1 /2 z −1 /2 z = √ 1+ + + ··· 3 z 3z z z2 = √ 1− + + ··· 1− + + ··· 24 32 17 = √ − z + z2 + · · · 12 96 12. 6 1+ −1 /2 z −1 /2 + 2 z 2 + ··· Laurent Series Result 12. 6.1 ... n=0 (ln 2) n n! (n + 1)(n + 2) 2n (−1)n n! (−1)n π 2n+1 (2n + 1)! (−1)n π 2n (2n)! (−π)n (2n)! Hint, Solution 57 0 Exercise 12. 24 Find the first three terms in the following Taylor series and state...

Ngày tải lên: 06/08/2014, 01:21

... = 0 .50 7 + 0 . 25 0 = 0. 757 in 3 52 Design of GAS-HANDLING Systems and Facilities (b)Head: |- == ( 1 25 ) ( 120 ) , _ ,— = y 50 5 in (2) (17 ,50 0) (0. 85) - (0 .2) ( 1 25 ) Required thickness = 0 .50 5 + 0 . 25 0 ... 0. 755 in Use—-in head (0.8 1 25 ) W = (0.34)(0.8 1 25 )( 120 )2 + (1.9)(0.8 1 25 )( 120 ) = 4,1631b (c) Cone: _ Pd ~ cos a (SE - 0.6P) t t= ( 1 25 ) ( 120 ) • = 0 .58 5 in (2 cos 30) (17 ,50 0 x 0. 85 - 0.6 x 1 25 ) ... (0 .23 ) (0 . 25 ) ( 120 )2 sin 30 lb (b) Shell: Height of cone = tan 30 = 8.7 ft Length of shell = 12 + 8.7 = 20 .7 ft Weight of shell = (11)( 120 )(0.8 1 25 ) (20 .7) = 22 ,20 0 Ib 353 354 Design of GAS-HANDLING...

Ngày tải lên: 06/08/2014, 02:20