1 8 propagation of electromagnetic waves

... the TE10 propagation mode these expressions for S 11 and S 21 are (Barroso and De Paula (2 010 ); Boughriet et al (19 97); Ghodgaonkar et al (19 90); Ligthart (19 83 )) ˆ S 11 = ˆ ˆ Γ − T2 , ˆ T2 1 Γ ˆ ... techniques of materials with thin configuration at microwave frequencies, Journal of Applied Physics 98( 8): 08 410 7 -1 08 410 7 -8 Nicolson, A M and Ross, G F (19 70) Measurement of the intrinsic properties of ... S 21 : from (5) and (6) one can write ˆ ˆ2 S2 − S 21 + ˆ K = 11 ( 21) ˆ 2S 11 ˆ ˆ ˆ Γ = K ± K2 − ˆ ˆ ˆ S 11 + S 21 − Γ ˆ T= ˆ 11 + S 21 Γ ˆ 1 S (22) (23) However, this procedure presents phase ambiguity...

Ngày tải lên: 19/06/2014, 19:20

... must accumulate on the surface of the conductors For example, in copper, τrel = ε 8. 85 × 10 12 = = 1. 6 × 10 19 sec σ 5.7 × 10 7 (84 ) By contrast, τrel is of the order of days in a good dielectric ... 11 = 1 + ( σ′ − 1 ) Cos 2I Sin 2D ′ 12 = −σ′2 SinI + ( σ′ − 1 ) Cos 2ICosDSinD ′ 13 = −σ′2CosICosD − ( σ′ − 1 ) CosISinISinD ′ σ 21 = σ′2 SinI + ( σ′ − 1 ) Cos 2ICosDSinD ′ ′ σ 22 = 1 ... Phys., Vol. 68 (12 ), pp .13 34 -13 39, 2006 [4] H Rishbeth, Review paper:The ionospheric E layer and F layer dynamos –a tutorial review, J Atmos Solar-Terr Phys., Vol.59 (15 ), pp . 18 73 - 18 80 , 19 97 [5] R...

Ngày tải lên: 19/06/2014, 19:20

... (1. 1 .12 ) gives dPs = If(i&, Using the Poynting T, O,, dA is dP S = I $1 dA = lSsl r2dS1, Putting coordinates (1. 1 .14 ) to define a dif- (1. 1 .15 ) (1. 1 .16 ) angle gives J d&If (s, &)I2 (1. 1 .17 ) $1. 1 ... &) by (1. 1 .14 ) dP S = ad&, IS i I and (1. 1 .15 ) gives ii) dfl, ad(L, b) = If (b, &)I2 Integrating (1. 1 .14 ) over scattered P S II i - S = (1. 1 .13 ) wave, from (1. 1.6), we have H = If&, h )12 da Comparing ... equation l d povl + $ (1. 5.7) in (1. 5 .11 ) v*pJG+~~=o aP1 (1. 5 .11 ) = gives (1. 5 .12 ) 32 ELECTROMAGNETIC From (1. 5.9) and (1. 5 .12 ) velocity c: SCATTERING we can form the wave equation d2p1 -V2Pl + -p@The...

Ngày tải lên: 17/03/2014, 13:40

... Structures 16 90 12 0 W 0 .8 0.6 15 0 W 0 .8 60 12 0 0.6 15 0 30 0.4 d TMz 90 12 0 60 30 0.4 90 0 .8 15 0 0.2 18 0 18 0 30 0.4 0.2 0.2 60 0.6 18 0 d 210 W 210 330 240 330 240 300 300 330 240 270 Wc=0 270 Wc=-0.0 015 ... configuration of linear array of three |Ez| 90 |Ez| j 90 12 0 60 90 60 0 .8 12 0 60 0 .8 0.6 d |Ez| 12 0 0 .8 0.6 15 0 30 0.6 15 0 30 0.4 15 0 30 0.4 0.2 0.4 0.2 18 0 0.2 18 0 18 0 j0 pla ne wa ve 210 330 240 ... -12 0 dielectric support -14 0 input waveguides -16 0 11 FDFD-MM EFIE [47] 11 .2 11 .4 11 .6 11 .8 12 f [GHz] (a) (b) Fig 11 Waveguide filter presented in Alessandri et al (2003): (a) schematic view of...

Ngày tải lên: 19/06/2014, 19:20

... ′ Λ = diag [ε 11 , ε 11 , ε 11 ] , 1 = diag [ε 11 , ε 11 , ε 11 ] (11 2) ′ ′ ′ Π = diag [ 11 , 11 , 11 ] , Π = diag [ 11 , 11 , 11 ] (11 3) 1 0  Φ = Ψ = 0    (11 4)  0 1   We can ... ω − 11 ε 11

Ngày tải lên: 19/06/2014, 19:20

... Univ., Vol 1, 69, 19 51 Fujisawa, K (19 58) General treatment of klystron resonant cavities, IRE Trans., MTT-6, 344, Oct 19 58 Gilmour, Jr.,A.S (19 86 ) Microwave Tube, Artech House, Chap 15 19 86 Goplen, ... = μ0 = 4π × 10 −7 H / m , hence, in case of that cavity material is copper, for f=6GHz, δ = 0 .85 μ m Rs = 2.02 × 10 −2 Ω R = 2.66 × 10 −3 Ω (17 ) 10 L = 1. 01 × 10 H L Q0 = ω = 14 31 R The shunt ... Digest, 10 27 19 96 Tobocman, W (19 84 ) Calculation of acoustic wave scattering by means of the Helmholtz integral equation I, J Acoust Soc Am., 76 (2), 599, Aug 19 84 Zander, A.T & Hieftje, G.M (19 81 ) ...

Ngày tải lên: 19/06/2014, 19:20

... 11 (2a) 11 (2b) 11 (2c) 11 (2d) 11 (2e) permittivity 5-7 5-6 5.5 -8 5.5-6 5-7.5 Samples number 5 13 10 11 high-grade ore medium-grade ore low-grade ore pyrite 11 (2f) 11 (2g) 11 (2h) 11 (2i) 10 -70 10 -12 ... Fig no 11 ( 4a) 11 (4b) 11 (4c) Permittivity 5-5.5 5-5.5 5-7.5 Samples number 14 11 albitophyre ore malachite oxide ore 11 (4d) 11 (4e) 5 -10 5-5.5 16 (No： 01- 09 ,11 -17 ) 14 (No.： 01- 14) Table Messages of rocks ... hornblende pyroxenite 11 (1d) 5 -17 pyroxene peridotite 11 (1f) 10 -20 ores: low-grade ore 11 (1g) 9-23 medium-grade ore 11 (1f) 20-70 high-grade ore 11 (1h) 5-95 Sample number 25 16 10 10 12 Table Rocks and...

Ngày tải lên: 19/06/2014, 19:20

... the estimation, like in [1] we have k = ω c = 2 ,1 ⋅ 10 m 1 , r = δ c = 2 ,1 ⋅ 10 m 1 , ω =6, 28 .10 12 s 1, δ = 6, 28 .10 13 s 1 For instance, the result of strength estimation of the electric filed impulse ... into account (1. 4) and (1. 5) there is ∂ ln E E0 ∂t ∂ ln = H H0 ∂t =0 (1. 11) By transforming (1. 11) we have ∂2 E ∂t 2  ∂ ln E  =  E  ∂t  (1. 12) 14 6 Behaviour of Electromagnetic Waves in Different ... V .17 7 № 10 P 11 33 11 37 [13 ] Mihajlov A.I., Mihajlov I.A A double nuclear photoeffect in relativistic region Angular and energy distributions of photoelectrons Moscow, JETP (19 98) V 11 4 № P 15 37...

Ngày tải lên: 19/06/2014, 19:20

... Rev Lett., Vol 53, No 16 , pp 15 55 15 58 (19 84 ) [20] Ch Fattinger, and D Grischkowsky, Point source terahertz optics, Appl Phys Lett., Vol 53, No 16 , pp 14 80 14 82 (19 88 ) [ 21] D H Auston, K P Cheung, ... Phys Lett., Vol 11 , No 12 , pp 386 388 (19 67)  18 8 Behaviour of Electromagnetic Waves in Different Media and Structures [ 51] A F Gibson, T W Granville, and E G S Paige, A study of energy-loss processes ... Opt Soc Am B, Vol 15 , No 6, pp 17 95 - 18 01 (19 98) [37] Q Wu, and X.-C Zhang, terahertz broadband GaP electro-optic sensor, Appl Phys Lett., Vol 70, No 14 , pp 17 84 -17 86 (19 97) [ 38] W L Faust, and...

Ngày tải lên: 19/06/2014, 19:20

... 0.6 0.9 1. 2 1. 5 1. 9 2.2 2.5 2 .8 3 .1 1.2 1. 1 1. 0 0.9 0 .8 0.7 0.6 0.5 0.4 0.3 0.2 0 .1 0.0 3.4 ts=0.98ps 0.0 0.3 0.6 0.9 1. 2 1. 5 1. 9 2.2 2.5 2 .8 3 .1 3.4 Time [ps] Time [ps] a) Wave shape of the Soliton ... field 1. 2 1. 2 0 .8 Ha [A/m] ts =0.98ps 0.4 Ea [V/m] 0.6 0 .8 0 .8 Vds [V] 1. 2 1. 0 1. 0 0.6 0.4 0.2 0.4 0.2 0.0 0.6 0.0 0.2 ts=0.98ps 0.0 0.3 0.6 0.9 1. 2 1. 6 1. 9 2.2 2.5 2 .8 3 .1 3.4 0.0 0.3 0.6 0.9 1. 2 ... Res., 11 0, doi :10 .10 29/2204JA 010 519 , 2005 [27] Carter, T A et al., Measurement of Lower-Hybrid Drift Turbulence in a Reconnecting Current Sheet, Phys Res Lett., 88 , DOI: 10 .11 03/PhysRevLett .88 . 015 0 01, 2005...

Ngày tải lên: 19/06/2014, 19:20

... 3.2G 10 G 1G 10 32 10 0 16 S 21 [dB] -10 -20 S 21 [dB] -10 -50 -60 -70 -80 -90 -10 0 10 k C02 C 01 LILC04 LILC 08 LILC16 LILC24 0 32k 10 0k 320k 1M 10 32 10 0 316 1, 3, 16 2 10 , 00 3.2M 10 M 32M 10 0M 320M 1G0 ... length 18 mm 12 mm 8mm 4mm 2mm 1mm 0.5mm 0.25mm 0 -10 -20 -30 -40 -50 -60 -70 -80 -40 0.25mm 0.5mm 1mm 2mm 4mm 8mm 12 mm 18 mm 10 0.7 63.5 40 .1 S 11 [dB] S 21 [dB] -20 -60 -80 -10 0 25.3 16 .0 10 .1 6.4 ... 2 71 Solitary Electromagnetic Waves Generated by the Switching Mode Circuit Fig 28 shows the circuit diagram of the test board VDD: 5V to Z1 LL1 OSC1 13 Z1 12 11 Z1 to Z2 LL2 10 Z1 Z3 ML1 11 Z2...

Ngày tải lên: 19/06/2014, 19:20

...  being the mass of free electron, ωo ≈ ωm,k,q z = 36.25meV , kB = 1. 380 7 10 -23j/K, no = 10 23m3, e = 1. 60 219 10 -19 C, ћ = 1. 05459 × 10 -34j/s Fig (13 ,14 ) shows the dependence of nonlinear absorption ... Vol 51, pp 13 2 513 30, ISSN 0374- 488 4, Available from http://www.kps.or.kr/jkps/downloadPdf.asp?articleuid=%7B9BAB8 5 18 -F80B41F5-A49D-5407B4 614 DD9%7D Bau, N Q and Phong ,T C (19 98) Calculations of ... Vol 48, pp 912 6- 912 9, ISSN 10 98- 012 1, ISSN(Online) 15 50235X, Available from http://prb.aps.org/abstract/PRB/v 48/ i12/p 912 6 _1 Rucker ,H.; Molinari ,E & Lugli, P. (19 92) Microscopic calculation of...

Ngày tải lên: 19/06/2014, 19:20

... Zeitschrift 31, 465-4 78 Hanl, H & Papapetrou, A (19 40) Zeitschrift fur Physik 1, 6, 15 3 - 18 3 Heisenberg, W (19 27) Z Phys 43, 17 2 (19 27) Huang, X, (2006) arxiv: physics/06 011 69 Jackson, J D (19 75) Classical ... University Press, Cambridge, 38- 40 Mulligan, B (20 08) Annals of Physics 3 21, 18 65 - 18 91 Neamtan, S M (19 52) Am J Phys 20, 450-4 51 Panofsky, W K H & Phillips, M (19 55) Classical Electricity and ... Royal Soc London A 13 3, 60-72 Dorling, J (19 70) Am J Phys 38, 510 - 512 Einstein, A (19 05) Ann.Phys .17 , 13 2 Feshbach, H (19 58) Ann Phys 5, 357-390 Feynman, R P (19 49) Phys Rev 76, (19 49) 749-759 Foldy,...

Ngày tải lên: 19/06/2014, 19:20

... x0 ei e1 > −4 f E1 < ( x0 + x2 + x3 )e1 e1 > +4 f E2 < x1x2 e1 e1 > +4 f E3 < x1x3 e1 e1 > 2          = [4 f E x0 x1 − f E (2 x0 − 1) + f E x1 x1 + f E x1 x2 + f E x1 x3 ] < e1 e1 >  ... x3 )e1 e1 − ( x0 + x1 + x3 )e1 e1 − ( x0 + x2 + x1 )e1 e1 >   2 2 2 2 2 2 2 2 2 = f Eμ [ xi xi − ( x0 + x2 + x3 ) − ( x0 + x1 + x3 ) − ( x0 + x2 + x1 )] < e1 e1 > 2 = −2(4 x0 − 1) ... xi e1 e1 > −4 f E1 < x0 e1 xi ei > −4 f E2 < x0 e2 xi ei > −4 f E3 < x0 e3 xi ei > ,         = f E xi xi < e1 e1 > −4 f E x0 x1 < e1 e1 > −4 f E x0 x2 < e1 e1 > −4 f E x0 x3 < e1 e1 >...

Ngày tải lên: 19/06/2014, 19:20

... 9, pp 988 - 989 (19 97) [in Japanese] [11 ] X -C Zhang et al., Generation of femtosecond electromagnetic pulses from semiconductor surfaces, Appl Phys Lett., Vol 56 (11 ), pp 10 11- 1 013 (19 90) [12 ] X ... Effect of Radiation Reaction, Phys Scr, Vol 81 , pp 1- 10 Wheeler, J A., & Feynman, R P., (19 45), Interaction with the Absorber as the Mechanism of Radiation, Rev Mod Phys, Vol 17 , pp 15 7 - 18 1; (19 49), ... Thermometers, Nucl Phys B, Vol 212 , pp .13 1 -14 9; (19 87 ), The Unruh Effect and Quantum Fluctuaions of Electrons in Storage Ring, Nucl Phys B, Vol 284 , pp 488 -5 08 Chen, P., & Tajima, T., (19 99) Testing Unruh...

Ngày tải lên: 19/06/2014, 19:20

... 11 , No 8, (April 19 75), pp 28 71- 287 6, ISSN 15 50 235x [12 ] L D Landau, E M Lifshitz and L P Pitaevskii (19 84 ), Electrodynamics of Continuous Media 2nd Butterworth-heinemann, ISBN 07506263 48 [13 ] ... Physics, Vol 88 , No 8, pp 484 5- 48 51, ISSN 10 89 -7550 [ 18 ] Y S Joe, J F D Essiben and E M Cooney (20 08) Radiation characteristics of waveguide antennas located on the same impedance plane Journal of Physics ... Journal of Chemical Physics, Vol 11 9, No 16 , (May 2003), pp 82 50 -82 55, ISSN 00 21- 9606 [22] J A Kong (19 72), Theorems of bianisotropic media Proceedings of the IEEE, Vol 60, No (June 2005) pp 10 36 -10 46,...

Ngày tải lên: 19/06/2014, 19:20

... pp 212 - 2 18 Narasimhan M S & Philips B (19 87 b) Synthesis of near-field patterns of a nonuniformly spaced array, Antennas and Propagation, IEEE Transactions on, vol 35, (November 19 87 ), pp 11 89 ... (19 90) Antenna pattern characteristics of phase-correcting Fresnel zone plates, 19 90 IEEE International Antennas and Propagation Symp Dig., vol 28, (May 19 90), pp 19 06 - 19 09 Graham W J (19 83 ) ... New York, USA Hansen R C (19 85 ) Focal region characteristics of focused array antennas, Antennas and Propagation, IEEE Transactions on, vol 33, (December 19 85 ), pp 13 28 - 13 37 Hansen R C (2009)...

Ngày tải lên: 19/06/2014, 19:20

... the TE10 propagation mode these expressions for S 11 and S 21 are (Barroso and De Paula (2 010 ); Boughriet et al (19 97); Ghodgaonkar et al (19 90); Ligthart (19 83 )) ˆ S 11 = ˆ ˆ Γ − T2 , ˆ T2 1 Γ ˆ ... techniques of materials with thin configuration at microwave frequencies, Journal of Applied Physics 98( 8): 08 410 7 -1 08 410 7 -8 Nicolson, A M and Ross, G F (19 70) Measurement of the intrinsic properties of ... E (19 87 ) Surface roughness of stainless steel and electroformed nickle standards using HeNe laser Opt Laser Technol 19 (4), 18 9 -19 6 [10 ] Mitsui, M., Sakai, A & Kizuka, O (19 88 ') Development of...

Ngày tải lên: 26/06/2014, 23:20

... to (2 .11 ) gives a system of homogeneous equations as ⎡ ⎢c ' − ke 15 ⎢ 44 ⎢ ⎢ kh ⎢ − ke15 e ⎢ e kh ⎢ ⎣ 1 ke15 − κ c 44 e15 / 11 ke15 e − kh e − kh − κ c 44 e κh e15 κh e 11 1 ⎤ A' ⎧ 1 κ c ... 600kHz 80 Figure 4 .10 Distribution of T33 at far field along thickness direction at 1, 100kHz 81 Figure 4 .11 Distribution of T22 at far field along thickness direction at 1, 100kHz 81 Figure 4 .12 Experimental ... can be determined (Bleustein, 19 69) by V B = V2 where k15 = k15 1 (1 + k15 ) (2.26) e15 For the materials used here, VB = 2 18 1m/s c 44 Ξ 11 The dispersion curves of the SH wave for this structure...

Ngày tải lên: 12/09/2015, 11:00

... Waves ˜ 1 matrix M : ˜ 1 ˜ ˜ U = M J (11 ) By introducing new function according to ˜ ψ0 = , k2 − k2 (12 ) we define the inverse matrix: 1 ˜ ˜ −G0 ˜ 1 ˜ −(ε ε) G1 , M = ψ0 ˜ ˜ −G0 ( μ μ ) 1 ... inverse Fourier transformation ˜ M 1 = F 1 [ M 1 ˜ J = F 1 [J], ], ˜ U = F− [ U ] (16 ) and using the property of convolution: ˜ 1 ˜ F 1 [M J] = M 1 ∗ J, (17 ) where symbol "∗" denotes the convolution ... to get the solution of the Maxwell equations (4) as: U = M 1 ∗ J, ( 18 ) where ⎛ M− = −(ε ε) 1 G1 −G0 or E H = −G0 ψ0 , (μ0 μ ) 1 G1 ∂ + k2 ∂x − ⎜ ∂2 ⎜ G1 = iω ⎝ ∂x∂y (iε εω ) 1 (∇∇ + k2 )(j ∗ ψ0...

Ngày tải lên: 19/06/2014, 21:20