1 10 channel capacity and ideal communication systems

... 16 5 16 5 16 8 16 9 17 0 17 2 17 3 17 4 17 7 17 9 17 9 18 3 18 4 10 Conclusions and Future Work 10 .1 Reduced-Complexity Detection Techniques 10 .1. 1 Conclusions of Part I 10 .1. 2 Future ... 12 2 12 2 12 4 12 8 12 8 13 1 13 1 13 3 13 5 Channel Estima136 13 6 13 9 14 1 14 3 14 5 14 9 15 2 15 3 15 5 ... 10 0 10 0 10 1 10 3 11 1 11 3 11 6 12 1 Contents iv Angle-Domain MIMO-OFDM Systems 7 .1 Introduction 7.2 MIMO-OFDM Systems 7.3 Angle-Domain MIMO-OFDM Systems...

Ngày tải lên: 14/09/2015, 14:12

... (n +1) -th frame n-th frame Sn ,1 Sn 1, N −2 Sn 1, N 1 Sn,0 + Sn ,1 Sn,N 1 Sn +1, 0 Sn,N 1 Sn +1, 0 + Sn 1, N −2 Sn 1, N 1 Sn,0 h2 rn 1, N −2 rn 1, N 1 rn,0 = rn ,1 Sn ,1 rn, N 1 Sn,N 1 ... channel 11 8 5 .1 The open-loop and closed-loop capacity for MIMO Systems 11 9 5 .1. 1 MIMO system model 11 9 5 .1. 2 MIMO system capacity 12 0 5 .1. 3 Numerical Results and discussion ... 10 2 .1. 1 Large scale propagation 11 2 .1. 2 Small scale propagation 13 2 .1. 3 Typical wireless channel models 17 2.2 OFDM systems 20 2.2 .1 Basic...

Ngày tải lên: 20/11/2012, 11:28

... 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, − 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 1, − 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, − 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, − 1, 1, 1, 1, 1} 1. 5 1 −0.5 0.5 ... 7.56 dB > +7.65 dB 10 0 10 1 10 1 10 2 10 −2 MSE MSE 10 0 10 −3 10 −3 10 −4 10 −4 10 −5 −4 −2 10 −5 LSPR= −6 dB LSPR= −3 dB LSPR= dB SNR (dB) 10 12 14 LSPR= dB LSPR= dB LSPR= dB Figure 13 : MSE performance ... as Hi = 1 Wi1 + Wi2 + Wi3 + Wi4 W Hin + in ≈ Hi × n =1 Xi Xi (11 ) 2.5 1. 5 0.5 0 50 10 0 ⎪ ⎪ ⎪ ⎩ (12 ) 2.5 1. 5 0.5 0 50 10 0 P0 = = 320 16 0 n =1 xS (n) 15 0 200 250 300 2.5 1. 5 0.5 0 50 10 0 15 0 200...

Ngày tải lên: 21/06/2014, 23:20

... Example: Send T = 11 010 1 011 Receive T’ = 11 010 1 011 (no errors) No way of knowing how many errors occurred or which bits are In error 10 01 110 1 010 11 10 01 010 00 10 01 00 011 01 10 01 010 01 10 01 000 => No ... 2r/G and T will be a multiple of G • Choice of G is a critical parameter for the performance of a CRC Example r = 3, G = 10 01 M = 11 010 1 => M2r = 11 010 100 0 10 01 110 011 11 010 100 0 10 01 010 00 10 01 ... Example: c1 = x1 + x2 + x3 c2 = x2 + x3 + x4 c3 = x1 + x2 + x4 Single Parity Check Code • The check bit is if frame contains odd number of 1' s; otherwise it is 10 110 11 -> 10 110 11 110 011 0 -> 11 0 011 0...

Ngày tải lên: 07/08/2014, 12:21

... 1. 1 Evolution of Cellular Mobile Communication Systems 1. 1 .1 Analogue First Generation Cellular Systems 1. 1.2 Digital Second Generation Cellular Systems 1. 1.3 Third ... 13 1. 3 .1 Multicarrier CDMA 13 1. 3.2 Space-Time Coding 16 iv 1. 4 Motivations 18 1. 4 .1 Performance and Capacity in the Presence of Carrier Frequency Offset 19 ... introduced 1. 1 Evolution of Cellular Mobile Communication Systems 1. 1 .1 Analogue First Generation Cellular Systems In the late of 19 70s and early 19 80s, various first generation (1G) cellular mobile communication...

Ngày tải lên: 16/09/2015, 15:54

... thay truyền dòng bit trực tiếp, truyền dòng bit 11 100 000 011 100 0 có nghĩa là, lặp lại bit ba lần Bây giờ, cho giả định dòng bit nhận 10 100 0 010 111 000 Hai lỗi giới thiệu kênh Nhưng còn, giải mã ... ứng với dòng bit: 11 0 11 0 10 11 1 Sơ đồ mã hóa yều cầu trung bình 1. 65 bits/ký tự Nếu mã hóa ký tự trực tiếp mà không xét đến xác suất, sơ đồ mã hóa là: AA 00 AB 01 BA 10 BB 11 Như cần bits/ký tự ... truyền âm với W = 310 0 Hz, SNR = 30 dB Theo trên, ta có: 30 = 10 log(S/N) log(S/N) = S/N =10 00 Vậy C= 310 0 log2 (1+ 100 0)=30.894 bps Vì vận chuyển liệu với tốc độ nhanh giá trị C được.Một điểm quan cần...

Ngày tải lên: 18/09/2012, 10:13

... System and Results 14 3 14 3 14 5 14 8 14 8 15 1 15 2 15 2 15 3 15 4 15 4 15 6 15 8 15 8 15 8 15 9 15 9 16 1 16 2 16 2 16 3 16 4 16 4 16 5 16 5 16 6 16 7 16 8 16 9 16 9 16 9 17 0 17 2 17 5 17 5 17 6 17 7 17 9 18 1 18 2 18 2 18 3 CONTENTS ... Representation and Processing 83 87 88 88 91 93 94 96 96 97 10 2 10 4 10 6 10 6 10 8 10 9 11 0 11 1 11 2 11 2 Stereo Analysis Nicole Atzpadin and Jane Mulligan 11 5 7 .1 Stereo Analysis Using Two Cameras 7 .1. 1 Standard ... Curvature 12 .4.2 Magnification and Miniaturization Effects 18 5 18 6 18 7 19 0 19 1 19 3 19 3 19 4 19 4 19 5 19 8 19 9 2 01 202 202 202 204 205 205 206 207 208 209 210 210 212 214 214 217 219 219 220 220...

Ngày tải lên: 12/05/2013, 10:21

... In 19 47, a pilot saw c) There were over Worldwide in 19 52 d) In 19 54, a woman and her children saw house e) A farmer saw in 19 64 f) In 19 71, two men g) A pilot in 19 78 ... soil samples in 19 64 claimed they were captured by aliens and F- In 19 71, two men taken abroad a spacecraft and his plane disappeared after sighting G- A pilot a UFO in 19 78 that he saw ... hour 1, 500 UFO sightings C- There were over worldwide in 19 52 a UFO above their D- In 19 54 , a woman and her children saw house an egg-shaped object in one of his E- A farmer saw fields and...

Ngày tải lên: 24/06/2013, 01:27

... Subprograms 10 9-2 11 0 DBMS_TTS Using DBMS_TTS 11 0-2 Summary of DBMS_TTS Subprograms 11 0-3 11 1 DBMS_XDBT Using DBMS_XDBT 11 1-2 Summary of DBMS_XDBT ... 10 1-3 10 2 DBMS_TRANSFORM Summary of DBMS_TRANSFORM Subprograms 10 2-2 10 3 DBMS_TYPES Using DBMS_TYPES 10 3-2 10 4 DBMS_UTILITY Using DBMS_UTILITY 10 4-2 ... Subprograms 10 6-2 10 7 DBMS_WM Documentation of DBMS_WM 10 7-2 xv 10 8 DBMS_XDB Using DBMS_XDB 10 8-2 Summary of DBMS_XDB Subprograms 10 8-4 10 9 DBMS_XDB_VERSION...

Ngày tải lên: 24/10/2013, 17:15

Ngày tải lên: 08/04/2014, 10:02

... Application Publication 2 011 / 011 2784 (12 May 12 , 2 011 )] [14 ] IS Gradshteyn, IM Ryzhik, Table of Integrals, Series, and Products, 5th edn (Academic Press, New York, 19 94) [15 ] PAM Dirac, The Principles ... control [US Patents 7 ,10 7,306 (Sep 12 , 2006), 7, 418 ,469 (Aug 26, 2008), and 7, 617 ,270 (Nov 10 , 2009)] [13 ] AV Nikitin, Method and apparatus for adaptive real-time signal conditioning and analysis [US ... of interchannel interference in digital communication systems, in Proceedings of IEEE Radio and Wireless Symposium, pp 11 8 12 1 (Phoenix, AZ, 2 011 ) [5] M Abramowitz, IA Stegun (eds.), Handbook...

Ngày tải lên: 18/06/2014, 22:20

... Application Publication 2 011 / 011 2784 (12 May 12 , 2 011 )] [14 ] IS Gradshteyn, IM Ryzhik, Table of Integrals, Series, and Products, 5th edn (Academic Press, New York, 19 94) [15 ] PAM Dirac, The Principles ... control [US Patents 7 ,10 7,306 (Sep 12 , 2006), 7, 418 ,469 (Aug 26, 2008), and 7, 617 ,270 (Nov 10 , 2009)] [13 ] AV Nikitin, Method and apparatus for adaptive real-time signal conditioning and analysis [US ... of interchannel interference in digital communication systems, in Proceedings of IEEE Radio and Wireless Symposium, pp 11 8 12 1 (Phoenix, AZ, 2 011 ) [5] M Abramowitz, IA Stegun (eds.), Handbook...

Ngày tải lên: 20/06/2014, 04:20

... 805– 811 (2004) doi :10 .10 16/j sigpro.2004. 01. 0 01 11 AV Nikitin, RL Davidchack, Method and apparatus for analysis of variables US Patents 7 ,13 3,568 (Nov 7, 2006) and 7,242,808 (July 10 , 2007) 12 ... Processing 2 011 , 2 011 :13 7 http://asp.eurasipjournals.com/content/2 011 /1/ 137 Page of 10 μs GHz gain W Mbit/s modulation μs notch at 1. 045 GHz 1. 045 GHz 1. 045 GHz transmitter Out-of-band receiver ... lowpass filter of bandwidth much larger than Δf Nikitin EURASIP Journal on Advances in Signal Processing 2 011 , 2 011 :13 7 http://asp.eurasipjournals.com/content/2 011 /1/ 137 Page 10 of 10 Abbreviations...

Ngày tải lên: 20/06/2014, 21:20

... Comput Commun 26 (18 ), 2052–2060 (2003) doi :10 .10 16/S 014 0-3664(03)0 018 8-9 HY Lin, Security and authentication in PCS Comput Electr Eng 25(4), 225–248 (19 99) doi :10 .10 16/S0045-7906(99)00 010 -5 HY Lin, ... for mobile satellite communication systems Comput Electr Eng 35 (1) , 41 48 (2009) doi :10 .10 16/j.compeleceng.2008.05.003 Page 10 of 10 17 A Aziz, W Diffe, Privacy and authentication for wireless local ... communication systems ACM SIGOPS Oper Syst Rev 39 (1) , 70–84 (2005) doi :10 .11 45 /10 44552 .10 44560 16 TH Chen, WB Lee, HB Chen, A self-verification authentication mechanism for mobile satellite communication...

Ngày tải lên: 21/06/2014, 00:20

... Pastoralism: Research, Policy and Practice 2 011 , 1: 10 http://www.pastoralismjournal.com/content /1/ 1 /10 been felt equally across the developed and developing countries and between low and high population ... Sons, Chichester Plachter H and Hampicke (eds) 2 010 Large scale-livestock grazing: A management tool for nature conservation, SpringerVerlag Berlin doi :10 .11 86/20 41- 713 6 -1- 10 Cite this article as: ... conservation-oriented, reduced Page of Oba Pastoralism: Research, Policy and Practice 2 011 , 1: 10 http://www.pastoralismjournal.com/content /1/ 1 /10 deforestation, the expansion of agriculture in Brazil involved...

Ngày tải lên: 21/06/2014, 04:20

... branch for various values of 2N at 12 EURASIP Journal on Advances in Signal Processing 10 0 10 0 10 1 10 2 10 −4 10 −3 BER SER 10 −2 10 −4 10 −6 10 −5 10 −8 10 −6 10 15 20 Average SNR per symbol per diversity ... Journal on Advances in Signal Processing 13 10 0 10 0 0. 316 9 0.5584 0.7998 10 1 3 Multipath BER BER 10 1 AWGN 10 −2 10 −3 10 −2 0 .1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 10 −3 PCF Traditional receiver GR Figure ... channel (l) K − 2(N − T)β2 δ (K − 1) + , N N2 = (10 2) (l) EL 1, k ⎧ ⎪ ⎨ (l) ⎧ ⎨ = EL Rk ⎩ ⎪ ⎩ K j =1, j = k / K K K (l) ρ(l) ρmk ⎭ jm K + j =1, j = k / j =1, j = k m =1, m = j,k / / 10 −6 10 −8 10 ...

Ngày tải lên: 21/06/2014, 05:20

... should satisfy α (k) C1,2 (k) − C − C − α(k) C1 (k) − C ≥ (11 ) (13 ) subject to (10 ), (11 ), and (12 ) (14 ) and if the postswitching ratio α(k)C1 (k)/C1,2 (k) meets the condition (12 ) The optimal α ... Lower-level RRM 10 FFR −5 Upper-level RRM MD 10 15 15 10 Lower-level RRM −5 1 (dB) 10 15 λ = 0.5 λ =1 λ=2 Figure 5: Boundary conditions of switching a RRC This can be further rewritten as + γ2 1+ λ λ ... by α (k) = α(k)C1 (k) C1,2 (k) (15 ) (ii) If C1,2 (k) − C − C = and C1 (k) − C < 0, α (k) can be chosen arbitrarily subject to (10 ) and (12 ) (iii) If C1,2 (k) − C − C > and C1 (k) − C ≤ 0, α...

Ngày tải lên: 21/06/2014, 11:20

... Signal Processing 10 1 10 0 10 1 100 10 −2 NMSE BER 10 1 10 3 10 −4 10 −2 10 −5 10 −3 10 −6 10 −4 10 15 20 25 30 35 Number of pilot blocks 40 45 50 CP = 0, w/o IBI cancellation CP = 10 , w/o IBI cancellation ... Processing 10 0 10 0 10 1 10 1 10 2 10 −3 BER BER 10 −2 10 −4 10 −4 10 −5 10 −6 10 −3 10 −5 10 12 14 16 18 20 22 24 26 28 30 SNR (dB) CM4 CP = 20 0th it IBI cancel Ch Est pilots CM4 CP = 20 1st it IBI cancel ... 10 −5 10 −6 10 12 14 16 18 20 22 24 26 28 30 SNR (dB) en (1) Lc 1 h(r) dn 1 N + L p + − r − dn (N − r + 1) , = CM4 CP = 20 0th it IBI cancel Ch Est 10 pilots CM4 CP = 20 1st it IBI cancel Ch Est 10 ...

Ngày tải lên: 21/06/2014, 16:20

... = 31 Hz fD = 93 Hz (a) RX array motion along the x-axis 10 0 10 −3 10 −4 10 −5 10 −2 10 −3 10 −4 10 1 TX-x/RX-x AS = 1 10 −2 10 −3 10 −4 10 1 10 5 10 −5 10 20 30 40 Normalised total TX power (dB) 10 0 10 0 ... 0.5λ 10 −2 10 −3 10 −4 10 1 10 5 10 20 30 40 Normalised total TX power (dB) 10 0 10 0 Average BER 10 −2 10 1 Average BER Average BER 10 1 100 TX-x/RX-x AS = 0.5λ TX-x/RX-x AS = 1 10 −2 10 −3 10 −4 10 1 ... BER 10 0 10 −5 10 20 30 40 Normalised total TX power (dB) TX-y/RX-y AS = 1 10 −2 10 −3 10 −4 10 −5 10 20 30 40 Normalised total TX power (dB) 10 20 30 40 Normalised total TX power (dB) LOS OLOS Ideal...

Ngày tải lên: 21/06/2014, 18:20

... 0.5 0.3 10 SNR (dB) 12 14 16 18 10 −5 10 SNR (dB) 12 14 16 18 (b) MSE of the delay estimates Figure 5: The averaged hit rate (a) and MSE (b) versus the SNR in the algorithms A1–A5 when p = 10 , L ... p1 , τ p1 +1 , , τ p , 1 + TK1 , , τ p1 1 + TK1 , (25) 10 12 14 16 18 20 22 24 The means over realizations are: 0.8 (A2), 0.83 (A4) and 0.7 (A5) that is, the original 1 , , τ p1 1 ... A5 mean 0 .12 0 .12 A4 mean 0.09 0 .1 0.08 0.06 0 .15 0 .14 0 .13 Root squared CRLB 0 .12 A2 mean 0.07 0.04 0 .11 10 12 14 CIR 16 18 20 22 24 0 .1 Mean error of gain 10 SNR (dB) (a) A2 A4 A5 0.4 0.3 Figure...

Ngày tải lên: 21/06/2014, 23:20