1—introduction scope and definitions 1 1 — introduction
recommendations for design of beam-column connections in monolithic reinforced concrete structures
Ngày tải lên :
24/10/2014, 16:04
... (19 .0) 11 .9 (300) 15 .4 (390) 13 .0 (330) 0.875 (22.2) 13 .8 (350) 17 .3 (440) 14 .6 (370) 1. 000 (25.4) 15 .8 (4 01) 19 .3 (4 91) 16 .1 ( 411 ) 1. 128 (28.6) 17 .8 (4 51) 21. 3 (5 41) 17 .8 (4 51) 10 1. 270 ( 31. 8) ... (Alcocer 19 93; Alcocer and Jirsa 19 93; Ammerman and Wolfgram-French 19 89; Aoyama 19 85; Durrani and Wight 19 87; Durrani and Zerbe 19 87; Ehsani and Wight 19 85; Fujii and Morita 19 87; Gentry and Wight 19 92; ... Bessho, and Matsuzaki 19 91; Kitayama, Otani, and Aoyama 19 87; Kurose et al 19 91; LaFave and Wight 19 97; Leon 19 84; Pantazopoulou, Moehle, and Shahrooz 19 88; Paulay and Park 19 84; Quintero-Febres and...
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Thermodynamics Kinetics of Dynamic Systems Part 4 pdf
Ngày tải lên :
19/06/2014, 11:20
... Fig 11- Fig .15 Fig 11 Pressure variation along the pipeline Modeling and Simulation for Steady State and Transient Pipe Flow of Condensate Gas Fig 12 Temperature variation along the pipeline Fig 13 ... constraints on basic quantities of dissipative fluid (11 ; 12 ): u μ u μ = 1 (12 a) u qμ = (12 b) μ ◦ ◦ Π μν = Π νμ (12 c) ◦ uν Π μν = ◦ μ Π μ (12 d) = (12 e) Of course, the metric is symmetric gμν = gνμ ... undetermined in the framework of EIT (11 ; 13 ; 14 ) On the other hand, based on the Grad’s 14 -moment approximation method of molecular motion, Israel and Stewart (12 ) have obtained the transport coefficients...
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MANAGING THE RISKS OF PAYMENT SYSTEMS CHAPTER 4 pot
Ngày tải lên :
02/07/2014, 16:21
... 4A-4 01 and 4A-3 01( b) 99 Wire Transfers 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 Official Comment to U.C.C § 4A- 211 U.C.C § 4A- 211 (e) U.C.C § 4A- 211 (g) The rule is similar to and ... Division X1 Division X1 Division X1 Division X1 Division X1 Corporation X Yes/Yes Yes/Yes Yes/Yes Yes/Yes Yes/Yes Yes/Yes 1, 000,000,000 1, 000,000,000 1, 000,000,000 1, 000,000,000 1, 000,000,000 1, 000,000,000 ... X1 Division X1 Division X1 Division X1 Division X1 Corporation X DOL Transaction Limit Yes/Yes Yes/Yes Yes/Yes Yes/Yes Yes/Yes Yes/No 1, 000,000,000 1, 000,000,000 1, 000,000,000 1, 000,000,000 1, 000,000,000...
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Design and Optimization of Thermal Systems Episode 1 Part 4 pps
Ngày tải lên :
06/08/2014, 15:20
... liquids Radiative transport Condensation Fluidized bed h(W/m2 · K) 5 10 50 10 0 35 0—5 50 50 0—2 ,500 600 10 ,000 600 10 ,000 60 0—5 ,000 Convection has the advantage of heating the materials only up ... in thickness from D1 to D2 across a set of rollers, as shown in Figure 1. 10(d), mass conservation leads to the equation U1D1 U2 D2, where U1 is the speed before the rollers and U2 after, if the ... different sources, and constructive criticism Several such methods that may help to develop creative thinking are discussed by Alger and Hays (19 64) and by Lumsdaine and Lumsdaine (19 95) Techniques...
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Design and Optimization of Thermal Systems Episode 2 Part 4 doc
Ngày tải lên :
06/08/2014, 15:20
... valve –25°C Evaporator Entropy, s 2a T(°C) –25 P(kPa) 15 1.5 Saturated vapor 18 8.7 11 67 .1 Superheated vapor 30 11 67 .1 Saturated liquid –25 15 1.5 Liquid-vapor mixture FIGURE 5.3 Thermodynamic cycle ... specific volume at state and the p’s are the pressures Thus, h 4s h3 v3 (p4 – p3) 16 7.57 1. 0078 16 7.57 8.64 17 6. 21 kJ/kg 10 (8.5 81 – 0.007384) 10 3 where the pressures are in MPa and 10 3 is used to obtain ... System 313 0 .15 0 Solid thickness (m) 0 .12 5 0 .10 0 Tpour = 18 50 K 0.075 d = 3.0 cm Mold material Iron 0.050 h values (W/m2K) h = 20 h = 40 h = 70 h = 10 0 0.025 0.00 0.0 220.0 440.0 660.0 880.0 11 00.0...
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Design and Optimization of Thermal Systems Episode 3 Part 4 ppsx
Ngày tải lên :
06/08/2014, 15:21
... equations, w1 0. 611 and w2 0.389 Therefore, C* (3.5/0. 611 )0. 611 (14 .8/0.389)0.389 11 .965 Then, from Equation (10 .13 ) and Equation (10 .14 ), 3.5 m1.4 0. 611 C* which gives m (0. 611 C*/3.5 )1/ 1.4 1. 692 ... function, U(x1, x2, , xn), in unconstrained problems, which can be treated by geometric programming are U x2 / U U U x1x1/ x1 x1 550 10 5 x1 x1x2 x1 x1 x3.3 (10 .1) (10 .2) 12 0, 000 10 x1 x1 (10 .3) 2 ... in Equation (10 .9), yielding U * w1 A w1 B w2 w2 (10 .12 ) Also, it will be shown later, in Section 10 .1. 3, that w1 w2 * u1 u u * * * u2 u * u * * u1 U* (10 .13 ) * u2 U* Therefore, w1 and w2 represent...
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Validation of Communications Systems with SDL phần 4 docx
Ngày tải lên :
07/08/2014, 21:20
... start transition, timer TIMER1 is started, and process proc1 is in state st1 system L_time block b1 process proc1 st1 SET (TIMER1) b1 proc1 NONE st1 x:= st1 TIMER TIMER1:= 15 .0; DCL x Integer; Figure ... scenarios: 10 11 12 13 14 15 16 This geodesim script replays scenarios to test V.76 and writes the results into test_res1.wri define test_failed False echo echo Execution of script1.wri: || ... to step 27 - 16 = 11 redo returns to step 11 + = 19 4.3.7 .11 Declaring simulation variables Simulation variables can be declared in the Simulator: • work variables: using the command dcl, like...
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Fundamentals of Database systems 3th edition PHẦN 4 pps
Ngày tải lên :
08/08/2014, 18:22
... Note Note Note 10 Note 11 Note 12 Note 13 Note 14 Note 15 Note 16 Note 17 Note 18 Note 19 Note Codd (19 85) specified 12 rules for determining whether a DBMS is relational Codd (19 90) presents ... connectives—(F1 and F2), (F1 or F2), not(F1), and not(F2)—depending on whether it is free or bound in F1 or F2 (if it occurs in either) Notice that in a formula of the form F = (F1 and F2) or F = (F1 ... F1 and F2 as follows: a (F1 and F2) is TRUE if both F1 and F2 are TRUE; otherwise, it is FALSE b (F1 or F2) is FALSE if both F1 and F2 are FALSE; otherwise it is TRUE c not(F1) is TRUE if F1...
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FUNDAMENTALS OF DATABASE SYSTEMS Fourth Edition phần 4 pptx
Ngày tải lên :
08/08/2014, 18:22
... E 12 3456789 333445555 999887777 9876543 21 666884444 453453453 987987987 888665555 19 65- 01- 09 19 55 -12 -08 19 68-07 -19 19 41- 06-20 19 62-09 -15 19 72-07- 31 1969-03-29 19 37 -11 -10 ADDRESS DNUMBER 7 31 Fondren,Houston,TX ... Borg,James E 12 3456789 333445555 999887777 9876543 21 666884444 453453453 987987987 888665555 19 65- 01- 09 19 55 -12 -08 19 68-07 -19 19 41- 06-20 19 62-09 -15 19 72-07- 31 1969-03-29 19 37 -11 -10 7 31 Fondren,Houston,TX ... 9876543 21 666884444 453453453 987987987 888665555 19 65- 01- 09 19 55 -12 -08 19 68-07 -19 19 41- 06-20 19 62-09 -15 19 72-07- 31 1969-03-29 19 37 -11 -10 7 31 Fondren, Houston, TX 638 Voss,Houston, TX 33 21 Castle,Spring,TX...
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Analysis and Control of Linear Systems - Chapter 4 ppt
Ngày tải lên :
09/08/2014, 06:23
... Systems 11 1 1 ⎤ EXAMPLE 4 .1. – let us suppose that L = ⎢ ⎥ , and W is the main straight line ⎣ 0⎦ 1 1 ⎡0 ⎤ 1 ⎢0⎥ : L W = L {0} = KerL = ⎢ ⎥ 1 ⎦ ⎣ ⎦ Let V be a basis matrix of V and W t ... very similar to algorithms [4.5] and [4.4]: i i n * * A = {0}, A 1+ 1= E−1HA 1, ⇒ A = A = E−1HA [4 .18 ] n A = X , A i +1= H−1EA i , ⇒ A = A * = H−1EA * 2 2 [4 .19 ] The regularity of the beam [pE-H] ... Conference, ECC’93, p 11 19 -11 24, 19 93 [MAL 97] MALABRE M., MARTINEZ-GARCIA J.C., DEL MURO CUELLAR B., “On the fixed poles for disturbance rejection”, Automatica, vol 33, no 6, p 12 09 -12 11, 19 97 [MAR 94]...
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the behavior of stock market prices eugene f fama the journal phần 4 pps
Ngày tải lên :
09/08/2014, 20:20
... 15 9 209 14 3 14 2 17 2 16 2 19 8 19 3 16 2 .1 153.7 17 2.4 15 5.9 17 2.5 16 0.4 15 9.3 2 21. 6 16 1.9 16 0 .1 224.7 19 1.4 205.2 15 7.6 16 4.2 16 4.0 19 3.9 16 0.0 16 8.6 19 0.6 17 2.8 228.4 15 9.2 19 7.2 15 5.2 15 0.5 16 1.4 ... 672.0 713 .2 712 .6 826.0 699 .1 743.3 858.9 748 .1 979.0 704.0 877.6 654.2 620.9 699.3 662.0 825.5 868.4 735 .1 759.8 16 0 15 1 16 9 16 5 17 8 16 6 16 3 223 16 0 15 4 225 18 5 202 15 1 15 9 16 3 19 0 17 3 17 1 18 0 16 7 ... 4.2 12 6.9 6 .1 149.0 4.0 96 .1 -1. 1 12 1 .1 -5 .1 95 .1 0.9 98.6 3.4 98.9 -2.9 12 8 .1 -7 .1 139.3 1. 7 13 9.4 4.6 13 7.5 1. 5 13 2.8 2.2 2.2 16 6.8 70.8 5.2 61. 3 2.7 98.4 -0.4 62.3 0.7 10 5.6 0.4 15 2.4 -4.4...
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Mechanics of Microelectromechanical Systems - N.Lobontiu and E.Garcia Part 4 doc
Ngày tải lên :
10/08/2014, 05:20
... microhinges, microbridges 10 5 where the compliances of Eqs (2 .13 8) are calculated as: The superscripts (1) and (2) in Eqs (2 .13 9), (2 .14 0) and (2 .14 1) indicate the first component and the second component, ... force calculated by Eq (2. 51) and the real force is: and Fig 2 .11 is a plot giving the relative errors for the case where c = 0.5 Figure 2 .11 Errors between the real force and the apparent one in ... applying two forces, and and a moment (none of them are shown in Fig 2 .18 ) By applying the same procedure as above, the in-plane displacements and loads that correspond to bending and axial loading...
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The Behavior of Structures Composed of Composite Materials Part 4 potx
Ngày tải lên :
10/08/2014, 12:21
... of 0 .12 7 mm (0.005") cited in Problem 6, calculate the elements of the [A], [B] and [D] matrices for the following laminates: (a) [+45/-45/-45/+45] (b) [+45/-45/+45/-45] (c) 81 10 11 12 13 (d) ... due to lateral loads given by Equations (3 .14 ), (3 .15 ) and (3 .12 ) become: 92 where Equations (3 .16 ) and (3 .17 ) can be substituted into Equation (3 .18 ) with the result that: The above equations ... to be 0 .1" and neglecting Poisson’s Ratio, what are the new moduli in the and directions 15 The properties of graphite fibers and a polyimide matrix are as follows: GRAPHITE POLYIMIDE 16 17 (a)...
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Dynamics of Mechanical Systems 2009 Part 4 docx
Ngày tải lên :
10/08/2014, 20:20
... lθ1n 11 and aO2 = lθ1n 11 − l 1 n13 (5.6.5) and in terms of NX and NZ, they are: ˙ vO2 = l 1 (cos 1 N X − sin θ1N Z ) (5.6.6) and [( ) ( ) ] ˙˙ ˙2 ˙˙ ˙2 aO2 = l 1 cos 1 − 1 sin 1 N X + − 1 ... + 3n1 × ( 10 n ) + 4n × ( 15 n1 ) + 3n1 × ( −8n ) + 4n × (8n ) + + 12 n × (12 n1 + 16 n ) = 30n = 60n − 24n − 32n1 − 14 4n + 19 2n1 or: MO = 16 0n1 − 30n − 16 8n ft lb (6.3 .15 ) 0593_C06_fm Page 16 9 ... G1 = (l 2) θ1n 11 and aG1 = (l 2) θ1n 11 − (l 2) 1 n13 (5.6.2) In terms of NX and NZ, these expressions become: ˙ v G1 = (l 2) 1 (cos θ1N X − sin θ1N Z ) n j1 Oj Bj (5.6.3) θj G n k1 n j3 Ok θ...
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The Design of Manufacturing Systems Part 4 pdf
Ngày tải lên :
11/08/2014, 05:22
... Manufacturing Systems 4 .1 4.2 Introduction The FMS Operational Model and the Manufacturing System Deadlock The FMS Operational Model • The Underlying Resource Allocation System (RAS) and the RAS Taxonomy ... Deadlock and Generic Resolution Approaches • Literature Review of the FMS Deadlock Problem • Developing Correct and Scalable Deadlock Avoidance Policies for Contemporary FMS 4.3 The Single-Unit RAS and ... RAS 4.7 Additional Issues and Future Directions in FMS Structural Control Current strategic and technological trends in discrete-part manufacturing require extensive and flexible automation of...
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Theory and Design of CNC Systems Part 4 potx
Ngày tải lên :
11/08/2014, 20:21
... register: Δ X(k − 5) 10 10 10 10 10 10 10 10 10 10 10 10 10 10 11 10 12 10 13 10 Σ 80 Output of Output Adder: S(k) Pulse: Δ X0 (k) 10 20 30 40 50 10 50 10 50 10 50 10 40 30 20 10 0 80 As shown in ... a( j + 1) 1 0 2 0 2 2 2 a( j) a( j − 1) a( j − 2) 0 0 0 0 0 0 b( j) b ( j) b ( j) 0 0 0 0.25 1 0.75 2 4 4 4 2 4 2 2 2 2 0 2 11 2 21 10 11 12 6 6 6 4 6 4 4 4 4 2 4 31 41 13 14 15 16 17 18 19 20 ... K 10 11 12 Σ Input Pulse: Δ X(k) 10 10 10 10 10 10 10 10 0 0 80 Output of Adder: 15 35 45 50 50 50 50 45 35 15 Output Pulse: Δ Xo (k) 10 10 10 10 80 4.2 Acc/Dec Control After Interpolation 11 7...
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Maintenance of Petroleum Systems B Episode 4 pot
Ngày tải lên :
12/08/2014, 16:20
... operations All settings and functions are the same as the 41AF 49 UFC 3-460-03 21 JANUARY 2003 Figure 5 .12 Combination Dual Rate-of-Flow Control Valve and Solenoid Valve (41AF -10 ) 5 .16 .2 Combination ... Shutoff, and Check Valve (51AF-4) 5 .16 .3 .1 Low-Pressure CRL Setting: 5 .16 .3 .1. 1 Place the magnet on the refueling KISS switch to pressurize the system (no hose cart is need for this procedure) 5 .16 .3 .1. 2 ... deactivated and the system shuts down Spring-loaded covers over the refuel and defuel switches may be removed 5 .13 Hydrant Adapter and Liquid Control Valve (352AF) 5 .13 .1 The 352AF (Figure 5 .10 ) provides...
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Modeling of Combustion Systems A Practical Approach 4 doc
Ngày tải lên :
13/08/2014, 05:22
... 5.70 6 .11 25.44 25.03 24.63 24.22 23. 81 129. 61 132.88 13 5.93 13 8.78 14 1.47 97.57 10 0.84 10 3.88 10 6.73 10 9.42 10 20 .1 1 018 .2 10 16.4 10 14.7 10 13.2 11 17.6 11 19.0 11 20.3 11 21. 5 11 22.6 0. 016 245 15 8.87 ... 12 9.0 13 0.0 11 1.3 11 2.3 11 3.3 11 4.3 11 5.3 344.95 345.55 346 .15 346.74 347.33 316 .4 317 .1 317 .7 318 .3 319 .0 874.8 874.3 873.8 873.3 872.8 11 91. 2 11 91. 3 11 91. 5 11 91. 6 11 91. 7 0. 017 93 0. 017 94 0. 017 94 ... 10 6.42 10 7.8682 11 2. 411 11 4. 818 11 8. 710 12 1.760 -18 -16 -1 -18 -18 -0 -18 -18 -1 -18 -18 -2 -18 -18 -3 -18 -18 -4 -18 -18 -5 +3 78 +2 79 +1 80 +1 81 +1 82 +2 83 77 +4 +4 +3 +2 +3 +4 +3 Ir Pt Au 19 2. 217 -32 -15 -2...
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A methodology for validation of integrated systems models with an application to coastal-zone management in south-west sulawesi
Ngày tải lên :
06/11/2012, 10:35
... models………………………… 10 3 10 3 10 3 10 4 10 4 10 5 10 5 10 6 10 9 10 9 11 0 References……………………………………………………………………… 11 1 Symbols…………………………………………………………………………… 12 3 Acronyms and abbreviations…………………… 12 7 Summary………………………………………………………………………… ... Preface…….……………………………………………………………………… 11 Introduction ……………………………………………… ….………… 13 1. 1 General introduction …………………………………………….…… 1. 2 Background………………………………………………………….…… 1. 2 .1 Systems approach………………………………………………… 1. 2.2 Integrated ... of 19 91 to 20 01 is depicted in Fig .1. 7 It is noted that, due to the Asian economic crisis in 19 97, the inflation of the Indonesian Rupiah is remarkably high 1. 6 1. 4 1. 2 0.8 0.6 0.4 0.2 19 91 1992...
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DIA 4-HDSX of nguoi dan o DB NB
Ngày tải lên :
20/08/2013, 20:10
... ngày 20 tháng năm 2009 Địa lí Hoạt động sản xuất người dân đồng Nam Bộ (tt) Hoạt động 1: Thảo luận nhóm SGK /12 4 12 5 Dựa vào sách giáo khoa, đồ công nghiệp Việt Nam, hình ảnh nội dung mục 3, thu thập ... CHỮ KỲ DIỆU C H Ế B I Ế N 8 10 5 7 Đây ô chữ có chữ hoạt động sản xuất người dân lương thực thực phẩm, đem lại hiệu lớn TRÒ CHƠI: Ô CHỮ KỲ DIỆU C H Ế B I M Ê C Ô N G 8 10 Ế N 5 7 Đây ô chữ có chữ ... I M Ê C Ô N G Đ Ồ N G B Ằ N G 8 10 Ế N 5 7 Đây ô chữ có chữ vùng đất rộng lớn phẳng TRÒ CHƠI: Ô CHỮ KỲ DIỆU C M Ê C Ô Đ Ồ N G B Ằ N S Ô N G H Ế B I N G G Ế N 5 10 Đây ô chữ có chữ cái: Nét văn...
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