а 1 solving differential equations by the laplace transform technique

... -0.5 -1. 0 -16 Amplitude 2.5 s-Domain -15 -12 -8 -4 Frequency 12 16 16 -4 -2 0 Real axis (F) -8 Imaginary axis (jT) -16 Imaginary Part Imaginary Part 2.0 1. 5 15 1. 0 0.5 0.0 -0.5 -1. 0 -16 -12 -8 ... Fourier transform, and into the s-domain using the Laplace transform 1. 0 0.5 0.0 -0.5 -4 -3 -2 -1 Time Fourier Transform Laplace Transform Frequency Domain Real Part Real Part 15 Amplitude 2.0 1. 5 1. 0 ... divided by the s-domain representation of the input signal Further, H (s) is equal to the Laplace transform of the impulse response, just the same as H (T) is equal to the Fourier transform of the...

Ngày tải lên: 13/09/2012, 10:20

Ngày tải lên: 14/03/2014, 13:20

... (implicit) RK schemes 12 5 12 6 12 6 12 7 12 9 13 1 13 3 13 4 13 5 13 7 13 7 13 9 13 9 13 9 14 2 14 2 14 3 14 8 14 9 15 2 15 4 15 7 16 0 16 2 16 6 16 6 16 7 16 8 16 8 16 8 16 9 17 0 17 1 17 2 17 3 17 5 17 7 17 9 18 2 18 4 CONTENTS 5.3 5.4 ... 67 69 70 71 74 76 77 79 82 84 84 84 86 88 89 89 89 91 92 93 93 94 96 99 10 2 10 3 10 3 10 4 10 6 10 7 10 8 11 0 11 3 11 4 11 5 11 6 11 9 12 0 12 2 X CONTENTS Continuous Elements for 2D Problems 4 .1 4.2 4.3 ... E(v) = -(L(u, 71) - l(i1) Proof: The functional E is bounded from below since E (11 ) 1 ~ C ~ L l l t- I1 l1 21 1 ~ = -(Call4 ~ ~ 2cU - 11 111 ) - 1I~1l2 ~ u2 c 11 l1I2 2C, Let eo = irif(E( 71) ;ZJ t W }and...

Ngày tải lên: 31/03/2014, 15:57

... FIG 11 Normalized magnitude of the eigenvalues of Z Hb Zf b f The same input data as in Fig 7, but SNR Å 20 dB 11 7 04 -18 -96 17 :38:26 88.2 11 3.4 17 8.2 23.4 88.2 11 3.4 17 8.2 23.4 THE FOURIER TRANSFORM ... a3m 02 Å vm Å 2pfm; a3m 01 Å ÉAmÉ; a3m Å um; m Å 1, , K Å diag{[S1 ] 313 , [S2 ] 313 , , [SK ] 313 } (4.2 .16 ) [Sm ] 313 Å diag{ÉAmÉ 01 , 1, ÉAmÉ 01 }; The CRB provides the goodness of any estimate ... be proved [11 ] that F 01 may be decomposed as 01 01 F 3K 13 K Å s S3K 13 K P 3K 13 K S3K 13 K , (4.2.20) a T Å [ a1 , a2 , a3 , , a3K 02 , a3K 01 , a3K ], (4.2 .15 ) where where S3K 13 K a3m 02 Å...

Ngày tải lên: 26/03/2014, 00:29

... of the structure of the sparse matrix A The matrix is split into two parts A=E−F (19 .0 .12 ) where E is easily invertible and F is the remainder Then (19 .0 .10 ) becomes E·u= F·u+b (19 .0 .13 ) The ... equation (19 .0.3) by the finite-difference method We represent the function u(x, y) by its values at the discrete set of points 8 31 19.0 Introduction ∆ yL A B y1 y0 x0 x1 xJ Figure 19 .0.2 Finite-difference ... ui−(L +1) + ui +1 + ui 1 − 4ui = ∆2 ρi (19 .0.8) This equation holds only at the interior points j = 1, 2, , J − 1; l = 1, 2, , L − The points where j=0 [i.e., i = 0, , L] j=J [i.e., i = J(L + 1) ,...

Ngày tải lên: 28/10/2013, 22:15

... Seinfeld, J 19 71, Numerical Solution of Ordinary Differential Equations (New York: Academic Press) 16 .1 Runge-Kutta Method The formula for the Euler method is yn +1 = yn + hf(xn , yn ) (16 .1. 1) which ... like (16 .1. 1) to take a “trial” step to the midpoint of the interval Then use the value of both x and y at that midpoint to compute the “real” step across the whole interval Figure 16 .1. 2 illustrates ... from NUMERICAL RECIPES IN C: THE ART OF SCIENTIFIC COMPUTING (ISBN 0-5 21- 4 310 8-5) Copyright (C) 19 88 -19 92 by Cambridge University Press.Programs Copyright (C) 19 88 -19 92 by Numerical Recipes Software...

Ngày tải lên: 15/12/2013, 04:15

... in the case of hOR1D2, only in two out of four experiments Other olfactory receptors, such as mOR167-4, mOR199 -1, M 71, M72 and mOR2 41- 1 B C D E Fig The C-terminus of OR2AG1 interacts with MUPP1 ... MINT-7290 219 : hOR3A1 (uniprotkb:P478 81) binds (MI:0407) to MUPP1 (uniprotkb:O75970) by peptide array (MI:00 81) MINT-729 019 1: hOR1D2 (uniprotkb:P34982) binds (MI:0407) to MUPP1 (uniprotkb:O75970) by ... cells These cells express MUPP1 endogenously and, by reducing the amount of MUPP1 by RNA interference, we aimed to investigate the functionality of the interaction between MUPP1 and hOR2AG1 Transfection...

Ngày tải lên: 18/02/2014, 13:20

... De novo synthesis – CDP-DAG Reverse reaction Lower phase Upper phase Exchange reaction – CMP + lM CMP –PIS 2 019 ± 71 )10 8 ± 10 3 ± 13 )1 125 ± 11 09 ± 13 8 0 exogenous PtdIns De novo synthesis was ... soybean (Fig 1B), but other molecular species are eluted at times which allow a perfect distinction between the two sets of PtdIns molecules: the C16:0/C17c + C18 :1/ C17c and C16:0/C19c peaks are ... followed by CDP-DAG + 3H-inositol fi 3H-PtdIns + CMP PtdIns molecular species were then separated by radio-HPLC In E coli (Fig 1A), C14:0/ C16:0 PtdIns elutes almost at the same time as the C16:0/ C18:3...

Ngày tải lên: 22/02/2014, 04:20

... GOA -1 and Gao [ 31, 32] The five regions of the Ga-subunit involved in receptor recognition are the a2 helix, the b6 ⁄ a5 loop, the a5 helix and the N- and C- extreme termini [ 31] In addition, the ... Biomol Screen 10 , 12 7 13 6 Gether U & Kobilka BK (19 98) G protein-coupled receptors J Biol Chem 273, 17 979 17 982 Lefkowitz RJ (19 89) G protein-coupled receptors J Biol Chem 273, 18 677 18 680 Perfus-Barbeoch ... identified GOA -1 is the Gai ⁄ o ortholog in C elegans [15 ] GOA -1 is specifically expressed in neurons in adults [16 ,17 ] Knockout and overexpression of goa -1, the gene encoding GOA -1, affect some...

Ngày tải lên: 07/03/2014, 11:20

... [(S)-b3-HAla9]SP (10 ) [(R)-b2-HPhe8]SP [(R)-b2-HPhe7]SP 1. 6 19 00 1. 1 44 24 19 0 2.6 73 0.64 64 5.2 53 2400 2500 8±2 >5000 10 ± 12 5 ± 30c 375 ± 50 12 50 ± 50 24 ± 11 30 ± 370 4.8 ± 1. 2 290 ± 74 40 ± 360 ± 55 >10 ... binding site NK-1M (85%) is labelled by [3H][Pro9]SP and is coupled to cAMP production, whereas the less abundant binding site NK-1m (15 %) is labelled by [3H]propionyl[Met(O2 )11 ]SP(7 11 ) and associated ... Ki, NK-1m (nM) EC50, phospholipase C SP (1) a Propionyl[Met(O2 )11 ]SP(7 11 )a [Pro9]SP (2)a [Aib9]SP (3)b [Pro10]SP [Gly9(YCH2CH2)Gly10]SP (4) [Gly9(YCH2CH2)(S)Leu10]SP (5) [Gly9(YCH2CH2)(R)Leu10]SP...

Ngày tải lên: 08/03/2014, 08:20

... Ala 31 des-(2,3)-Ala 31 Leu60 Ala31Leu60 IGF-II and analogues IGF-II Des- (1 6) Arg6 Leu27 Des- (1 6 ,10 )-Leu27 kd ´ 10 )3 (1/ s) Kd ´ 10 )9 (M) Relative Kd 2.70 2.52 3.60 3.65 2.89 ± ± ± ± ± ± 1. 16 1. 07 ... ± ± ± ± ± ± 1. 16 1. 07 0.88 1. 90 0.94 ± ± ± ± ± ± 4.29 4.25 2.44 5.20 3.25 88.6 16 1.0 53.4 48.2 945.0 ND 1. 00 1. 01 1.76 0.83 1. 32 0.05 0.03 0.08 0.09 0.005 ND 1. 00 0. 51 0.97 ± ± 2.35 2.90 2.25 ... Ala 31- IGF-I, des-(2,3)-Ala 31- IGF-I and Leu60IGF-I were made to probe interactions with the IGF1R These analogues bound with much lower af®nities to the rhIGF1R than IGF-I (Fig 1F±H and Table 1) The...

Ngày tải lên: 08/03/2014, 22:20

... S1 Formation of the complex Nt-S1ÆADPÆVi shifted the thermal transition of Nt-S1ÆADP by 10 .7 °C, from 42.4 °C to 53 .1 °C, and increased its enthalpy by almost 60%, from 740 to 11 70 kJÆmol )1 The ... 49.4 to 57 .1 °C, and caused a pronounced increase of DHcal by 18 %, from 12 30 to 14 50 kJÆmol )1 In the case of the complex t-S1ÆADPÆBeFx, the thermal transition of t-S1 shifted to 55 .1 °C and its ... uncleaved S1 did (about lmolÆPiÆmin )1 mg )1) , the activity of Nt-S1 was about 50–60% of that for t-S1 and uncleaved S1 The trypsincleaved S1 preparations, t-S1 and Nt-S1, were also examined for their...

Ngày tải lên: 17/03/2014, 10:20

... recombinant Der p (0 .1 ngámL )1 to 10 lgámL )1) Liberated histamine was measured by the ¯uorimetric method essentially as described by Siraganian [33] The protocol was approved by the medical ethical ... sequences (81E, 12 4A, 13 6S, 14 9A and 215 E) with those published by Chua et al [15 ] Of the six reported polymorphisms, only one was observed, being either a tyrosine or a histidine at postition 50 The ... rpro-Der p (SMD 116 8h); lane 5, rpro-Der p Endo H-treated (SMD 116 8h); lane 6, rpro-Der p (GS 115 ); lane 7, rpro-Der p Endo H-treated (GS 115 ); lane 8, Endo H (control); lane 9, nDer p 1; lane 10 , nDer...

Ngày tải lên: 17/03/2014, 11:20

... satisfies the hypothesis of theorem (2.3) then the solution of Eq. (12 ) in the case µ = is asymptotic equivalence to the solution of Eq. (12 ) in the case µ = Ackowledgments This paper is based on the ... extention of Levinson’s theorem to the case of linear delay differential equations under nonlinear perturbation (see [1, 13 , 14 ]) Let’s consider the two following differential equations: dx(t) = Ax(t), ... populations generator (A, D(A)), then we can investigate the assertion (2.5) for Eq. (13 ) (see [7, 11 , 12 ]) Applying the process of argument of parts 2 .1 and 2.2 to the uniformlly stable and asymptotic...

Ngày tải lên: 22/03/2014, 11:20

... this receptor We used the human astrocytoma cell line 13 21N1 and the human alveolar epithelial cell line A549 In 13 21N1 cells, mithramycin A reduced the PAR -1 mRNA level by 60–75%, whereas in ... Res 3, doi: 10 .11 86/rr166 12 Folkerts G & Nijkamp FP (19 98) Airway epithelium: more than just a barrier! Trends Pharmacol Sci 19 , 334– 3 41 13 Jordana M, Newhouse MT & Gauldie J (19 87) Alveolar ... epithelial A549 cell line, Sp1 inhibition, as in human lung fibroblasts, did not influence the PAR -1 basal transcription, whereas in the human astrocytoma cell line 13 21N1, the inhibition of Sp1...

Ngày tải lên: 30/03/2014, 04:20

... 30.6 kDa (Fig 1B) The PPP1R3G cDNA sequence 14 79 Novel glycogen-targeting subunit of PP1 A S Munro et al Gene -272 417 719 E1 12 79 17 13 18 19 E2 3036 317 6 E3 3660 E4 6656 E5 mRNA (ATG) E1 837 (STOP) ... sharing similarities to the human genomic sequences PPP1R3E, PPP1R3F and PPP1R3G (Accession nos: AL049829, NM_033 215 , AL035653) with chromosomes locations 14 q 11. 2, Xp 11. 23 and 6p24.3-25.3, respectively ... a (10 mmolÆL )1, phosphorylated by FEBS Journal 272 (2005) 14 78 14 89 ª 2005 FEBS Novel glycogen-targeting subunit of PP1 phosphorylase kinase) and GS (1 mmolÆL )1, phosphorylated by GSK3) in the...

Ngày tải lên: 30/03/2014, 16:20

... to )11 , Exon 2); Kin60: 5¢-dCGAGGCCGCAG AGGAAGGTGA-3¢ (+ 211 to +19 1, Exon 2); Kin129: 5¢-dCCCTCGCCCCACCCTCGG-3¢ ( )19 6 to )18 0, Exon 1) ; Kin130: 5¢-dGTTCAGTGGCACGATCTT-3¢ ( )19 8 to )18 1, Exon 1b); ... AC00 517 5 is 41 303 bp and contains the reverse complement of the TP coding sequence from nucleotides 5¢ 11 127–244 81 3¢ For bioinformatic analysis, the reverse complement of nucleotides 5¢ 11 127–244 81 ... within E1 and/or E1b, the TI site of TPb occurs at )15 to )12 As neither E1 nor E1b were present on the TPb mRNA transcript, this also suggests that neither P1 nor P2 are regulating the expression...

Ngày tải lên: 31/03/2014, 09:20

... & Front View 6.59 in 6. 81 in (16 .73 cm) (17 .30 cm) 6.59 in 6. 81 in (16 .73 cm) (17 .30 cm) 5.00 in (12 .70 cm) 5.00 in (12 .70 cm) 0.98 in (2.49 cm) 0.98 in (2.49 cm) NOTE: These diagrams are for ... Programming with the Crestron AppBuilder Programming with SIMPL Windows Problem Solving 11 Troubleshooting 11 Further Inquiries 12 Future Updates ... by selecting hardware from the Device Library In Configuration Manager, drag the PRO2 from the Control Systems folder of the Device Library and drop it in the upper pane of the System Views The...

Ngày tải lên: 03/04/2014, 11:20

... = 1, n? 38 a3 a1 b1 t1 a2 a5 b3 a4 b2 t2 b5 b4 t3 t5 t4 We can guess the answer as follows We know b1 P (a1 ≤ W (t1 ) ≤ b1 ) = a1 x2 − 2t1 e √ 2πt1 dx1 ; and given that W (t1 ) = x1 , a1 ≤ ... P (A1 ∩ · · · ∩ Am ) = P (X1 ∈ B1 , , Xm ∈ Bm ) = B1 × ×Bm = fX1 ···Xm (x1 , , xm ) dx1 · · · dxm fX1 (x1 ) dx1 fXm (xm ) dxm B1 by (3) Bm = P (X1 ∈ B1 ) · · · P (Xm ∈ Bm ) = P (A1 ) ... general, we would therefore guess that P (a1 ≤ W (t1 ) ≤ b1 , , an ≤ W (tn ) ≤ bn ) = (2) b1 a1 ··· bn g(x1 , t1 | 0)g(x2 , t2 − t1 | x1 ) g(xn , tn − tn 1 | xn 1 ) dxn dx1 an The next assertion...

Ngày tải lên: 08/04/2014, 12:24

Ngày tải lên: 08/04/2014, 12:25