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Introduction to Programming with Fortran pdf

Introduction to Programming with Fortran pdf

Ngày tải lên : 10/03/2014, 02:20
... Java 3.15.7 C# 19 19 20 20 20 20 20 21 21 22 22 23 23 24 24 24 24 25 25 25 26 26 26 26 27 27 28 28 28 29 29 29 29 30 30 31 31 31 32 32 33 33 Contents ix 3.16 Back to Fortran! ... Sets 22 .6 Perfectly Balanced Tree 29 9 29 9 300 20 .3 20 .4 20 .5 20 .6 20 .7 20 .8 20 .9 20 .10 20 .11 27 2 27 3 27 5 27 5 27 8 27 9 28 1 28 2 28 2 28 2 28 3 28 3 28 5 28 5 3 02 305 306 307 Contents 22 .7 xvii ... Interface 21 .11 Summary 21 . 12 Problems 28 7 28 7 28 8 28 8 28 8 29 0 29 0 29 2 29 2 29 4 29 5 29 5 29 5 29 5 29 6 29 6 29 6 29 7 22 Simple Data Structuring in Fortran 22 .1 Introduction...
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java an introductioan to problem solving and programming 6th edition

java an introductioan to problem solving and programming 6th edition

Ngày tải lên : 27/10/2014, 00:50
... for-each Statement 22 2 22 0 xxv xxvi TABLE OF CONTENTS 4 .2 PROGRAMMING WITH LOOPS The Loop Body 22 2 22 3 Initializing Statements 22 4 Controlling the Number of Loop Iterations 22 5 Case Study: Using ... fixed by the hardware but depend on the program using the memory FIGURE 1.1 Main Memory Bytes Byte addresses 3 021 11110000 3 022 11001100 3 023 10101010 3 024 11001110 3 025 00110001 3 026 11100001 3 027 ... 01100011 3 028 10100010 3 029 01111111 3030 10000001 3031 10111100 2- byte memory location at address 3 021 1-byte memory location at address 3 023 3-byte memory location at address 3 024 2- byte memory...
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A practical introduction to programming and problem solving 3 edition

A practical introduction to programming and problem solving 3 edition

Ngày tải lên : 23/03/2014, 15:53
... 14 61 21 28 20 20 >> fliplr(mat) ans = 94 47 75 42 45 75 45 94 47 42 61 28 20 14 21 20 45 46 CHAPTER 2: Vectors and Matrices >> mat mat = 14 61 21 28 20 20 >> flipud(mat) ans = 20 20 21 28 14 61 ... the result of rot90 another 90 degrees) >> mat mat = 14 61 21 28 20 20 >> rot90(mat ,2) ans = 42 45 47 75 94 2 75 45 94 47 42 20 28 61 20 21 14 If a negative number is passed for n, the rotation ... opposite direction, that is, clockwise >> mat mat = 14 61 21 28 75 20 20 45 >> rot90(mat,-1) ans = 20 21 14 20 28 61 45 75 42 47 94 94 47 42 2.1 Vectors and Matrices The function repmat can be used...
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MATLAB a practical introduction to programming and problem solving

MATLAB a practical introduction to programming and problem solving

Ngày tải lên : 06/02/2016, 08:23
... mat ¼ 14 21 20 61 28 20 75 45 94 47 42 >> fliplr(mat) ans ¼ 94 47 75 42 45 61 28 20 14 21 20 >> mat mat ¼ 14 21 20 75 45 94 47 42 45 75 42 47 94 61 28 20 >> flipud(mat) ans ¼ 20 20 21 28 14 61 ... the result of rot90 another 90 degrees) >> mat mat ¼ 14 21 20 61 28 20 75 45 94 47 42 >> rot90(mat ,2) ans ¼ 42 45 20 47 75 28 94 61 20 21 14 If a negative number is passed for n, the rotation ... Stormy Attaway — 2nd ed p cm Includes index ISBN 978-0- 12- 385081 -2 Numerical analysis—Data processing MATLAB Computer programming I Title QA297.A87 20 11 518. 028 553—dc 22 20110150 32 British Library...
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Introduction to optical waveguide analysis solving maxwell's equation and the schrdinger equation   kenji kawano, tsutomu kitoh

Introduction to optical waveguide analysis solving maxwell's equation and the schrdinger equation kenji kawano, tsutomu kitoh

Ngày tải lên : 17/03/2014, 14:41
... Eq: 2: 20†Š; 2: 24† ‰from Eq: 2: 21†Š; 2: 25† C2 cos…g2 W ‡ a† ˆ C3 ‰from Eq: 2: 22 Š; 2: 26† Àg2 C2 sin…g2 W ‡ a† ˆ Àg3 C3 ‰from Eq: 2: 23†Š: 2: 27† The resultant equations are Àg1 C1 ˆ g2 C2 sin ... (2. 25) by Eq (2. 24), we get   g1 a ˆ À tan ‡ q1 p g2 À1 …q1 ˆ 0; 1; 2; †: 2: 28† On the other hand, dividing Eq (2. 27) by Eq (2. 26), we get   g3 g2 W ˆ tan À a ‡ q2 p g2 À1 …q2 ˆ 0; 1; 2; ... n2 : x 2: 83† Subtracting Eq (2. 81) from Eq (2. 83) and Eq (2. 81) from Eq (2. 82) , we get 2 g2 ˆ k0 …n2 À n2 † À kx ; x 2: 84† 2 g2 ˆ k0 …n2 À n2 † À ky : y 2: 85† 2. 3 MARCATILI'S METHOD 27 The...
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Báo cáo khoa học: "A PROBLEM SOLVING APPROACH TO GENERATING TEXT FROM SYSTEMIC GRAMMARS" docx

Báo cáo khoa học: "A PROBLEM SOLVING APPROACH TO GENERATING TEXT FROM SYSTEMIC GRAMMARS" docx

Ngày tải lên : 18/03/2014, 02:20
... involve a choice * This analogy was probably first made by Firth (1957) and has been used several times since see [Winograd, 1983, p .28 7J 25 2 indicative / finite_ I i-I I J I interrogative I J ... DOSSlbility would be SUPDorted by a fever II so we ask I does she have one il Remember that at present, the features that would be preselected by the semantics must be preselected by hand for each individual ... Linguistic Analysis Blackwell, Oxford, 1957, PP 1- 32 Reprinted in Palmer, F.R.,[ed.) Selected Papers of J.R.Firth 19 52- 1959 Longman, London, 1968, PP ~'8 :2~ 5 Forgey,C.L "OPS5 User's Manual" CMU-CS-81135...
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Báo cáo khoa học: "PROBLEM SOLVING APPLIED TO LANGUAGE GENERATION" pptx

Báo cáo khoa học: "PROBLEM SOLVING APPLIED TO LANGUAGE GENERATION" pptx

Ngày tải lên : 24/03/2014, 01:21
... INFORM Act This sub-plan is marked by a tag indicating that it is to be realized by an Unpcrative The split specifics which h)wer level acuons arc performed by the utterance of the imperative ... bccn done by Scaric till,and has been incorporatcd into a planning system by Cohen [3] Not much has been done to formally specify the actions of focusing and concept activation Sidncr [ 12] has developed ... globally, considering the interactions bctwccn its parts, resolving conflicts, making the best choice among availab;e alternatives, and noticing redundant acuons or actions that could bc subsumed by minor...
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A Professional’s Guide to Decision Science and Problem Solving ppt

A Professional’s Guide to Decision Science and Problem Solving ppt

Ngày tải lên : 30/03/2014, 18:20
... Satisfaction 28 .10% 10 30.30% 10 33.30% 30.00% 38 30.40% Minimize Logistics Costs 18.80% 21 .20 % 10.00% 13.30% 20 16.00% Maximize Growth 28 .10% 21 .20 % 23 .30% 30.00% 32 25.60% Maximize Sales 25 .00% 27 .30% ... Management 28 .10% 10 30.30% 10 33.30% 29 31% Max/Improve Financial Soundness 18.80% 21 .20 % 10.00% 16 17% Max/Improve Market Position 28 .10% 21 .20 % 23 .30% 23 24 % Max/Enhance Technology Development 25 .00% ... Methodologies 22 1 B.1 B .2 B.3 B.4 B.5 B.6 B.7 B.8 B.9 Nominal Group Technique (NGT) 22 1 Normalized Direct Weighting 22 2 Analytical Hierarchy Process...
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Introduction to statics and dynamics problem book

Introduction to statics and dynamics problem book

Ngày tải lên : 08/04/2014, 11:27
... y x z problem 2. 26: F (Filename:pfigure2.vec1 .26 ) 2m 0.8 m D B C H G 45o O x problem 2. 20: A problem 2. 23: (Filename:pfigure2.vec1 .20 ) B z y E x B x (Filename:pfigure2.vec1 .23 ) 2. 27 In the structure ... (f) a x (Filename:pfigure2.vec2.3) 2. 61 Find the moment of the force 3 x W θ problem 2. 60: y b /2 /2 x b x 3 O y 45o x (e) y b x a b 2m (Filename:pfigure2.vec2 .2) (d) θ1 2. 50 What is the distance ... maximum? D O x x problem 2. 24: (Filename:pfigure2.vec1 .24 ) y 3m 2m Q B 1m A θ x D ˆ 2. 25 Find the unit vector λ , directed from AB point A to point B shown in the figure B y C 6" 2. 22 The top of an L-shaped...
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good cat! a proven guide to successful litterbox use and problem solving (howell cat book of distinction)

good cat! a proven guide to successful litterbox use and problem solving (howell cat book of distinction)

Ngày tải lên : 01/06/2014, 10:32
... Illustrations by John Martin Copyright © 20 05 by Wiley Publishing, Inc., Hoboken, New Jersey Illustrations copyright © 20 05 by John Martin All rights reserved Howell Book House Published by Wiley ... please contact our Customer Care Department within the U.S at (800) 7 62- 2974, outside the U.S at (317) 5 72- 3993 or fax (317) 5 72- 40 02 Wiley also publishes its books in a variety of electronic formats ... illustrations by John Martin.—1st ed p cm Includes index ISBN 0-7645-6936-8 (pbk.: alk paper) Cat litter boxes Cats—training Cats—Behavior I Title SF447.34.K35 20 04 636.8'0835—dc 22 2004019708 Printed...
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an introduction to diophantine equations a problem-based approach.pdf

an introduction to diophantine equations a problem-based approach.pdf

Ngày tải lên : 05/06/2014, 18:59
... equivalent to (x2 + 2) 2 − (2x )2 = py , which can be written as (x2 − 2x + 2) (x2 + 2x + 2) = py We have gcd(x2 − 2x + 2, x2 + 2x + 2) = Indeed, if d | x2 − 2x + and d | x2 + 2x + 2, then d must ... n )2 (2) If a, b, c are positive integers satisfying 1 + = , a b c then a2 + b2 + c2 is a square Indeed, a2 + b2 + c2 = k2 m2 (m + n )2 + n2 (m + n )2 + m2 n2 = k2 (m + n)4 − 2mn(m + n )2 + m2 n2 ... and (x2 , y2 , z2 ) = (14, 39, 42) we have 2 x2 + y1 + z1 = 59 and 2 x2 + y2 + z2 = 5 92 Define now (xn , yn , zn ), n ≥ 3, by xn +2 = 59xn , yn +2 = 59yn , zn +2 = 59zn , for all n ≥ Then 2 2 x2 +...
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Báo cáo toán học: " An introduction to 2-fuzzy n-normed linear spaces and a new perspective to the Mazur-Ulam problem" docx

Báo cáo toán học: " An introduction to 2-fuzzy n-normed linear spaces and a new perspective to the Mazur-Ulam problem" docx

Ngày tải lên : 20/06/2014, 21:20
... Ψ(hn−1 ) − Ψ(q2 f ) = Ψ(rf ) − Ψ(q2 f ), Ψ(h1 ) − Ψ(q2 f ), Ψ(h2 ) − Ψ(q2 f ), , Ψ(hn−1 ) − Ψ(q2 f ) = rf − q2 f, h1 − q2 f, h2 − q2 f, , hn−1 − q2 f α = (q2 − r) f, h1 − q2 f, h2 − q2 f, ... hn−1 − q2 f ≤ (q2 − q1 ) f, h1 − q2 f, h2 − q2 f, , hn−1 − q2 f = q1 f − q2 f, h1 − q2 f, h2 − q2 f, , hn−1 − q2 f β α α α = Ψ(q1 f ) − Ψ(q2 f ), Ψ(h1 ) − Ψ(q2 f ), Ψ(h2 ) − Ψ(q2 f ), ... Ψ(q2 f ), Ψ(h2 ) − Ψ(q2 f ), , Ψ(hn−1 ) − Ψ(q2 f ) = (r + q2 ) Ψ(f ), , Ψ(h1 ) − Ψ(q2 f ), Ψ(h2 ) − Ψ(q2 f ), , Ψ(hn−1 ) − Ψ(q2 f ) Since rf − q2 f, h1 − q2 f, h2 − q2 f, , hn−1 − q2...
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A Guide to MATLAB for Chemical Engineering Problem Solving ppt

A Guide to MATLAB for Chemical Engineering Problem Solving ppt

Ngày tải lên : 29/06/2014, 02:20
... this polynomial over the range of 20 -30 hours we define a n e w time vector (the independent variable) »newtime = [20 :30] newtime = 20 21 22 23 24 25 26 27 28 29 30 Use the function polyval(coefficient_vector,independent ... 0.0896 0.1 627 0 .23 04 0 .29 32 0.3517 0.4063 0.45 72 0.5049 0.5496 0.5916 0.6310 0.6681 0.7031 0.7360 0.7671 0.7930 cu = 0.0103 0.0856 0.1498 0 .20 48 0 .25 23 0 .29 34 0. 329 1 0.36 02 0.3875 0.4115 0.4 326 0.4513 ... in the workspace, Who&Size by typing whos at the command prompt use the c o m m a n d » whos Name Size T a ans b conc e k t time 1 1 3 1 by by by by by by by by by 3 12 11 3601 Total Complex 3...
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A Guide to MATLAB for Chemical Engineering Problem Solving phần 1 docx

A Guide to MATLAB for Chemical Engineering Problem Solving phần 1 docx

Ngày tải lên : 06/08/2014, 13:22
... ans = 1.1667 -0.5000 0.1667 »a' 0.3 529 0.8 824 -0.1765 »a\b 2. 4 722 -0 .25 00 -0.1944 -1.6111 1.5000 0. 722 2 »t = [0:8] t = And again, the element element operator - by - »a./b »t = t' ans = t = 1.0000 ... -13 »conv(a,b) ans = 57 17 42 -61 -65 Answer: 57X4 + 17X3 + 42X2 - 61X - 65 Exercise: What is (3X + 2X + 5) * (X3 + 2X2 - 2) ? answer: 3X6 + 6X5 + 2X4 + 3X3 + 10X2 - 4X + 10 The roots of a polynomial ... ans = 30 66 1 02 25 64 operator causes it to be e x e c u t e d on a element -by- element basis p »b = [1 1] b = 1 Print date: 10/4/00 a = 1 »a/b ans = 1.1569 0.3 922 0. 921 6 -0.5686 -0. 921 6 0.7843 ans...
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A Guide to MATLAB for Chemical Engineering Problem Solving phần 2 potx

A Guide to MATLAB for Chemical Engineering Problem Solving phần 2 potx

Ngày tải lên : 06/08/2014, 13:22
... this polynomial over the range of 20 -30 hours we define a n e w time vector (the independent variable) »newtime = [20 :30] newtime = 20 21 22 23 24 25 26 27 28 29 30 Use the function polyval(coefficient_vector,independent ... 0.0896 0.1 627 0 .23 04 0 .29 32 0.3517 0.4063 0.45 72 0.5049 0.5496 0.5916 0.6310 0.6681 0.7031 0.7360 0.7671 0.7930 cu = 0.0103 0.0856 0.1498 0 .20 48 0 .25 23 0 .29 34 0. 329 1 0.36 02 0.3875 0.4115 0.4 326 0.4513 ... in the workspace, Who&Size by typing whos at the command prompt use the c o m m a n d » whos Name Size T a ans b conc e k t time 1 1 3 1 by by by by by by by by by 3 12 11 3601 Total Complex 3...
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Advanced IQ Tests: The Toughest Practice Questions to Test Your Lateral Thinking, Problem Solving and Reasoning Skills

Advanced IQ Tests: The Toughest Practice Questions to Test Your Lateral Thinking, Problem Solving and Reasoning Skills

Ngày tải lên : 06/10/2014, 09:27
... articulate 22 13 × 82 = 0. 125 × ? Complete the equation by correctly identifying the missing part of the calculation from the list of options below a 21 32 b 59 36 c 8696 d 23 12 22 e 58 36 23 Which ... invigorate 11 32 + 27 2 = ? Complete the equation by correctly identifying the missing part of the calculation from the list of options below a 124 2 − 505 b 1478 ÷ c 123 2 60% d 125 46 8 42 e 17 12 Change ... Answer 22 46 2. 5 5= ? 0. 125 Complete the equation by correctly identifying the missing part of the calculation from the list of options below a 5.75 × b 11.75 e 15.75 – c 2. 2 52 × d 2. 75 × 23 Which...
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the first chapter will start with the introduction to the problem that mai dong mechanical company has been facing and also the research design and methodology of the research

the first chapter will start with the introduction to the problem that mai dong mechanical company has been facing and also the research design and methodology of the research

Ngày tải lên : 14/10/2014, 01:10
... key staffs Total number of resigned staffs Turnover rate 20 06 20 07 20 08 20 09 58 62 68 72 13 15 11% 13% 19% 21 % (Source: MDC HR department, 20 09) The above chart clearly shows key manpower numbers ... Figure 3 .2: Total Revenue in 20 06 -20 09 (Source: Finance & Accounting Dept at MDC, 20 06 -20 09) The critical trend of revenue from the year 20 06 to 20 09 is shown clearly in the Figure 3 .2 The business ... down dramatically from the year 20 08 to 20 09, decreased by 9.5% in 20 08 and 8.1% in 20 09 in terms of total revenue In 20 07, with the same difficulties like the year 20 06, MDC had mobilized the working...
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An introduction to disk drive modeling

An introduction to disk drive modeling

Ngày tải lên : 12/09/2012, 14:16
... Rotational speed HP C 220 0A 335 MB 1449 5 .25 ” 40 02 RPM HP 97560 1.3 GB 1935 5 .25 ” 40 02 RPM Average 8KB access Host interconnect type max speed 33.6 ms HP-IB 1.2MB/s 22 .8 ms SCSI -2 10 MB/s Table describes ... 0 .2 real model 0.1 0 10 15 20 25 30 Time (ms) 35 40 45 50 mean demerit 20 .00ms 10.2ms 40% 25 .35ms mean simulation 20 25 30 Time (ms) 35 40 45 50 8.9ms 35% demerit 22 .08±0.08ms 3.71ms 15% 0.9 ... simulation 25 .49±0.09ms 0.66ms 2. 6% simulation 24 .31±0.08ms 1.57ms 6 .2% Figure 4: I/O time distributions for four different models for the C 220 0A The real disk has a mean I/O time of 25 .36±0.09ms 12 describes...
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C++ - I/O Streams as an Introduction to Objects and Classes

C++ - I/O Streams as an Introduction to Objects and Classes

Ngày tải lên : 12/09/2012, 22:49
... out_stream.precision (2) ;  precision is a member function of output streams  After out_stream.precision (2) ; Output of numbers with decimal points…    will show a total of significant digits 23 2. 2e7 2. 2 6.9e-1 ... OR will show digits after the decimal point 23 .56 2. 26e7 2. 21 0.69 0.69e-4 Calls to precision apply only to the stream named in the call Copyright © 20 07 Pearson Education, Inc Publishing as Pearson ... in_stream2;  in_stream1.open and in_stream2.open are the same function but might have different arguments Copyright © 20 07 Pearson Education, Inc Publishing as Pearson Addison-Wesley Slide 6- 23 Class...
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