Solution manual for introduction to chemical engineering thermodynamics 8th edition by smith

Solution Manual for Introduction to Chemical Engineering Thermodynamics 8th Edition by Smith Full file SVNAS at https://TestbankDirect.eu/ Edition Annotated Solutions th power = Chapter energy J Nm kg m2 = = = time s s s3 charge time charge = current*time = A s current = energy = current*electric potential time energy kg m2 electrical potential = = current*time A s3 power = electrical potential resistance electrical potential kg m resistance = = current A s current = Updated 16/01/2017 p of 19 Copyright © McGraw-Hill Education All rights reserved No reproduction or distribution without the prior written consent of McGraw-Hill Education Full file at https://TestbankDirect.eu/ Solution Manual for Introduction to Chemical Engineering Thermodynamics 8th Edition by Smith Full file SVNAS at https://TestbankDirect.eu/ Edition Annotated Solutions th Chapter charge electrical capacitance charge As A2 s4 electrical capacitance =   electrical potential kg m kg m A s3 electrical potential = P Sat / torr b    a  t / C  c    10 B    7.5  P Sat / kPa=7.5exp  A   T /K C    b B     exp  2.303  a   =7.5exp  A   T / K - 273.15  c   T / K  C     b B   2.303 a   =ln  7.5 +A  T / K - 273.15  c  T /K C  Updated 16/01/2017 p of 19 Copyright © McGraw-Hill Education All rights reserved No reproduction or distribution without the prior written consent of McGraw-Hill Education Full file at https://TestbankDirect.eu/ Solution Manual for Introduction to Chemical Engineering Thermodynamics 8th Edition by Smith Full file SVNAS at https://TestbankDirect.eu/ Edition Annotated Solutions th Chapter The point of this problem is just for you to practice evaluating and plotting a simple function You will a number of problems over the course of the semester (and many more over the course of your career) in which the results are best presented in graphical form The only thing to be careful of in plotting the Antoine equation is to pay attention to the units of T and Psat and to whether the constants are given for use with the base 10 logarithm or the natural logarithm The parameters in Table B.2 are for use with T in °C, P in kPa, and the natural logarithm I used MS Excel to prepare the plots for diethyl ether A portion of the spreadsheet (containing the plots) is shown below: 13.9891 B Psat (kPa) 3.450361508 3.684455127 3.931786307 4.192943086 4.468531566 4.759176154 5.065519787 5.388224158 5.727969934 6.085456959 6.461404464 6.856551255 7.271655907 7.707496937 8.16487298 8.644602953 9.147526209 9.674502686 10.22641305 10.80415881 11.40866246 12.0408676 12.70173902 13.39226279 14.11344639 14.86631874 15.65193033 16.4713532 17.3256811 18.21602942 19.14353533 20.10935774 2463.93 C 223.24 Vapor pressure of Diethyl Ether Vapor pressure of Diethyl Ether 200 180 100 160 Vapor Pressure (kPa) T (deg C) -30 -29 -28 -27 -26 -25 -24 -23 -22 -21 -20 -19 -18 -17 -16 -15 -14 -13 -12 -11 -10 -9 -8 -7 -6 -5 -4 -3 -2 -1 Vapor Pressure (kPa) A 140 120 100 80 60 10 40 20 -30 -20 -10 10 20 30 Temperature (°C) Updated 16/01/2017 40 50 60 -30 -10 10 30 50 Temperature (°C) p of 19 Copyright © McGraw-Hill Education All rights reserved No reproduction or distribution without the prior written consent of McGraw-Hill Education Full file at https://TestbankDirect.eu/ Solution Manual for Introduction to Chemical Engineering Thermodynamics 8th Edition by Smith Full file SVNAS at https://TestbankDirect.eu/ Edition Annotated Solutions th Chapter SVNAS, problem 1.4 300 T (deg C or deg F) 200 100 deg C -100 -200 deg F -300 -400 -500 50 100 150 200 250 300 350 T (K) Updated 16/01/2017 p of 19 Copyright © McGraw-Hill Education All rights reserved No reproduction or distribution without the prior written consent of McGraw-Hill Education Full file at https://TestbankDirect.eu/ Solution Manual for Introduction to Chemical Engineering Thermodynamics 8th Edition by Smith Full file SVNAS at https://TestbankDirect.eu/ Edition Annotated Solutions th   Chapter        Updated 16/01/2017 p of 19 Copyright © McGraw-Hill Education All rights reserved No reproduction or distribution without the prior written consent of McGraw-Hill Education Full file at https://TestbankDirect.eu/ Solution Manual for Introduction to Chemical Engineering Thermodynamics 8th Edition by Smith Full file SVNAS at https://TestbankDirect.eu/ Edition Annotated Solutions th Chapter    Updated 16/01/2017 p of 19 Copyright © McGraw-Hill Education All rights reserved No reproduction or distribution without the prior written consent of McGraw-Hill Education Full file at https://TestbankDirect.eu/ Solution Manual for Introduction to Chemical Engineering Thermodynamics 8th Edition by Smith Full file SVNAS at https://TestbankDirect.eu/ Edition Annotated Solutions th Updated 16/01/2017 Chapter p of 19 Copyright © McGraw-Hill Education All rights reserved No reproduction or distribution without the prior written consent of McGraw-Hill Education Full file at https://TestbankDirect.eu/ Solution Manual for Introduction to Chemical Engineering Thermodynamics 8th Edition by Smith Full file SVNAS at https://TestbankDirect.eu/ Edition Annotated Solutions th Chapter dP MP  g dz RT dP Mg  dz P RT P Mg ln      z  zo  RT  Po   Mg P  Po exp    z  zo    RT   0.029*9.8 P  101325exp   1609    83430 Pa  8.314*283  Updated 16/01/2017 p of 19 Copyright © McGraw-Hill Education All rights reserved No reproduction or distribution without the prior written consent of McGraw-Hill Education Full file at https://TestbankDirect.eu/ Solution Manual for Introduction to Chemical Engineering Thermodynamics 8th Edition by Smith Full file SVNAS at https://TestbankDirect.eu/ Edition Annotated Solutions th Updated 16/01/2017 Chapter p of 19 Copyright © McGraw-Hill Education All rights reserved No reproduction or distribution without the prior written consent of McGraw-Hill Education Full file at https://TestbankDirect.eu/ Solution Manual for Introduction to Chemical Engineering Thermodynamics 8th Edition by Smith Full file SVNAS at https://TestbankDirect.eu/ Edition Annotated Solutions th Updated 16/01/2017 Chapter p 10 of 19 Copyright © McGraw-Hill Education All rights reserved No reproduction or distribution without the prior written consent of McGraw-Hill Education Full file at https://TestbankDirect.eu/ Solution Manual for Introduction to Chemical Engineering Thermodynamics 8th Edition by Smith Full file SVNAS at https://TestbankDirect.eu/ Edition Annotated Solutions th Chapter     Updated 16/01/2017 p 11 of 19 Copyright © McGraw-Hill Education All rights reserved No reproduction or distribution without the prior written consent of McGraw-Hill Education Full file at https://TestbankDirect.eu/ Solution Manual for Introduction to Chemical Engineering Thermodynamics 8th Edition by Smith Full file SVNAS at https://TestbankDirect.eu/ Edition Annotated Solutions th Chapter         Updated 16/01/2017 p 12 of 19 Copyright © McGraw-Hill Education All rights reserved No reproduction or distribution without the prior written consent of McGraw-Hill Education Full file at https://TestbankDirect.eu/ Solution Manual for Introduction to Chemical Engineering Thermodynamics 8th Edition by Smith Full file SVNAS at https://TestbankDirect.eu/ Edition Annotated Solutions th Chapter  Updated 16/01/2017  p 13 of 19 Copyright © McGraw-Hill Education All rights reserved No reproduction or distribution without the prior written consent of McGraw-Hill Education Full file at https://TestbankDirect.eu/ Solution Manual for Introduction to Chemical Engineering Thermodynamics 8th Edition by Smith Full file SVNAS at https://TestbankDirect.eu/ Edition Annotated Solutions th Chapter  m   q  1.25 kg m3 *55880 m3 s1 = 69850 kg s1  Updated 16/01/2017 p 14 of 19 Copyright © McGraw-Hill Education All rights reserved No reproduction or distribution without the prior written consent of McGraw-Hill Education Full file at https://TestbankDirect.eu/ Solution Manual for Introduction to Chemical Engineering Thermodynamics 8th Edition by Smith Full file SVNAS at https://TestbankDirect.eu/ Edition Annotated Solutions th Updated 16/01/2017 Chapter p 15 of 19 Copyright © McGraw-Hill Education All rights reserved No reproduction or distribution without the prior written consent of McGraw-Hill Education Full file at https://TestbankDirect.eu/ Solution Manual for Introduction to Chemical Engineering Thermodynamics 8th Edition by Smith Full file SVNAS at https://TestbankDirect.eu/ Edition Annotated Solutions th Updated 16/01/2017 Chapter p 16 of 19 Copyright © McGraw-Hill Education All rights reserved No reproduction or distribution without the prior written consent of McGraw-Hill Education Full file at https://TestbankDirect.eu/ Solution Manual for Introduction to Chemical Engineering Thermodynamics 8th Edition by Smith Full file SVNAS at https://TestbankDirect.eu/ Edition Annotated Solutions th Updated 16/01/2017 Chapter p 17 of 19 Copyright © McGraw-Hill Education All rights reserved No reproduction or distribution without the prior written consent of McGraw-Hill Education Full file at https://TestbankDirect.eu/ Solution Manual for Introduction to Chemical Engineering Thermodynamics 8th Edition by Smith Full file SVNAS at https://TestbankDirect.eu/ Edition Annotated Solutions th Chapter A 12.74 B 2017.87 C -80.87 T (°C) -18.5 -9.5 0.2 11.8 23.1 32.7 44.4 52.1 63.3 75.5 T(K) 254.65 263.65 273.35 284.95 296.25 305.85 317.55 325.25 336.45 348.65 Psat (kPa) ln (Psat) ln (Psat)fit Error2 Psatfit (kPa) 3.18 5.48 9.45 16.9 28.2 41.9 66.6 89.5 129 187 1.157 1.701 2.246 2.827 3.339 3.735 4.199 4.494 4.860 5.231 1.125 1.697 2.253 2.849 3.368 3.767 4.211 4.479 4.841 5.201 1.02E-03 2.03E-05 4.77E-05 4.61E-04 7.96E-04 1.02E-03 1.43E-04 2.24E-04 3.50E-04 9.19E-04 3.08 5.46 9.52 17.27 29.01 43.26 67.40 88.17 126.61 181.42 Error Sum 5.01E-03 6.000 200 180 5.000 160 4.000 Pressure(kPa) ln(Pressure(kPa)) Relative Error -3.2% -0.4% 0.7% 2.2% 2.9% 3.3% 1.2% -1.5% -1.9% -3.0% 3.000 2.000 140 120 100 80 60 40 1.000 20 0.000 200 250 300 Temperature (K) ln P sat / kPa  A  350 400 -50 50 Temperature (°C) 100 B T / KC Updated 16/01/2017 p 18 of 19 Copyright © McGraw-Hill Education All rights reserved No reproduction or distribution without the prior written consent of McGraw-Hill Education Full file at https://TestbankDirect.eu/ Solution Manual for Introduction to Chemical Engineering Thermodynamics 8th Edition by Smith Full file SVNAS at https://TestbankDirect.eu/ Edition Annotated Solutions th Updated 16/01/2017 Chapter p 19 of 19 Copyright © McGraw-Hill Education All rights reserved No reproduction or distribution without the prior written consent of McGraw-Hill Education Full file at https://TestbankDirect.eu/ .. .Solution Manual for Introduction to Chemical Engineering Thermodynamics 8th Edition by Smith Full file SVNAS at https://TestbankDirect.eu/ Edition Annotated Solutions th Chapter... https://TestbankDirect.eu/ Solution Manual for Introduction to Chemical Engineering Thermodynamics 8th Edition by Smith Full file SVNAS at https://TestbankDirect.eu/ Edition Annotated Solutions th Chapter... https://TestbankDirect.eu/ Solution Manual for Introduction to Chemical Engineering Thermodynamics 8th Edition by Smith Full file SVNAS at https://TestbankDirect.eu/ Edition Annotated Solutions th Chapter