ĐỀ THI TUYỂN SINH ĐẠI HỌC, CAO ĐẲNG NĂM 2010 Môn thi : HOÁ, khối A - Mã đề : 596 H = 1; He =4, Li =7, Be =9, C = 12; N = 14; O = 16; Na = 23; Mg = 24; Al = 27; S = 32; Cl = 35,5; K = 39; Ca = 40; Cr = 52, Mn = 55; Fe = 56; Cu = 64; Zn = 65; Br = 80; Rb = 85, Sr = 88, Ag=108; Sn = 119; Cs =133; Ba = 137: Pb = 207. PHẦN CHUNG CHO TẤT CẢ THÍ SINH (40 câu, từ câu 1 đến câu 40) Câu 1 : Dung dịch X có chứa: 0,07 mol Na+; 0,02 mol SO42- và x mol OH-. Dung dịch Y có chứa ClO4-, NO3- và y mol H+; tổng số mol ClO4- và NO3- là 0,04. Trộn X và Y được 100 ml dung dịch Z. Dung dịch Z có pH (bỏ qua sự điện li của H2O) là A. 1 B. 2 C. 12 D. 13 ĐLBTĐT: 0,07 = 0,02*2 + x ⇒ x = 0,03 (mol); y = 0,04 (mol) . Vậy nH+ dư = 0,01 (mol). [H+] = 0,01:0.1 = 0,1 (M) ⇒ pH = 1 Câu 2 : Cho 19,3 gam hỗn hợp bột Zn và Cu có tỉ lệ mol tương ứng là 1 : 2 vào dung dịch chứa 0,2 mol Fe2(SO4)3. Sau khi các phản ứng xảy ra hoàn toàn, thu được m gam kim loại. Giá trị của m là A. 6,40 B. 16,53 C. 12,00 D. 12,80 65x + 64*2x = 19,3 ⇒ nZn = 0,1 (mol) ; n Cu = 0,2 (mol) ; nFe3+ = 0,4 (mol). Zn + 2Fe3+ → 2Fe2+ + Zn2+ Cu + 2Fe3+ → 2Fe2+ + Cu2+ 0,1 ----→0,2 0,1 ←-- 0,2 Vậy còn dư 0,1 mol Cu m = 0,1*64 = 6,4 (g)
Giải đề thi ĐH-CĐ năm 2010 !"#$%&'( ) * + ), - ). /+ )' ) * ) ,* ) (* 0 ) 1* 2 ) ,* 3 ) .* ) 1* 3 ) 1&&* 4)1'*0),*5)&)&&*6+)&(*7)(,*8)(&*/5)9*:;)9&5)992)9*)'*<)11*/0) 1.=;).> =?@ABCD E7F72G H IJIK L IM L 0.NK30 O *NK3 , " P0 Q RNK3 " >F72G H IIK L IM L 03 , " 1 " P0 Q SNK3 O * T 2 <LNK33 , " PU 1 " 30 Q ,>5 H JP0 Q $MV H IN3G72G H I8>F72G H I8IK L WC;K T X70<M H $Y H 3I7 T 0 D30 Q > /> > F>1 ⇒ !"# $ %&!'$ (!) ⇒ *$ E7K'120NZV H W; H 8P0 Q 7IK L [ T 3Y H NK3MV2M L 230 Q P0 Q KG72G H IIM L 0NK36+ C , D 1 >07 I0 L I W0 T M L 2R0 T S50K0 Q K0 Q 7$MV H IN20N N3K0 H >0 L 5 H I7 T 0N30 Q >(, />(&1 > F>9 +,+- ⇒ . / 01 ! .01 → 01 . /01 → 01 / 22223422 "# 5%&/++6 E71ZV H W [ L J2QN P0 Q IK L [ T L <KPV L +;\Q29>7K L 2JN H V Q 205K2;[ Q [ L CIK L ; H 6+30 Q NR7 L I 0 L ID7$MV H IZV H W [ L IK L [ T L<KPV L +;\Q2>Y H 7<7ELI7 T 0W0 T M L 2 T 2V H W 1 30 Q >&] />1(] >,] F>&] /78797:*;<= >?2<$ !<@)A2<A ⇒ < B?&:6= *7CD6= $ ⇋ =$ A 2A2 ⇒ 797:* EAEE 4*1,8 1 2 hh hh m M n x = = − ⇒ ,! ⇒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€ 1 C D>4\2Y H $ H [ Q [ T LI7 T 0ZV H W [ L <KPV L 20 T N$>=0 L ;Y T 7 $7 L 2 K L PYQIE;\Q20 Q S30 Q >=0 T M L 22 H IK0 T Y H IE;\Q2G H II7SY T +KIYQ77E H \2Y H $ H > />=0 T M L 27E H K0 T Y H IE;\Q2G H II7SY T +KIYQ72 H I \2Y H $ H > >=0 T M L 22 H I7Y H IE;\Q2G H II7SY T +KIYQ77E H \2Y H $ H > F>=0 T M L 27E H 7Y H IE;\Q2G H II7SY T +KIYQ72 H I \2Y H $ H > "^_[7IV7QV797:*>`V$ 6VCLYI797:*a6YI*7M[7ba6E717W67R7! "# *7CD6c<7Vd[7Va67VdeJK67 f%R7717VW67R7! E7.KN20N0P0 Q K3[ L G72G H I0 1 Q2$ H 0NK3_37$MV H I3[ L G72G H IJ>-ELS3[ L G72G H IJ0 L I G7 H 2PV L G72G H I/03 CGMD7$MV H I920N YL7 T 0>\ H 0 L IIK3[ L G72G H IJP0 Q KG72G H I03 CGMD5Q$7 K L 2<07 YL7 L II0 L IW0 T M L 27$MV H I.20N YL7 T 0>0 L 5 H I7 T 00NMV2M L 230 Q >,P0 Q ,9 />.P0 Q 1 >9P0 Q ,9 F>,P0 Q , /@ </T + /</T L%%B@IV/T 2 >?$/T 2 %&! $/T 2 T$ 2 3/T 2 $ T< /T 2 3</T + ← 222+ ← 2222222222222222222222222222222222222222222222+"# +A6 $/T 2 3/T 2 /T $ T/< /T 2 3/</T !YIg<$/T 2 ?+ 222222222223G+G 22!/@+G!"# <AGA) E79 H WEM T <0II05K`VIK L >N H 2LIβ"237IK`VP0 Q N H 2LIβ"a57IK`V />N H 2LIβ"237IK`VP0 Q N H 2LIα"a57IK`V >02L Iα"237IK`V F>N H 2LIα"237IK`VP0 Q N H 2LIβ"a57IK`V h*hi! E7'RK0 L YL20NZV H W00IK3$VIM L I0 Q 0$+IEQPM Q 0$7 T ,920N7>KK0 Q ; H 3MV H 20$+ 5Y0 L IG7 H 2PV L 3MV H 2GMG72G H I2 1 5K2 1 7$MV H I1.(20N2>00IK330 Q > & & /> & 1 . > 1 & F> 1 & 1 Tài liệu luyện thi Đại học năm 2010 - 2011 Giải đề thi ĐH-CĐ năm 2010 / $ T$/T → / $ T/ $ T /T < <%17V + j6 2,2 36,67 0,06 ancol M = = ># e7O/$ T$ 3 2 1 2 4 2 n n n n CH OH HCHO Ag C H OH C H O Ag + → → → → 0,06 0, 05 4 2 0,22 0,01 x y x x y x + = = ⇒ + = = 797:*< ,) kT$ k+E!j5UV?/ $ T$ E7ZV H W2QN0IK3K$VIM L IJP0 Q 0RI0I;KRS3I$VIM L I$YQ7N0 H IV T PUIK L I7 Q 2<L 27SYM T T 2<L NK3I7 T 00IEL 30 Q &NK3C<LNK3I7 T 03V L V<LNK3I7 T 0JD>YL7$L I0 L SK0 Q K0 Q [ Q 7$MV H I11(3[ L [ L C$ ID P0 Q &20N >\ H 0 L IYL7$7K L 2PV L , $\ H I$Y T M H IY H W0 T M L 2+<+K0 L CY H 7<7EL30 Q 9]D[ Q <L20N+<+ 7$MV H I30 Q >1, />.1( >9 F>9, HI/ /T G 77 ># <?/ $ T$3$ T!"^ =&` l /T L<V[7\6! jV@/@$/$ /$2/TT$3$ T ,>? !<@>? 7# /$m/2/TT$3$ T ,>? !<@>? UV n l B oY1?/$ /$2/TT/ $ !"`V /$/$2/TT/$ AA6 E7KG72G H IJ2QN.NK30 O *1NK30 O *(NK33 " *( 3 HCO − P0 Q NK3 3 NO − >Y T 3K0 H ;K T YL 0 O 5K2JIEQN H 3MV H 2Pb0$7 T G72G H IIM L 0020N0CD [ L 05 H I7 T 0030 Q > /> >,,, F>9 /<T$ ! T$2 >? /< !71WJ?V T$ 2 $/T 2 3/T 2 $ T +2222222223+ /< /T 22 3/</T ! +/7_@7c<p!"# <6 E7ZV H W [ L 0 Q K<07$ES 2Q0 H V T Y H $ H MV Q 2c > P0 Q 6 />3 P0 Q > P0 Q F>P0 Q 0 ?*7V[VU77O*7CD6p7Vd>`V$ 6< CN6J@6IV>?7VdeNO! E717K L 2ZV H W [ L J2QNNK3 P0 Q 1NK3 5K2N H ;[ Q [ L CR7 L I0 L ID7$MV H IZV H W [ L > K3 H M Q M Q P0 Q K;[ Q MV L I;5KNCGMD<07 YL7 L II0 L IW0 T M L 2 L 3MV H 2;[ Q \2N20NP0 Q IK L 9N3ZV H W [ L 8C$ IDK0 L 50>[ T LI7 T 08<KPV L 30 Q 9>0 L 5 H I7 T 0N30 Q >19 />& >&9& F>( N6,[7b7hN<?$ >?/ $ + , /$+ $ ,A,E!GA$ >?GA/ $ + ! a6 797:*; 2 [7b7hN<! +EGAEGAA6 E7,72K L 2M Q 2I\ H WIEL5K2;[ Q [ L CD6+OC5DCD6+ 1 OC DC1D7O C DC,D7O7C 1 D C5DC&D 7O4 1 C5DC(D3O03C5D>0 L I5MV Q 2V H WR0 T S50W0 T M L 2KRK0 L N3K0 H 30 Q >CDC1DC(D />CDC1DC,D >CDC,DC&D F>CDC&DC(D /7_@,@*7CD6/7_@,[VUV?7O[7M! E7& T 2<LIEL M Z 7IVN0 H IV T IK L I7 Q 2I2M L IWEM T , 30 Q >1 /> > F>, /h//U77q*7r7:*$/TT/$ /$ /TT$$T2/$ 2/$T E7(K L I0 L IW0 L ;Y T 7<07 CD-M77S Q WKWK$YQ7;LII0 L S YLWR7 L IPV L 5 1 CDK6+ 1O IK L IEL7[ Q +3+I5KPYL2K H 30 Q d5e1G & C1D/ H NM H ;L II0 L S YLWR7 L IPV L [ L I3K C,D=+ Q I70IK L I2M L I0 , >3 C , D 1 >, >0 L IW0 L ;Y T 7$7 L 230 Q >CDC1DC,D />CDC1DC,D >CDCDC1D F>CDCDC,D X7hJVfY<V*7s7<@/Xt HT !j HT !$ T! E7.=0 L ;Y T 70 Q K<07$ES$7 L 2c >0 L I N3K0 H 05;05;+5$YQ70 L IG7 H 2PV L MV L IV T Y H $ H MV Q 2 />4N3K0 H R+5$MV H IG7 Q 2$Y T IYL0 H KYL;0 Q KX702$Y H >4N3K0 H N02+IK L Y T 7N0 H 2Y T 3E H WWMV2ENGY H F>+KIYQ7\2GEQI7 T 0$Y H [ L I0 H EI0 L I N3K0 H YQN T CM Q ;+5$YL;05DIK L Y H $ H K L 2I0 T S20 T NGEQ UVj>^1t7\6h%u6>`V&`UV/>^)6@V77fu*7&Q6UVi>^t[VW7]@YvJV7VL7Vde [7\671wV#>^7x6@[VfU6V77f[7h7<! E79K0 Q 0K0 Q K0 Q N20N8 , P0 Q KMV L I$MV H IG72G H IJ>YL7IKN3G72G H I4P0 Q KJ[ Q 7$MV H I 1020N YL7 T 0>\ H 0 L IYL7IK,N3G72G H I4P0 Q KJ[ Q 7$MV H I020N YL7 T 0>0 L 5 H I7 T 0N30 Q >1 />,& >.. F>( =7#7O [g<6VC%;L*7CD6@%&=<T$!y8VYI.HT ;^<GA! /@*7CD6.HT =<T$3.T$ =< HT <.T$ =<T$3=< .T $ T 2E"# E &Q6vN&z67:*2 yVCV7d!"# ++6 E7'KI0 L I3K0 H V;2VI0W5KVR+373K`V0R+0V\QNV5K3K"((>LV T 2V H W30 Q >1 />, > F>& Q]67:*?Q<*NQVNV2++ E75K2<LI0 L IW0 L ;Y T 7<07PYQW+K3C ( & D CD=+K30[ L 5K2MV L IM20YQ75K2G72G H I3 2 Tài liệu luyện thi Đại học năm 2010 - 2011 Giải đề thi ĐH-CĐ năm 2010 CD=+K3IK L [ L 0RG72G H IW+K3 230 Q N$ T N0 Q 7X7S Q [ L N C1D=+K3G7 Q 2$Y T <0 T R7EL +KG0 L IELGY H ELNNLI C,D=+K30N20W0 T M L 2YL;5KNP0 Q YL5KGYZV;+`+ 0 L IW0 L ;Y T 7$7 L 230 Q >CDCDC,D />CDC1DC,D >CDCDC1D F>CDC1DC,D UV>^*71[7\6<N6&`[7\6*7CD6>`V$/L[7\6<N6%%$/! E7K L ;0KY75W+WCN0 H IV T D 0 L I3K0 H N0 Q 7S T WEK0 Q K0 Q $YQ77$MV H I10NK0R23SR030P0 Q W+S3030c >1 />' >, F>( f7g *7UN<<V<V[7h7<7^<V<VUL*1*V*7?V[7h7<@? yV2j<2X71*712<<26V<<26V2*71*7126V2<<<<2*7126V6V2*712<< E7ZV H W [ L J2QN$N+S30NP0 Q 0$5KI0I;K$Q2$\ T 23YYLW>L I0 L SK0 Q K0 Q N3ZV H WJ;\Q2 N H 3MV H 2KRPM Q 0$7 T 7$MV H I&&N3ZV H W2QN [ L P0 Q VMV L I>YL7IK$X70G72G H I0R<7a75I$\ H ICGMD[ Q IK Q 30 H &N3 [ L CI0 L IY T [ L I [ L P0 Q V$KV T I7 Q 2$YQ7 Y H D>2M L IWEM T I7 T 00$5KI0I;K30 Q > ( P0 Q 1 9 /> 1 ( P0 Q , 9 > , P0 Q ( F> , P0 Q 1 ( " $T " 6Vp ,!" /T " = " 5UV ,!i" 77 L 2 50 N V ml < { 200 250 2 2,5 100 100 C= < < = {UV/! 2=?<[<7^ 2 2 2 2 2 300 250 50 C H N Ankan H O CO N V V V V ml + + = − = − = ≠ {"\|{i E71=0 L ;Y T 7$7 L 230 Q >47S T WE$YLI7 Q 2I0 L IW5K+$V20 T <+ Z IKZV H WI0 L Iα"0NK0R />4IKG72G H I3K Q 25\L 25M L 2P0 Q K7CD ELSR7ELY H WM L IN0 Q 7R0$E H N >f`N0N30`0R7 L I0 L IIKW0 T M L 27S T WER+373K`V0 Q N0K`V F>R7I3+I30 Q WK3+<+I7 T 00RWKWK5IP0 Q 237IK`V h*hj! E7,L I0 L SK0 Q K0 Q N20NZV H W10IK3$VIM L I7 H II7 Q 2G0 Z S$Q2$\ T 27$MV H I1993[ L [ L C$ IDP0 Q &,20N >0 L 5 H I7 T 0N30 Q >,. />&, >., F>&. /T $T <! < 2 2 1 17 13 n n C H OH n + ⇒ = 17 0,13*(14 18) 0,13*(14* 18) 4, 72 ( ) 13 m n g= + = + = E7&E H $ H 0 Q K<07$ES$7 L 2 K L PYQ127SYM T 26 55 26 13 26 12 X, Y, Z ? >J7 H II7 Q 2N H 27SYLK0 L K H I />JP0 Q 8IK L I7 Q 2<L L >JP0 Q IK L I7 Q 2<LV5K F>J830 Q $Q2P H I7 T 0I7 Q 2N H 27SYLK0 L K H I h*hj! E7(KRNK36+0K0 Q K0 Q 5K2G72G H IIM L 0SNK3 , C[ T 3Y H RS)&D7$MV H IN H <0 T WE T N M T G7S ELP0 Q G72G H II[ T IM L 0NL<7a0>LNK3+3+I5KGK3MV H 26+5YMV Q 2 ; H K0 Q 030 Q >1R />S >R F>S =$ HT 01301HT $ !UV>^ !=+$ HT 01301 HT HT +$ T!UV>^ @Y N<UC7<VIV01 >?01 !HT 2 $ 13HT $ T! HT 2 ?\VN&z6HT G{17 JC?HJ<;@ $ HT <@17!HT E7.R+K$MV H I$YQ7IYL;\Q2I0 L IKRK0 L I7N+V Q KR<07$K L 7S T WE5K2G72G H I , 3K0 Z 2>Y T 7$MV H I ,&20N0R+K[ Q 3MV H 2I7N+IEQG7 Q 2C20 T <M T Y H 7<7ELX70 L 5[ Q $YQ7IYL$0 H .&]D30 Q >120N />&20N >,20N F>(20N HQ}/ + $ , /$/$ 2 3 1, 2, O H O + + → /$ /T! 145 2,5 ( ) 58 xeton cumen n mol n = = = 2,5*120*100 400 ( ) 75 m g = = E79KI0 L IIEL0 1 3CD 1 6+CD 1 63 , 3>L IEL0 L IG7 H 2$MV H IPV L G72G H I03K0 Z 2V T Y H $ H MV Q 230 Q >, />& >1 F>( /h7Oh%u6>`V=<T$ 7&z6?=<$/T jT$ $0/ =$ /! E7'7S T WEK0 Q K0 Q NK3N H +<+fIEQG7 Q 2PM Q 0$7 T 20NG72G H I0,]7$MV H IN H 0IK3P0 Q ,1( 20NZV H WN7LI7 T 000RI0I;KRS3I$VIM L I>00R$K L 30 Q >P0 Q 1 /> 1 P0 Q & > & P0 Q 1 . F>P0 Q & =<T$ +! 3 NaOH este n n = !=Lo?NV1Y1 3 3 ( ) ' 3 3 '( )RCOO R NaOH RCOONa R OH+ → + 43,6 72,67 5,67 0,6 RCOONa R= = ⇒ = !7O?$/TT$YIUV/! +A)+!)A/$ /TT=< ># 7O$/TT$>< ~ /$ /TT$ E710 L I27SYLM Q -$YL6+KIYQ7\2I7 T 0$Y H [ L I0 H E[ Q >/0 L [ L 27SYM T P0 Q $ H EN$Y H $YQ7\2 />/0 L [ L 27SYM T \2$ H EN$Y H 20 T N >/0 L [ L 27SYM T 20 T N$ H EN$Y H \2 F>/0 L [ L 27SYM T P0 Q $ H EN$Y H $YQ720 T N V0r67[^LJ< • [€ • 76 L& • 6V< • \ ‚ VL ‚ a6 E71K&NK3 1 & CD C0R2370NIDPUK.&N3G72GgI37$MhIG72GgIJ>K0 GMPUKG72GgIJ>07 IiIWjk2RjS50KUKU<!NK30$#Wjk23U 3 Tài liệu luyện thi Đại học năm 2010 - 2011 Giải đề thi ĐH-CĐ năm 2010 >&> />(&> >.> F>&&> $ =/ $ , /TT$ $/ → /$ =/ $ , /TT$ ! ,,,$/%&,E, /$ =/ $ , /TT$ =<T$3$ =/ $ , /TT=< =</$ T$/=<T$3=</$ T ,2222222222222222 → , → "# =<T$ +, E71K.20NlhW2mNNn N3Ko %NJPUNn N3Ko %NpiIGq2rPs3Mh2GMG72GgI 33K#27$MhI&(3t tC$ ID>4N3KoJ3U >05PUN02+> />3PU;+5> > 03PUI0R> F> 03PU;05> 2 (1 2); 2 2 . 7,1 7,1 7,1 0,5 0,25. . ì 14,2 28, 4. à Na ; Mg 0,5 n M ne M n H e H n M n V M KL l M M + + − → < < + → → ¬ = ⇒ < < E711u00KUKU9',20NlhW2mN04PU/0PUKMsI7$MhIG72GgIJPU(993t t C$ ID> F72GgI2mN3PU , v3wNK3MV2k23U,>572u0G72GgIJ;xG72GgIp2 !3Mh2IiI N7!$MhIoK503U >1.20N> />9,(20N> >.920N> F>,(20N> <@$ T3T$ 2 ƒ$ ! T$2 !$/$ HT 7^ /2 HT $ + ⇒ ! IV t /2 HT A-,,-+A+6 E71,K<V$mI7Syz0 1 ( 2 dung dich Br → J NaOH → 0 ,CuO t → 8 2 ,O xt → 0 3 , ,CH OH t xt → fCf<+$0 IkID>Y2{I|03U >W5KW0"1"$K3> />W5KW0""$K3> >W5KW0""K3> F>23R+5K3> "^o?1Y1<7DL*7CV?<V<7D># / $ + ?V*N*<7O;^?*N*<22V! E71&K,G72GgI , 3K#22 1 7 , 26>} 2iIGq2$MhIPsIj,G72GgI5Y3U >4> />/03 > > 1 > F>0 1 > /7_@=<=T [7\6*7CD6>`V%p h7ONL! E71(=jk2$wWEG72GgI73 CPs$wI~I5VDPUWjk2\Nu$wz0RjS50 •2hW N8" 7PUKG72GgI3Iz$€I$yN3U >=jk2RjS5037 •N+K<~Wi<Gu2$w> />%7<507xI~IEN> >=jk2xI~IENIz<~0N20I|0 N3KoK€IK N3Ko F>=jk2xI~IGMV2$%73U<~KRz03 " > UVNj>^Vd*7VL7u%56Vd! Y<V>^v.[VUV.JRa5 E71. +JhWMsIoKU1"+S3W+0"1"K3>YI|0J3U >1"+S3W+"1"+> />"+S3W+""+> >1"+S3W+""+> F>1"+S3W+""+> /$ 2/$ 2/T$E/$ 2/$ 0 2 4 ,170H SO C → /$ 2/$/2/$ 2/$ $ T /$ 2/$ /$ 2/$ 21 *121 E719K<V$mI7Syz05K3+ 0 2 ( , )H du Ni t+ → J 0 ,NaOH du t+ → HCl+ → 8> YI|083U >0R3K3+I> />0RK3+I> >0RW0NI> F>0R<+05I> HQ}>VUV NV1V'/ $ /TT / $ , ( 0 2 ( , )H du Ni t+ → '/ $ , /TT / $ , B 0 ,NaOH du t+ → / $ /TT=<n HCl+ → / $ /TT$E<VY1<NV.! E71'=i;y7 2$•23U >$5K<7a70;gKRz0;xMsII3Kxw$nM‚2> />4NIMV20Iƒa73+5+3UIiIGo2„ƒI|0I0I;K> >}IjIiI27SY!03K2+$%7IzIiI<!KRz0"OO1O&PUO.5K2IiIhWI}> F>5K2I22wWWKWK$MhI<jR7};…2IiI72lhWX7€2WKWK5IiPU0I!Ix 5K2 3u$w> /h7<61@YIV7@<2,N67:*7O!N0*7V[VU77O\@YIV7@<2N67:*7O! E7,!IiSKUKUNn+<+$VIkINoIxJCWE†Iz<!3Y rπ‡V1D7$MhIytI t ;…2(_.ytI t $#Wjk2CIiIytI t$KxI„2$%7 wD>KN20NJiIGq2KUKUPsN3G72 GgI4.7$MhIG72GgI>Io7$MhI9920NI}5ˆ 0>i5gI|0N3U >.> />(((> >999> F>&(> y8V<?YIVL[„N66I7V%N<J!iYIVL[„N6BlL<l! 2 2 2 2 2 2 3 2 6 3 2 6 12 ( ) ( ) . *( ) . 18 6 12 14 2 7 2 4 n n a n a n a a C H O O nCO n a H O n n a n n − − − − − + + → + − ⇒ = ⇔ − − = ⇔ = /7_@<7c<p/X/ $ + T @//$/TT/ $ , >?/$ /TT/$ ! 7MtT$*7CD67[7IV&:6IV[7\67c<p!=LtT$%& / $ + T tT$3k/TT$k…T$k…?/$ 7†/ $ , T$?YI1Y1l! ‡*%u6t 1Y1 tT$ kZ k…T$ ⇔ ,+AAk…! ⇔ 3 2 5 '( ) 15 0,12 57 ' 5,04 '( ) 29 0,18 ( ) R CH x x R x R C H x sai − = ⇒ = − = − = ⇒ = !"# AAA6 >=?:‰CIE7D"7bYV77_&:?eN67<V*7;*7;j7† >+KIMV25ƒ7ŠCIE7bIE7,$rIE7&D 4 Tài liệu luyện thi Đại học năm 2010 - 2011 Giải đề thi ĐH-CĐ năm 2010 E7,}$MhIG„2$yŠS5ˆ22}SPU;n2}S5K2I22wW3U > > /> > > > F> > HT @b7ˆ ?&:D6%u6?7Oˆ ?N6\667Vd*6VO >CV! E7,lhWJ2mNNK30NK0RKNoIxPUNK30NKNoIx>JIz j\2Wjk2!$0PsNK3 3K€INK30>!IiSKUKUJ7$MhI(NK3 RNK3 PUSNK3 >iI2i5gRSMV2k23U >9PU> />9PU&> >.PU> F>.PU&> HI7@E=$ $/ G B G!"# <VQ7D<V<V@e7@E=$ ! HI7@E/TT$g<<V<V =<T$ GG!"# <V<V@7<V7@E/TT$! /Xg<7O? 2 6 . 3 2 CO n y z t hh n C H O N n n ⇒ = = = <%r6 n 7C<V>?<V<Vf6VCVh! 2 2 2 2 2 3 7 2 2 2 2 min : ( ) 3 2,5 0,5 ; min : 3 4,5 0,5 1 3 2,5 0,5 1 3 4,5 0,5 a oaxit NH CH COOH CO H O N a C H NH CO H O N → + + → + + − − − − − − − − → → → − − − − − − → → → ,, ,, E7,1b920N237IK`V;…2WMV2WiW3YN+5Mh77$MhI020N0IK3+S3ICw7<7}9]D>Rz0020N 0IK3+S3I;…2WMV2WiW3YN+2}N7$MhIlhWJ>y572u0lhWJI‹.N3G72GgI0 >w7<7}X7i5ƒ3YN+2}N3U >9]> />]> >']> F>]> "`V<6< 6‰Q =<T$ !/ + $ T + 3/ $ , T$3/$ /TT$=<T$<?$F;^ 3A22222222223A< A< ⇒ <-7< $F-F E7,,iII}Pb0iIGq2$MhIPsG72GgI3Pb0iIGq2$MhIPsG72GgI2 1 3U >732> />876+> >20/0> F>8> h%u6>`Vj6=T 7^?[VUVUVj/>^/T)6T!h%u6>`V$/LtN&`$UV>^/Y<$! E7,&5K2Wjk24 5 . O3→53 1 O3 O43O !WE†3$z2P05uI} †;…2 3‹p2<!WE†30N20Wjk2>i5gI|0 3U >,_.> />_.> >1_,> F>1_.> X7CD6t /N T $/ → /N/ / t/$ T!]6 $/ $/ @6><VN57O[7M?/ → +$/!"# [+GG! E7,(‡bbb22{$rr1N3G72GgI3PUKN3G72GgIIk00 1 PU0 1 <07 Wjk27$MhI<!NK3 3U >1> />> >> F>&> $ /T 2 → $/T 2 !$/T 2 $ → $ T/T ! → !%&$ 222222222 → E7,.KN20NlhW+003PUW5KW003Wjk2KUKUPs3Mh2GMG72GgI2 1 5K2 1 7$MhI,1 20N r|0PUG72GgIIk0.&20NN7!0NKI|000RŒ7IV>i5gI|0N3U >'> />,1> >> F>'&> j6 XD 3 3 2 4 4 3 2 3 2 2R CHO AgNO NH H O R COONH Ag NH NO − + + + → − + + t IV<V j6 =$=T E $T E =$ E j6=T ! ,A2A2+E-6 E7,9lhW2mNNK3Nn0RI0I;KRS3I$VIkIPUNK3N7!I|00R$zPs N3Ko %NIzp2 !3Mh23U &920N>YI|00R5Y3U >0RW5KW0KI> />0RN+0KI> >0R+0KI> F>0R;70KI> jVk/TT$IVk/TT)k,k),A ⇒ k)+-! k ⇒ )+UVk, ⇒ )-tk- ⇒ )UV!"# <V?/$ /TT$<V1<V E7,'!IiSKUKUNn3Mh2$5KI0I;KJ>}WqKU;n<jWŠNIiSPUKG72GgI/0CD CGMDoK50 '&&20N r|0G72GgI<07Wjk2Iz !3Mh22jN'1&20N<KPsG72GgI/0CD ;0$‹7>2kIWE †I|0J3U > 1 , > /> ( > > 1 ( > F> 1 9 > /T Š,! yVC g< 2 /T $T ⇒ $T g< E /T 2 6VC -,,E,E-,+6! $T { /T ⇒ <[<!/ $ >`V /T G B ,G2,!/X/ $ A ! E7&wWECPs$wI~I5VDNnG72GgI2mN03PU7 , IzI„2<!NK3$r xI0KR7}w;{ tƒ Gb2$wWE>5K2IjX7i5ƒ$wWE5Y<jWŠN7$MhIx0K3U > t3 PU > /> t PU > >IvIz t3 > F> t3 PU > XVd*7=<//HT dpdd → =< HT // !/HT %&$ T dpdd → /$ HT GT ! "# [7b?/ >?T ! />+KIMV25ƒE2I0KCIE7bIE7&$rIE7(D E7&5K2IiIWK3N+<07CDWK3CN+S3N+0I5S30D*CDWK3<5+*C1D3K".*C,DWK3C+S3+"+5+W030D*C&D3K"((* C(DWK3CPS30R+0DIiIWK3N+3U<jWŠNI|0Wjk25„22M23U >CDC1DC(D> />C1DC,DC&D> >CDCDC1D> F>CDC1DC&D> /@V2*V1 121N1*7<<,V2++?h*V1g<*7CD6Nr66&6 =$ 2/$ + 2/TT$ → $ T'2=$2/$ + 2/T2( V2 5 Tài liệu luyện thi Đại học năm 2010 - 2011 Giải đề thi ĐH-CĐ năm 2010 $T2/$ 2/$ T$$TT/2/ + $ 2/TT$3$ T'2T2/$ 2/$ TT/2/ + $ 2/T2( *V1 121N1*7<<7< Q<*Y< =$ 2/$ + 2=$ $TT/2/$ 2/TT$ → $ T'2=$2/$ + 2=$/T2/$ 2/T2( V2++ E7&wWEC$wI~I5VDG72GgIJIk0NK37 , PUNK303;…2Gu2$wIzIM‚2$n>ytI tC$ IDKi50x0K<07'(&2ES$wWE3U >,3t> />'3t> >.'3t> F>1,,3t> ‡*%u6R7#0<N<%< 64*2*9650 6,4.( ) 0,1( ) 2*96500 Cu Cu m g n mol = = ⇒ = =<//HT dpdd → =< HT // !/HT %&$ T dpdd → /$ HT GT ! 22223+2222222222222222222222223+3+&:6/5UV%22223 "# "[7b+-b E7&1K,,93t t 1 C$ ID$X70!2<k$~2(20N772z27$MhII}5ˆJC2j<†Wjk2RjS50 KUKUD>=‹5\N !3Mh2I|075K2J3U >1.]> />9.(1]> >,]> F>9&99]> =$ /T !/T=$ dpdd → = /$ T! ← 222222222222222222222 → 64*0,03 % *100 12,37(%). 64*0,03 80(0,2 0,03) Cu = = + − E7&,!IiSKUKU^3tVNn0NJ;…2Nn3Mh2KRPb0$|oK509^3tlhW2mN tI0I;KI tV PUVMsICIiIytI tPUV$%7$KxI„2$%7 wD>NJiIGq2Ps0R5Vxw$nM‚22jWz2 t V>}J3U > )"" 1 > /> 1 " "" 1 > > 1 " " " > F> )" " > t7Vh%u6>`V$=T U[7b= LB?<VJ#S!UVj! 7M>`Vh*h/!/ $ =$ → /T ,$ T,= "[7b,,Ax6 E7&&$5Kz0I}Œ7IVJ7$MhIC 1 D CD 1 >}JIzY0Sr3U >N+S3<KW5KWS3R+K3> />1"N+S3;70""K> >1"N+S3;70""K3> F>"N+S3;70"1"K> Be6$L[7\6UVj/!/78i! E7&(5K2<!IiI27m\23Mh2CD|S$wCD2zC1DN€5‚C,Dz0oI*Œ227m\23Mh2<oI3U >CDC1DC,D> />CDC1DC,D> >CDCDC,D> F>CDCDC1D> =a6&:6$@<7U77g ?7<h%;c6 \7V‹\VN&z6>?7VW>OW[7hUV E7&.KlhWJ2mN0IK3N+S3IPU00RI0I;KRS3ICK$VIkI rrW075K2G#S$m2$•2DiIGq2 rPs02jWz250(.3t t C$ ID>r7$7z2lhWJCIz , $€I3UNR•IiIDƒIiII}5K2lhW Wjk2Pb0$|Ps07oKU&20NlhW+<+C2jrWjk2+<+z0$ow7<7}]D>00R5K2l hWJ3U >PU 1 > /> 1 PU & > > & PU 1 . > F> . PU , ' > = 77 $ +!i<Vh%u6g>`V/$ T$L <V /$T$ !! 3 3 2 R COOH CH OH R COOCH H O − + → − + ! 3 R COOCH M − ,GA ⇒ k/$ 2>?/ $ , 2 "# <V?/$ /TT$>?/ $ , /TT$! E7&9KN20NlhW;nJ2mN;0 N3Ko85Iz<!NK3;…207iIGq2rPs3Mh2GMG72GgI3 3K#2z27$MhIG72GgIPU t >IoG72GgI7$MhI9'920NN7! 0>r7IKN20NlhWJiI Gq2KUKUPs CGMD$yoKlhW1KRƒytI t C$ IDWjk23U >(3t> />(.3t> >1,,3t> F>93t> [VUV>`V$/p6@6WJRV7@<7?7YIV7@<!/5[7Vh%u6T .U/NUHU! 2y8VYI9V[VUV?<7^ 2 65 52 119 3 .( 71) 8,98 0,02 3 MCl m a a + + = + = => = ! 2C?17whN^7h%u6T 2 2.0,02 3.0,02 4.0, 02 0,045( ) 1, 008( ) 4 O n mol lit + + = = <=> {! E7&'iIMsIlhW2mN0IK3+S3IPU0IK3IvoK500 +>!IiSI„2<!NK3Nl0IK3ƒ3Mh2MsI <50b0IK3US;…2&_13‹3Mh2MsI<50b0IK3 0>IK33U > 1 " "CD" 1 > /> 1 " " " "> > 1 " " "> F> 1 "CD" 1 > / $ , T$3$ TL$ T%<nUN<?, ⇒ @$># <?/ $ TUV/i! ih7&`7_U<[1Ln?<J#OU7!/78! E7(JŽIE;…2 , C D € C Dx& >4I7SyGgI<02Nn5o2iIE;…2Nsr7m2$nI|0 , \23Y'3‹ƒm2$nI|0 >\2'3‹> />\213‹> >\2,&3‹> F>2jN13‹> 2 2 2 2 4 2 4 [ ] [ ] .[ ] [ ] C C NO K NO K N O a N O = => = = !t7V'= T (a6-;7^ 2 2 4 [ ] .9.[ ] C NO K N O = <{! 6 Tài liệu luyện thi Đại học năm 2010 - 2011 . liệu luyện thi Đại học năm 2010 - 2011 Giải đề thi ĐH-CĐ năm 2010 >&> />(&> >.> F>&&> $ =/. 4)1'*0),*5)&)&&*6+)&(*7)(,*8)(&*/5)9*:;)9&5)992)9*)'*<)11*/0)