Solution manual fundamentals of physics extended, 8th editionch11

... need to find the center of mass speed v, which we using the projectile motion equations of Chapter With voy = 0, Eq 4-2 2 gives the time -of- flight as t = 2h/g Then Eq 4-2 1 (squared, and using... edge of the roof as our reference level for computing U) Its final kinetic energy (as it leaves the roof) is (Eq 1 1-5 ) K f = 21 Mv + 21 Iω Here we use v to denote the speed of its center of mass... rotational inertia about the center of mass, m = 140 kg, and v = 0.150 m/s is the speed of its center of mass Eq 1 1-2 relates the angular speed to the speed of the center of mass: ω = v/R Thus, K= FG