Solution manual fundamentals of heat and mass transfer 6th edition ch03

... t ss + Nt l + (N - 1)t lcm = × × × 1 0-3 m + × × 1 0-3 m + (5 - 1) × 182 × 1 0-6 m = 20.7 × 1 0-3 m = 20.7 mm < (c) For side area, As = 4HL and heater area, Ah = L2 The heater-to-side area ratio... unlawful Surface temperatures, Tsi or Tso (C) PROBLEM 3.2 (Cont.) 40 30 20 10 -1 0 -2 0 -3 0 -3 0 -2 5 -2 0 -1 5 -1 0 -5 Outside air temperature, Tinfo (C) Tsi; ho = 100 W/m^2.K Tso; ho = 100 W/m^2.K... a decrease of Ts,2 by 11.3°C and -1 increase in the heat loss by a factor of (0.553) = 1.81 Excerpts from this work may be reproduced by instructors for distribution on a not-for-profit basis