Problem 327 5 Spin System AMX3 JAM = 15.3 Hz is typical of a coupling between vinylic protons which are trans to each other see Section 5.7... Problem 328 5 Spin System ADMX3 The criti
Trang 1Solutions Manual
Trang 21,2-butanedione (biacetyl)
C4H6O2
CH2C
N N
2-propanol
C3H8O
Br H
Trang 3+ -
1-phenylethanol
C8H10O
29
CH2 C CH3O
benzyl methyl ketone
Trang 433
O CH3
O O
t-butyl acetoacetate
C8H14O3
34 CH3CH2 O C
O H
ethyl formate
C3H6O2
35
O O
Odiethyl oxalate
C6H10O4
43
CH3 O O
O CH3O
ethylene glycol diacetate
C6H10O4
44
CH3O
OCH3O
O O C
diethyl succinate
C8H14O4
Trang 5OCH31,2,3-trimethoxybenzene
C12H18
Trang 665 CH3 CH3
H CH3
pentamethylcyclopentadiene
3-hydroxybutanone (acetoin)
C4H8O2
O
pentanone
4-hydroxy-4-methyl-2-C6H12O2
71
O CH3O
Trang 718-crown-6
C12H24O6
83
H 2 C C CH2ClCl
4-chlorobutyl acetate
C6H11O2Cl
85
OH O Br
Trang 9H O
C O
H3C
O OH
4-acetoxybenzoic acid
C9H8O4
121
NH2C
CH3O
H C O
O O
Trang 10O O
O O
O O O
diethyl o-phthalate
C12H14O4
136
C O O C
O O
diethyl isophthalate
C12H14O4
C O
O
1,3-dihydroxyphenyl dipropionate
C12H14O4
138
C C
CH3O
O O
cyclopropane carboxylic acid
C4H6O2
C Obenzoylcylopropane
C10H10O
C O OCH2CH3
ethyl cyclobutanecarboxylate
C7H12O2
Trang 11145 C(CH
3 )3O
4-t-butylcyclohexanone
C10H18O
146
H 3 C CH3N
benzyl benzoate
C14H12O2
150
O O
p-cresyl phenylacetate
C15H14O2
1,3-bis(trichloromethyl)- benzene
C8H4Cl6
C O NEt 2
C9H8O4
Br Br
3,5-dibromocumene
C9H10Br2
159
COOH Br
H O
piperonal
C8H6O3
Trang 122-hydroxycyclohex- 1-en-3-one
C13H8O
Trang 13177
O O O
CH3
CH3
CH32,4,6-trimethyl- 1,3,5-trioxane
C6H12O3
178
O O
H4-ethyl-4-methyl-2,6-piperidinedione
2,5-diol
C8H14O2
C C H
H O H
4-amino-3,5-C12H9NO2
189
CH3 CH2Br Br
H
CH3H
H
2-butanol
C4H10O
Trang 14193
S O
dibenzyl sulfoxide
C14H14OS
194
S COOH
O O
4
tetraethylene glycol ditosylate
phenylacetaldeyde ethylene glycol acetal
C10H12O2
204
O CH(CH 3 ) 2
(Z)-β-bromostyrene
C8H7Br
Trang 15209
NO 2
Br
H H
homophthallic acid
C9H8O4
212
O O
CH 3 O
CH 3 O
5,6-dimethoxy-2- coumaranone
C10H10O4
213
C H
Cl
COOH Cl
2,4,5-trichlorophenoxy- acetic acid (2,4,5-T)
Odiethyl isopropylidene- malonate
C10H16O4
218
H
CN O
dimethylbutyraldehyde
4-cyano-2,2-C7H11NO
O H
2-chloroacetaldehyde diethylacetal
Trang 16styrene epoxide
C8H8O
233
C C C
C O
O
CH3
Hcitraconic anhydride
2-furyl t-butyl ketone
C12H13N
Trang 172-methyl- tetrahydrofuran-3-one
Otetramethyl-1,3-cyclobutanedione
cyclopentanone oxime
C5H9NO
251
N OH
cyclohexanone oxime
C6H11NO
252
N H O
ε-caprolactam
C6H11NO
253
HO N(CH3)2OH
CH3
CH3H
pseudoephedrine
C10H15NO
255
N H
O
C(CH3)3H
H C O
CH 3
N-acetylcysteine
C5H9NO3S
Trang 182-methyl-2,4-pentanediol
C6H14O2
266
OH OCH 3
H
CH3O H
N
H
CH 3
O H O
CH 3
H N OCH 2 CH 3
N-acetyltyrosine ethyl ester
Trang 19273 COOH
COOH
2,3-naphthalene- dicarboxylic acid
C12H8O4
NO21-methoxy-4-nitro-
naphthalene
C11H9NO3
CH31,5-dimethylnaphthalene
H
C O
dimethoxy-1-coumarinone
3-hydroxy-3-methyl-5,8-C13H16O4
Trang 20Chapter 9.2 – The Analysis of MixturesProblem 284
Trang 23Proton Chemical Shift ( δ)
5
Trang 24a b c
Trang 251 2 3 4
Trang 28Problem 310
environments
Number of 13C environments
Trang 29Problem 313
Chemical Shifts δA = 150 Hz / 400 MHz = 0.375 ppm
δX = 300 Hz / 400 MHz = 0.750 ppm
Problem 314 Spin System A2X3
Chemical Shifts δA = 3.36 ppm = 3.36 x 60 = 202 Hz from TMS
δX = 1.11 ppm = 1.11 x 60 = 67 Hz from TMS
1st Order Analysis ΔνAX = νA - νX = 202 - 67 = 135 Hz
ΔνAX / JAX = 135 / 7 = 19.3 This ratio is much greater than 3 so a 1st order analysis is justified
Trang 30Problem 315 Spin System AMX
Problem 316 Spin System AMX
Trang 31Problem 317 Spin System AMX
Problem 318 Spin System AMX
Trang 32Problem 319 Spin System AX3
Trang 33Problem 321 4 Spin System AMX2
Trang 34Problem 323 4 Spin System AM2X
Problem 324 4 Spin System A2MX
Trang 35Problem 325 4 Spin System AMX2
Problem 326 5 Spin System A2M2X
Trang 36Problem 327 5 Spin System AMX3
JAM = 15.3 Hz is typical of a coupling between vinylic protons which are
trans to each other (see Section 5.7)
Trang 37Problem 328 5 Spin System ADMX3
The critical coupling constant is JDM = 15.8 Hz which is typical of a coupling
between vinylic protons which are trans to each other (see Section 5.7)
The compound is:
CH3
HC
H
OHA
XM
D
Trang 38Problem 329 5 Spin System AMX3
Chemical Shifts δA = 80 Hz / 60 MHz = 1.33 ppm
δM = 220 Hz / 60 MHz = 3.67 ppm
δX = 320 Hz / 60 MHz = 5.33 ppm
Problem 330 3 Spin System A2X
Of the 6 isomeric anilines, only compounds 4 and 6 have the correct
symmetry to give a spectrum with only two chemical shifts in the aromatic region, in the ratio 2:1
Both 4 and 6 would give A2X spin systems The measured coupling constant is 7.7 Hz which is in the
range for protons which are ortho to
each other Compound 4 is the
correct answer
NH2BrBr
HX
Trang 39Problem 331
The spectrum is obtained after D2O exchange so the carboxylic acid and
phenolic protons will not be present and the spectrum only contains the
aromatic and vinylic protons
The spectrum shows 6 distinct resonances therefore compounds 5 and 6
can be eliminated because they would each have only 4 resonances (on
symmetry grounds)
The proton at about δ 7.1 shows no large coupling (> 7 Hz), this means
that it has no protons ortho to it This eliminates compounds 1 and 2 since
all protons in these compounds will have at least one large ortho coupling
Compounds 3 and 4 differ by the stereochemistry at the double bond The
proton at δ 6.4 is clearly one of the vinylic protons and it is coupled to the
other vinylic proton at δ 7.6 The coupling constant is 16 Hz and this
characteristic of vinylic protons which are trans to each other
The correct answer is compound 3
OH
COOH
Problem 332
All of the protons in the 1H spectrum 1,5-dichoronaphthalene have protons
which are ortho to them This means that every proton must have at least one large (>7 Hz) ortho coupling The spectrum has one proton (at δ 7.1)
which has only a small coupling so this cannot be the spectrum of 1,5-dichloronaphthalene
The spectrum is an AMX spectrum with couplings between A and X of
about 8.3 Hz (typical of an ortho coupling) and coupling between M and X
of about 2.7 Hz (typical of a meta coupling) Two possible structure are
given below
Cl Cl