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Solution manual microeconomics 7e by pindyck ch11a

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To download more slides, ebook, solutions and test bank, visit http://downloadslide.blogspot.com Chapter 11: Appendix CHAPTER 11 APPENDIX TRANSFER PRICING IN THE INTEGRATED FIRM EXERCISES Review the numerical example about Race Car Motors Calculate the profit earned by the upstream division, the downstream division, and the firm as a whole in each of the three cases examined: (a) there is no outside market for engines; (b) there is a competitive market for engines in which the market price is $6,000; and (c) the firm is a monopoly supplier of engines to an outside market In which case does Race Car Motors earn the most profit? In which case does the upstream division earn the most? The downstream division? ► Note: The answers at the end of the book (first printing) inadvertently used p instead of π as the symbol for profit The correct symbols are used below We shall examine each case, then compare profits information about Race Car Motors: We are given the following The demand for its automobiles is P = 20,000 – Q Therefore its marginal revenue is MR = 20,000 – 2Q The downstream division’s cost of assembling cars is CA(Q) = 8000Q, so the division’s marginal cost is MCA = 8000 The upstream division’s cost of producing engines is CE (QE ) = 2QE2 , so the upstream division’s marginal cost is MCE(QE) = 4QE Case (a): To determine the profit-maximizing quantity of output, set the net marginal revenue for engines equal to the marginal cost of producing engines Because each car has one engine, QE equals Q, and the net marginal revenue of engines is NMRE = MR – MCA, or NMRE = (20,000 – 2Q) – 8000 = 12,000 – 2QE Setting NMRE equal to MCE : 12,000 – 2QE = 4QE , or QE = 2000 The firm should produce 2000 engines and 2000 cars The optimal transfer price is the marginal cost of the 2000th engine: PE = MCE = 4QE = (4)(2000) = $8000 The profit-maximizing price of the cars is found by substituting the profit-maximizing quantity into the demand function: P = 20,000 – Q, or P = 20,000 – 2000 = $18,000 209 Copyright © 2009 Pearson Education, Inc Publishing as Prentice Hall To download more slides, ebook, solutions and test bank, visit http://downloadslide.blogspot.com Chapter 11: Appendix The profits for each division are equal to πE = (8000)(2000) – 2(2000) = $8,000,000, and πA = (18,000)(2000) – (8000 + 8000)(2000) = $4,000,000 Total profits are equal to πE + πA = $12,000,000 Case (b): To determine the profit-maximizing level of output when an outside market for engines exists, first note that the competitive price for engines on the outside market is $6000, which is less than the transfer price of $8000 With the market price less than the transfer price, this means that the firm will buy some of its engines on the outside market To determine how many cars the firm should produce, set the market price of engines equal to net marginal revenue We use the market price, since it is now the marginal cost of engines, and the optimal transfer price 6000 = 12,000 – 2QE , or QE = 3000 The total quantity of engines and automobiles is 3000 The price of the cars is determined by substituting QE into the demand function for cars: P = 20,000 – 3000, or P = $17,000 The company now produces more cars and sells them at a lower price To determine the number of engines that the firm will produce and how many the firm will buy on the market, set the marginal cost of engine production equal to 6000, solve for QE, and then find the difference between this number and the 3000 cars to be produced: MCE = 4QE = 6000, or QE = 1500 Thus, the upstream Engine Division will supply 1500 engines and the remaining 1500 engines will be bought on the external market For the engine-building division, profits are found by subtracting total costs from total revenue: πE = TRE – TCE = ($6000)(1500) – 2(1500) = $4,500,000 For the automobile-assembly division, profits are found by subtracting total costs from total revenue: πA = TRA – TCA = ($17,000)(3000) – (8,000 + 6,000)(3000) = $9,000,000 Total profit for the firm is the sum of the two divisions’ profits, πT = $13,500,000 Case (c): In the case where the firm is a monopoly supplier of engines to the outside market, the demand in the outside market for engines is: PE,M = 10,000 – QE , which means that the marginal revenue curve for engines in the outside market is: MRE,M = 10,000 – 2QE To determine the optimal transfer price, find the total net marginal revenue by horizontally summing MRE,M with the net marginal revenue from “sales” to the downstream division, 12,000 – 2QE For output of QE greater than 1000, this is: NMRE,Total = 11,000 – QE 210 Copyright © 2009 Pearson Education, Inc Publishing as Prentice Hall To download more slides, ebook, solutions and test bank, visit http://downloadslide.blogspot.com Chapter 11: Appendix Set NMRE,Total equal to the marginal cost of producing engines to determine the optimal quantity of engines: 11,000 – QE = 4QE, or QE = 2200 Now we must determine how many of the 2200 engines produced will be sold to the downstream division and how many will be sold on the external market First, note that the marginal cost of producing these 2200 engines, and therefore the optimal transfer price, is 4QE = $8800 Set the optimal transfer price equal to the marginal revenue from engine sales in the outside market: 8800 = 10,000 – 2QE, or QE = 600 Therefore, 600 engines should be sold in the external market To determine the price at which these engines should be sold in the external market, substitute 600 into demand in the outside market for engines and solve for P: PE,M = 10,000 – 600 = $9400 Finally, set the $8800 transfer price equal to the net marginal revenue from the “sales” to the downstream division: 8800 = 12,000 – 2QE, or QE = 1600 Thus, 1600 engines should be sold to the downstream division for use in the production of 1600 cars To determine the sale price of the cars, substitute 1600 into the demand curve for automobiles: P = 20,000 – 1600 = $18,400 To determine the level of profits for each division, subtract total costs from total revenue: πE = [($8800)(1600) + ($9400)(600)] – 2(2200) = $10,040,000, and πA = ($18,400)(1600) – (8000 + 8800)(1600) = $2,560,000 Total profits are equal to the sum of the profits from the two divisions, or πT = $12,600,000 The table below gives profits earned by each division and the firm for each case Profits with Upstream Division Downstream Division Total (a) No outside market 8,000,000 4,000,000 12,000,000 (b) Competitive market 4,500,000 9,000,000 13,500,000 (c) Monopolized market 10,000,000 2,600,000 12,600,000 The upstream division, building engines, earns the most profit when it has a monopoly on engines The downstream division, building automobiles, earns the most when there is a competitive market for engines Because of the high cost of engines, the firm does best when engines are produced at the lowest cost by an outside, competitive market 211 Copyright © 2009 Pearson Education, Inc Publishing as Prentice Hall To download more slides, ebook, solutions and test bank, visit http://downloadslide.blogspot.com Chapter 11: Appendix Ajax Computer makes a computer for climate control in office buildings The company uses a microprocessor produced by its upstream division, along with other parts bought in outside competitive markets The microprocessor is produced at a constant marginal cost of $500, and the marginal cost of assembling the computer (including the cost of the other parts) by the downstream division is a constant $700 The firm has been selling the computer for $2000, and until now there has been no outside market for the microprocessor a Suppose an outside market for the microprocessor develops and that Ajax has monopoly power in that market, selling microprocessors for $1000 each Assuming that demand for the microprocessor is unrelated to the demand for the Ajax computer, what transfer price should Ajax apply to the microprocessor for its use by the downstream computer division? Should production of computers be increased, decreased, or left unchanged? Explain briefly Ajax should charge its downstream firm a transfer price equal to the marginal cost of $500 Although its production of processors will be greater than when there was no outside market, this will not affect the production of computers, because the extra production of processors does not increase their marginal cost b How would your answer to (a) change if the demands for the computer and the microprocessors were competitive; i.e., if some of the people who buy the microprocessors use them to make climate control systems of their own? Suppose that the demand for processors comes from a firm that produces a competing computer Extra processors sold imply a reduced demand for Ajax’s computers, which means that fewer computers will be sold by Ajax However, the firm should still charge the efficient transfer price of $500, and it would probably want to raise the price that it charges on microprocessors to the outside firm and lower the price that it charges for its computer Reebok produces and sells running shoes It faces a market demand schedule P = 11 – 1.5QS, where QS is the number of pairs of shoes sold and P is the price in dollars per pair of shoes Production of each pair of shoes requires square yard of leather The leather is shaped and cut by the Form Division of Reebok The cost function for leather is TC L = + Q L + 0.5Q L where QL is the quantity of leather (in square yards) produced Excluding leather, the cost function for running shoes is TCS = 2QS 4Correction: Quantities are pairs of shoes and square yards of leather, not thousands of pairs and thousands of square yards as your book may indicate Also, price is dollars per pair of shoes a What is the optimal transfer price? With demand of P = 11 – 1.5QS, marginal revenue is MR = 11 – 3QS Because TCS = 2QS, the marginal cost of shoe production is $2 per pair The marginal product of leather is 1; i.e., square yard of leather makes pair of shoes Therefore, the net marginal revenue for leather is NMRL = (MRS – MCS )(MPL ) = (11 – 3QS – 2)(1) = – 3QL 212 Copyright © 2009 Pearson Education, Inc Publishing as Prentice Hall To download more slides, ebook, solutions and test bank, visit http://downloadslide.blogspot.com Chapter 11: Appendix For the optimal transfer price, choose the quantity so that NMRL = MCL = PL With the total cost for leather equal to + QL + 0.5QL2 , the marginal cost is + QL Therefore, set MCL = NMRL, which implies + QL = – 3QL, or QL = square yards With this quantity, the optimal transfer price is equal to MCL = + = $3 per square yard b Leather can be bought and sold in a competitive market at the price of PF = 1.5 In this case, how much leather should the Form Division supply internally? How much should it supply to the outside market? Will Reebok buy any leather in the outside market? Find the optimal transfer price The transfer price should be set at the competitive price, $1.50 At this price, the leather producer sets price equal to marginal cost: i.e., 1.5 = + QL , or QL = 0.5 square yard For the optimal transfer quantity, set NMRL = PL , 1.5 = – 3Q, or Q = 2.5 square yards Therefore, the shoe division should buy 2.5 – 0.5 = square yards from the outside market, and the leather division should sell nothing to the outside market c Now suppose the leather is unique and of extremely high quality Therefore, the Form Division may act as a monopoly supplier to the outside market as well as a supplier to the downstream division Suppose the outside demand for leather is given by P = 32 – QL What is the optimal transfer price for the use of leather by the downstream division? At what price, if any, should leather be sold to the outside market? What quantity, if any, will be sold to the outside market? For the outside market, the leather division can determine the optimal amount of leather to produce by setting marginal cost equal to marginal revenue, + QL = 32 – 2QL , or QL = 10.33 square yards At that quantity, MCL = $11.33 per square yard At this marginal cost (and transfer price), the shoe division would optimally demand a negative amount; i.e., the shoe division should stop making shoes, and the firm should confine itself to selling leather At this quantity, the outside market is willing to pay PL = 32 – QL , or PL = $21.67 per square yard The House Products Division of Acme Corporation manufactures and sells digital clock radios A major component is supplied by the electronics division of Acme The cost functions for the radio and the electronic component divisions are, respectively, TCr = 30 + 2Qr TCc = 70 + 6Qc + Qc2 Note that TCr does not include the cost of the component Manufacture of one radio set requires the use of one electronic component Market studies show that the firm’s demand curve for the digital clock radio is given by Pr = 108 – Qr 213 Copyright © 2009 Pearson Education, Inc Publishing as Prentice Hall To download more slides, ebook, solutions and test bank, visit http://downloadslide.blogspot.com Chapter 11: Appendix a If there is no outside market for the components, how many of them should be produced to maximize profits for Acme as a whole? What is the optimal transfer price? Radios require exactly one component and assembly radio assembly cost: TC r = 30 + 2Qr component cost: TC C = 70 + 6Q C + Q C radio demand: Pr = 108 − Qr First we must solve for the profit-maximizing number of radios to produce We must then set the transfer price Pt that induces the internal supplier of components to provide the profit-maximizing level of components Profits are given by: π = (108 − Qr )Qr − (30 + 2Qr ) − (70 + 6Qc + Qc2 ) Since one and only one component is used in each radio, we can set Qc = Qr: π = (108 − Qc )Qc − (30 + 2Qc ) − (70 + 6Qc + Qc2 ) Profit maximization implies: dπ/dQc = 108 – 2Qc – – – 2Qc = or Qc = 25 We must now calculate the transfer price that will induce the internal supplier to supply exactly 25 components This will be the price for which MCc(Qc = 25) = Pt or Pt = MCc(Qc = 25) = + 2Qc = $56 We can check our solution as follows: Component division: Max πc = 56Qc – (70 + 6Qc + Qc ) dπc/dQc = ⇔ 56 – – 2Qc = ⇔ Qc = 25 Radio assembly division: Max πr = (108 – Qr)Qr – (30 + 2Qr) – 56Qr dπr/dQr = ⇔ 108 – 2Qr – – 56 = ⇔ Qr = 25 b If other firms are willing to purchase in the outside market the component manufactured by the electronics division (which is the only supplier of this product), what is the optimal transfer price? Why? What price should be charged in the outside market? Why? How many units will the electronics division supply internally and to the outside market? Why? (Note: The demand for components in the outside market is Pc = 72 – 1.5Qc.) We now assume there is an outside market for components; the firm has market power in this outside market where market demand is: Pc = 72 – 3(Qc/2) First we solve for the profit-maximizing level of outside and internal sales Then, we set the transfer price that induces the component division to supply the total output (sum of internal and external supply) We define Qc as the outside sales of components and Qi = Qr as components used inside the firm to produce digital clock radios Total profits for the company are given by: π = (108–Qi)Qi + (72–(3/2)Qc)Qc – (30+2Qi) – (70+6(Qi+Qc)+(Qi+Qc) ) 214 Copyright © 2009 Pearson Education, Inc Publishing as Prentice Hall To download more slides, ebook, solutions and test bank, visit http://downloadslide.blogspot.com Chapter 11: Appendix Profit maximization implies: ∂π/∂Qi = 108 – Qi – – – (Qi + Qc) = ∂π/∂Qc = 72 – 3Qc – – 2(Qi + Qc) = which yields: Qi + Qc/2 = 25 5Qc + 2Qi = 66 and Qc = Qi = 23 Thus, total components will be 23 + 4, or 27 As in part (a), we solve for the transfer price by finding the marginal cost of the component division of producing the profit-maximizing level of output: * * Pt = MCc = + 2(Qi + Qc ) = + 2(27) = $60 The outside price for the component will be: Pc = 72 –(3/2)Qc = $66, which is greater than the internal transfer price, as it should be The outside price is greater than the transfer price (Pt < Pc) because the firm has market power in the external market, and therefore, Pt = MCc = MRc < Pc 215 Copyright © 2009 Pearson Education, Inc Publishing as Prentice Hall ... profits are found by subtracting total costs from total revenue: πE = TRE – TCE = ($6000)(1500) – 2(1500) = $4,500,000 For the automobile-assembly division, profits are found by subtracting total... produced at the lowest cost by an outside, competitive market 211 Copyright © 2009 Pearson Education, Inc Publishing as Prentice Hall To download more slides, ebook, solutions and test bank, visit... downstream division Suppose the outside demand for leather is given by P = 32 – QL What is the optimal transfer price for the use of leather by the downstream division? At what price, if any, should leather

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