Lecture no08 gradient series

Interest Formulas (Gradient Series) Lecture No Chapter Contemporary Engineering Economics Copyright © 2016 Contemporary Engineering Economics, th edition Park Copyright © 2016 by Pearson Education, Inc All Rights Reserved Linear Gradient Series A Strict Gradient Series Contemporary Engineering Economics, th edition Park Gradient Series as a Composite Series of a Uniform Series of N Payments of A1 and the Gradient Series of Increments of Constant Amount G Copyright © 2016 by Pearson Education, Inc All Rights Reserved Example 3.18: Linear Gradient: Find P, Given A1, G, N, and i  Given: A1 = $1,000, G = $250, N = years, and i = 12% per year  Find: P Contemporary Engineering Economics, th edition Park Copyright © 2016 by Pearson Education, Inc All Rights Reserved Solution Excel Solution Contemporary Engineering Economics, th edition Park Copyright © 2016 by Pearson Education, Inc All Rights Reserved Gradient-to-Equal-Payment Series Conversion Factor, (A/G, i, N)  Given: G = $1,000, N = 10 years, i = 12%  Find: A Solution • Cash Flow Series • Factor Notation Contemporary Engineering Economics, th edition Park Copyright © 2016 by Pearson Education, Inc All Rights Reserved Example 3.19: Linear Gradient: Find A, Given A1, G, i, and N  Given: A1 = $1,000, G = $300, N = years, and i = 10% per year  Find: A Contemporary Engineering Economics, th edition Park Copyright © 2016 by Pearson Education, Inc All Rights Reserved Solution Contemporary Engineering Economics, th edition Park Copyright © 2016 by Pearson Education, Inc All Rights Reserved Example 3.20: Declining Linear Gradient Series: Find F, Given A1, G, I, and N  Given: A1 = $1,200, G = -$200, N = years, and i = 10% per year  Find: F Contemporary Engineering Economics, th edition Park Copyright © 2016 by Pearson Education, Inc All Rights Reserved Solution  Strategy: Since we have no interest formula to compute the future worth of a linear gradient series directly, we first find the equivalent present worth of the gradient series and then convert this P to its equivalent F  Solution Contemporary Engineering Economics, th edition Park Copyright © 2016 by Pearson Education, Inc All Rights Reserved Present Worth of Geometric Gradient Series  Formula  Factor Notation Contemporary Engineering Economics, th edition Park Copyright © 2016 by Pearson Education, Inc All Rights Reserved Example 3.21: Geometric Gradient Series  Given: A1 = $54,600, g = 7%, N = years, and i = 12% per year  Find: P Contemporary Engineering Economics, th edition Park Copyright © 2016 by Pearson Education, Inc All Rights Reserved Solution Contemporary Engineering Economics, th edition Park Copyright © 2016 by Pearson Education, Inc All Rights Reserved Example 3.22: Retirement Plan: Saving $1 Million  Given: o F = $1,000,000, o g = 6%, o i = 8%, and o N = 20  Find: A1 Contemporary Engineering Economics, th edition Park Copyright © 2016 by Pearson Education, Inc All Rights Reserved Solution Contemporary Engineering Economics, th edition Park Copyright © 2016 by Pearson Education, Inc All Rights Reserved ...Linear Gradient Series A Strict Gradient Series Contemporary Engineering Economics, th edition Park Gradient Series as a Composite Series of a Uniform Series of N Payments of A1 and the Gradient Series. .. interest formula to compute the future worth of a linear gradient series directly, we first find the equivalent present worth of the gradient series and then convert this P to its equivalent F ... Education, Inc All Rights Reserved Gradient- to-Equal-Payment Series Conversion Factor, (A/G, i, N)  Given: G = $1,000, N = 10 years, i = 12%  Find: A Solution • Cash Flow Series • Factor Notation Contemporary