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DSpace at VNU: Deterministic Joint Remote Preparation of an Arbitrary Qubit via Einstein-Podolsky-Rosen Pairs tài liệu,...

Int J Theor Phys (2012) 51:2272–2281 DOI 10.1007/s10773-012-1107-9 Deterministic Joint Remote Preparation of an Arbitrary Qubit via Einstein-Podolsky-Rosen Pairs Cao Thi Bich · Nung Van Don · Nguyen Ba An Received: 11 October 2011 / Accepted: 14 February 2012 / Published online: March 2012 © Springer Science+Business Media, LLC 2012 Abstract Joint remote state preparation is a secure and faithful method based on local operation and classical communication to transmit quantum states without the risk of full information leaking to either of the participants In this work, we propose a new deterministic protocol for two parties to remotely prepare an arbitrary single-qubit state for a third party using two Einstein-Podolsky-Rosen pairs as the nonlocal resource We figure out the advantages as well as the disadvantages of this new protocol in comparison with others, showing in general that the proposed protocol is superior to the existing ones We also describe the situation when there are more than two preparers Keywords Joint remote state preparation · EPR pairs · Feed-forward measurements · Unit success probability Introduction About three decades ago questions such as “Why one cannot precisely measure two conjugate variables at the same time?”or “Why an arbitrary quantum state cannot be cloned?” or “Why there is spooky action at distance?”, etc., were regarded as idle The loath answer at that time was likely “God only knows” Nowadays, perhaps because of “God is subtle but malicious he is not”, people have become aware that such weird features, which are laws of Nature, constitute the very necessary ingredients to guarantee absolute cryptography [1], to exponentially speed up computation [2] or to perform a global task only by means of local operation and classical communication (LOCC), etc C.T Bich ( ) · N.V Don · N.B An Center for Theoretical Physics, Institute of Physics, 10 Dao Tan, Hanoi, Vietnam e-mail: ctbich@iop.vast.ac.vn C.T Bich Physics Department, Hanoi University of Education No 1, 136 Xuan Thuy, Hanoi, Vietnam N.V Don Physics Department, Hanoi University of Science, 334 Nguyen Trai, Hanoi, Vietnam Int J Theor Phys (2012) 51:2272–2281 2273 In quantum cryptography [1] information is encoded in classical keys which are however distributed in a quantum way under the enemy’s very nose√by sending qubits prepared ran√ domly in one of the four states {|0 , |1 , |+ = (|0 + |1 )/ 2, |− = (|0 − |1 )/ 2}, with {|0 , |1 } the two orthonormal states of a qubit in the computational basis Information can also be encoded quantumly in the state of a qubit of the form | = a|0 + beiϕ |1 , (1) with any parameters a, b, ϕ ∈ R satisfying the normalization condition a + b = Nevertheless, transmitting quantum information by physically sending such informative qubits is dangerous since any unauthorized parties can alter the qubits before they reach the intended party without detection of the latter Therefore, secure and faithful transmission of quantum information without sending the qubits themselves proves to be a great idea This implicitly means that the transmission should be performed by LOCC, which appears realizable if some nonlocal resource is provided between the sending and the receiving parties The first intriguing protocol of such kind of global tasks, called quantum teleportation (QT), was proposed in 1993 by Bennett et al [3] using the quantum entanglement [4] as the nonlocal resource In principle, by QT any unknown quantum states can be transmitted (see, e.g., [5–10] and references therein), if the transmitter owns the states Yet, transmission of known states can be done by a simpler method with the same nonlocal resource as in QT but without the need of having the states at hand This method was referred to as remote state preparation (RSP) [11–14] As a per se feature of RSP, the preparer knows the full information encoded in the to-be-prepared quantum state, that may appear unwanted in some circumstances To avoid this feature, joint remote state preparation (JRSP) protocols [15–30] have recently been designed, in which there are N ≥ preparers [19], who jointly perform the task but no one among them is able to identify the full content of the encoded information Experimental architecture of JRSP has also been dealt with in Ref [31] In this work we concentrate on JRSP of an arbitrary qubit state of the most general form as in (1) In fact, such a problem was studied previously [15–18] The nonlocal resource employed in Refs [15, 16] was a single Greenberger-Horne-Zeilinger (GHZ) trio [32], while it was two Einstein-Podolsky-Rosen (EPR) pairs [34] in Ref [16] and one W state [33] in Ref [17] However, all those cited protocols were probabilistic, i.e., they succeed just with −1 a probability Psuc < As the overhead expenses in resources scales with Psuc , on average, if several protocols use the same amount/kind of resource, then the better is the one that has a greater success probability and, of course, the best one it that having Psuc = Although GHZ trios and W states are also useful (see e.g Refs [15, 17]), we aim at employing EPR pairs as the nonlocal resource because these are the most elementary kind of entanglement and their production/distribution is easier than those of GHZ trios and W states For joint remote preparation of state | in (1) two EPR pairs are necessary [16, 18] In Ref [16] Psuc < 1, while in Ref [18] Psuc = Here we shall propose a different protocol which also uses two EPR pairs as the nonlocal resource and has Psuc = but offers pronounced advantages From an application point of view, our work would reveal diversity and flexibility in the ways a quantum task can be done given the same physical resource In the next section we present in detail our protocol for the case of N = preparers Then, in the conclusion section, we compare it with other existing protocols to expose its merit We also provide an Appendix to deal with the generalization to any N > preparers 2 Our Protocol Consider the simplest case of N = The two preparers are Alice and Bob, while the receiver’s name is Charlie The full information contained in state | , (1), is S = {a, b, ϕ}, 2274 Int J Theor Phys (2012) 51:2272–2281 which can be somehow divided into S1 and S2 in such a way that S cannot be inferred from either S1 or S2 , but can from both Let S1 be given only to Alice, S2 only to Bob, but no information to Charlie The two EPR pairs |EPR AC |EPR BC used in Refs [16, 18] have the qubits’ distribution shown in Fig 1, i.e., qubit A belongs to Alice, qubit B to Bob and qubits C, C to Charlie Here, we adopt the notation |EPR XY = √ |00 + |11 XY (2) The protocol in Ref [16] is a two-step one The first step is called the preparation step and the second the reconstruction one In the preparation step Alice (and independently Bob) measures her (his) own qubit in a basis determined solely by S1 (S2 ), then publicly broadcasts their outcome In the reconstruction step Charlie first performs a controlled-NOT gate1 on her two qubits, followed by measuring one of them in the computational basis In a lucky case when Charlie’s measurement outcome “matches” those of Alice and Bob, she will apply a proper operator on her unmeasured qubit to reconstruct it into the desired state Although there are many ways to divide S into S1 and S2 [15–17], neither one can make the protocol in Ref [16] deterministic Its maximum success probability is just Psuc = 1/2 The protocol in Ref [18] uses the same nonlocal resource with the same qubits’ distribution as in Fig (i.e., as in Ref [16]), but it is deterministic To achieve Psuc = it was designed to be a three-step (not two-step) one: there are two preparation steps and one reconstruction step In the first preparation step Bob does nothing, Alice does the same thing as in Ref [16] and, at the same time, Charlie performs a controlled-NOT gate on her two qubits, followed by measuring one of them in the computational basis, but postpones application of any operators on the unmeasured qubit Then, both Alice and Charlie openly announce their measurement outcomes In the second preparation step Bob starts his action by measuring his qubit in a basis that is judiciously determined by him, making use not only of S2 but also of the concrete outcomes announced by Alice and Charlie in the first step After the measurement, Bob publishes his outcome via a classical communication channel as well What remains in the last step (i.e., the reconstruction step) is Charlie’s application on the untouched qubit of the right operator conditioned on the outcomes of both Alice and Bob Note that the division of S into S1 and S2 in Ref [18] should be S1 = {a, b} (3) S2 = ϕ (4) and After a condensed summary of the protocols in Refs [16, 18], our purpose here is to propose a new deterministic protocol that also uses two EPR pairs but relaxes the function of Charlie The state of nonlocal resource employed in the new protocol is |Q ABA C = |EPR AB |EPR A C with the qubits’ distribution shown in Fig which is remarkably different from that in Refs [16, 18] Now, Alice holds two qubits A and A , while Bob and Charlie each holds just a qubit (B and C) We also adopt the division S ⇒ {S1 , S2 } as in (3), (4) and the new protocol is a three-step one as well However, it proceeds differently as follows Controlled-NOT gate denoted by CN OT XY is a quantum gate acting on two qubits X (control qubit) and Y (target qubit) as CN OTXY |i X |j Y = |i X |i ⊕ j Y , where i, j ∈ {0, 1} and ⊕ stands for an addition mod Int J Theor Phys (2012) 51:2272–2281 2275 Fig The qubits’ distribution for JRSP of the most general single-qubit state via two EPR pairs following the protocols proposed in Refs [16, 18] Qubits are represented by dots and entangled qubits are connected by solid lines Fig The qubits’ distribution for JRSP of the most general single-qubit state via two EPR pairs following the protocol proposed in this work Qubits are represented by dots and entangled qubits are connected by a solid line In the first preparation step only Alice plays a role She measures qubits A and A in the basis determined solely by S1 = {a, b} as ⎛ |u00 ⎜ |u01 ⎜ ⎝ |u10 |u11 ⎞ AA AA AA AA ⎛ |00 ⎟ ⎜ ⎟ = U (a, b) ⎜ |01 ⎠ ⎝ |10 |11 ⎞ AA AA AA AA ⎟ ⎟, ⎠ (5) 2276 Int J Theor Phys (2012) 51:2272–2281 with ⎛ a ⎜b ⎜ U (a, b) = ⎝ 0 0 a −b ⎞ b −a ⎟ ⎟, ⎠ 0 b a (6) and publicly publishes kl (k, l ∈ {0, 1}), if the outcome |ukl AA is found Since the transformation U (a, b) is unitary, the states {|ukl AA } constitute an orthonormal complete set in a 4D Hilbert space Inversing (5) yields |00 AA = a|u00 AA + b|u01 AA , (7) |01 AA = a|u10 AA − b|u11 AA , (8) |10 AA = b|u10 AA + a|u11 AA |11 AA = b|u00 AA − a|u01 AA (9) and (10) As is well known, thanks to the effect of entanglement swapping, after Alice completed her measurement the two qubits B and C are projected onto an entangled state, despite they are far apart and still untouched This is verified mathematically by substituting (7)–(10) into the expression of the two EPR pairs in use |Q ABA C = |EPR AB |EPR A C , which can then be rewritten in the form |Q ABA C = 1 |ukl AA |Lkl BC (11) l=0 k=0 where |L00 BC = a|00 BC + b|11 BC , (12) |L01 BC = b|00 BC − a|11 BC , (13) |L10 BC = a|01 BC + b|10 BC (14) and |L11 BC = −b|01 BC + a|10 BC (15) In the second preparation step only Bob plays a role He measures the qubit B but the choice of measurement basis is delicate To achieve Psuc = 1, Bob must make use not only of S2 = ϕ, which he is supposed to know, but also of the Alice’s outcome kl, which he hears from the public media It turns out, however, that only ϕ and l suffice Explicitly, if l = 0, Bob chooses the measurement basis as 1 e−iϕ |0 B |v0 B =√ , (16) iϕ |v1 B e −1 |1 B whereas if l = 1, he chooses the measurement basis as |v0 |v1 1 eiϕ |0 B =√ (17) −iϕ e −1 |1 B B Combining (16) and (17), Bob’s measurement bases are determined by ϕ and l in the following fashion: B |v0(l) |v1(l) B B = V (l) (ϕ) |0 |1 B B , (18) Int J Theor Phys (2012) 51:2272–2281 2277 Table The collapsed state | klm C of Charlie’s qubit C and her reconstruction operator Rklm , depending on the outcomes kl and m of Alice and Bob, respectively I is the identity operator, X = {{0, 1}, {1, 0}} the bit-flip operator and Z = {{1, 0}, {0, −1}} the phase-flip one # klm | klm C Rklm 1, 000 or 111 I 3, 011 or 100 a|0 C + beiϕ |1 C a|1 C + beiϕ |0 C 5, 010 or 101 ZX 7, 001 or 110 a|1 C − beiϕ |0 C a|0 C − beiϕ |1 C X Z where V (l) (ϕ) = √ e−(−1) iϕ −1 l e (−1)l iϕ (19) Obviously, for a given l, the states {|vm(l) B ; m = 0, 1} constitute an orthonormal complete set in a 2D Hilbert space because V (l) (ϕ) is a unitary transformation In terms of {|v0(l) B , |v1(l) B }, we have |0 B = √ |v0(l) |1 B l = √ e(−1) iϕ |v0(l) + e−(−1) iϕ |v1(l) l B (20) B and B − |v1(l) B (21) In measuring the quit B, if Bob finds it in state |vm(l) B , he reveals m ∈ {0, 1} publicly Using (20) and (21) in (12)–(15) we see that, conditioned on the outcomes klm, Charlie’s qubit C would collapse, up to a global phase factor, into a certain state labeled | klm C , all of which are collected in Table In the last step only Charlie plays a role She makes use of the outcomes klm announced by Alice and Bob to decide the right operator Rklm to be applied on her qubit C to cast it to the target state | C The concrete operators Rklm are also listed in Table It is interesting that we can express the dependence of Rklm on klm by a single compact formula as Rklm = Z l⊕m X k⊕l , (22) where ⊕ denotes an addition mod The probability for Alice finding state |ukl AA and Bob finding state |vm(l) B is Pklm = 1/8, independent of concrete values of k, l and m Since there exists a reconstruction operator for each of the eight possible outcomes, our protocol succeeds with the total probability 1 Psuc = Pklm = × m=0 l=0 k=0 = 1, (23) i.e., it is deterministic Conclusion We have reconsidered the problem of joint remote preparation of an arbitrary qubit Although this problem was dealt with previously, the present investigation exhibits enlightening aspects The nonlocal resource in terms of a GHZ trio and a W state was employed 2278 Int J Theor Phys (2012) 51:2272–2281 for the task in Ref [15] and Ref [17], respectively In this work we instead concentrate on two EPR pairs as the nonlocal resource, which were already employed in Refs [16, 18] The nice feature of the protocol in Ref [16] is that the receiver participates only in the last step and his function is just to reconstruct the target state without the need of classical communication It however suffers a bad feature of being probabilistic (i.e., Psuc < 1) As for the protocol in Ref [18], the nice feature is that it is deterministic (i.e., Psuc = 1) On the other hand, its bad feature is that the receiver’s function is more involved: she participates not only in the last step but also in the first preparation step in which she is required to perform a controlled-NOT gate and to carry out a measurement as well as to communicate his measurement outcome As described in detail in the preceding section, the present protocol, though being executed also via two EPR pairs, incorporates the nice features of both the protocols in Refs [16, 18] That is, in the new protocol both Psuc = and simple function of the receiver are achieved The only price to pay is the first preparer’s ability to carry out a two-qubit measurement instead of just a single-qubit one as in Refs [16, 18] This price is regarded cheaper than that spent by the receiver in Ref [18] Moreover, an additional advantage of the present protocols over those in Refs [16, 18] rests in the symmetry between Bob and Charlie (compare Figs and 2) Hence, this new protocol allows, in case of need, to exchange the role of Bob and Charlie, while the other protocols not Concerning classical communication cost, it is two bits in the probabilistic protocol [16] As for those in Ref [18] and here, an extra bit arises, but this is worth to make them deterministic To conclude, we emphasize that to achieve unit success probability, Psuc = 1, the protocol should consist of three steps (two preparation steps and a reconstruction step) and, more importantly, feed-forward measurements should be done in the two first steps Namely, the basis for the measurement in the second step should be decided by the measurement outcome in the first step Last but not least we would like to mention two meaningful issues The first one concerns the question “What if the quantum channel initially consists of partially entangled qubit-pairs?” and the second one asks “How about the situation of more than two preparers?” Of course partially entangled quantum channels can also the job (usually with auxiliary qubits and measurements on them), but only in a probabilistic manner Maximum entanglement is therefore a prerequisite for determinism of JRSP protocols If it were not so, a priori local filtering [35] or distillation process [36] is required to supply the participants with (maximally entangled) EPR pairs As for the situation of any N > preparers, the procedure is somewhat nontrivial, very different from Ref [19] and, thus, deserves a separate description in the Appendix Acknowledgements We thank the two anonymous referees for their suggestions that improved the manuscript This work is supported by the Vietnam Foundation for Science and Technology Development (NAFOSTED) through a project no 103.99-2011.26 Appendix In this Appendix we generalize the situation with two preparers (Alice and Bob) described in the main text to that with an arbitrary N > preparers (Alice, Bob 1, Bob 2, and Bob N − 1) The pre-shared quantum channel consists of N EPR pairs distributed among the N + participants (N preparers plus a receiver) as shown in Fig For clarity, let us first consider N = in detail The three EPR pairs of the quantum channel are |EPR A1 B1 |EPR A2 B2 |EPR A3 C = |Q A1 B1 A2 B2 A3 C , with qubits A1 , A2 , A3 hold by Alice, B1 by Bob 1, B2 by Bob and C by the receiver Charlie While Alice is allowed Int J Theor Phys (2012) 51:2272–2281 2279 Fig The qubits’ distribution for JRSP of the most general single-qubit state via N EPR pairs for the situation of N preparers (Alice, Bob 1, Bob 2, and Bob N − 1) Qubits are represented by dots and entangled qubits are connected by a solid line to know {a, b} as in the case of N = 2, Bob and Bob now share the knowledge of ϕ in the following way: Bob knows ϕ1 and Bob knows ϕ2 where ϕ1 and ϕ2 sum up to ϕ First, Alice measures her three qubits in the basis {|uklm A1 A2 A3 ; k, l, m ∈ {0, 1}}: ⎛ ⎞ ⎛ ⎞ ⎞⎛ |u000 A1 A2 A3 a 0 0 0 b |000 A1 A2 A3 ⎜ |u001 A A A ⎟ ⎜ b 0 0 ⎟ ⎜ −a ⎟ ⎟ ⎜ ⎜ ⎟ ⎜ |001 A1 A2 A3 ⎟ ⎜ |u010 A A A ⎟ ⎜ a 0 0 ⎟ ⎜ |010 A A A ⎟ b ⎟ ⎟ ⎜ ⎜ ⎟⎜ ⎜ |u011 A A A ⎟ ⎜ b 0 0 −a ⎟ ⎜ |011 A A A ⎟ ⎟ ⎟ ⎜ ⎜ ⎟ ⎜ ⎜ |u100 A A A ⎟ = ⎜ 0 a 0 b ⎟ (24) ⎜ 0 ⎟ ⎟ ⎜ ⎜ ⎟ ⎜ |100 A1 A2 A3 ⎟ ⎜ |u101 A A A ⎟ ⎜ 0 b 0 −a ⎟ ⎜ ⎟ ⎜ |101 A1 A2 A3 ⎟ ⎟ ⎜ ⎟ ⎜ ⎝ |u110 A A A ⎠ ⎝ 0 a b 0 ⎠ ⎝ |110 A1 A2 A3 ⎠ |u111 A1 A2 A3 |111 A1 A2 A3 0 −b a 0 and publicly broadcasts klm, if she finds state |uklm A1 A2 A3 , projecting qubits B1 , B2 and C onto an entangled state |Lklm B1 B2 C Expressing the quantum channel |Q A1 B1 A2 B2 A3 C through {|uklm A1 A2 A3 }, |Q we derive |Lklm A1 B1 A2 B2 A3 C B1 B2 C 1 = √ 2 m=0 l=0 |uklm A1 A2 A3 |Lklm B1 B2 C , (25) k=0 in the form |L000 B1 B2 C = a|000 |L001 B1 B2 C = −a|111 |L010 B1 B2 C = a|001 |L011 B1 B2 C = −a|110 |L100 B1 B2 C = a|010 |L101 B1 B2 C = −a|101 |L110 B1 B2 C = a|011 B1 B2 C + b|111 B1 B2 C B1 B2 C B1 B2 C B1 B2 C , B1 B2 C , + b|010 + b|100 B1 B2 C , B1 B2 C , + b|001 + b|101 B1 B2 C B1 B2 C + b|000 + b|110 B1 B2 C B1 B2 C , B1 B2 C , B1 B2 C (26) (27) (28) (29) (30) (31) (32) 2280 Int J Theor Phys (2012) 51:2272–2281 and |L111 B1 B2 C = a|100 B1 B2 C − b|011 (33) B1 B2 C Next, Bob and Bob independently measure their qubits in a basis conditioned not only on ϕ1 and ϕ2 but also on Alice’s outcome Concretely, when klm = 000 or 010, each Bob j (j = 1, 2) uses a measurement basis determined by |v0 |v1 Bj Bj = V (0) (ϕj ) |0 |1 Bj (34) , Bj with V (0) (ϕj ) given in (19) However, for klm = 001 or 011, the basis for each Bob j is |v0 |v1 Bj Bj = V (1) (ϕj ) |0 |1 Bj (35) , Bj with V (1) (ϕj ) given in (19) In case klm = 100 or 110, Bob uses the basis |v0 |v1 B1 |v0 |v1 B2 B1 = V (0) (ϕ1 ) |0 |1 B1 = V (1) (ϕ2 ) |0 |1 B2 , (36) (37) B1 but the basis for Bob is B2 B2 Finally, if klm = 101 or 111, the bases for Bob and Bob are differently defined as |v0 |v1 = V (1) (ϕ1 ) |0 |1 = V (0) (ϕ2 ) |0 |1 B1 B1 B1 (38) B1 and |v0 |v1 B2 B2 B2 (39) , B2 respectively Then the states |Lklm B1 B2 C in (25) can be, up to an unimportant global phase factor, decomposed in terms of {|vn B1 , |vs B2 } as follows |Lklm B1 B2 C = 1 |vn + B1 |vs B2 Rklmns | C, (40) s=0 n=0 with Rklmns either the identity operator or a Pauli one This implies that after Alice, Bob and Bob announce their measurement outcomes, Charlie will be able to convert the qubit C to be in the desired state | C by applying Rklmns on C The reconstruction operators Rklmns that Charlie needs in the last step are shown in Table Because each of the 25 = 32 possible outcomes klmns is associated with a reconstruction operator Rklmns , the total success probability is obviously As inferred from the cases of N = and N = 3, for any N > the quantum channel should consist of N EPR pairs, |Q A1 B1 A2 B2 AN−1 BN−1 AN C = |EPR A1 B1 |EPR A2 B2 |EPR AN−1 BN−1 |EPR AN C (see Fig 3) The information is split in such a way that Alice still knows {a, b}, but Bob j (j = 1, 2, , N − 1) just knows ϕj in such a way that the constraint N−1 j =1 ϕj = ϕ is satisfied The basis for Alice to measure N qubits A1 , A2 , , AN is spanned by 2N orthonormal states {(−1)i1 a|i1 i2 iN A1 A2 AN + b|i1 i2 iN A1 A2 AN ; in ∈ {0, 1}; in = − in } As for Bob j , each of them independently measures qubit Bj in the basis V (0) (ϕj ).{|0 Bj , |1 Bj } or V (1) (ϕj ).{|0 Bj , |1 Bj }, depending on Alice’s outcome Such generalized JRSP protocol works deterministically since for each of the 22N−1 possible measurement outcomes of the N preparers there exists a corresponding reconstruction operator for the receiver to obtain the target state | C Int J Theor Phys (2012) 51:2272–2281 2281 Table The reconstruction operator Rklmns , conditioned on the measurement outcomes klm, n and s of Alice, Bob and Bob 2, respectively I is the identity operator, X = {{0, 1}, {1, 0}} the bit-flip operator and Z = {{1, 0}, {0, −1}} the phase-flip one # klmns Rklmns 1–8 00000, 00011, 10000, 10011, 01101, 01110, 11101 or 11110 I 9–16 01000, 01011, 11000, 11011, 00101, 00110, 10101 or 10110 X 17–24 00100, 00111, 10100, 10111, 01001, 01010, 11001 or 11010 ZX 25–32 01100, 01111, 11100, 11111, 00001, 00010, 10001 or 10010 Z References Bennett, C.H., Brassard, G.: In: Proceedings of IEEE International Conference on Computers, Systems and Signal 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