BI TP AMINOAXIT TC DNG VI AXIT KIM (LTH 2016) Hng dn: DS Trn Vn Hin i Hc Y Dc Hu - D: 01642689747 LU HNH NI B Cõu 1: Hn hp X gm mol aminoaxit no, mch h v mol amin no, mch h X cú kh nng phn ng ti a vi mol HCl hoc va vi mol NaOH t chỏy hon ton X thu c mol CO2, x mol H2O v y mol N2 Cỏc giỏ tr x, y tng ng l A v 1,0 B v 1,5 C v 1,0 D v 1,5 Cõu 2: a) Hn hp X gm alanin v axit glutamic Cho m gam X tỏc dng hon ton vi dung dch NaOH (d), thu c dung dch Y cha (m + 30,8) gam mui Mt khỏc, nu cho m gam X tỏc dng hon ton vi dung dch HCl, thu c dung dch Z cha (m + 36,5) gam mui Giỏ tr ca m l A 112,2 B 165,6 C 123,8 D 171,0 b) Hn hp X gm glyxin v Lysin Cho m gam X tỏc dng hon ton vi dung dch NaOH (d), thu c dung dch Y cha (m + 22) gam mui Mt khỏc, nu cho m gam X tỏc dng hon ton vi dung dch HCl, thu c dung dch Z cha (m + 51,1) gam mui Giỏ tr ca m l : A 112,2 g B 103,4 g C 123,8 g D 171,0 g Cõu 3: Cho 0,02 mol amino axit X tỏc dng va vi 200 ml dung dch HCl 0,1M thu c 3,67 gam mui khan Mt khỏc 0,02 mol X tỏc dng va vi 40 gam dung dch NaOH 4% Cụng thc ca X l B H2NC3H5(COOH)2 C (H2N)2C3H5COOH D H2NC3H6COOH A H2NC2H3(COOH)2 Cõu 4: Cho mol amino axit X phn ng vi dung dch HCl (d), thu c m1 gam mui Y Cng mol amino axit X phn ng vi dung dch NaOH (d), thu c m2 gam mui Z Bit m2- m1 = 7,5 Cụng thc phõn t ca X l : A C4H10O2N2 B C5 H9O4N C C4H8O4N2 D C5H11O2N Cõu 5: Trong phõn t aminoaxit X cú mt nhúm amino v mt nhúm cacboxyl Cho 15,0 gam X tỏc dng va vi dung dch NaOH, cụ cn dung dch sau phn ng thu c 19,4 gam mui khan Cụng thc ca X l: B H2NC3 H6COOH C H2NC2H4COOH D H2NCH2COOH A H2NC4 H8COOH Cõu 6: - aminoaxit X cha mt nhúm -NH2 Cho 10,3 gam X tỏc dng vi axit HCl (d), thu c 13,95 gam mui khan Cụng thc cu to thu gn ca X l: A H2NCH2COOH B H2NCH2CH2COOH C CH3CH2CH(NH2)COOH D CH3CH(NH2)COOH Cõu 7: -amino axit X cha mt nhúm NH2 Cho 10,3 g X tỏc dng vi axit HCl (d), thu c 13,95 g mui khan CTCT thu gn ca X l A CH3CH2CH(NH2)COOH B H2NCH2CH2COOH C CH3CH(NH2)COOH D H2NCH2COOH Cõu 8: Cho mt -amino axit X cú mch cacbon khụng phõn nhỏnh - Ly 0,01mol X phn ng va vi dd HCl thu c 1,835g mui - Ly 2,94g X phn ng va vi dd NaOH thu c 3,82g mui Xỏc nh CTCT ca X? A CH3CH2CH(NH2)COOH B HOOCCH2CH2CH(NH2)COOH C HCOOCH2CH(NH2)CH2COOH D HOOCCH2CH2CH2CH(NH2)COOH Cõu 9: X l mt amino axit no ch cha nhúm NH2 v nhúm COOH Cho 15,1 g X tỏc dng vi HCl d thu c 18,75 g mui CTCT ca X l A H2N-CH2-COOH B CH3-CH(NH2)-COOH C C6H5-CH(NH2)-COOH D C3H7-CH(NH2)-COOH Cõu 10: Trung ho mol -amino axit X cn mol HCl to mui Y cú hm lng clo l 28,286% v lng CTCT ca X l A H2N-CH2-CH(NH2)-COOH B H2N-CH2 -COOH C CH3-CH(NH2)-COOH D H2N-CH2-CH2-COOH Cõu 11: Hp cht Y l - amino axit Cho 0,02 mol Y tỏc dng va vi 80 ml dd HCl 0,25M Sau ú cụ cn c 3,67 gam mui Mt khỏc trung ho 1,47 gam Y bng lng va dd NaOH, cụ cn dd thu c 1,91 gam mui Bit Y cú cu to mch khụng nhỏnh CTCT ca Y l: A H2N CH2 CH2 COOH B CH3 CH(NH2) COOH C HOOC CH2 CH2 CH(NH2) COOH D HOOC CH2 CH(NH2) COOH Cõu 12: Amino axit X mch khụng nhỏnh cha a nhúm COOH v b nhúm NH2 Khi cho mol X tỏc dng ht vi dd NaOH thu c 144 gam mui CTPT ca X l: A C3H7 NO2 B C4H7NO4 C C4H6N2 O2 D C5H7NO2 Cõu 13: Cht A cú phn trm lng cỏc nguyờn t C,H, O, N ln lt l 32,00%, 6,67%, 42,66%, 18,67% T hi ca A so vi khụng khớ nh hn A va tỏc dng vi dd NaOH va tỏc dng vi dd HCl CTCT ca A l: A CH3-CH(NH2)-COOH B H2N-(CH2)2-COOH C H2N-CH2-COOH D H2N-(CH2)3-COOH Cõu 14: Cht A cú phn trm cỏc nguyờn t C,H, N, O ln lt l 40,45%, 7,86%, 15,73%, cũn li l O Khi lng mol phõn t ca A nh hn 100g/mol A va tỏc dng vi dd NaOH va tỏc dng vi dd HCl, cú ngun gc t B H2N-(CH2)2-COOH thiờn nhiờn Cụng thc cu to ca A l: A CH3-CH(NH2)-COO C H2 N-CH2-COOH D H2N-(CH2)3-COOH Cõu 15: un 100ml dung dch mt aminoaxit 0,2M tỏc dng va vi 80ml dd NaOH 0,25M Sau phn ng ngi ta chng khụ dung dch thu c 2,5g mui khan Mt khỏc, li ly 100g dung dch aminoaxit núi trờn cú nng 20,6% phn ng va vi 400ml dung dch HCl 0,5M CTPT ca aminoaxit: A H2NCH2COOH B H2NCH2CH2COOH C H2N(CH2)3COOH D a v c ỳng Cõu 16: Trong phõn t aminoaxit X cú mt nhúm amino v mt nhúm cacboxyl Cho 15,0 gam X tỏc dng va vi dung dch NaOH, cụ cn dung dch sau phn ng thu c 19,4 gam mui khan Cụng thc ca X l A H2NC4H8COOH B H2NC3 H6COOH C H2NC2H4COOH D H2NCH2COOH Cõu 17: Hp cht hu c X ch cha hai loi nhúm chc amino v cacboxyl Cho 100ml dung dch X 0,3M phn ng va vi 48ml dd NaOH 1,25M Sau ú em cụ cn dung dch thu c c 5,31g mui khan Bớờt X cú mch cacbon khụng phõn nhỏnh v nhúm NH2 v trớ alpha CTCT ca X: A CH3CH(NH2)COOH B CH3C(NH2)(COOH)2 C CH3CH2C(NH2)(COOH)2 D CH3CH2CH(NH2)COOH Cõu 18: un núng 100 ml dung dch amino axit 0,2 M tỏc dng va vi 80 ml dung dch NaOH 0,25 M hoc vi 80 ml dung dch HCl 0,5 M Cụng thc phõn t ca amino axit l: A (H2N)2C2H3-COOH B H2N-C2H3 (COOH)2 C (H2N)2C2H2(COOH)2 D H2N-C2H4-COOH Cõu 19: Cho 15 gam hn hp amino axit tỏc dng va vi dung dch HCl 1,2 M thỡ thu c 18,504 gam mui V y th tớch dung dch HCl phi dựng l: A 0,8 lớt B 0, 08 lớt C 0,4 lớt D 0,04 lớt Cõu 20: X l mt amino axit no ch cha mt nhúm COOH v nhúm NH2 Cho 2,06 gam X phn ng va vi NaOH, cụ cn dung dch sau phn ng thu c 2,5 g mui Vy cụng thc ca X l: A H2N-CH2-COOH B CH3 -CH(NH2)COOH C CH3 -CH(NH2)CH2COOH D C3H7CH(NH2)COOH Cõu 21: Cho 22,15 g mui gm CH2NH2COONa v CH2NH2CH2 COONa tỏc dng va vi 250 ml dung dch H2SO4 1M Sau phn ng cụ cn dung dch thỡlng cht rn thu c l : A 46,65 g B 45,66 g C 65,46 g D Kết khác Câu 22: Cho 4,41 g aminoaxit X tác dụng với dung dịch NaOH d cho 5,73 g muối Mặt khác lợng X nh trờn nu cho tác dụng với dung dịch HCl d thu đợc 5,505 g muối cloruA Xỏc nh CTCT X A HOOC-CH2CH2CH(NH2)COOH B CH3CH(NH2)COOH C HOOCCH2CH(NH2)CH2COOH D Cả A B Cõu 23: Cho mol amino axit X phn ng vi dung dch HCl (d), thu c m1 gam mui Y Cng mol amino axit X phn ng vi dung dch NaOH (d), thu c m2 gam mui Z Bit m2 - m1 = 7,5 Cụng thc phõn t ca X l A C4H10O2N2 B C5 H9O4N C C4H8O4N2 D C5H11O2N Cõu 24: Cho 0,02 mol amino axit X tỏc dng va vi 200 ml dung dch HCl 0,1M thu c 3,67 gam mui khan Mt khỏc 0,02 mol X tỏc dng va vi 40 gam dung dch NaOH 4% Cụng thc ca X l A H2NC2H3(COOH)2 B H2NC3H5(COOH)2 C (H2N)2C3H5COOH D H2NC3H6COOH Cõu 25: Cho 2.46 gam hn hp gm HCOOH, CH3COOH, C6H5OH, H2NCH2COOH tỏc dng va vi 40 ml dung dch NaOH 1M Tng lng mui khan thu c sau phn ng l A 3,52 gam B 6,45 gam C 8,42 gam D 3,34 gam Cõu 26: Cho 0,15 mol H2NC3H5(COOH)2 (axit glutamic) vo 175 ml dung dch HCl 2M, thu c dung dch X Cho NaOH d vo dung dch X Sau cỏc phn ng xy hon ton, s mol NaOH ó phn ng l A 0,50 B 0,65 C 0,70 D 0,55 Cõu 27 Amino axit mch khụng phõn nhỏnh X cha a nhúm -COOH v b nhúm -NH2 Khi cho 1mol X tỏc dng ht vi axit HCl thu c 169,5 gam mui Cho mol X tỏc dng ht vi dung dch NaOH thu c 177 gam mui.CTPT ca X l A C4H7NO4 B C3H7NO2 C C4H6N2O2 D C5H7NO2 Cõu 28 Cho 0,1 mol -amino axit X tỏc dng va vi 50 ml dung dch HCl 2M Trong mt thớ nghim khỏc, cho 26,7 gam X vo dung dch HCl d, sau ú cụ cn cn thn dung dch thu c 37,65 gam mui khan Vy X l: A Alanin B Axit glutamic C Valin D Glyxin Cõu 29 Hp cht X cha vũng benzen, cú cụng thc phõn t CxHyN Khi cho X tỏc dng vi dung dch HCl thu c mui Y cú cụng thc dng RNH3Cl (R l gc hirocacbon) Phn trm lng ca nit X l 13,084% S ng phõn cu to ca X tha cỏc iu kin trờn l A B C D Cõu 30: Cho 25,65 gam mui gm H2NCH2COONa v H2NCH2CH2COONa tỏc dng va vi 250 ml dung dch H2SO4 1M Sau phn ng cụ cn dung dch thỡ lng mui H2NCH2COONa to thnh l: A 29,25 gam B 18,6 gam C 37,9 gam D 12,4 gam Cõu 31: Cho 0,02 mol cht X (X l mt -aminoaxit) phn ng va ht vi 160ml dd HCl 0,125 M thỡ to 3,67g mui Mt khỏc, 4,41g X tỏc dng vi mt lng NaOH va thỡ to 5,73g mui khan Bit X cú mch cacbon khụng phõn nhỏnh Vy cụng thc cu to ca X l : A HOOC-CH(NH2)-CH(NH2)-COOH B CH3-CH2-CH(NH2 )-COOH C HOOC-CH2-CH2-CH(NH2 )-COOH D CH3-CH2 -CH2-CH(NH2)-COOH Cõu 32: Cho 0,02 mol amino axit X tỏc dng va vi 200ml dung dch HCl 0,1M c 3,67gam mui khan Mt khỏc 0,02mol X tỏc dng va vi 40gam dung dch NaOH 4% S cụng thc cu to ca X l: A B C D Cõu 33: Cht X l mt aminoaxit Cho 100ml dung dch X 0,02M phn ng va ht vi 160ml dung dch NaOH 0,25M Cụ cn dung dch sau phn ng ny thỡ c 3,82g mui khan Mt khỏc X tỏc dng vi HCl theo t l 1:1 Cụng thc phõn t ca X l: A C3H7NO2 B C4H7NO4 C C5H11NO4 D C5H9 NO4 Cõu 34: Cho m gam hn hp X gm axit glutamic v alanin tỏc dng vi dung dch HCl d Sau phn ng lm bay hi cn thn dung dch thu c (m + 11,68) gam mui khan Nu cho m gam hn hp X tỏc dng vi dung dch KOH va , sau phn ng lm bay hi cn thn dung dch thu c (m + 19) gam mui khan Giỏ tr ca m l: A 38,92 gam B 35,4 gam C 36,6 gam D 38,61 gam Cõu 35: Dung dch X cha 0,01 mol ClH3N-CH2-COOH, 0,02 mol CH3-CH(NH2)COOH; 0,05 mol H COOC6 H5 Cho dung dch X tỏc dng vi 160 ml dung dch KOH 1M un núng phn ng xy hon ton Cụ cn dung dch sau phn ng thu c m gam cht rn khan Giỏ tr ca m l: A 12,535 gam B 16,335 gam C 8,615 gam D 14,515 gam Cõu 36: Hn hp X gm amino axit no, mch h Ly 8,9 gam X cho tỏc dng vi dung dch HCl d c a gam mui, cng lng 8,9 gam X tỏc dng vi dung dch NaOH d thỡ lng mui thu c l (a 1,45) gam Hai amino axit ú l A NH2C4H8COOH v NH2 C3H6COOH B NH2CH2COOH v NH2C2H4COOH C NH2C2H4COOH v NH2 C3H6COOH D NH2CH2COOH v NH2C3 H6COOH Cõu 37: -aminoaxit X cha mt nhúm -NH2 Cho 10,3 gam X tỏc dng vi axit HCl (d), thu c 13,95 gam mui khan Cụng thc cu to thu gn ca X l A H2NCH2COOH B H2NCH2CH2COOH C CH3CH2CH(NH2)COOH D CH3CH(NH2)COOH Cõu 38: Trong phõn t aminoaxit X cú mt nhúm amino v mt nhúm cacboxyl Cho 15,0 gam X tỏc dng va vi dung dch NaOH, cụ cn dung dch sau phn ng thu c 19,4 gam mui khan Cụng thc ca X l A H2NC4 H8COOH B H2NC3 H6COOH C H2NC2H4COOH D H2NCH2COOH Cõu 41: Hp cht hu c A cú 15,7303%N v 35,9551%O v lng A tỏc dng vi HCl ch to R(O)z-NH3Cl (R l gc hidrocacbon) Xỏc nh CTCT ca A Bit A tham gia phn ng trựng ngng Cõu 42: Cho mol amino axit X phn ng vi dung dch HCl (d), thu c m1 gam mui Y Cng mol amino axit X phn ng vi dung dch NaOH (d), thu c m2 gam mui Z Bit m2 - m1 = 7,5 Mt khỏc cho 0,01 mol A tỏc dng va vi dung dch HCl sau ú cụ cn cn thn thu c 1,835 gam mui Cụng thc ca X l : A H2NC2H3(COOH)2 B H2NC3H5(COOH)2 C (H2N)2C3H5COOH D H2NC3H6COOH Cõu 44: Cho dung dch X cú cha 0,01 mol Glixin, 0,02 mol ClH3N-CH2-COOH v 0,03 mol phenyl fomat tỏc dng vi 150 ml dung dch NaOH 1M un núng c dung dch Y Cụ cn dung dch Y thu c cht rn khan cú lng l A 9,6 gam B 6,12 gam C 11,2 gam D 11,93 gam Cõu 45: Cho 17,8 gam hn hp hai amino axit no cha mt chc -COOH v mt chc -NH2 (t l lng phõn t ca chỳng l 1,373) tỏc dng vi 110 ml dung dch HCl 2M, c dung dch A é tỏc dng ht cỏc cht dung dch A cn dựng 140 ml dung dch KOH 3M Phn trm s mol mi amino axit hn hp ban u bng A 25% v 75% B 50% v 50% C 20% v 80% D 40% v 60% Cõu 46: Cho m gam hn hp X gm axit glutamic v valin tỏc dng vi dung dch HCl (d), sau phn ng hon ton lm bay hi cn thn dung dch, thu c (m + 9,125) gam mui khan Nu cho m gam X tỏc dng vi dung dch NaOH (d), kt thỳc phn ng to (m + 7,7) gam mui Giỏ tr ca m l A 26,40 B 39,60 C 33,75 D 32,25 Amino axit tỏc dng vi axit hoc baz sau ú ly sn phm thu c tỏc dng vi baz hoc axit Cõu 1: Cho 0,15 mol H2NC3H5(COOH)2 (axit glutamic) vo 175 ml dung dch HCl 2M, thu c dung dch X Cho NaOH d vo dung dch X Sau cỏc phn ng xy hon ton, s mol NaOH ó phn ng l : A 0,50 B 0,65 C 0,70 D 0,55 Cõu 2: 0,01 mol amino axit Y phn ng va vi 0,01 mol HCl c cht Z Cht Z phn ng va vi 0,02 mol NaOH Cụng thc ca Y cú dng l A H2NR(COOH)2 B H2NRCOOH C (H2N)2RCOOH D (H2N)2R(COOH)2 Cõu 3: Mt amino axit A cú cha nhúm chc amin, mt nhúm chc axit 100ml dd cú cha A vi nng 1M phn ng va vi 100ml dd HCl aM c dd X, dd X phn ng va vi 100ml dd NaOH bM Giỏ tr ca a, b ln lt l A 2; B 1; C 2; D 2; Cõu 3: Cho 0,2 mol amino axit X phn ng va vi 100 ml dung dch HCl 2M thu c dung dch A Cho dung dch A phn ng va vi dung dch NaOH, sau phn ng cụ cn sn phm thu c 33,9g mui X cú tờn gi l: A glixin B alanin C valin D axit glutamic Cõu 4: X l amino axit cú cụng thc tng quỏt dng H2N R COOH Cho 8,9 gam X tỏc dng vi 200 ml dd HCl 1M thu c dung dch Y phn ng ht vi cỏc cht dd Y cn dựng 300 ml dd NaOH 1M CTCT ỳng ca X l: A H2N CH2 COOH B H2N CH2 CH2 COOH C CH3 CH(NH2) COOH D CH3 CH2 CH(NH2) COOH Cõu 5: A l mt -amino axit mch cacbon khụng phõn nhỏnh Cho 0,1 mol A vo dung dch cha 0,25 mol HCl (d), c dung dch B phn ng ht vi dd B, cn va 300 ml dd NaOH 1,5 M un núng Nu cụ cn dung dch sau cựng, thỡ c 33,725 g cht rn khan A l: A Glixin B Alanin C axit glutamic D axit -amino butiric Cõu 6: Cho 0,1 mol amino axit phn ng va vi 200 ml dung dch HCl 0,5M, thu c dung dch X Cho dd NaOH 0,5M vo dung dch X thỡ thy cn dựng va ht 600ml Xỏc nh s nhúm chc amino -NH2 v cacboxyl - COOH ? Cõu 7: X l mt -amino axit cú cha vũng thm v mt nhúm NH2 phõn t Bit 50 ml dung dch X phn ng va vi 80 ml dung dch HCl 0,5M, dung dch thu c phn ng va vi 50 ml dung dch NaOH 1,6M Mt khỏc nu trung hũa 250 ml dung dch X bng lng va KOH ri em cụ cn thu c 40,6 gam mui CTCT ca X l: A C6H5-CH(CH3)-CH(NH2)COOH B C6H5-CH(NH2)-CH2COOH C C6H5-CH(NH2)-COOH D C6H5-CH2CH(NH2)COOH Cõu 8: Cho 0,1 mol alanin phn ng vi 100 ml dung dch HCl 1,5M thu c dung dch A Cho A tỏc dng va vi dung dch NaOH thu c dung dch B, lm bay hi dung dch B thu c bao nhiờu gam cht rn khan? A 14,025 gam B 8,775 gam C 11,10 gam D 19,875 gam Cõu 9: Cho 0,15 mol hn hp X gm hai aminoaxit : R(NH2)(COOH)2 v R(NH2)2(COOH) vo 200 ml dung dch HCl 1,0 M, thu c dung dch Y Y tỏc dng va ht vi 400 ml dung dch NaOH 1,0 M S mol ca R(NH2 ) (COOH)2 0,15 mol X l A 0,1 mol B 0,125 mol C 0,075 mol D 0,05 mol Cõu 10: Cho 27,15 gam tyrosin tỏc dng vi 225 ml dung dch HCl 1M thu c dung dch X Cho X tỏc dng vi 600 ml dung dch NaOH 1M thu c dung dch Y Tng lng cht rn khan thu c cụ cn cn thn dung dch Y l A 40,9125 gam B 49,9125 gam C 52,6125 gam D 46,9125 gam Cõu 11: Ly 0,3 mol hn hp X gm H2NC3H5(COOH)2 v H2NCH2COOH cho vo 400ml dung dch HCl 1M thỡ thu c dung dch Y Y tỏc dng va vi 800ml dung dch NaOH 1M nthu c dung dch Z Lm bay hi Z thu c m gam cht rn khan, giỏ tr ca m l? A 52,2 gam B 55,2 gam C 28,8 gam D 31,8 gam Cõu 12: Cho m gam hn hp X gm hai -aminoaxit cựng s mol, u no mch h, cú nhúm amino v nhúm cacboxyl tỏc dng vi dd cha 0,44 mol HCl c dd Y Y td va ht vi dd cha 0,84 mol KOH t chỏy hon ton m gam X ri hp th sn phm chỏy bng dd KOH d thy lng bỡnh tng 65,6 g CTCT cht X l A H2NCH(C2H5 )COOH v H2NCH(CH3 )COOH B H2NCH2COOH v H2NCH(CH3)COOH C H2NCH(C2H5)COOH v H2NCH2CH2COOH D H2NCH2 COOH v H2NCH(C2 H5)COOH Cõu 13: Cho -aminoaxit X ch cha mt chc NH2 tỏc dng vi 200ml dung dch NaOH 1M thu c dung dch Y Dung dch Y phn ng va vi 500ml dung dch HCl 1M thu c dung dch Z Cụ cn cn thn dung dch Z thu c 49,35 gam cht rn khan X l: A Valin B Lysin C Glyxin D Alanin Cõu 14: Cho 20,15 gam hn hp X gm glyxin v alanin phn ng vi 200 ml dung dch HCl 1M, thu c dung dch Y Dung dch Y phn ng va vi 450 ml dung dch NaOH 1M Thnh phn % v lng ca glyxin hn hp X l A 55,83% B 53,58% C 44,17% D 47,41% Cõu 15: Cho dung dch cha 0,01 mol mt aminoaxit A tỏc dng va vi 100ml dung dch HCl 0,1M thu c dung dch X , tỏc dng ht vi dung dch X cn ti thiu 300ml NaOH 0,1M, cụ cn dung dch sau phn ng thu c 2,845 gam cht rn A l: A Lysin B Axit glutamic C Tyrosin D Alanin Cõu 16: Cho 0,12 mol alanin tỏc dng va vi dung dch HCl thu c dung dch X Thờm vo dung dch X 300 ml dung dch NaOH 1M thu c dung dch Y Cụ cn dung dch Y thu c m gam cht rn khan Giỏ tr ca m l: A 17,70 gam B 22,74 gam C 20,10 gam D 23,14 gam Cõu 17: Cho 19,2 gam hn hp gm hai amino axit no cha mt chc axit v mt chc amin (t l lng phõn t ca chỳng l 1,373) tỏc dng vi 110 ml dung dch HCl 2M, c dung dch A tỏc dng ht vi cỏc cht dung dch A cn dựng 140 ml dung dch KOH 3M Phn trm s mol ca mi aminoaxit hn hp ban u bng: A 25% v 75% B 20% v 80% C 50% v 50% D 40% v 60% Cõu 18: Cho 13,35 g hn hp X gm CH2NH2CH2COOH v CH3CHNH2 COOH tỏc dng vi V ml dung dch NaOH 1M thu c dung dch Y Bit dung dch Y tỏc dng va vi 250 ml dung dch HCl 1M Giỏ tr ca V l : A 100 ml B 150 ml C 200 ml D 250 ml Cõu 19: Cho 20,15 g hn hp X gm (CH2NH2COOH v CH3CHNH2COOH) tỏc dng vi 200 ml dung dch HCl 1M thu c dung dch Y Y tỏc dng va vi 450 ml dung dch NaOH.Phn trm lng cỏc cht X l A 55,83% v 44,17% B 53,58% v 46,42% C 58,53% v 41,47% D 52,59% v 47,41% Cõu 20 : Ly 20 ml amino axit X cú nhúm -NH2 phn ng vi 100 ml dung dch HCl 0,1M thu c dung dch Y Cho dung dch Y phn ng va vi 300 ml dung dch NaOH 0,1M Mt khỏc trung hũa ht 250 ml X bi KOH sau phn ng cụ cn sn phm thu c 26,125 g mui Xỏc nh cụng thc CT ca X ? Cõu 21: Ly m gam hn hp X gm hai amino axit cú nhúm -NH2 v nhúm -COOH phn ng vi 55 ml dung dch HCl 2M thu c dung dch Y tỏc dng ht vi cỏc cht dung dch Y cn dựng 70 ml dung dch KOH 3M Mt t chỏy hon ton m(g) X v cho sn phm chỏy qua dd KOH d thỡ lng bỡnh ny tng thờm 14,85 gam Bit t l phõn t gia hai amino axit l 1,187 Xỏc nh cụng thc CT ca X ? Cõu 22: Cho hn hp A gm ( 0,15 mol axit glutamic v 0,1 mol glyxin ) vo 175 ml dung dch HCl 2M, thu c dung dch X Cho NaOH d vo dd X Sau cỏc phn ng xy hon ton, s mol NaOH ó phn ng l A 0,80 B 0,60 C 0,75 D 0,65 Cõu 23: Cho m gam aminoaxớt (trong phõn t ch cha mt nhúm NH2 v mt nhúm COOH), tỏc dng vi 110ml dd HCl 2M c dd X phn ng ht vi cỏc cht dd X cn 200 gam dd NaOH 8,4% c dd Y, cụ can dd Y thỡ c 32,27 gam cht rn Cụng thc phõn t ca aminoaxớt trờn l: A NH2CH2COOH B NH2C2H2COOH C NH2C2H4COOH D NH2C3H6COOH Cõu 24: Hn hp X gm aminoaxit (H2N)2R1COOH v H2NR2(COOH)2 cú s mol bng tỏc dng vi 550ml dung dch HCl 1M thu c dung dch Y Y tỏc dng va vi lớt dung dch NaOH 1M Vy to thnh dung dch Y thỡ ? A HCl v aminoaxit va B HCl d 0,1 mol C HCl d 0,3 mol D HCl d 0,25 mol Cõu 25: Hn hp M gm hai cht CH3COOH v NH2CH2COOH trung ho m gam hn hp M cn 100ml dung dch HCl 1M Ton b sn phm thu c sau phn ng li tỏc dng va vi 300ml dung dch NaOH 1M Thnh phn phn trm theo lng ca cỏc cht CH3COOH v NH2CH2 COOH hn hp M ln lt l ; A 61,54 v 38,46 B 72,80 v 27,20 C 44,44 v 55,56 D 40 v 60 Cõu 26: X l axit , iaminobutiric Cho dung dch cha 0,25 mol X tỏc dng vi 400 ml dung dch NaOH 1M, sau ú cho vo dung dch thu c 800ml dung dch HCl 1M v sau phn ng kt thỳc cụ cn dung dch s thu c bao nhiờu gam cht rn khan : A 47,75 gam B 74,7 gam C 35 gam D 56,525 gam BI TP NNG CAO Cõu 1: Cho 100 ml dung dch amino axit X nng 0,4M tỏc dng va vi 80 ml dung dch NaOH 0,5M, thu c dung dch cha gam mui Cụng thc ca X l A NH2C3H6COOH B NH2C3H5(COOH)2 C (NH2)2C4H7COOH D NH2C2H4COOH Cõu 2: Hn hp X gm mol amin no mch h A v mol aminoaxit no mch h B tỏc dng va vi mol HCl hay mol NaOH t a gam hn hp X cn 46,368 lớt O2(ktc) thu c 8,064 lớt khớ N2 (ktc) Nu cho a gam hn hp trờn tỏc dng vi dung dch HCl d thu c bao nhiờu gam mui? A 75,52 B 84,96 C 89,68 D 80,24 Cõu 3: Hn hp X gm s aminoaxit no mch h 0,43 mol hn hp X tỏc dng va vi 0,55 mol NaOH hay 0,51 mol HCl t m gam hn hp X cn 98,672 lớt O2 (ktc) thu c 80,192 lớt CO2 (ktc) Giỏ tr ca m l A 99,39 B 100,14 C 101,17 D 99,71 Cõu 4: Hn hp X gm amino axit no (ch cú nhúm chc COOH v NH2 phõn t), ú t l mO : mN = 80 : 21 tỏc dng va vi 3,83 gam hn hp X cn 30 ml dung dch HCl 1M Mt khỏc, t chỏy hon ton 3,83 gam hn hp X cn 3,192 lớt O (ktc) Dn ton b sn phm chỏy (CO 2, H2O v N2) vo nc vụi d thỡ lng kt ta thu c l A 20 gam B 13 gam C 10 gam D 15 gam Cõu 5: Cho hn hp m gam X gm tyrosin (HOC6H4CH2CH(NH2)COOH)) v alanin Tin hnh hai thớ nghim sau: - Thớ nghim 1: Cho m gam X tỏc dng va vi dung dch HCl thu c dung dch Y, cụ cn dung dch Y thỡ thu c m + 9,855 gam mui khan - Thớ nghim 2: Cho m gan X tỏc dng vi 487,5ml dung dch NaOH 1M thỡ lng NaOH dựng d 25% so vi lng cn phn ng Giỏ tr ca m l A 44,45gam B 37,83 gam C 35,99 gam D 35,07 gam Cõu 6:Hn hp Xgm valin v glyxylalanin Cho a mol Xvo 100 ml dung dch H2SO40,5M (loóng), thu c dung dch Y Cho Yphn ng va vi 100 ml dung dch gm NaOH 1M v KOH 1,75M un núng, thu c dung dch cha 30,725 gam mui Giỏ tr ca a l A 0,275 B 0,125 C 0,150 D 0,175 Cõu 7: Hp cht hu c X ch cha hai loi nhúm chc l NH2 v COOH Cho 0,1 mol X tỏc dng va vi 0,2 mol HCl thu c 21,9 gam mui Y S nguyờn t hiro phõn t mui Y l A 13 B 16 C 14 D 15 Cõu 8: Amino axit X cú cụng thc H 2N-CxHy-(COOH)2 Cho 0,1 mol X vo 0,2 lớt dung dch H 2SO4 0,5M, thu c dung dch Y Cho Y phn ng va vi dung dch gm NaOH 1M v KOH 3M, thu c dung dch cha 36,7 gam mui Phn trm ca nguyờn t nit X l: A 10,526% B 9,524% C 11,966% D 10,687% Cõu 9: Hn hp X gm mt s amino axit (ch cha nhúm chc COOH v NH2 phõn t), ú t l mO : mN = 16 : tỏc dng va vi 10,36 gam hn hp X cn va ỳng 120 ml dung dch HCl 1M Mt khỏc cho 10,36 gam hn hp X tỏc dng vi 150 ml dung dch NaOH 1M ri cụ cn thu c m gam rn Giỏ tr ca m l A 14,20 B 16,36 C 14,56 D 13,84 Cõu 10: Cho hn hp X gm mui A (C5H16O3N2) v B (C4H12O4N2) tỏc dng vi mt lng dung dch NaOH va , un núng n phn ng xy hon ton ri cụ cn thu c m gam hn hp Y gm hai mui D v E (M D < ME) v 2,24 lớt hn hp Z gm hai amin no, n chc ng ng k tip cú t hi i vi H2 l 18,3 Khi lng ca mui E hn hp Y l A 2,12 gam B 3,18 gam C 2,68 gam D 4,02 gam Cõu 11: Hn hp E gm mt amin X v mt amino axit Y (X, Y u no v cú cựng s nguyờn t C; Y ch cha nhúm -COOH) Ly 0,3 mol hn hp E tỏc dng va vi 150 ml dung dch HCl 2M thu c dung dch X Dung dch X phn ng va vi 250 ml dung dch NaOH 2M thu c dung dch Y Cụ cn n khụ dung dch Y thu c 39,75 gam rn khan Cụng thc phõn t ca X l A C2H7N B C3H9N C C4H11N D C5H13N Cõu 12: Cho 0,02 mol cht X (X l mt anpha-amino axit) phn ng va ht vi 160 ml dung dch HCl 0,125M thỡ to 3,67 gam mui Mt khỏc 4,41 gam X phn ng vi lng NaOH va thỡ to 5,73 gam mui khan Bit X cú mch cacbon khụng phõn nhỏnh Vy cụng thc cu to ca X l A HOOC-CH(NH2)-CH(NH2)COOH B HOOC-CH2-CH2-CH(NH2)-COOH C CH3-CH2-CH(NH2)-COOH D.CH3-CH2-CH2-CH(NH2)-COOH Cõu 13: Hn hp A gm hai aminoaxit no cha mt chc amin, mt cha axit, liờn tip dóy ng ng Dựng khụng khớ d t chỏy hon ton 3,21 gam hn hp A Hn hp thu c sau phn ng em lm khụ c hn hp khớ B Cho B qua dung dch Ca(OH)2 d thu c 9,5 gam kt tA Phn trm s mol cỏc amino axit hn hp A ln lt l : A 50% v 50% B 62,5% v 37,5% C 40% v 60% D.27,5% v 72,5% Cõu 14: tỏc dng va vi 29,94 gam hn hp X gm s amino axit (ch cú nhúm chc -COOH v -NH2), khụng cú nhúm chc khỏc) cn 380 ml dung dch KOH 1M Mt khỏc t chỏy 29,94 gam hn hp X cn 24,528 lớt O2 (ktc) thu c m gam CO2; p gam H2O v 3,36 lớt N2(ktc) a m cú giỏ tr l : A 39,60 gam B 42,24 gam C 52,80 gam D.38,72 gam b p cú giỏ tr l : A 18,54 gam B 18,72 gam C 19,44 gam D 20,16 gam Cõu 15 Hn hp X gm s amino axit no (ch cú nhúm chc -COOH v -NH2, khụng cú nhúm chc khỏc) cú t l lng mO : mN = 48 : 19 tỏc dng va vi 39,9 gam hn hp X cn 380 ml dung dch HCl 1M Mt khỏc t chỏy 39,9 gam hn hp X cn 41,776 lớt O2 (ktc) thu c m gam CO2 m cú giỏ tr l A 66 gam B 59,84 gam C 61,60 gam D 63,36 gam Cõu 16 A l mt anpha-aminoaxit Cho bit mol A phn ng va vi mol HCl, hm lng clo mui thu c l 19,346% Cụng thc ca A l: A HOOC-CH2-CH2-CH(NH2)-COOH B CH3-CH2-CH(NH2)-COOH C HOOC-CH2-CH2-CH2-CH(NH2)-COOH D CH3CH(NH2)COOH Cõu 17 Cht hu c A cú nhúm amino v chc este Hm lng nit A l 15,73%.X phũng húa m gam cht A, hi ancol bay cho i qua CuO nung núng c anehit B Cho B thc hin phn ng bc thy cú 16,2 gam Ag kt tA Giỏ tr ca m l A 7,725 gam B 3,375 gam C 6,675 gam D 5,625 gam Cõu 18: t chỏy hon ton mt amin X no, n chc mch h thu c CO2 v H2O cú t l mol : Y l anphaamino axit no cha nhúm -NH2 v nhúm -COOH t chỏy hon ton 0,5 mol hn hp E cha X, Y cn dựng 48,72 lớt O2 (ktc) thu c CO2, H2O v N2 ú t l mol mol CO2 v H2O l 10 : 13 Cụng thc cu to ca Y l A NH2-CH2-COOH B CH3-CH(NH2)-COOH C CH3-(CH2)2-CH(NH2)-COOH D CH3-CH2-CH(NH2)-COOH Cõu 19: Hn hp E gm aminoaxit no (ch cha nhúm -NH2 v nhúm -COOH) tỏc dng va vi 48,5 gam hn hp E cn dựng 300 ml dung dch HCl 2M Mt khỏc t chỏy hon ton 48,5 gam hn hp E cn dựng 38,64 lớt O2 (ktc) Sn phm chỏy gm CO2, H2O v N2 c dn qua dung dch Ca(OH)2 d, sau lc b kt ta thy lng dung dch thu c gim x gam so vi dung dch Ca(OH)2 ban u Giỏ tr ca x l A 145,0 gam B 49,7 gam C 81,2 gam D 95,3 gam Cõu 20: Cho m gam hn hp X gm glyxin, alanin, axit glutamic v lysin (trong ú m O : mN = 16 : 9) tỏc dng vi mt lng dung dch NaOH va thu c dung dch Y Cụ cn dung dch Y ri t chỏy ht lng mui thu c 7,42 gam Na2CO3 Cho ton b khớ cacbonic v hi nc sinh qua bỡnh ng dung dch Ca(OH) d thu c 49 gam kt ta ng thi thy lng bỡnh tng 31,64 gam so vi ban u Cỏc phn ng xy hon ton Giỏ tr ca m l A 14,98 B 13,73 C 14,00 D 14,84 Cõu 21: Cho a gam hn hp X gm glyxin, alanin v valin phn ng vi 200 ml dung dch HCl 0,1M, thu c dung dch Y phn ng ht vi cỏc cht dung dch Y cn 100 ml dung dch KOH 0,55M t chỏy hon ton a gam hn hp X, thu c hn hn hp Z gm CO2, H2O v N2 Cho Z vo bỡnh ng dung dch Ba(OH) d, thy lng bỡnh tng thờm 7,445 gam Bit cỏc phn ng xy hon ton Giỏ tr ca a gn nht vi ? A 3,5 B 3,3 C 3,7 D 3,9 Cõu 22: Cho 28,05 gam hn hp E gm CH6O3N2 v C2H7O3N vo 500 ml lng dung dch NaOH 1M un nh, thu c dung dch F cha cỏc hp cht vụ c cú lng 30,65 gam v khớ X lm quỡ tớm m húa xanh Trn ton b X vi 0,1 mol mt amin Y thu c hn hp cú t so vi H2 bng 26,125 Cụng thc ca Y l A C2H5NH2 B C2H5NHCH3 C NH2-(CH2)6-NH2 D C6H5NH2 -Ht-