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~ L ~- ~ N -~ ~U ' , DO an dQng co dOt ~~~ ]-~, DO AN D R = S = 105 = 52,Smm Ta c6: 11,=0,25 tra bang (0-1) ([3],34) rp= 90° => Sr=l,125R=l,125.52,5=59,06mm = 180° => Sr=2R=2.50,25= 105mm - R (fJ = 270° ==> Sp= (fJ = 360° ==> 1, 125R= l,125.52,5=59,06mm Sp=O Sp(mm) 90 80 70 60 so -+-Sp{mm) 40 30 20 10 0 100 200 300 T6c chuy~n dong cua pittong: VP = CtJ Ra{ sin rp + ~ sin 2rp) (4-2) ([2],61) = trn = tr.Sgoo = 607 06(rad Is) 30 30 ' Ta co : 11,= 0,25 tra bang (0-2) ([3],34) (()=90° ::::> Vp=wR=607,06.52,5=31870 (fJ = I 80° ==> V -=O (fJ = 270° ==> Vp=-wR=-607,06.52.5=-31870 (fJ = 360° ==> Vr=O mm/s mm/s 400 Vp(mm/s) 25000 20000 - 15000 10000+ + ->1, 5000+-+ - -+-Vp(mm/s) -5000 -10000 + -20000 + -15000 -25000 _ Gia t6c chuy~n dong cua pittong i: i; =Ral(cosq:,+lcos2q:,) (4-2) ([2],61) Ta c6 J.= 0,25 tra bang (0-3) ([3],35) (fJ = 0° => j= 1,25 a/ R= 1,25.607,062.52,5=2,4.107 (fJ = 90° => j=-0,25 (fJ = 180° => j=-0,75 (fJ = 270° => (f)= 360° => j=l,25 (mm/s") a/ R=-0,25.607,06.52,5=-0,48.107 a/ R=-0,75 607,06.52,5=-l,4.107 j=-0,25 al R=-0,25 607,06.52,5=-0,48.107 a/ R=l,25.607,06.52,5=2,4 (mm/s") (mm/s) (mrn/s') 107 (mm/s') jp(mm/s2) 20000000 ~ - 15000000 ~ l'-10000000 5000000 +-'\ - -1 - -.-jp(mm/s2) -+ ~ - -+ -5000000 -+ -"" 10000000 -15000000 ~ - 400 CHUONG V: D(>NG LVC HQC TRUYEN ca cAu KHUYU TRT)C THANH LU'c th~ tac dung len pittong: h Pkh=Fp.pe (5-1) ([l],75) Trang do: F P = 1rD2 = "· 1052 = 86,59mm2 = 8659.10-6 m2 Tada tinh duoc: Pc=0,7 (MN/m2) Pkh=8659.10-6.0,7.106= 6061,3 N=6,06lkN LU'C guan tinh: a LU'C guan tinh chuy~n dong tinh ti~n: ~ = -ma/ R ( ccetp + Jcos2tp) (5-2) ([l],83) Trong do: R la ban kinh quay cua !f\IC khuyu [m] co la v~n t6c g6c true khuyu (rad/s) la h~ s6 k~t du m la khoi hrong chuyen dong tinh tien ta tinh m nhir sau: m= mnp + m, ([3],4) mnp: kh6i hrong nh6m pittong m.: kh6i hrong dfiu nho truyen m= ffinp+ m, Ma ta c6 kh6i = m ; ";;r =-m KT hrong cua khuyu true truyen = 5(kg I kW)=> mKT = 5Ne Ia voi Ne= 45,94 (Kw) la cong su~t c6 ich cua e dong CO' V~y d6i voi may thi cong su~t co ich la Ne= 45,94/4=11,48 => mKT = 5.11,48 = 57,4kg => m= ffinp + m1 =-.57,4 voi (kW) = 14,35kg cac thong s6 lai da bi~t ta tinh duce nhir sau: Voi 1=0,25 tra bang (0-4) ([3],35) rp = o => pj =-m w2 R(l + )=-1,25.14,35.607,062.0,0385=-229kN rp=90° => pj=m o/ R.1=0,25.14,35 607,062.0,0385=45,8k.N rp= 180° => Pj=-m o/ R(-1+ 1)=0,75.14,35 = 607,062.0,0385=137,45k.N 270° => pj =m o/ R 1=0,25.14,35.575,962.0,0385=45,8kN Pj =-m R(l + ,i )=-1,25.14,35.575,962.0,0385=-229Kn Pj(kN) 200~ -1~ 100 r -=:::;;;;+;;;;;;:::: - 50~ -0 -50-~ - vv -100 ~' -~ -150 _,._ -200 -~ -~ -250 -300 -350 - b LU'C guan tinh chuy~n dong quay: Pv= m al R (5-3) ([2],76) V6i m> mk+ m2 =imKr = I.57,4 = 43,05kg => Pv= 43,05.575,962.0,0385 c T6ng IU'C =549,82kN tac dung len pittong: P=Pkh+Pj (5-4) ([3],4) P=3,26-229=-225, 74 kN P=3,26+45,8=49,06 kN P=3,26+137,45=140,71 = 270° => P=3,26+45,8=49,06 kN P=3,26-229=-225, 74 Kn kN -+-Pj(kN) P(kN) 200 ~ ~ ::::;;;;;4~= - 1~ 100 + - 50+ -0 + 4~~ ~ ~ 400 -50 -100+ -1 -150 + , -200 -+-1 - -250 d Thanh phin lrrc ti~p tuy~n T: T = P sin(/J + (f)) cos/J (5-5) ([3] 5) ' Tra bang (0-5) ([3],36) T=O qJ=0° ~ (f)=90° ~ T = P = 49,06 kN (f)= 180° ~ T=O (f)=270° T = -P qJ=360°~ ~ T=O = -49,06 kN + -+- P{kN) T(kN) 60 -+-T(kN) -60 - e Thanh phin hrc phap tuy~n Z: Z= Pcos(/J + rp) (5-6) ([3 ],5) cos/J Tra bang (0-4) ([3],35) ta duce: (f)=0° (f) = Z=P=-225,74 kN => 90° => (f)=l80°=> Z=-0,256 P =-0,256 49,06 =-12,56kN Z=-P=-140,71kN (f) = 270° => Z=-0,256 P =-0,256 49,06 =-12,56kN (f) = 360° => Z=P=-225,74 kN 41 GVHD _THA Y GIA.O : HOANG NGOC DVONG Z(kN) o- -, 400 -50 -+-Z{kN) -150 -250 ~ - f Thanh phAn p s = -cs-7) cos/3 IU'C doc tac dung len truy~n: C[3J,s) Tinh cos/3? rp = O" ~ /3 =0° ~ cos/3 = rp = 90° ~ cos(/J + rp) = -0,256 ~ tg/3 = 0,256 ~ cosf] f]=0°~cosf]=l rp=l80°~ (fJ = 270° ~ rp = 360° ~ /3 = 14,36° ~ cos/3 = 0,97 (nrong nr tren) /3=0° ~ cos/3 = V~y nen ta tinh duoc: rp=0° ~ fJ = 14,36° S=P=225,74kN rp = 90° ~ S = 49•06 = 50 57kN 0,97 ' ~ cosf] = 0,97 cp = 180° => S=P=140,7 lkN cp = 270° => S = cp = 360° => 49•06 = 50,57kN 0,97 S=P=225,74Kn S(kN) 250 200 150 -+-S{kN) 100 so 1- 0 100 200 300 400 TAI Ll)J:U THAMKHAO Huong Dftn D6 An D(mg Ca D6t Trong-TS.Vy Hfru Thanh,Ths Vii Anh Tuftn• Nha xuftt ban H9c Vi~n KT Th~t Quan Str Ha N[...]... Li Pr trong do : Pih la Li Pr ap suftt khi thai ra ngoai la ap su~t th~t thoat qua xuppap xa duong 6ng xa Thong thtrong Pr duce xac dinh theo c6ng thirc thuc nghiern: Pr= (0,11-0,12) MPa chon Pr= 0,11 MPa=l,12 7 Nhiet (2-2) bar do khi sot Tr: ([2],30) Doi voi dong ca xang thi Tr=(900-1100)°K (2-3) ([2],30) Chon Tr=l000°K 8 Do tang nhiet do khi nap moi: Khi khi nap moi duce hut vao xy lanh thi trong. .. kh6ng khi thuc tS Il?P vao xy lanh dong CO' irng voi 1 kg nhien lieu Mt Mt= a Mo (2-18) ([l],48) = 0,9.0,512=0,46 (Kmol/kgnl) -Ltrong h6n hop chay M1 (xang va khi) irng voi hrong kh6ng khi thirc tS Mt da Il?P vao: M1 = «t«, I +-(Kmol/kgnl) µnl (2-19) ([l],48) Trong do: µn, la trong hrong phan tu cua nhien lieu µnl =110-114 (kg/kgnl) ([1],48) Chon µnl =112 (kg/kgnl) 1 -:::::;, M1 = 0,9.0,512+- -S6 112... chira d§u trong ch6t khuyu; 15-tfl,lc khuyu; lri-mieng ph€u d6 dau Nguyen ly hoat d(>ng: barn dfiu 2 hut dfiu tu cacte 1 d~ dua dfiu c6 ap suat toi binh loc 6, sau d6 qua ket lam mat 8 d€n dirong d§u chinh 13 Tu dirong d§u chinh, d§u c6 ap sufit di vao 16 khoan tren than may d€n boi tron cac c6 chinh va cac 6 do true cam Tu cac c6 chinh d§u di vao cac 16 xien tren true khuyu d€n kh6ng gian r6ng 14 trong. .. NHIET: 1 Qua trinh nap: n.: -H~ s6 nap Trong do: &=9· ' Tk =302 °K-' ~ T=l5°K- ' Pa=0,927 bar; pk=l,03 bar; Pr=l,12 bar; , = 1 ' 02 ' · ,~, = l ' · JI = 1' 15 '', m la chi s6 nen da bien trung binh cua kh6ng khi m= 1,5 'lv =-1- 302 9-1 302+15 tt; = 0, 74 E _0,81r6.102-115.1.(QJ1\l=O 1,03 ' ' 0,81 ' 74 (0, 70-0, 75) xuppap treo ([2],35) -H~ s6 khi s6t r.: (2-13) ([2],36) Trong d6 : , = 1 '02 ·' ,.~, = l '·... kh6ng OUQ'C qua gioi han cho phep Phai dam bao khoi dong lai diroc nhieu lftn Ti s6 nen tu banh rang cua may khoi dong va banh rang cua banh da nam trong gioi han cho phep (nr 9 ~ 18) Chieu dai, dien tro cua day dftn n6i tu acqui c1€n may khoi dong phai nam trong gioi han quy djnh ( vong qua cua dong + Me= 3·l04.Ne nn (Nm) CO' n ta se c6 Ne nrong irng (3-2) ([l],70) (3-3) ([l],70) GVHD _THA Y GIA.O : HOANG NGOC DVONG 30 30 Trong d6: ~=251 (g/kWh)=0,389 (kg/kWh); Ne[kW]: GVHD _THA Y GIA.O... (2-10)([2),34) Chon rpd =0,95 16 Ty s6 tang ap ( ,1,p) La ti s6 giita ap suftt cuoi qua trlnh chay voi ap suftt cuoi qua trinh nen ,1,p = Pz Pc la ap suat cuoi qua trinh chay Po la ap su~t cu6i qua trlnh nen trong d6 : Pz d6i voi dong ca xang: AP =3-4 (2-11) ([2],35) chon AP =3,5 so STT Thom;? Ki hieu Gia tr] DO'n v] 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 Cong suat danh nghia So vong quay danh nghia So xy lanh... 6 do true cam Tu cac c6 chinh d§u di vao cac 16 xien tren true khuyu d€n kh6ng gian r6ng 14 trong chot khuyu r6i tu d6 d§u sach di vao b6i tron bac d§u to thanh truyen va chot khuyu Cac can bfrn lftn trong d§u duce gift lai m~t thanh xa tam quay cua kh6ng gian 14 nho tac dung ly tam cua d§u quay theo true khuyu Tu duong d§u chinh con CO mot dirong d§u dftn toi true r6ng 12 CUa gian c§n bfry xupap,... dien tu 7, hrc hut Joi tu trier tieu nen Ive lo XO 9 d~y tay don 11 gat banh rang 12 sang trai, C~t truyen dong giira cap banh rang 12 va 13 kSt thuc khoi dong CHUONG II: TINH TOAN NHI~T D()NG CO DOT TRONG A CHON cAc THONG 1 Loai dong so CHO TRUOC CUA DONG CO: CO': -Dong CO' thiSt kS la dong CO' xang vi dong CO' xang co kSt du nho gon.nhe tich hop cho viec thiSt kS 6 t6,du ljch,6 t6 V?n tai nhe duy ... CO' Qua ban thi€t k€ "Dfi an dc}ng CO' d6t trong" da giup chung ta phan nao c6 th€ hinh dung duce each tinh toan, trinh tu thi€t k€ mot dong CO' d6t trong. Va diroi day la ban thi€t k€ d6 an dong... = 0,9.0,512=0,46 (Kmol/kgnl) -Ltrong h6n hop chay M1 (xang va khi) irng voi hrong kh6ng thirc tS Mt da Il?P vao: M1 = «t«, I +-(Kmol/kgnl) µnl (2-19) ([l],48) Trong do: µn, la hrong phan tu cua... ([1],55) QT.gi Trong d6: QT=43960 (KJ/kgnl); gi=257 (g/KWh)=257.10-3 (kg/KWh) ~ = g, 3600 = 225 43960.257.10-3 ' Cac thong s6 co ich: a A.p suAt t6n hao CO' trung binh: Pea=0,05+0,0155Cm c, Trong C