!"#$%&'%( !)*+*,$-%.!/0 Câu 1%1*2 3!4!5 67 x y x + = − , !846906:;*<0!*=>5>?1@0!A#B,!5 673 ; C*<0.!DE+0FG!0*<.0HI<#B,1@0!A;*<00*<.0HI<1J64+64+>K* 1D)+0!L+ ( y x= − + 3 Câu 2%1*2 3 ,!4+J# α 0!M, N$ π π α < < >5 & #46 ( α = − 3O! 0, & A π α = − ÷ ;!467.!P# z 0!M, N!Q0!P# ( ) ( ) ( ) ( ) z i i z i− − = + + 3G R1H#B,67 .!P# z 3 Câu 3%1*2 3O!0O#!.!S % 6* #46I x xdx π = + ∫ Câu 4%1*2 3 ,*8*.!DE+0FG! ( ) T 4+ T 4+ % x x x x + + + = ;U00V#JW!"#6*!0F4+1J#J!"#6*!X>5&!"#6*!, 3Y<.+ZH !*=W!"#6*!1J0![4 U0!5++,+3O!\9#6H]012!"#6*!X1P+ #^!!,H3 Câu 5%1*2 3F4+_!R++*,>K*!Q0",1U Oxyz #!4 ( ) W`&`aI >5 b0.!L+ $ %P x y z+ − + = 3cd..!DE+0FG!#B, b0#H S #J0S I >50*<.\/#>K* b0 .!L+ ( ) P 3G 0",1U0*<.1*2 #B, ( ) P >5 S 3 Câu 6%1*2 3!4!G!#!J. 3S ABCD #J19I ABCD 5!G!>HR+#^!;e+ a SA >HR++J#>K* b0.!L+ ABCD +J#+*X,1D)+0!L+ SB >5 b019I;e+ a% o 3"* M N Df050FH+1*2 #B,#9#14^ AD CD 3O!0!20O#!_!7*#!J. 3S BMN >5_!48+#9#!+*X,!,*1D)+0!L+ BM SN 0![4 a 3 Câu 7%1*2 3F4+ b0.!L+>K*!Q04^1U Oxy #!40, +*9# ABC #S0^* A #J ( ) `M 50FH+1*2 #B,#^! BC 3g*<0#!S1D)+#,4#B,0, +*9# ABC _h0i B 5 a ` ( ( K − ÷ >50FH+1*2 #B,#^! AB e 0F=1D)+0!L+ $ %x y∆ − + = 3 G 0",1U#9#1j! A B C 3 Câu 8%1*2 3*8*!Q.!DE+0FG!$ ( ) ( ) ( ) & & y x y x y x y y x y y x y y − + + + = + + − ∈ ∈ + + − = ¡ ¡ Câu 9%1*2 3!4 a b 5#9#670!:#kDE+3G +*90FA!M!]0#B,;*2H0!P#$ - 3 W & & P a b a b ab a b = − + + + + + ''''''''''''''''<0'''''''''''''''' %( SH U*kH+ *2 , Tp xỏc nh: Ă { } S bin thiờn: l!*mH;*<0!*=$ ( ) ( n % y x x =- < " ạ - 3 %3( l5 67+!A#!;*<0F=#9#_!48+ ( ) `- Ơ >5 ( ) `+Ơ 3 l *K*!^>50*Q #d$ l * * x x y y đ- Ơ đ+Ơ = = $0*Q #d+,+$ y = * ` * x x y y + - đ đ =+Ơ =- Ơ ị 0*Q #d1P+ x = 3 %3( lg8+;*<0!*=$ x + n y y + %3( o# th: l@0!A#p0Oy0^* %` O ổ ử ữ ỗ - ữ ỗ ữ ỗ ố ứ l@0!A#p0Ox0^* `% O ổ ử ữ ỗ - ữ ỗ ữ ỗ ố ứ lS 17*\P+51*2 ( ) `I 3 8 6 4 2 -2 -4 -6 -8 -15 -10 -5 5 10 15 f x ( ) = 2 x+1 x-2 %3( ; Q67+J#_q'( ( ) ( ( x x x = − ⇒ = − ⇔ = − %(% 00*<.0HI<0^*`W$Iq'(\o4^*3 00*<.0HI<0^*`'$Iq'(\o3 CdI0*<.0HI<#0G 5Iq'(\o3 %(% , 0, 0, & 0, A π α α α − = − = ÷ + %( & T 6* #46 ( ( α α = − = − − = ÷ CG ` π α π ∈ ÷ = 6* % α < 3r41J0i6HIF,$ 6* 6* 0, ( #46 & α α α α = − ⇒ = = 3!<>540,1Df# W A = − %( ;b0 ( ) z a bi a b= + ∈¡ `_!*1J `z a bi= − O!*QHs5!Q0!P# 0F4+1m;5*0,#Js ( ) ( ) ( ) ( ) ( ) ( ) W & %a bi i i a bi i a b a b i⇔ + − − = + − + ⇔ + − + − + − = 3 %( % W & % a b a a b b + − = = ⇔ − + − = = 3r41J z = + = %( % % % 6* #46 #46 6* #46I x xdx xdx x xdx π π π = + = + ∫ ∫ ∫ %( b0 % % #46 ` 6* #46I xdx I x xdx π π = = ∫ ∫ ,#J % % #46 6* I xdx x π π = = = ∫ %( ( ) % % % % #46 6* #46 6* #46 #46 #46 3 x I x xdx x xdx xd x π π π π = = = − = − = ∫ ∫ ∫ 3 CdI ( I I I= + = + = %(% & 3,*mH_*Q ( ) T % Tx x x+ > ⇔ < − !4b# %x > 3 CK*1_0F=.!DE+0FG!1N#!40DE+1DE+>K*$ ( ) ( ) T 4+ T 3 % 4+ T % x x x x x + + = ⇔ + = %( ( ) T - %x x x⇔ + = ⇔ = − ∨ = − 37*#!*<H>K*1_0,4^* -x = − 3 CdI.01N#!4#J+!*Q kHI!]0 %x = − 3 %( ;"*t5;*<#7$u!"#6*!X1P+#^!!,Hv3 ow7;*<#71@+_!8+$Y<.W!"#6*!+ZH!*=#J67!49 >A5Wx3 ow7#9#!\<.!"#6*!X1P+#^!!,H$4*!"#6*!X5 .!0y_<0!f.>K*&!"#6*!, 6HIF,#J(.!0y#J(x9#! 6p.\<.3CK* z*#9#!6p.\<.1J^*#Jx9#!!49>A!"#6*! X3CdI#J(x3x#9#!6p.\<.3 %( Y9#6H]0#B,;*<#7t5 (xx Wx W p A = = %( ( g9_O!#B,w5 R d I P= = %( 0 b0#Hw$ ( ) ( ) ( ) W & a &x y z− + − + − = %( 01D)+0!L+k1*{H,>5>HR++J#>K*$ W & a x t y t z t = + = + = − %( *<.1*2 Wo0`&o0`a'00!HU# ( ) ( ) T - W & a % ` ` t t t t M⇒ + + + − − + = ⇒ = − ⇒ %( a w r t g i+*80!*<06HIF, w g qw tgr lw r 'w gt 'w g q - &&- aaaa a =−−− wtqtg30,a% % q a `C wg q wt3w g q - a %(% s,#Jg ⊥ t ⇒ g ⊥ wt>5g#p0wt0^* F4+wt$_h ⊥ w ⇒ 514^>HR++J##!H+#B,g>5 w3kgwq3 ,#J$tq ( a tq ( ( a q ( % a >5wq W a %( ∆ >5 ∆ wt1@+k^+ ⇒ SN IN SA IK = ⇒ -( 3 a SN INSA IK == 3 CdIC wg q - a kgwq -( a %( & W "*50FH+1*2 #B,14^tg3 ( ) $ % ` N x y N n n∈∆ − + = ⇒ + 3 , +*9#tg>HR+0^*#J50FH+1*2 #B,tg AN BN MN ⇒ = = 3 , +*9#tg>HR+0^*#J50FH+1*2 #B,tg AN BN KN ⇒ = = 3 wHIF,q ( ) a ( ( n n n n n ⇒ − + = + + − ⇔ = ÷ ÷ 3CdI`3 %(% "*5+*,4#B,g>53g#J.0\'Io(q%3#J.0\oI' Wq%3wHIF, T ` ( ( I − ÷ 350FH+1*2 #B,g3wHIF, ( ) ( ) %`( ` a` B C − 3 %(% - b0 ( ) ( ) ` %` %u x y v y u v x u v= + = ≥ ≥ = − 3 01H#B,!Q0F|0!5!$ ( ) ( ) ( ) ( ) ( ) %v u u v v u v u v u v− + − + = + − ⇔ − − + + = %( $Hq x y x y⇒ + = ⇒ = − 3!<>54.00!P!,*#B,!Q0,1Df#$ ( ) & & & %y y y y y y y y+ − + − = ⇔ − + − − = ( ) ( ) ( ) ( ) ( ) ( ) & & & & & - % & % & y y y y y y y y y y y y y y y y y − − ⇔ − + = − + − + + + ⇔ − + = ⇔ = − + − + !*1J\q'3 %(% $>q3wHIF,Iq`\q3 $Ho>oq%$CR+!*Q 3 CdI!Q1N#!4#J!,*+!*Q $ ( ) ( ) ( ) ` ` `x y = − %( T ,#J ( ) W & & W & 3& W & & -a b ab a b a b a b a b a b+ + = + + ≤ + + + = + 0![4;10R6*3 wHIF, ( ) P a b t t f t a b t a b ≥ − + + = − + = + + 1b0 t a b = + %(% ( ) n % % f t t t t t t = − − = ⇔ − − = ⇔ = 3 cd.;8+;*<0!*=#B, ( ) f t >K*0}%0,#J *q~q & ( & ( a a b a b b = + = ⇔ ⇔ = = %(% Thạch Thành, ngày 3 tháng 4 năm 2015. Người ra đề và làm đáp án: Bùi Trí Tuấn ( . + ''''''''''''''''<0'''''''''''''''' %( SH U*kH+ *2 , Tp xỏc nh: Ă { } S bin thi n: l!*mH;*<0!*=$ ( ) ( n % y x x =- < " ạ - 3 %3( l5 67+!A#!;*<0F=#9#_!48+ (. ( a a b a b b = + = ⇔ ⇔ = = %(% Thạch Thành, ngày 3 tháng 4 năm 2015. Người ra đề và làm đáp án: Bùi Trí Tuấn (