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Hai tam gi c b ng nhau th ng d ng v i nhau.B. Hai tam gi c         ng d ng v i nhau th b ng nhau.C. Hai tam gi c vu ng lu n ng d ng v i nhau.           C u 6: H nh h p ch nh t c s m t h nh ch nh t l :A. 4             B. 6 C. 8 D.12C u  7: H nh h p ch nh t c s c nh l :A. 6.2 B. 6.3         C # EMBED Equation.3 ### D.# EMBED Equation.3 ###C u 8: H nh ch p t gi c u c c nh y a =15cm v chi u cao h nh ch p l               h=12,5cm. Th t ch ch p l : A . 937,5 cm3 B. 1050cm3     C. 781,25cm3 D. 250cm3Ph n II(8 )T lu n:C u 9(1,5 ) Gi i        ph ng tr nh:  a, # EMBED Equation.3 ### b, (2x-1)(x+2)=(3x-2)(2x-1)C u  10(2 ) Cho bi u th c:   A=# EMBED Equation.3 ### a, V i gi tr n o c a x      th bi u th c c x c nh      b, H y r t g n bi u th c A c,T m gi        tr c a x bi u th c A c gi tr b ng1.C u11(1,5 ) M t t ch y tr n qu ng                  ng AB. L c i t ch y v i v n t c 35km/h , l c v t ch y v i v n t c                  42km/h. V v y th i gian v t h n th i gian l n a gi . T nh chi u d i o n                ng ABC u 12(3 ) Cho tam gi c ABC (AB>BC) D l m t i m tr n c nh AB. ng            th ng k qua D song song v i BC v ng th ng k qua C song song v i AB c t          nhau F. BF v DF c t AC l n l t I v E.       a, Ch ng minh r ng t gi c BDFC     l h nh b nh h nh    b, Ch ng minh r ng n u BD=BC th BF l tia ph n gi c c a g c          ABC c, Ch ng minh r ng v i D l m t i m tu tr n AB ta lu n c ng th c               IC2=IE.IA p n :Ph n1 Tr c nghi m(2 ).M i c0,25 C u1.DC u2.DC u3.DC u4.C              C u5.AC u6.BC u7.A C u8.APh nII.T lu n(8 )C u9C u a (0.75 ) : # EMBED            Equation.3 ### * i u ki n x c nh c a ph ng tr nh:x# EMBED         Equation.3 ###(0,25 ) * # EMBED Equation.3 ### 1+2(x-1)=3-2x # EMBED Equation.3 ###x=1 (0.25 )# Ta th y x=1 kh ng tho m n i u       ki n x c nh. V y ph ng tr nh VN (0.25 )       C u b (0,75 ) :  (2x-1)(x+2)=(3x-2)(2x-1) # EMBED Equation.3 ###(2x-1)(4-2x)=0 # EMBED Equation.3 ###2x-1=0 ho c 4-2x=0 # EMBED Equation.3 ###x=# EMBED Equation.3 ### ho c x=2 #K t lu n c t p nghi m c a        ph ng tr nh l S=# EMBED Equation.3 ### C u 10(2 )a, T m ng i u ki n x c            nh c a A (0.25 )   x# EMBED Equation.3 ### b, R t g n bi u th c A (1 ) :     - R t g n ng trong ngo c (0.75 ) #      EMBED Equation.3 ###=# EMBED Equation.3 ### (0,25 )=# EMBED Equation.3  ###=# EMBED Equation.3 ### (0,25 )=# EMBED  Equation.3 ###=# EMBED Equation.3 ### (0,25 ) - Th c hi n ph p chia trong ngo c cho # EMBED Equation.3     ### ra ng k t qu (0.25 )A=# EMBED Equation.3 ###=# EMBED Equation.3 ###=#     EMBED Equation.3 ### c, KX c a Al :x# EMBED Equation.3 ###,x#     EMBED Equation.3 ###,x# EMBED Equation.3 ###(0,25 ) A=1# EMBED Equation.3 ### # EMBED Equation.3 ###x2+12=(x+2) (x-1) (0,25 ) # EMBED Equation.3  ###x2+12=x2+2x-x-2 # EMBED Equation.3 ### x=14(TM KX ) (0,25 ) V y x=14 th Ac gi tr b ng 1C u11 (1,5 )           [...]... height="30" src=#"http://i912.photobucket.com/albums/ac327/vietha9/vtv1.gif" width=#"80" border="0"> . src=#"http://i912.photobucket.com/albums/ac327/vietha9/vtv1.gif" width=#"80" border="0"></a> <a href=#"http://www.truyenhinhtructuyen.biz/vtv2.html" target=#"_blank"><font. src=#"http://i912.photobucket.com/albums/ac327/vietha9/vtv2.gif" width=#"80" border="0"></font></a> <a href=#"http://www.truyenhinhtructuyen.biz/vtv3.html". src=#"http://i912.photobucket.com/albums/ac327/vietha9/vtv3.gif" width=#"80" border="0"></font></a> <a href=#"http://www.truyenhinhtructuyen.biz/vtv4.html"

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