ĐỀ 1: Câu 1: x y x − + = − ! "#$%&!' !()*+,-./01&)2/3, !4'$- 52'06&7&8,9:;<4!'/=>- Câu 2: 52?&1>3@') ! y x x = + + − 52&)%(A&)BA ! x y x e= − )4 [ ] CD Câu 3: "/01&)2 ( ) ( ) E E E %& E %& C %& Ex x+ + − + = − "A/01&)2 F- G- C x x− − + − > Câu 4 5HH/= ! I - I x x dx= + ∫ ( ) %J x xdx= − ∫ 5H8>H2/7&&(4J06& y x x= − )*+: Câu 52K/L&M3N$OPK4,Q&!@4R/(S,T &KQ&GC C -5H'H2K/N$OPU!- Câu 6: 5)&?V&&!(>#!T+:,W'$@X@ S/7&Y Cx y z+ + − = ./01&)206&7&8Z3!$3V&&K(Y- 52#!T233V&&K !'$)Y- ./01&)2S[3NK=$N/:\(Y Câu 7: 52V3 !/L ( ) X z i i= − + − "/01&)2!3)]/ ! ( ) ( ) ( ) E Xi z i i z+ + + = − C Cz z− + = Cz z− + − = ĐỀ 2: Câu 1: G y x x= − + ! ./01&)2/3, !4'$3T'$KTQ&^- P_&>%3]U&> !/01&)2 G Cx x m− + − = - Câu 2: 52?&1>3@') % x y x= − 52&)%(A&)BA ! y f x x x x= = − − + )4 E D − Câu 3: "/01&)2 - C x x+ + − = ÷ ÷ "A/01&)2 %& C x x − < ÷ + Câu 4 5HH/= ! ( ) C I x x xdx π = + ∫ % % e e x x J dx x + = ∫ 2/7&`&(4J06& y x= + D,9CD :9CD:9-5H'H !?)a:!,4?Z3!,2`Z3!)*+:- Câu 52K)a:!,bN-5)&, !2KKT23V&$OPK 4Q&!T/@ · C GCASB = -5H8>H:3&Z3!'H2KK- Câu 6: 5)&?V&&!(>#!T+:,WS/7&Y E Cx y z+ − + = !' $C@C@X@ODCDC ./01&)206&7&8Z3!$3V&&K(Y- 52#!T233V&&K !'$)Y- ./01&)2/cZ3!$@O3V&&K/Y Câu 7: 52V3 !/L ( ) ( ) ( ) X z i i i= + − + − "/01&)2!3)]/ ! ( ) ( ) ( ) X G Ei z i i z− + + = − E I Cz z− + = X G Cz z+ − = ĐỀ 3: Câu 1: Xy x x mx = − − + + 52'K) !?9C ./01&)2/3, !4'$3T'$KTQ&- X52!'/01&)2 Cx x a + + = K!&>/=>- Câu 2: 52?&1>3@') ! X y x x= − 52&)%(A&)BA ! X y x x = + + )4 [ ] D 52M: ! %& X x y x − = + Câu 3: "/01&)2 X F %& X%& %& x x x+ + = "/01&)2 - X- C x x− + − = Câu 4 5HH/= ! ( ) C X x I x e xdx= + ∫ ( ) ( ) C X XJ x x x dx − = + + + ∫ 5H8>H2/7&`&(4J06& y x= D,9CD,9:^- Câu 52K/N$OK,$O%!&M34!@4N$3V&&K, $O@4NOR/(,T&KXE C -5H'H2K/N$OU!- Câu 6: 5)&?V&&!(>#!T+:,W'$^@C@S/7&Y Cx y z+ − − = D8 x y z+ − = = − 52#!T23d !$)8 52#!T&!' !8Y X./01&)2S[3NK=$/:\/Y- Câu 7: 52V3 !/LWB! ( ) Xi z i− + = − "/01&)2!3)]/ ! ( ) ( ) ( ) X E G Ii z i i z i− + + − + − = + F e Cz z− + = X I C Cz z+ + = ĐỀ 4: Câu 1: X y x m x = − + + 52'Z3!'$@ !?9 ./01&)2/3, !4'3TKTQ&^ XP_&@f,>%3]U?&> !/01&)2 X Cx x k − + − = - Câu 2: 52?&1>3@') ! G Ey x x= − + − 52&)%(A&)BA ! %y x x= )4 [ ] De 52M: ! E %& x y x + = − Câu 3: "/01&)2 %& E%& G Cx x− + = "/01&)2 C x x+ − − = Câu 4 5HH/= ! C x I dx x + = + ∫ C X J x xdx π = − ∫ 5H8>H2/7&`&(4J06& y x x= − y x x= − - Câu 52K/N$OK,$O%!&3V&4$@4O9!@4 N$9NO9N9!-5H'H2[3&4/2K/N$O- Câu 6: 5)&?V&&!(>#!T+:,W'$@^@!06&7&8 x y z+ − = = − D8 x y z+ − = = L&)Q&8 8 g!3 ./01&)2/YL!8 &&(8 ./01&)2/cZ3!$&&(8 8 Câu 7: 52V3 !/LWB! ( ) E G F Xi z i i− − + = + "/01&)2!3)]/ ! ( ) ( ) ( ) X G Ei z i i z− + + = − Cz z− + = X F Cz z− − = ĐỀ 5: Câu 1: ax y x a − = − 52!'&)h&?&: !?!9 .//3, !4&!' !K+: X52'8 y x m= + <4!'/=> Câu 2: 52?&1>3@') ! % x y x = 52&)%(A&)BA ! Xf x x x= + )4 CD π 52M: ! ( ) %& EX - x x y − = − Câu 3: "/01&)2 ( ) ( ) %& %& x x x+ + + + = "A/01&)2 ( ) ( ) X x x x+ − + + > − Câu 4 5HH/= ! I -I x x dx= + ∫ C X J x xdx π = + ∫ 5H8>H2/7&`&(4J06& E y x= + @ y x= + Câu 523V&$OPK4Q&!-5)06&7&3V&&K($OP8& h=+ !23V&$OP%A,T'N! a OS = -5H'H2[3&4/ 2K/N$OP- Câu 6: 5)&?V&&!(>#!T+:,W!'$@C@C@O@@@ @ @ C ÷ ./01&)2/Y ⊥ +4-ij!'+@O@7&&- ./01&)2S[3N=O@?HQ& kg)H01& !S[3N (/Y ./01&)2S/7&Z3!!'$@O@ Câu 7: 52V3 !/L X i z i+ = − + "/01&)2!3)]/ ! X G - i z i i i− − + = + − + Cz z− + = X F Cz z− − = ĐỀ 6: Câu 1: y x x = − + ! P_&>%3]U&> !/01&)2 Cx x m− + = 5H8>H2/7&&(4J)* Câu 2: 52?&1>3@') ! y x x= − − − 52&)%(A&)BA ! X f x x x= + − )4 CD π Câu 3: "/01&)2 ( ) ( ) %& %& E x x− − − = "/01&)2 -I I X C x x+ − − + < Câu 45HH/= ! ( ) X % e I x xdx= + ∫ I C x dx J x = + ∫ Câu 52K/N$OPK,$OP%23V&4Q&!@4N$3V&&K (,$OP@4 SB a= 5H'H2K/N$OPU!- L&)Q&)3&'l !N%=S[3&4/2K/N$OP-5H ?HS[3,- Câu 6: 5)&?V&&!(>#!T+:,W' $@@C@O@@@^@@@P@^@@ ./01&)2/$O-N3,)!$OP%2L8> "#i233V&&K !'P)/+:W-./01&)28Z3!i 3V&&K(/$O ./01&)2S[3N&4/?L8>$OP Câu 7: "/01&)2!3)]//L ! ( ) ( ) ( ) E i z i i− + = − − + ( ) ( ) - - z i iz i i− + = + + 52:,)Q& ( ) x i x yi− = + ĐỀ 7: Câu 1: x y x + = + ! ./01&)2/3, !@/3,&&(06&7& CCey x= + 5H8>H2/7&&(4J)*#!T X52'8D,9:;<4!'/=>- Câu 2: 52?&1>3@') ! Xy x x= − 52&)%(A&)BA ! - x f x x e − = )m!?& [ ) CD+∞ Câu 3: "/01&)2 E %& %&x x + = − + "/01&)2 e- C C x x− + − = Câu 4 5HH/= ! % e e x I dx x − + = ∫ E % J x x dx= − ∫ 5H8>H2/7&&(4J Cx y− = @ x y+ = Câu 52%n&)*L&$O$ O K,$O%!&3V&=($O9$9!- o06&gO 4(S$ $ T&KQ&GC C - 5H'H2%n&)*K 52'H2[3&4/?%n&)* Câu 6: 5)&?V&&!(>#!T+:,W!' $^@X@@O@@^@^E@C@C/Y Cx y z+ − + = ./01&)2/$O- ./01&)2/cZ3!O@3V&&K(/Y ./01&)2S[3NZ3!$@O@K=lQ)/Y Câu 7: "/01&)2!3)]//L ! ( ) ( ) ( ) X F i z i i+ = − + − E X Cz z− + − = 52:,)Q& ( ) F x i x yi+ = − + . 5)&?V&&!(>#!T+:,W'$@X@ S/ 7 &Y Cx y z+ + − = ./01&)206& 7 &8Z3!$3V&&K(Y- 52#!T233V&&K. 5)&?V&&!(>#!T+:,WS/ 7 &Y E Cx y z+ − + = !' $C@C@X@ODCDC ./01&)206& 7 &8Z3!$3V&&K(Y- 52#!T233V&&K. + ∫ 5H8>H2/ 7 &`&(4J06& E y x= + @ y x= + Câu 523V&$OPK4Q&!-5)06& 7 &3V&&K($OP8& h=+