50 ir answer and explanation (gmac)

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50 IR answer and explanation (GMAC) Composed by: HuyNguyenKhac Page 1 1. CC + ROB: Attendees can save (110-70)*2=80$ (because the attendees are required 2 nights lodging) + In block: Attendees can save 720-620=100$ Answer: No FFNA: + ROB: Attendees can save (140-70)*2=140$ + In block: Attendees can save 325-75=50$ Answer: Yes HMHPA: + ROB: Attendees can save (104-79)*2=50$ (because the attendees are required 2nights lodging) + In block: Attendees can save 600-575=25$ Answer: Yes 2. Notice that - The question is asking whether the hotel would lose revenue if an attendee of any of the conferences used the ROB strategy. - If a room in the block is vacant, the conference organizers pay the hotel 25% of the block rate. Of course, if an attendee uses the ROB strategy, the hotel is still renting a room, but at a different rate. With the Asiawest Center we have three sponsor: RCD, QRTA, CDA. We only notice the sponsor that has the greatest difference between the bock rate and the lowest rate in the host hotel. It is RCD (or QRTA). If the attendee use ROB the hotel will have 185+0.25*195= 223$> 195$ > the hotel will not lose revenue. Answer is No 50 IR answer and explanation (GMAC) Composed by: HuyNguyenKhac Page 2 With Bardin Hotel the the bock rate and the lowest rate in the host hotel are the same. So easily the answer is No With Hilton we have 3 sponsors: CC, FFNA, PPOA. Take FFNA because it has the greatest difference between the bock rate and the lowest rate in the host hotel. If the attendee use ROB the hotel will have 70+0.25*140= 105$ <140$ > Answer is Yes 3. If the attendee employ ROB strategy, he or she will save : 2(X-Y) $. According to the paragraph, if the registration discount is at least half of the possible savings of the ROB or ROHH strategies, attendees will stay within the block, so the answer is = X-Y  Answer is C 4. Notice that the lowest rate for an available room in the city X on the same weekend is 65$. CC + ROHH: Attendees can save (110-65)*2=90$ (because the attendees are required 2 nights lodging) + In block: Attendees can save 720-620=100$ Answer: No FFNA: + ROHH: Attendees can save (140-65)*2=150$ + In block: Attendees can save 325-75=50$ Answer: Yes PPOA: 50 IR answer and explanation (GMAC) Composed by: HuyNguyenKhac Page 3 + ROHH: Attendees can save (105-65)*2=70$ (because the attendees are required 2nights lodging) + In block: Attendees can save 550-400=150$ Answer: No 5. Question 5 does not concern itself with the room rates in the table. Instead, it asks you to think about who is affected by the ROHH strategy that is, conference attendees staying outside the host hotel. So easily 5A &5C : No, 5B: Yes 6. We can deduce that the less different between the lowest rate in the host hotel and the lowest rate for an available room in the city X, the more likely the attendee will employ ROB strategy rather than ROHH strategy. In AMG this difference is 65- 65=0$, other sponsor the difference >0, so A is answer. 7. Consider 7A. The passage makes no connection between the (negative) correlation of stock share price and board prestige and underpricing , so nothing in that vein can be inferred. 7A is Not inferable. For 7B, check the table. Firestone East Africa's stock price slightly decreased on the first day, so in fact, it set its IPO price higher than it should have. 7B is Not inferable. 7C is answerable from the conclusion we drew in 7B. Firestone East Africa's IPO was not underpriced, so at least one firm did not have an underpriced IPO. 7C is Inferable. 8. Since board prestige was strongly negatively correlated with IPO stock share price, a company with a low IPO stock share price would likely have a board considered more prestigious than one with a higher IPO stock share price. Co-Operative 50 IR answer and explanation (GMAC) Composed by: HuyNguyenKhac Page 4 Bank's IPO stock share price was nearly double that of Safaricom, so it is inferable that Safaricom's board was considered more prestigious. 8A is Supported. While firm size was one of the variables the researchers considered, it was not one of the two that was discovered to have a strong negative correlation with IPO stock share price. Thus, given the limited information we have about the researchers' findings, nothing about firm size is inferable from IPO stock share price. 8B is Not supported. nvestor sentiment is one of the two variables that was discovered to have a strong negative correlation with IPO stock share price, so 8C is more complicated. If 8C is supported, we would expect that Kengen, with its better investor sentiment, would have a lower IPO stock share price than Scangroup or Eveready. But according to the table, Kengen had the higher IPO stock share price of the three. 8C is Not supported. 9. We can eliminate choice (A), which has nothing to do with board prestige. (B) is too broad for this question; while the researchers discover that some variables are not accurate predictors of IPO pricing, the reference to board prestige serves a narrower purpose. (C) is better: it acknowledges that board prestige is one of many variables, and specifies that it is one of the variables whose results were surprising. (D) is too narrow: the passage does more than simply mention board prestige. And (E) is too broad; while the passage cites correlations, it doesn't go into enough detail to "demonstrate" anything. (C) is correct. 10. The first statement is that there should be "no restrictions" on sports reporting. As in all parts of the GMAT Verbal section, extreme statements like this one are almost never supported. While the news organizations might prefer a world where this statement is true, it is clear that the sports association would not support it. 10A is Otherwise. 50 IR answer and explanation (GMAC) Composed by: HuyNguyenKhac Page 5 The second statement is more nuanced, with the phrase "adequately reported without broadcasting the event in its entirety." The sports association seems to believe so, since it wants to limit how much news organizations can publish, and news organizations would agree, since they have no wish to broadcast events in their entirety. 10B is Both accept. The final statement is more like the first in its stridency: "Any online activity benefits the association." The news organization might agree with that, though perhaps not so strongly, but the sports association, which is trying to limit online activities even though they may well increase interest in the sports, would not. 10C is Otherwise. 11. The first issue is not very clearly addressed in the passages. The sports organization does not seem to claim that online sports reporting does not generate interest, just that news organizations should pay for the privilege of publishing certain things. Since the association's perspective is unclear, 11A is Cannot infer disagreement. The second issue is more clear cut. The sports associations specifically take issue with news organizations posting live score updates. We don't know exactly how frequent they are, but for the association, they are too frequent. 11B is Disagree. The third issue is also one that the passages address. News organizations believe they should have free access to sporting events and the ability to publish whatever they like; the sports association wants to limit publication or revoke access. 11C is Disagree. 12. Choice (A) is irrelevant to the passage; neither side states a position about news consumers. (B) is the crux of the disagreement: consider the statement, "To charge news organizations or to place unnecessary conditions is to deny [them] their right to cover the news." (C) is also irrelevant: There is no mention of exclusivity in the news organizations' passage. (D) is not specifically addressed, and it is more likely that the news 50 IR answer and explanation (GMAC) Composed by: HuyNguyenKhac Page 6 organizations disagree that more live updates leads to lower attendance. Finally, (E) is a position held by the association, not by news organizations. Choice (B) is correct. 13. Table explanation: The height-for-age table has two variables: age (the independent variable) and height (the dependent variable). Thus, if we know a boy's age, we know the approximate likelihood that he is a certain height. Or if we know his height, we know approximately how tall he is relative to his age group. But the process doesn't work as well in reverse. If we know, for instance, that a boy is 93cm tall, we don't know very much about the likelihood that he is a certain age. Sure, he would be a very tall 2:0 year old, a fairly tall 2:3 year old, a slightly above average 2:6 year old, and so on, but the level of precision in this direction is much lower. Take a boy, age 3:9 (3 years old, 9 month), height is 105.8  we can see his percentile is 85 th . It means that with that heigh, the boy is taller than 85% the boy of that age. For the table weight-for-height, we have 2 variables: height ((the independent variable)) and weight (the dependent variable). Take a boy with the height is 105cm, the weight is 18kg. we can see that his percentile fall between the line of 85 th and 97 th percentile (approximately 90 th percentile). This mean that this boy is heavier than 90 percent of the boys who have the same height (105cm) We are given a boy's age, height, and weight. From there, we can find where his height falls in the distribution based on his age (a bit above the 85th percentile) and where his weight falls in the distribution based on his height (a bit above the 50th percentile). But 13A tries to infer a distribution based on his weight, which is not found in either of the tabs. We cannot infer anything based on his weight, so 13A is No. 50 IR answer and explanation (GMAC) Composed by: HuyNguyenKhac Page 7 13B is more straightforward. The 85th percentile for a boy aged 4:3 is 109.5cm, so if this boy is 110cm tall, he is above the 85th percentile. Put another way, fewer than 15% of boys at his age are taller. 13B is Yes. 13C asks you compare this boy to boys of a different age group. In the 5:0 group, the 50th percentile is 110cm, the same as this boy. Thus, this boy's height is indeed greater than or equal to half of the boys in the older age group. 13C is Yes. 14. 14A asks you to consider several age groups. The 50th percentile height distribution for the 3:3 age group is 98cm. Thus, if a boy is aged 3:3, there is a 50% chance that he is at least 98cm. If he is older, the probability is higher than he is at least 98cm. 14A is Yes. In 14B, you must look to the other tab. At 105cm tall, the 3rd percentile is approximately 14kg, meaning that there is a 3% chance that the boy weighs 14kg or less. If he is taller, the 3rd percentile is heavier, so the probability is less than 3%. 14B is Yes. 14C does not specify an age, but refers to the age-height table. Essentially, it claims that regardless of age, 114cm is the 85th percentile or higher. However, the 85th percentile of boys aged 5:0 is 114.8cm, so 114cm is below the 85th percentile. 14C is No. 15. Based on the discussion above about independent and dependent variables, we can quickly eliminate each of the first three choices. We don't have distributions of age based on height (choice (A)) it's the other way around. The same applies to (B) and (C). The final two choices are testable. Choice (D) says that his weight at 5:0 is 150% of his weight at 2:0. First, we need his height at the two ages. At 2:0, his 50th percentile height is 87.1cm; at 5:0, it is 110cm. The corresponding 50th percentile 50 IR answer and explanation (GMAC) Composed by: HuyNguyenKhac Page 8 weights are 12kg at 2:0 and 18kg at 5:0. 18kg is 150% of 12kg, so choice (D) is correct . 16. The prompt is the same as in question 13, but the statements are different. 13A asks you to look at the height-weight graph. A boy 110cm who weighs 19kg is above the 50th percentile (18kg) in weight but well below the 85th percentile (21kg). Thus, at least 15% of boys at this height weigh less than B in fact, more than half do. 16A is Yes. 16B takes us back to the age-height table. At age 4:3, 110cm falls just above the 85th percentile. 10% of 110 is 11, so any height between 99 (110-11) and 121 (110+11) is within 10% of B's height. 99cm is below the 15th percentile and 121cm is above the 97th percentile, so at least 82 percent of boys aged 4:3 have heights within 10% of B's height. 16B is Yes. In 16C, we compare B's height to the distribution of a different age group. If he were 4:0, his height of 110cm would fall about 1cm below the 97th percentile. The statement is the same as "B's height is at or above the 97th percentile." Since B's height is lower, 16C is No. 17. Question 17 is another general one. 17A is too strong to be supported by the data. Percentile tables tell us the likelihood that a boy of a certain age is above or below a certain height, not the probability that he is at an exact height. 17A is No. In 17B, we're asked to compare 81cm to the height distributions at every age. The lowest 3rd percentile height is 81.4cm, for boys aged 2:0. Thus, even at this lowest height distribution, 81cm is below the 3rd percentile, so any boy 81cm tall is shorter than at least 95% (97%, in fact) of boys his age. 17B is Yes. Finally, consider 17C. This statement reverses the independent/dependent variable relationship of the graphs. We don't know the weight distribution of boys at a certain age, so we can't infer that a boy of any height weights more than that many boys of age 2:6. 17C is No. 50 IR answer and explanation (GMAC) Composed by: HuyNguyenKhac Page 9 18. Same as question 15, easily elimilate A,B,C Choice (D) and (E ), we can evaluate. At age 2:0, his 97th percentile height is 92.9cm, and his 97th percentile weight is approximately 16kg. At age 5:0, his 97th percentile height is 118.7, and his 97th percentile weight is approximately 26kg. 26/16 is approximately 1 and 5/8, or 1.63, so we've gotten very close to 166%. Choice (D) is correct. 19. There are only three South American cities, and they had max temperatures of 29, 29, and 38. The mean must be between 29 and 38. The two Oceania cities had max temps of 25 and 29, for a mean between 25 and 29. Without doing any calculations, it is clear that the mean maximum temperature of the South American cities was greater than that for Oceania cities. 19A is Yes. 19B refers to the cities reporting "fine" weather. Use the sort function again, organizing by weather conditions to isolate the "fine" weather cities. There are seven such cities, and they reported max temperatures between 5 and 30. Thus, no city reporting fine weather had a max temp below 0. 19B is No. Sort again by continent to handle 19C. The minimum temperatures of the eight Asian cities are, in order: -3, -3, 3, 3, 21, 22, 24, 26. Since there is an even number of Asian cities, the median is the mean of the two middle numbers. The mean of 3 and 21 is 12, so 19C is Yes. 20. We can easily find out that the final score= ((exam1+exam2):2 +final exam):3  so 20A is No 20B is much easier, and it is made more so by the information in the prompt that there are 25 students. To find the median final score (not final exam score!) we need to put the final scores in order and identify the middle one. Use the sort function to get the final scores in ascending order, then count to find the 13th from 50 IR answer and explanation (GMAC) Composed by: HuyNguyenKhac Page 10 the top. (Better to know ahead of time that there are 25 students than to waste time counting yourself!) 13th from the top is Orlando, with a final score of 81.50. 20B is Yes . 20C is also more straightforward than 20A. Sort by "Year in Program" to find the 3rd-year students. There are six, and their Exam 1 scores vary from 51 to 91 at the extremes a range of 40. 20C is Yes. 21. 21A turns up a quirk of the table. Since "economic base" can contain multiple descriptions, sorting the column won't help. To isolate foraging populations, as we need to do for this question, we must find them ourselves. The populations that forage are Au (MI = 1), Hadza (MI = 0), Tsimane (MI = 7), and Yasawa (MI = 21). It is not entirely clear whether Yasawa should be included, since their economic base is "marine foraging," not "foraging," but it doesn't matter to the answer. Either way, all of these MI numbers are below the MI numbers for any other population in the table. 21A is Yes. 21B, by contrast, allows us to take advantage of the sort function. To identify the populations that both farm and work for wages, sort by "economic base," and then note the three relevant groups: Gusii, Isanga Village, and Maragoli. All three are sedentary, to answer the first part of the question. The five largest populations are easy to spot: They are the only five over 1,000 people. These three populations are among the five, so 21B is Yes. 21C asks us to compare ranges. To calculate range, find the difference between the lowest and highest numbers in a set. Of these 13 populations, the Mean MI varies from as low as 0 to as high as 82, for a range of 82. The Mean WR is as low as 0 and as high as 100, for a range of 100. Thus, the range in MI is less than the range in WR, and 21C is Yes. 22. [...]... A Composed by: HuyNguyenKhac Page 16 50 IR answer and explanation (GMAC) 35 The passage does not mention about the presence of manganese in the environment so A and B do not relate Because the penetration of manganese is not mentioned in the passage, C and E do not relate D is True because we know from the passage that rock varnish in extreme cold consists only iron If the temperatures on rocks in... v0t  at 2 2 T=10s and s=125m we have v10  v0  10a 1 125  10v0  102 a  10v0  50a 2 Make the table v0 v10 5 20 18 … 20 … 36 … 72 … So 44A is A, 44B is C 45 At first the journalist think that the the volcanic eruptions lead to the end of Triassic But then he suggest that volcanic eruptions is the indirect cause This Composed by: HuyNguyenKhac Page 21 50 IR answer and explanation (GMAC) means that... audience 49B is E Composed by: HuyNguyenKhac Page 23 50 IR answer and explanation (GMAC) 50 The conclusion is that the radio advertising has not improved mattress Answer that helpful to test the consultant’s claim will affect the this conclusion Make the table for all answer choice Because the conclusion is about radio advertising, newspaper advertising and television advertising do not relate to test... the answer for 29A is A Strongly positive Composed by: HuyNguyenKhac Page 14 50 IR answer and explanation (GMAC) There are 10 babies whose weight is less than 3.5 kg, there are 04 babies of group A whose weight is less than 3.5 kg So If a baby with weight less than 3.5 kg were selected at random, the probability that the baby would be a aprt of Group A is 4/10=0.4 29B is B 30 The ABC cars line and. .. least 1 hour but less than 2 hours, so The number of respondents who exercised on average less than one half hour per day during the week is between 5 and 8 inclusive 26 Composed by: HuyNguyenKhac Page 12 50 IR answer and explanation (GMAC) Children and teenagers account for (20+25)=45% of the population Seniors account for 17% of the population so The census indicates that 45/17=2.65 times as many... can see that when the number of floors is smaller than 70 (the red circles line below the 70 horizontal), the mean height per floor is big (more than 5m/floor) But when the Composed by: HuyNguyenKhac Page 13 50 IR answer and explanation (GMAC) number of floors is greater than 70, the mean height per floor is small The higher of the red circles, the lower of the black squares So 27B is A Strong negative... Mountains area of Antarctica consists only of limonite so F is False 36 There are 512 players participated in the first round so there are 512/2=256 teams Make the table Team remaining Rounds 256 1 128 2 64 3 32 4 16 5 8 6 4 7 2 8 Composed by: HuyNguyenKhac Page 17 50 IR answer and explanation (GMAC) So the 36A is C, 36B is A 37 From the passage we know that the increase in phytoplankton (food of sea star)... reviewer 40A is D Adiliah among reviewer, the same as 40A so 40B is D 41 Composed by: HuyNguyenKhac Page 19 50 IR answer and explanation (GMAC) Because the thin-walled pottery is more prone to breaking during transport, it is likely to be used by group who is sedentary rather than nomadic So 41A is A and 41B is C The stimulus does not mention anything about the thick-walled pots, so we do not know about.. .50 IR answer and explanation (GMAC) Sort the table by Cooked (Yes/No) we can see the median amount of protein of uncooked vegetables is 1 (1,1,1,1,3), the median of amount of protein of cooked vegetables is 3 (2,2,2,3,3,3,5,5,5,5) so 22A is Yes Sort the table by Carbonhydrate we can see the amount of carbonhydrate per serving of Cooked Corn is 32 and the median amount of carbonhydrate... reprimand would be absent for x days, with 4  y 3  x  4 but we have 2 answers satisfied??? Employee who qualified for a written reprimand would be absent for y days, with 4  y but we have 2 answers satisfied??? 49 Notice that the answer is asked with the conditions that there is no other alternatives listed Clearly, obtaining public funding to double the spending on stage productions and expanding . is 110cm. The corresponding 50th percentile 50 IR answer and explanation (GMAC) Composed by: HuyNguyenKhac Page 8 weights are 12kg at 2:0 and 18kg at 5:0. 18kg is 150% of 12kg, so choice (D). hour per day during the week is between 5 and 8 inclusive. 26. 50 IR answer and explanation (GMAC) Composed by: HuyNguyenKhac Page 13 Children and teenagers account for (20+25)=45% of the. boys of age 2:6. 17C is No. 50 IR answer and explanation (GMAC) Composed by: HuyNguyenKhac Page 9 18. Same as question 15, easily elimilate A,B,C Choice (D) and (E ), we can evaluate. At age