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Hindawi Publishing Corporation Advances in Difference Equations Volume 2009, Article ID 143175, 14 pages doi:10.1155/2009/143175 ResearchArticleOntheSpectrumofAlmostPeriodicSolutionofSecond-OrderNeutralDelayDifferentialEquationswithPiecewiseConstantof Argument Li Wang and Chuanyi Zhang Department of Mathematics, Harbin Institute of Technology, Harbin 150001, China Correspondence should be addressed to Li Wang, wanglimath@yahoo.com.cn Received 16 December 2008; Accepted 10 April 2009 Recommended by Ondrej Dosly Thespectrum containment ofalmostperiodicsolutionofsecond-orderneutraldelay differential equationswithpiecewiseconstantof argument EPCA, for short ofthe form xtpxt − 1 qx2t 1/2 ft is considered. The main result obtained in this paper is different from that given by some authors for ordinary differential equations ODE, for short and clearly shows the differences between ODE and EPCA. Moreover, it is also different from that given for equation xtpxt − 1 qxt ft because ofthe difference between t and 2t 1/2. Copyright q 2009 L. Wang and C. Zhang. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited. 1. Introduction and Some Preliminaries Differential equationswithpiecewiseconstant argument, which were firstly considered by Cooke and Wiener 1 and Shah and Wiener 2, combine properties of both differential and difference equations and usually describe hybrid dynamical systems and have applications in certain biomedical models in the work of Busenberg and Cooke 3. Over the years, more attention has been paid to the existence, uniqueness, and spectrum containment ofalmostperiodic solutions of this type ofequations see, e.g., 4–12 and reference there in. If g 1 t and g 2 t are almost periodic, then the module containment property modg 1 ⊂ modg 2 can be characterized in several ways see 13–16. For periodic function this inclusion just means that the minimal period of g 1 t is a multiple ofthe minimal period of g 2 t. Some properties of basic frequencies thebaseofspectrum were discussed for almostperiodic functions by Cartwright. In 17, Cartwright compared basic frequencies the base of spectrum ofalmostperiodic differential equations ODE ˙x ψx, t, x ∈ R n ,with those of its unique almostperiodic solution. For scalar equation, n 1, Cartwright’s results in 17 implied that the number of basic frequencies of ˙x ψx, t,x∈ R, is the same as that of basic frequencies of its unique solution. 2 Advances in Difference EquationsThespectrum containment ofalmostperiodicsolutionof equation xtpxt − 1 qxt ft was studied in 9, 10. Up to now, there have been no papers concerning thespectrum containment ofalmostperiodicsolutionof equation xtpxt − 1 qx 2 t 1 2 f t , 1.1 where · denotes the greatest integer function, p, q are nonzero real constants, |p| / 1, q / − 2p 2 1,andft is almost periodic. In this paper, we investigate the existence, uniqueness, and spectrum containment ofalmostperiodic solutions of 1.1. T he main result obtained in this paper is different from that given in 17 for ordinary differential equations ODE, for short. This clearly shows differences between ODE and EPCA. Moreover, it is also different from that given in 9, 10 for equation xtpxt − 1 qxt ft. This is due to the difference between t and 2t 1/2. As well known, both solutions of 1.1 and equation xtpxt − 1 qxt ft can be constructed by the solutions of corresponding difference equations. However, noticing the difference b etween t and 2t 1/2, thesolutionof difference equation corresponding to the latter can be obtained directly see 4, while thesolution {x n } of difference equation corresponding to the former i.e., 1.1 cannot be obtained directly. In fact, {x n } consists of two parts: {x 2n } and {x 2n1 }. We will first obtain {x 2n } by solving a difference equation and then obtain {x 2n1 } from {x 2n }. Similar technology can be seen in 8. A detailed account will be given in Section 2. Now, We give some preliminary notions, definitions, and theorem. Throughout this paper Z, R,andC denote the sets of integers, real, and complex numbers, respectively. The following preliminaries can be found in the books, for example, 13–16. Definition 1.1. 1 AsubsetP of R is said to be relatively dense in R if there exists a number p>0 such that P ∩t, t p / ∅ for all t ∈ R. 2 A continuous function f : R → R is called almostperiodic abbreviated as APR if the -translation set of f T f, τ ∈ R : f t τ − f t <, ∀t ∈ R 1.2 is relatively dense for each >0. Definition 1.2. Let f be a bounded continuous function. If the limit lim T →∞ 1 2T T −T f t dt 1.3 exists, then we call the limit mean of f and denote it by Mf. If f ∈APR, then the limit lim T →∞ 1 2T Ts −Ts f t dt 1.4 exists uniformly with respect to s ∈ R. Furthermore, the limit is independent of s. Advances in Difference Equations 3 For any λ ∈ R and f ∈APR since the function fe −iλ· is in APR, the mean exists for this function. We write a λ; f M fe −iλ· , 1.5 then there exists at most a countable set of λ’s for which aλ; f / 0. The set Λ f λ : a λ; f / 0 1.6 is called the frequency set or spectrum of f. It is clear that if ft n k1 c k e iλ k t , then aλ; fc k if λ λ k , for some k 1, ,n;andaλ; f0ifλ / λ k , for any k 1, ,n. Thus, Λ f {λ k ,k 1, ,n}. Members of Λ f are called the Fourier exponents of f,andaλ; f’s are called the Fourier coefficients of f. Obviously, Λ f is countable. Let Λ f {λ k } and A k aλ k ; f.Thusf can associate a Fourier series: f t ∼ ∞ k1 A k e iλ k t . 1.7 The Approximation Theorem Let f ∈APR and Λ f {λ k }. Then for any >0 there exists a sequence {σ }of trigonometric polynomials σ t n k1 b k, e iλ k t 1.8 such that σ − f≤, 1.9 where b k, is the product of aλ k ; f and certain positive number depending on and λ k and lim →0 b k, aλ k ; f. Definition 1.3. 1 For a sequence {gn : n ∈ Z}, define gn,gnp {gn, ,gn p} and call it sequence interval with length p ∈ Z.AsubsetP of Z is said to be relatively dense in Z if there exists a positive integer p such that P ∩n, n p / ∅ for all n ∈ Z. 2 A bounded sequence g : Z → R is called an almostperiodic sequence abbreviated as APSR if the -translation set of g T g, τ ∈ Z : g n τ − g n <, ∀n ∈ Z 1.10 is relatively dense for each >0. 4 Advances in Difference Equations For an almostperiodic sequence {gn}, it follows from the lemma in 13 that a z; g lim N →∞ 1 2N N k−N z −k g k , ∀z ∈ S 1 { z ∈ C : | z | 1 } 1.11 exists. The set σ b g z : a z; g / 0,z∈ S 1 1.12 is called the Bohr spectrumof {gn}. Obviously, for almostperiodic sequence gn m k1 r k z n k , az; gr k if z z k , for some k 1, ,m; az; g0ifz / z k , for any k 1, ,m. So, σ b g{z k ,k 1, ,m}. 2. The Statement of Main Theorem We begin this section with a definition ofthesolutionof 1.1. Definition 2.1. A continuous function x : R → R is called a solutionof 1.1 if the following conditions are satisfied: i xt satisfies 1.1 for t ∈ R, t / n ∈ Z; ii the one-sided second-order derivatives xtpxt − 1 exist at n, n ∈ Z. In 8, the authors pointed out that if xt is a solutionof 1.1, then xtpxt − 1 are continuous at t ∈ R, which guarantees the uniqueness ofsolutionof 1.1 and cannot be omitted. To study thespectrumofalmostperiodicsolutionof 1.1, we firstly study thesolutionof 1.1.Let f 1 n n1 n s n f σ dσ ds, f 2 n n−1 n s n f σ dσ ds, h n f 1 n f 2 n . 2.1 Suppose that xt is a solutionof 1.1, then xtpxt − 1 exist and are continuous everywhere on R. By a process of integrating 1.1 two times in t ∈ 2n − 1, 2n 1 or t ∈ 2n, 2n 2 as in 7, 8, 18, we can easily get x 2n 1 p − 2 − q x 2n 1 − 2p x 2n − 1 px 2n − 2 h 2n , 1 − q 2 x 2n 2 p − 2 x 2n 1 1 − 2p − q 2 x 2n px 2n − 1 h 2n1 . 2.2 These lead to the difference equations px 2n−2 1 − 2p x 2n−1 p − 2 − q x 2n x 2n1 h 2n , 2.3 px 2n−1 1 − 2p − q 2 x 2n p − 2 x 2n1 1 − q 2 x 2n2 h 2n1 . 2.4 Advances in Difference Equations 5 Suppose that |p| / 1. First, multiply the two sides of 2.3 and 2.4 by p and 2p − 1, respectively, then add the resulting equations to get x 2n1 1 2p − 1 2 ph 2n − p p − 2 − q x 2n − p 2 x 2n−2 2p − 1 h 2n1 − 1 2p − 1 2 2p − 1 1 − q 2 x 2n2 2p − 1 1 − 2p − q 2 x 2n . 2.5 Similarly, one gets x 2n−1 1 2p − 1 2 2 − p h 2n − 2 − p p − 2 − q x 2n − 2 − p px 2n−2 1 2p − 1 2 h 2n1 − 1 − q 2 x 2n2 − 1 − 2p − q 2 x 2n . 2.6 Replacing 2n by 2n 2 in 2.6 and comparing with 2.5,onegets 1 − q 2 x 2n4 − p 2 − 2pq 3q 2 x 2n2 2p 2 2pq − q 2 1 x 2n − p 2 x 2n−2 h 2n3 2 − p h 2n2 1 − 2p h 2n1 − ph 2n . 2.7 The corresponding homogeneous equation is 1 − q 2 x 2n4 − p 2 − 2pq 3q 2 x 2n2 2p 2 2pq − q 2 1 x 2n − p 2 x 2n−2 0. 2.8 We can seek the particular solution as x 2n ξ n for this homogeneous difference equation. At this time, ξ will satisfy the following equation: p 1 ξ 1 − q 2 ξ 3 − p 2 − 2pq 3q 2 ξ 2 2p 2 2pq − q 2 1 ξ − p 2 0. 2.9 From the analysis above one sees that if xt is a solutionof 1.1 and |p| / 1, then one gets 2.3 and 2.4. In fact, a solutionof 1.1 is constructed by the common solution {x n } of 2.3 and 2.4. Moreover, it is clear that {x n } consists of two parts: {x 2n } and {x 2n1 }. {x 2n } can be obtained by solving 2.7,and{x 2n1 } can be obtained by substituting {x 2n } into 2.5 or 2.6. Without loss of generality, we consider 2.5 only. These will be shown in Lemmas 2.5 and 2.6. Lemma 2.2. If f ∈APR,then{f i n }, {h n }∈APSR, i 1, 2. Lemma 2.3. Suppose that |p| / 1 and q / −2p 2 1, then the roots of polynomial p 1 ξ are of moduli different from 1. 6 Advances in Difference Equations Lemma 2.4. Suppose that X is a Banach space, LX denotes the set of bounded linear operators from X to X, A ∈LX, and A < 1,thenId −A is bounded invertible and Id −A −1 ∞ n0 A n , I −A −1 ≤ 1 1 − A , 2.10 where A 0 Id, and Id is an identical operator. The proofs of Lemmas 2.2, 2.3,and2.4 are elementary, and we omit the details. Lemma 2.5. Suppose that |p| / 1 and q / − 2p 2 1,then2.7 has a unique solution {x 2n }∈ APSR. Proof. As the proof of Theorem 9 in 8, define A : X → X by A{x 2n } {x 2n2 }, where X is the Banach space consisting of all bounded sequences {x n } in C with {x n } sup n∈Z |x n |. It follows from Lemmas 2.2–2.4 that 2.7 has a unique solution {x 2n } PA −1 {h 2n5 2 − ph 2n4 1 − 2ph 2n3 − ph 2n2 }∈APSR. Substituting x 2n into 2.5,weobtainx 2n1 . Easily, we can get {x 2n1 }∈APSR. Consequently, the common solution {x n } of 2.3 and 2.4 can be obtained. Furthermore, we have that {x n }∈APSR is unique. Lemma 2.6. Suppose that |p| / 1 and q / − 2p 2 1, f ∈APR.Let{x n }∈APSR be the common solutionof 2.3 and 2.4.Then1.1 has a unique solution xt ∈APR such that xnx n ,n∈ Z. In this case thesolution xt is given for t ∈ R by x t ⎧ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎩ ∞ k0 −p k ω t − k , p < 1, − ∞ k1 −p −k ω t k , p > 1, 2.11 where ω t x 2n px 2n−1 y 2n t − 2n qx 2n t − 2n 2 2 t 2n s 2n f σ dσ ds, y 2n x 2n1 p − 1 − q 2 x 2n − px 2n−1 − f 1 2n , 2.12 for t ∈ 2n − 1, 2n 1,n∈ Z; {y 2n }∈APSR,ωt ∈APR. The proof is easy, we omit the details. Since thealmostperiodicsolution xt of 1.1 is constructed by the common almostperiodicsolutionof 2.3 and 2.4, easily, we have that xtpxt − 1 are continuous at t ∈ R. It must be pointed out that in many works only one of 2.3 and 2.4 is considered while seeking the unique almostperiodicsolutionof 1.1,and it is not true for the continuity of xtpxt − 1 on R, consequently, it is not true for the uniqueness see 8. Advances in Difference Equations 7 The expressions of x 2n ,x 2n1 ,y 2n ,ωt, and xt are important in the process of studying thespectrum containment ofthealmostperiodicsolutionof 1.1. Before giving the main theorem, we list the following assumptions which will be used later. H 1 |p| / 1, q / −2p 2 1. H 2 kπ / ∈Λ f , for all k ∈ Z. H 3 If λ ∈ Λ f , then λ kπ / ∈Λ f ,0 / k ∈ Z. Our result can be formulated as follows. Main Theorem Let f ∈APR and H 1 be satisfied. Then 1.1 has a unique almostperiodicsolution xt and Λ x ⊂ Λ f {kπ : k ∈ Z}. Additionally, if H 2 and H 3 are also satisfied, then Λ f {kπ : k ∈ Z}⊂Λ x , that is, the following spectrum relation Λ x Λ f {kπ : k ∈ Z} holds, where the sum of sets A and B is defined as A B {a b : a ∈ A, b ∈ B}. We postpone the proof of this theorem to the next section. 3. The Proof of Main Theorem To show the Main Theorem, we need some more lemmas. Lemma 3.1. Let f ∈APR,thenσ b f i 2n ,σ b f i 2n1 ,σ b h 2n ,σ b h 2n1 ⊂ e i2Λ f , i 1, 2.If(H 3 )is satisfied, then σ b f i 2n σ b f i 2n1 e i2Λ f , i 1, 2. Furthermore, if (H 3 ) and (H 2 ) are both satisfied, then σ b h 2n σ b h 2n1 e i2Λ f . Proof. Since f ∈APR,byLemma 2.2 we know that {f i 2n }, {f i 2n1 }, {h 2n }, {h 2n1 }∈APSR, i 1, 2. It follows from The Approximation Theorem that, for any m>0,m ∈ Z, there exists P m t nm k1 b k,m e iλ k t ,λ k ∈ Λ f such that P m −f≤1/m, where lim m →∞ b k,m aλ k ; f,and we can assume that b k,m e iλ k t and b k,m e −iλ k t appear together in the trigonometric polynomial P m t. Define Q 1 m,2n 2n1 2n s 2n P m σ dσ ds nm k1 c 1 k,m e i2λ k n , Q 2 m,2n 2n−1 2n s 2n P m σ dσ ds nm k1 c 2 k,m e i2λ k n , Q 1 m,2n1 2n2 2n1 s 2n1 P m σ dσ ds nm k1 c 1 k,m e iλ k e i2λ k n , Q 2 m,2n1 2n 2n1 s 2n1 P m σ dσ ds nm k1 c 2 k,m e iλ k e i2λ k n , 3.1 8 Advances in Difference Equations where c 1 k,m ⎧ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎩ b k,m 2 ,λ k 0, −b k,m e iλ k − 1 − iλ k λ 2 k ,λ k / 0, c 2 k,m ⎧ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎩ b k,m 2 ,λ k 0, −b k,m e −iλ k − 1 iλ k λ 2 k ,λ k / 0. 3.2 Obviously, σ b Q i m,2n ,σ b Q i m,2n1 ⊂ e i2Λ f , i 1, 2, for all m ∈ Z. For any z ∈ S 1 , az; f i 2n lim m →∞ az; Q i m,2n , az; f i 2n1 lim m →∞ az; Q i m,2n1 , thus, we have σ b f i 2n ,σ b f i 2n1 ⊂ e i2Λ f , i 1, 2. Since h 2n f 1 2n f 2 2n and h 2n1 f 1 2n1 f 2 2n1 , for all n ∈ Z. For all z ∈ S 1 , we have a z; h 2n a z; f 1 2n a z; f 2 2n , 3.3 a z; h 2n1 a z; f 1 2n1 a z; f 2 2n1 . 3.4 Thus, σ b f i 2n ⊂ e i2Λ f and σ b f i 2n1 ⊂ e i2Λ f imply σ b h 2n ⊂ e i2Λ f and σ b h 2n1 ⊂ e i2Λ f , respectively, i 1, 2. If H 3 is satisfied, then for any λ j ∈ Λ f , we have a e i2λ j ; f 1 2n lim m →∞ a e i2λ j ; Q 1 m,2n lim m →∞ c 1 j,m ⎧ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎩ a λ j ; f 2 ,λ j 0, −a λ j ; f e iλ j − 1 − iλ j λ 2 j ,λ j / 0, a e i2λ j ; f 2 2n lim m →∞ a e i2λ j ; Q 2 m,2n lim m →∞ c 2 j,m ⎧ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎩ a λ j ; f 2 ,λ j 0, −a λ j ; f e −iλ j − 1 iλ j λ 2 j ,λ j / 0, a e i2λ j ; f 1 2n1 lim m →∞ a e i2λ j ; Q 1 m,2n1 lim m →∞ e iλ j c 1 j,m , a e i2λ j ; f 2 2n1 lim m →∞ a e i2λ j ; Q 2 m,2n1 lim m →∞ e iλ j c 2 j,m . 3.5 Easily, we have ae i2λ j ; f i 2n / 0andae i2λ j ; f i 2n1 / 0, that is, e i2λ j ⊂ σ b f i 2n ,e i2λ j ⊂ σ b f i 2n1 , i 1, 2. By the arbitrariness of λ j ,wegete i2Λ f ⊂ σ b f i 2n and e i2Λ f ⊂ σ b f i 2n1 .So,e i2Λ f σ b f i 2n σ b f i 2n1 ,i 1, 2. Advances in Difference Equations 9 If H 3 and H 2 are both satisfied, suppose that there exists z 0 e i2λ j ∈ e i2Λ f such that az 0 ; h 2n 0. H 2 implies e iλ j / ± 1. Moreover, since H 3 holds, we have az 0 ; f i 2n / 0,i 1, 2. az 0 ; h 2n az 0 ; f 1 2n az 0 ; f 2 2n leads to e iλ j 1, which contradicts with e iλ j / ± 1. So, e i2Λ f ⊂ σ b h 2n . Noticing that σ b h 2n ⊂ e i2Λ f , we have e i2Λ f σ b h 2n . Similarly, we can get e i2Λ f σ b h 2n1 . The proof is completed. Lemma 3.2. Suppose that (H 1 ) is satisfied, then σ b x 2n ⊂ e i2Λ f .If(H 1 ), (H 2 ), and (H 3 )areall satisfied, then σ b x 2n e i2Λ f ,where{x 2n } is the unique almostperiodic sequence solutionof 2.7. Proof. Since H 1 holds, from Lemma 2.5 we know {x 2n } p 1 A −1 {g n1 }∈APSR, where g n h 2n3 2 − ph 2n2 1 − 2ph 2n1 − ph 2n , for all n ∈ Z. For any z ∈ S 1 , it follows from Lemma 2.3 that p 1 z / 0. Noticing the expressions of {x 2n } and g n ,weobtain za z; g n p 1 z a z; x 2n , 3.6 a z; g n z 1 − 2p a z; h 2n1 2z − pz − p a z; h 2n . 3.7 Those equalities and Lemma 3.1 imply that σ b x 2n σ b g n and σ b x 2n ⊂ e i2Λ f , when H 1 is satisfied. If H 1 , H 2 ,andH 3 are all satisfied, we only need to prove e i2Λ f ⊂ σ b g n . Suppose that there exists z 0 e i2λ j ∈ e i2Λ f , obviously, e iλ j / ± 1, such that az 0 ; g n 0. From Lemma 3.1 , az 0 ; h 2n / 0,az 0 ; h 2n1 / 0. Thus, 0 z 0 1−2paz 0 ; h 2n1 2z 0 −pz 0 − paz 0 ; h 2n , that is, e i2λ j 1−2pe iλ j pe i2λ j −2e i2λ j p, which leads to e iλ j p. This contradicts with H 1 .Thus,e i2Λ f ⊂ σ b g n ,thatis,e i2Λ f ⊂ σ b x 2n . Noticing that σ b x 2n ⊂ e i2Λ f ,so, e i2Λ f σ b x 2n . The proof is completed. As mentioned above, the common almostperiodic sequence solution {x n } of 2.3 and 2.4 consists of two parts: {x 2n }and {x 2n1 }, where {x 2n }∈APSR is the unique solutionof 2.7,and{x 2n1 } is obtained by substituting {x 2n } into 2.5. Obviously, {x 2n1 }∈APSR. In the following, we give thespectrum containment of {x 2n1 }. Lemma 3.3. Suppose t hat ( H 1 ) is satisfied, then σ b x 2n1 ⊂ e i2Λ f .If(H 1 ), (H 2 ), and (H 3 )areall satisfied, then σ b x 2n1 e i2Λ f . Proof. Since {x 2n }, {h 2n }, {h 2n1 }∈APSR, {x 2n1 }∈APSR. Noticing the expression of x 2n1 , for any z ∈ S 1 , we have 2 p − 1 2 a z, x 2n1 pa z, h 2n 2p − 1 a z, h 2n1 − z −1 p 2 z a z, x 2n , 3.8 where p 2 z2p − 11 − q/2z 2 −3p 2 2p − 1 − 2pq q/2z p 2 .IfH 1 is satisfied, it follows from Lemmas 3.1 and 3.2 that σ b x 2n1 ⊂ e i2Λ f . If H 1 , H 2 ,andH 3 are all satisfied, supposing there exists z 0 e i2λ j ∈ e i2Λ f , obviously, e iλ j / ± 1, such that az 0 ; x 2n1 0, that is, z −1 0 p 2 z 0 az 0 ,x 2n paz 0 ,h 2n 2p −1az 0 ,h 2n1 . Noticing 3.3–3.7, this equality is equivalent to p 2 e i2λ j e i2λ j 1 −2p − p 1 e i2λ j 2p −1e iλ j p 2 e i2λ j 2e i2λ j −pe i2λ j −p − pp 1 e i2λ j 0, that is, q −2e i3λ j 2p −4 − 2qe i2λ j 4pq−2e iλ j 2p 0. Considering equation q−2x 3 2p−4−2qx 2 4pq−2x2p 0, its roots are x 1 , x 3 ,andx 2 , obviously, x i / ±1, i 1, 2, 3. We claim that |x i | / 1, i 1, 2, 3, that is, this equation has no imaginary root. Otherwise, suppose that |x 1 | 1andx 3 x 1 , then by the relationship between roots and coefficient of three-order equation, we know q 0, which 10 Advances in Difference Equations leads to a contradiction. Thus q − 2e i3λ j 2p − 4 − 2qe i2λ j 4p q − 2e iλ j 2p / 0; this contradiction shows e i2Λ f ⊂ σ b x 2n1 . Noticing that σ b x 2n1 ⊂ e i2Λ f ,thus,σ b x 2n1 e i2Λ f . The proof is completed. Lemma 3.4. Suppose that (H 1 ) is satisfied, then σ b y 2n ⊂ e i2Λ f .If(H 1 ), (H 2 ), and (H 3 )areall satisfied, then σ b y 2n e i2Λ f ,where{y 2n } is defined in Lemma 2.6. Proof. From Lemma 2.6, we have y 2n x 2n1 p − 1 − q/2x 2n − px 2n−1 − f 1 2n , for all n ∈ Z. For any z ∈ S 1 a z, y 2n 1 − pz −1 a z, x 2n1 p − 1 − q 2 a z, x 2n − a z, f 1 2n . 3.9 Since H 1 holds, it follows from Lemmas 3.1–3.3 that we have σ b y 2n ⊂ e i2Λ f . If H 1 , H 2 ,andH 3 are all satisfied, supposing there exists z 0 e i2λ j ∈ e i2Λ f such that az 0 ; y 2n 0, it follows from H 2 that e iλ j / ± 1. Notice that 3.3–3.8, az 0 ; y 2n 0 is equivalent to pz 0 −paz 0 ,h 2n z 0 −p2p −1az 0 ,h 2n1 −2p − 1 2 z 0 az 0 ,f 1 2n p −1− q/22p − 1 2 z 2 0 −z 0 −pp 2 z 0 p 1 z 0 −1 z 0 1 −2paz 0 ,h 2n1 2z 0 −pz 0 −paz 0 ,h 2n 0. This equality is equivalent to e iλ j − 1 − iλ j e iλ j e −iλ j − 2p 1 e i2λ j −1 1 − q/2e i6λ j 1 q/2e i5λ j pq − p 2 − 1 − 3q/2e i4λ j − p 2 1 q/2e i3λ j p 2 pqe i2λ j p 2 e iλ j . Since λ j ∈ R,thatis,λ j λ j , this leads to e −i5λ j e iλ j − 1 2 e iλ j 1 2 e i2λ j 1−pe i4λ j p 2 1 − 2p − q/2e i3λ j 2p 2 − 2p 2 qe i2λ j p 2 1 − 2p − q/2e iλ j − p0. We firstly claim that the equation −px 4 p 2 1 − 2p − q/2x 3 2p 2 − 2p 2 qx 2 p 2 1 − 2p − q/2x − p 0 has no imaginary root, that is, equations x 2 a/2 − a 2 /4 − b 2x 1 − √ 1 − a 0and x 2 a/2 a 2 /4 − b 2x 1 √ 1 − a 0 both have no imaginary roots, where a q/2 − 1−p 2 2p/p, b 2p −q −2−2p 2 /p. If these two equations have imaginary roots, then a 1, b 4 −4p 1/p. Since p / 0, |p| / 1, then b<−4orb>12. If the first equation has imaginary roots, then −4 <b≤ 9/4, which contradicts with b<−4orb>12. If the second equation has imaginary roots, then 0 <b≤ 9/4, which also contradicts with b<−4orb> 12. The claim follows. Thus −pe i4λ j p 2 1−2p−q/2e i3λ j 2p 2 −2p2qe i2λ j p 2 1−2p−q/2e iλ j −p / 0, and e iλ j ±i. Substituting e iλ j ±i into e iλ j −1 −iλ j e iλ j e −iλ j −2p 1 e i2λ j −1 1 −q/2e i6λ j 1q/2e i5λ j pq−p 2 −1−3q/2e i4λ j −p 2 1q/2e i3λ j p 2 pqe i2λ j p 2 e iλ j ,wegetλ j 0. This is impossible. Thus, for any z 0 e i2λ j ∈ e i2Λ f , we have az 0 ; y 2n / 0, that is, e i2Λ f ⊂ σ b y 2n . Noticing that σ b y 2n ⊂ e i2Λ f , we have σ b y 2n e i2Λ f . The proof has finished. In Lemma 2.6, we have given the expression ofthealmostperiodicsolutionof 1.1 explicitly by a known function ω. This brings more convenience to study thespectrum containment ofalmostperiodicsolutionof 1.1. Now, we are in the position to show the Main Theorem. The proof of Main Theorem Since H 1 is satisfied, by Lemma 2.6, 1.1 has a unique almostperiodicsolution xt satisfying xtpxt−1ωt. Thus, for any λ ∈ R, we have aλ; ωt 1pe −iλ aλ; xt. Since H 1 holds, then Λ x Λ ω . We only need to prove Λ ω ⊂ Λ f {kπ, k ∈ Z} when H 1 is satisfied, and Λ f {kπ, k ∈ Z} Λ ω when H 1 –H 3 are all satisfied. [...]... 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Advances in Difference Equations 12 R. Yuan, On the spectrum of almost periodic solution of second-order differential equations with piecewise constant argument,” Nonlinear Analysis: Theory, Methods. to: On the spectrum of almost periodic solution of second order scalar functional differential equations with piecewise constant argument”,” Journal of Mathematical Analysis and Applications,