Ôn thi Thí nghiệm vật lí HCMUT

20 19 0
Ôn thi Thí nghiệm vật lí HCMUT

Đang tải... (xem toàn văn)

Tài liệu hạn chế xem trước, để xem đầy đủ mời bạn chọn Tải xuống

Thông tin tài liệu

Tổng hợp công thức, cách trình bày báo cáo để ôn thi cuối kì môn Thí nghiệm vật lí HCMUT. Từ bài báo cáo số 1 đến bài số 9 ( trừ bài 4 làm tại nhà không thi ). Nếu có nhu cầu về bài báo cáo số 4, có thể liên hệ email luongngoc1123gmail.com. Cảm ơn bạn đã quan tâm đến tài liệu này.

Dot vo vat doing TO THE TRENH # ① whatbhi long M va f MEHIEM: V, khihing ring dwor ein bang: I(kg/m3) = kep 150 long ding bang this h Do s loin kick the to BÀI thetich ME: TOM TATIY I cud mm ngoi D, ding kinh o, docow the rich aid kha true ring: (CCX 0,02mm): dng kink = · 4,(D2 v = cam · & The · kink cavien bi = - brg the kep 150mm (CX (CX 0,02 g) = khinhisng Can 0,02mm) Do lin = thebangcom kythat200g(CCX 0,02g) KHAI TRIEN SAISO: ea vien by m VE COMETHOC kni long ring: * rich knowtru * The = Am + = = = rng: IDgAd a = LD-dashI V1 = / ① Not Loin D3 + E BANG SO LIEU: = therich endingdingthe in =4 + Loin 2 & I Not Loin co D AD I TB to rich cavien bythep: 23 BB hiony: xot khoi ③ TB com bs CONE THE TIMH # ding boing com bythat 200g hink can: tick cuavien bi v4 · d) h thishionym waving ding to - m Am My AMB Einh toan: E Xaidish ① Tink the rich a chicring sting: AT 0.02 0,013 0,033 (103m) Ad= Adht+Ad 0.02 0,013:0,033 (10-3m) Ah Annt 1n 0.02 0,0843 0,1043 (10m) AD * APh+ = + = = = = = Y =,(52 = = = + + = = Tinh AD APk 1D 0.02 0,009 0.029 + = + = = ↓ Iz G4.53 7.3,14.6,427 138,932(10m3) = =1 = w + = + = 0.05 AVs ↓ = kei lan = = the tich vien bitip:Vs= Is AVs=138,9 ③ Xai dinh khoi long: a phepato: Son so Thyido, * Am, Am =Amiht Amz AM3h+ AM, ketqua aaphp oto khihing: = m m1 my ms = Am 29,936 = AM3 = ④Xasdinh_kl Fr 8, m1 1,047 = = = A 91 = Am1 19 = 138,932 1055 Ams = Als 57 = => ⑭ 0,018 0,038 (10 kg) 9.103 0,02940 0.02 + = + 0.02 + kitlm: m mam bo) = My m3 =Amy = tinh en s the ↓ 8204,659(kg/m3) = - 0.038 + 29,933 8204,659 0,0213 7536,061(kg/m3) ge 0,0427 = 321,790(bg(m3) 0,0427.7536,061= virship:s* *s-Eins I 0.17.109(kg/m3) 0,32.10(kg/m3) I - ↓ 174,759(kg(m3) = = = = KET LUAN: / Am, Ams = = 0,0213 = 8, tink > = + " *Te 1,047.103 Is (159mb) =0,838(10-3kg) 0,023 C10 kg) 3648,293.10-9 = 2.1 we ratran dining: hingring 29,933.10-3 I * = + = * = + = I.5 = S= = = AVz I 0,015.138,932 2,084(10m3) * AD (10-m) - Yo 0,02 = 10,213 = - + 72,9659(10m3) 0.02 3648,296 = 0,1043 2.92,14.0,033 24,04.0,8e 32,142 -24,042 = v 4, IAl, 3648173 (109m) Xac dink therich cavien bi thep: & * ↓ = = - I AV, => I I -I) * a + + = = = A 2.5D d.Ad,A 808, it - An = ).5 11"(32,14-24,023.10,213=3648, egetangmi + + * AD, Ad, Al=? -L kit luan: fr =Af = +3 A93 = = = ↓ Als:? TOM TAY I c YTHUYET: in la las cu ki doo BÀI - laivatli, dong T1 doing quant true khidow -"I amuncatiquoration B =litoinh contaithuo di de lacon qua Of lacon lawthnom langhich chuki dat so R 24 = Next= mghich 442L g = 42 I TRINH TO THI MEHIEM: ① chucki t To to & ke giva A dow ding not any a bring bring doing hodo thisgian (C(X 0,01s) kep (ecx=0,02mm) toworthis lac thio'c = se orthe totwhat ③ chukiT1.I Do # COMETHE g I = TIMH VE 4N? L = BAME touce,'"oting hoctot.gion (CCX 0,011) In + 42 LIEU: SO vi ri giatrong 2(mm) 50T,() 50t(1) (m) 40 = + (mm) vi to (mm) (mm) = x= Loin tryofwhatan= 1504/s) 504,(s) B I (mm) 50t(1) HH NAN: E 88: + L 70011 20 SAI = => = 20 RIEN COMETHEC KHAI ChukiT cuacon las thr mghich: 150t(1) va I · 1505 5052) f + = (*505, = A · 15) + At ATh+ = => = Gia g · to trong: t = 14 2+ = + = Ag 8.5 => = g g Ag = = II I AT & · AF + = = Iding F Aho · 1507,;505 lig.tr;trong bring = so ??? lie bring 2) towr.trir!) to BÀI TAY I TOM THOYEY: L! -> estayatbonegravingwayma vat room Momen quam' tint I didit ooi to don n.Ky.m? TRIMH TO # MEHIEM: B1 Do being THE - diong cua true bank kinkd xe bring M thickep (2x 0,02mm) = Below to ban seeNowwholeclotReamon corequotethinkthatothe (CX= mm to t By 1mm)_sy rah1 to gion (CCX 1m) 1000mm = bring S - to may gion him COMEHOL TNH A COME TOC # long this tinh ma Sms my sat so(00X=0,001s) va he=thus KHAIRIEN SAISO: true: he-he = S= => Cong hithe m mm++like the = this tinh momen *** The the Are quan'tinh: md[gt h,thel 1] - the ent+ telah -Sim+ I - - = Shai hong quainomy:m -22x -20X ad Ahic cud -Cox and - No = kep:0,02 I (kg) (mm) many to figion his80:0,001() this coca to milimit:1 (mm) vitri A:he=I (mm) e the Loin to t(5) At (s) dAd(mm) (mm) halmm) 1halmm) TB Einh = town:0,02 ↑ Ad: Adt * At Ad ↑0,001 Ath+ AE = + Abat Aky= Am + Am = Ske 0.0001 Am + o - Ah Ahsat Ath = o mm) ** tms=m5jeee - I Th ha) they itdoi: Sonso * m G= · => -m = + + T-teth/*h+a-the the + Afms S Ins = · d-Ethe s um I => # S2 I = KEt Ivan: Sms=Jms' Afms = I=I Al I (r) (kg m? TOM TAY I TUTE: Y chatwas bon TRIMH # ① MOHIEM: TO THE nic vien bi bring the (2x Panne blownvorvien bi nhi va vien bi lonri hi phip to thagion Do so s dwong kink Do ② gotohe chording his how we chatlong Eri soman phyto chas ling nor giann khiwhier Aving Don vi and it la ky/m soy lei He Bài I bring maydo thorgian him phichlocation, some reset 0,01mm) This = ghi ket qua nowbeing (CX so diechinh nitR Ra sow choharienbindodoctoring ghgtthgione 0,0011) = d denvia wi bng r roman song cng ne ↑ 8) chiendon (as to concom binbeing COMETHOC TIMH VE COMETHOC # Thr hng ring - I = KHAI TRIE SAI to = ca vien bi: (ag1m3) d A Am = eas =A+ A) o d(mm) a = -bla,d_(2D+2,4d) 4d yldi Son n A*+ + - BANE SO LIEU: I = SO: Heso whoend chat ling: - milimer (20x 1mm) this Ad(mm) -d(i 1,2,3) = At(s) I(s) Interit (age he doi:1 895189(kg/m3) Kech give I can ben: = (m) (m)s) y 9,81 =0,005 = I - TB - - * = Do exon ad and cas hoc to many (s)-ntch Paume:0,01mm t.gion:0,001 inst.it (mm) TINH I ⑪ TOAM: sosotuyetdecarasdo - A Fabo= Atht Ampho: Amp ALk6 AL = Coirdish he ⑧ A Adlin=Adht+ Adcon Enho Atlon=1tht Ammho Ampon Al AL + + what hiong rising Fahi=Muhi Enho 1Flin + Amht+Amson = ALn 1t + = long: aid chat so * hiong othe bi: and vien - · · Senho= Afuhi Am hi Inho Enho Asuhi=Tahi -> - - + Adhe Inhi Inhi=?? shot chatling: * He ↑ it · to = (Innotone; Enho:= · Enh t Anho + + + 52(125+ 2anhil mt 2.4 -> An=anho.I=??? Kethim: 1:I * LAM TWOMETO US I Al= VIEN BI LON Anho i TOM I Bài THOYEY: LY Ver ii ⑧ s to Chu ki * cuc dow t I tz -te Ag >t dong sick phing: = Un-U R C In T = Un-Vs TRIMH # TO THE MEHIEM: vousten neon bring - Do - Us X I Un v von bring him hectiction Umax=100V;3 2,5% as Do chu Do, by teen E Te pr gan 8I co Roe, Go ther sider Me fomi timimseemyundenkhi den Gunglongthisweighi giatiVs - = boing thing be, Soucto, von ngo low atthe 22x 0,011 = Ro, Ge - Un y + I *CoN Chu =He *e* IMH kigion doing vE cnetHOC tick phony una KHAI TRIE SAI So: mach Ro,Co: =notoinette n+no.acol-(Int elial an Hoid dish Re: Re noint = AR -> Fr Cloudsink En Ex: co I = = I A 8+ EK Ae - = + I BANE SO LIEU: -Volt ke:=Um 100V;6 2,5% Dien tromo:Ro 1,00 =0.01 (M-2) Dienching move:2 1,00 =0.01 (MF) = = = - - = - - Loin Dochinh xac cud many to this gian:Atht=0,015 ·Vs(V) AUsCU).ULV).AGCU).to(s).Ato(s) tr(s):Atp(s) te(s).Ate(s) TB I TIMH TOAN: ① Binh gitri: = Fo to In Eattothe Un-s ne - to + 2,5% Einh soi so: & AU=(AU) ht+AF 8% Um +AV = (AVsA++1ts 8% Um+AUs An AUn=(AUnCht+1Un STo Um AUs= = = Ato AbhI" aE = = + EE =In (E.AR Fo.1c) K.E + - (l n+ ARR Ro+R + = = => 82 ARa 81 Fa = A 10 + = + = AG S => = In KEY LUAN: II Vs=Ys AUs = Up U+IAU = Do giointiep: Jothic Re To = = tiep:to:t1Ato= I I = ARs G E AC = I Ato = *4+ (-(As] Bài I T* TOM THUE: LY Ohm donotmach Dinh liat R mit chier: dien = I Dinh hr Ohm I TOTHE B I - ~ Do die ! I ↓I D ↑ sort it C can !An I day tre Do he ③ din dung C and Bthe otion (trong machary chicR-C - I bong cuci S/ = ⑧ chi: = NEHIEM: know sat mach kin Volt-Ampe I say W TRINH # ormach dien E ↑ can day down mach seway chinR-L: C COMETHOC TIMH VECT SAI # SO: Heso'ticam: L_Icd-> Going I 2πg cd AZcd+r.Ar Zac - + = Ved redt to wie dow:Zcd- Dien dung:2 I I 24f = = 2nfc e A *- -> I Ve = + BANG SO'LIEU: Bring t 1: 30 Rp = = = .(r) Voltke DC:Um=20V;G 0,01;8x 0,5%;n Ampeke DC:Im 200mA; < 0, 1;8% = = W(V) AU(U) x I(mA) AI(mA) ↓ = 1,24;n = Sp% 19; 0,1; = = I I · Si 0, = = Omke:Rm 2002; AU= = = n 8% A= L = I+4, 1,2% +n.d ↓I 30,01 ta Bang 2: roA keA2:Um 200;20.04:8% 1, n Ampe keAC:Im in = = = 200 = I(mA) mA;2 0.1;85t 1.8% U(U) C = = Up(r) 2, n+C2 21122 Bring I = U2(V) 2(-) = R(e) e(n) C(F) 3: Ohmke:Rm 2001;G 0,1;8it=1%; = = n = Dien to rii:R= I(mA)/ wirs /reir)/G()) < *1=) " ⑳ INH TOAM: Einh gia'tri cudko, TOU= 1) E Pp Ro = 2.tp B.tp + + 1OV 4.82.183 = 13 6,76.10- = E it = 5((" 4B(-1).2] i 273 + + = Eink dien dung vo 2) he soi can: Mot Au dien 2: * U 2= R Un = Howtoan * artis E z 2c = R song song: W E = Heso thecaim: z E 2c I = E = = Howtheair mas z Ve r E = * R E = = y Ve = L = I R E = Tcal 3) - = Einh son so: Z, Ia ARp=Splo Rp * - 10,1 d + =leeHe t= - = A +(Ept At Spo:P = ARo Sp o => = Spt * =to = 10 =>ARt 8RA It = * at ((a- 4(m-r) = sai * -Not A- soctoi v tuotien; thee , 1,8% AV St.U+ n = !01 Yo 82 = => +E + + = AC8.2 = HoiAn dien mas notip: - AI SqoI = n.d + AUc Si.U = A => - = A2 How d + * + = = n = + I See mac song song: Al fil.I n to + = AV S.U = n.d + A V A* + = + = Soso'car" tocut, * % pla 5,1 AUC SY Vad = the along ↑5 y0,01 + n lam-no) - 4o] AI 8% = I n.d + 5!,1 si AUd+Al E= Sec = AZcd => Zcd Al => Ecol AZcal RAR, * + = Szod = I S E Jach = Zac =2 - I.S = ⑪Ket qua: Da va ctin tro: =1 Ro-(is) Ro ↑ Ato 2.tp B.tp + + lamin",n) *Ro ill:napin) asc.Di voi tu dien: I =AC cas bioc: = - GimE: I = 2rg Fe AG = = - Sim AC: Sim Al 2I AC2 = = D vo cun rr II = ↓ 1) Zaa + + = day: Ar = = L Si% I n AV 6% Uc n = - 2πf Re Al Einh AU Al-AZed AL:Zee - E + E - = * + Bài TOM TAY I LYTHUYEY: N ~I in s, B Grow tiein aid tiator: S H Gian N (n) die Grong Su ca2 do: n = TRIMH # lo: S, laanh Itsidodinythatin - kitethe THI NEHIEM: TO any handedbonthutichboing thing Do co wa boin LONG THEC TIMH VE CONG THEC KHAI Dodo ⑧ II Chief mat n o thing tink: - ① S1 S laat that i Chiefseatcud boin tia boin and thing Panme( boing kink him SAI (CX= 0,01m vi (CCX 0,002mm) - = SO: A + todoing this:d 0,5k+0,01m = doingbizn kien: ook:tong sorach hiera trin vchia aid thirstion m:so rach Do solving this tron 0,001(l-l0) (mm) N: d 0,2N = + [d 0,2N 0,001 (1+200-90) + = IV and quay BANG (l >, (0) (mm) (l 0:haith X 0: I TRINH TO THE NGHIEM: phrin ki - ① as to tie P cua phapSilberman: thoirkink hiAu: - A E B " phop " A B ! d ↳ Do P phoip "Fr X A " di B >YA L- a = 44 phon ki: ket: bien di v > in Ja the sit ae = V ⑭ CONO THOC INH WFi, Fl V L the asand thatkink 5t I > ·Fe - AI > atim = - fr & I Al I Bessor: Ch I B " W Lo L P - VE cone true SAI so: bin as I, 21 = aid thiskink - histu: AlAra Be = - ht I lag-glat+(naat D: bien as I cusithokink phan kij: Ja da.c - log-agg)"cut" log-gog)*'t - = dy+d BAMESO'LIEU IV I I I I Limmamms/simms/afims Lon to ↳um, silpermanagiams E Loin to da(mm) S ⑪ I PP dim d'(mm) bien kit 8(mm) Af1mm) Einh toan: s: Sovi +P phap Afrat=ALoht/4 silberman: 1th=/EgE*L+/ agnant P.phopBessel: - g P - ket: phoipdish bien = ·g) leg-cig) * Saiso Loan.Phag=Afratee Bessel: Afe=AlsatAfr ~lenket:Afe:Acht Diem ⑭Kei han: I Ii = Af1 = 12 Iz Afa = = + Ata *cht *

Ngày đăng: 03/07/2023, 11:23

Tài liệu cùng người dùng

  • Đang cập nhật ...

Tài liệu liên quan