Dap an de thi thu thpt quoc gia hoa hoc thai binh

� s SO GIAO Dl)C DAO T,;.O THAI BINH DE THI KHAO SAT CHAT LU(}NG LAN TRUONGTHPTCHUYEN NAM HQC: - MON: HOA HQC 12 M a d � 357 Thai gian lam bai: 50 phut (40 cdu trdc nghiem) Cho biet khoi luong nguyen tu (theo dvC) cua cac nguyen t6: H = l ; Li=7; Al=27; C=l2; N=l4; S=32; C l = , ; K=39; Ca=40; Cr=52; Mn=55; Fe=56; Cu=64; Zn=65; Br=80; = ; Na=23; Mg=24; Se=79; A g = l ; Sn=l ; B a = ; Pb=207 Cau (TH) (ID: 343852): Cho phan (mg h6a hoc: Mg + CuSQ4 -+ MgSQ4 + Cu Qua trinh nao duoi day bi�u thi su oxi h6a Cua phan (mg tren? A Mg -+ Mg2+ + 2e B Mg2+ + 2e Mg -+ C Cu -+ Cu2+ + 2e D Cu2+ + 2e -+ Cu Cau (NB) (ID: 343853): Nuce cirng la mroc c6 chira nhieu cation A Ca +, Mg C Na+, Zn2+ + D H+, Cu 2+ Cfiu (TH) (ID: 343854): Hop ch.it A1 c6 CTPT C3H602 thoa man so d6: ddNaOH ddH S0 ddAgN0 /NH 3 Cong thirc c.iu tao h6a hoc thoa man cua A1 la B CH3-CQ-CH2-0H D HCOO-CH2-CH3 Cau (VD) (ID: 5 ) : Hoa tan hoan toan , gam h6n hop Cu, Zn bing dung dich H2S04 d�c, n6ng thu duce san pham khir la , lit S02 (dktc) va 0,64 gam hru huynh Ph�n tram khoi luong cua Cu h6n hop ban d�u Ia A , % B , % C , % D , % Cau (VD) (ID: ) : Khi S\lC tu tu d�n du C02 vao dung dich h6n hop gorn a mol NaOH va b mol Ca(OH)2, k�t qua thi nghiem duoc bieu diSn tren d6 thi sau: 11CaC03 0.5 1.4 nco2 Ti 1� a : b la A : B : C : D : Cau (TH) (ID: 343857): Dien phan (dien cue tro) dung dich NaCl va CuS04 (ti 1� mol tuong (mg la : ) dSn catot xu�t hien bot thi dung lai San pham thu duce anot la A H2 va 02 B Cb va 02 C Cb va H2 D Ch Cau (TH) (ID: 343858): Day gorn cac nguyen t6 tu trai qua phai, duoc sip xSp theo chieu tang d�n tinh khir la A Mg, Al, Cu, Fe B Na, Mg, K, Li C Mg, Na, K, Rb D Mg, Na, K, Li Cau (VD) (ID: ) : Khi thuy phan hoan toan mot este don clnrc bing dung dich NaOH thu duce dung dich X NSu c6 can dn than dung dich X thu duoc , gam muoi Cho dung dich X vao dung dich AgN03 NH3 du thu duce , gam kSt tua Cong tlnrc phan tu cua este la A HCOOCH=CH2 B HCOOC6Hs Cau Cho cac este: (TH) (ID: 343863): C CH3COOC6Hs vinyl axetat, etyl benzoat, D HCOOC6H4CH3 benzyl fomat, etyl axetat, isoamyl axetat, phenyl axetat, anlyl axetat S6 este c6 thS diSu chS t11Jc tiep bing phan irng cua axit va ancol tuong irng (c6 H2S04 d�c lam xuc tac) la A B C D Cau (TH) (ID: 343864): Cho cac dung dich sau: NaHC03 (X1) CuS04 (X2) (NH4)2C03 (X3) NaN03 (X4) MgCb (Xs) KCl (X6) Nhirng dung dich khdng tao kSt tua cho kim loai Ba vao la A X1, X4, X6 B X1, X4, x, C X1, X2, X3 Cfiu 1 (TH) (ID: 343868): Phan irng kh6ng xay nhiet thuong la A Ca(HC03)2 + Ca(OH)2 � 2CaC03 t + 2H20 B Ca(OH)2 + 2NH4Cl � CaCb + 2H20 + 2NH3 j C CaCb + 2NaHC03 � CaC03 t + 2NaC1 + 2HC1 D Mg(HC03)2 + 2Ca(OH)2 � Mg(OH)2 t + 2CaC03 t + 2H20 Cau 12 (TH) (ID: 343869): Alanin (axit a-amino propionic) phan irng vira du voi HCl Nhan xet nao kh6ng dung vS san pham X thu duce? A X thuoc loai muoi amoni B Dung dich X c6 m6i tnrorig axit C X thuoc loai muoi cacboxylat D X kh6ng c6 tinh luong tinh Cau 13 (VD) (ID: 343870): H�p thu hoan toan V lit C02 (dktc) vao binh dung 200 ml dung dich NaOH IM va Na2C03 0,5M C6 can dung dich sau phan irng thu duoc , gam ch�t rin khan Gia tri V la A , B 1, 12 C 2,24 D , Cfiu (TH) (ID: 343877): Cho so d6 phan irng sau: HCI ->z � I CO , NH3 H O � X -�' - Y t cao p cao I i\aOH) T X, Y, Z, T tuong (mg la A (NH4)2C03, NH4HC03, C02, NH3 B (NH2)2CO, (NH4)2C03, C02, NH3 C (NH4)2C03, (NH2)2CO, C02, NH3 D (NH2)2CO, NH4HC03, C02, NH3 Cau (TH) (ID: 343878): X va Y la kim loai s6 cac kim loai sau: Al, Fe, Ag, Cu, Na, Ca, Zn - X tan dung dich HCl, dung dich HN03 d�c nguoi, dung dich NaOH ma khong tan H20 - Y khong tan dung dich NaOH, dung dich HCl, ma tan dung dich AgN03, dung dich HN03 d�c nguoi X, Y l�n hrot la A Zn va Cu Cau 16 (VD) (ID: 343879): B N a v a Mg C A l v a Cu Cho dung dich KOH du vao dung dich FeCb thu duce D C a v a Ag , gam k�t tua N�u thay dung dich KOH bang dung dich AgN03 du thi thu duoc m gam k�t tua Gia tri cua m la A , B 48,45 C , D , Cau (TH) (ID: 343880): Ngarn mot la Zn vao dung dich HCl th�y bot thoat it va cham N�u nho them vai giot dung dich X thi th�y bot thoat r�t nhieu va nhanh Ch�t tan dung dich X la A MgS04 B FeS04 Cfiu (VD) (ID: 8 ) : H6n hop A mach C H2S04 D NaOH gom ancol no don chirc va mot axit no don clnrc, chia A hai phan bang Ph�n I bi d6t chay hoan toan th�y tao 2,24 lit C02 ( dktc ) Ph�n II duce este hoa tan hoan toan va vira du thu duoc este Khi d6t chay h�t luong este thi luong mroc sinh la A 2,7 gam B , gam C , gam D , gam Cfiu (TH) (ID: 343882): Thuy phan este X rnoi tnrong axit thu duce hai ch�t hiru ca A v a B Oxi h6a A tao san pham la ch�t B Ch�t X khong th� la A vinyl axetat B metyl fomat C etyl axetat D isopropyl propionat Cau 20 (VD) (ID: 343883): Cho dung dich chira 6, 75 gam mot amin no don chirc, bac I tac dung voi dung dich Al Cb du thu duce , gam k�t tua Amin c6 cong thirc la A C2HsNH2 B (CH3)2NH C CH3NH2 D C2H7NH2 Cau (TH) (ID: 343884): D� phan biet ch�t din: Na2C03, CaC03, Na2S04, CaS04.2H20 dung lo m�t nhan rieng biet, nguoi ta dung nh6m thuoc thir nao sau day? A H20 va HCl B Dung dich NaOH va dung dich phenolphtalein C H20 va dung dich NaOH D Quy tim &m, dung dich H2S04 d�c Cau 22 (NB) (ID: 343885): Mot s6 ca so san xu�t thuoc bac thuong d6t mot ch�t bot rin mau vang (la mot don chat) d� tao X nham muc dich t&y trang, chong moc Tuy nhien, theo cac nha khoa hoc thi X c6 anh huong khong t6t d�n ca quan noi tang va X ciing la mot nhirng nguyen nhan gay rmra axit Khi X la A H2S B C02 C S02 D N02 Cau 23 (NB) (ID: 343892): Trong cong nghiep, nguoi ta di�u ch� nhorn bang each nao sau day? A Di�n phan n6ng chay Ab03 B Nhi�t phan Al(OH)3 C Nhi�t phan Al(N03)3 D Di�n phan dung dich AlCb Cau 24 (TH) (ID: 343893): Khi dun n6ng CH3CH2CHOHCH3 voi H2S04 dac, a l 70°C thi tong s6 dong phan (tinh ca dong phan hinh hoc) thu duce la c B A.4 D Cau 25 (TH) (ID: 343894): Cho cac phat bieu sau v� cacbohidrat: (a) T�t ca cac cacbohidrat d�u c6 phan (mg thuy phan (b) Thuy phan hoan toan tinh bot thu duoc glucozo ( c) Glucozo va fructozo d�u c6 phan (mg voi dung dich AgNQ3/NH3 ( d) Glucozo lam m�t rnau mroc brom S6 cau phat bieu dung la c A I B Cfiu 26 (TH) (ID: 343895): Cho cac cap kim loai tiep xuc tnrc tiep: Fe-Pb, Fe-Zn, Fe-Sn, Fe-Ni, Fe-Cu Nhung D.2 tung cap kim loai vao dung dich axit HCl S6 cap kim loai ma Fe c B A.3 bi an mon truce la D.2 Cau 27 (TH) (ID: ) : C6 b6n hop ch�t X, Y, Z va T Nguoi ta cho m�u thir cua m6i ch�t l�n hrot qua CuO d6t n6ng, CuSQ4 khan va binh chira dung dich Ca(OH)2 mau qua mau xanh; m�u Y chi tao kSt tua trang a Sau thi nghiern th�y m�u X chi lam CuSQ4 d6i binh chira mroc v6i; m�u Z tao hien tuong a ca hai binh nay, m�u T kh6ng tao hien tuong gi KSt luan dung cho phep phan tich la A X chi chira nguyen t6 cacbon B Y chi chira nguyen t6 hidro c z D T la ch�t v6 ca la mot hidrocacbon Cau 28 (TH) (ID: 343906): Cho phirong trinh phan irng: X + H S -+ Fe2(SQ4)3 + S02 + H20 S6 hop ch�t X chua nguyen t6 la A.4 c B D Cfiu 29 (TH) (ID: 343907): D� tach actemisin, mot ch�t c6 cay hao hoa vang d� chS thuoc chong s6t ret, nguoi ta lam nhu sau: ngam l a v a than cay hao hoa vang da barn nho hexan Tach phan ch�t long, dun va ngung tu d� thu d6i hexan Ph�n lai la ch�t long s�t duce cho qua cot sic ki va cho cac dung m6i thich hop chay qua d� thu tung phan cua tinh d�u KI thuat nao sau day khong duce SU dung? A Sic ki B Chung dt C ChiSt xuat D Chung dt 16i cuon hoi mroc Cau 30 (NB) (ID: 343908): Trong cac polime sau: (1) poli(metyl metacrylat); (2) polistiren; (3) nilon-7; (4) poli(etylen terephtalat); (5) nilon-6,6; (6) poli(vinyl axetat) Cac polime la san pharn cua phan irng trung ngung la A ( ) , (3), (5) Cau (VDC) (ID: B ( ) , (2), ( ) 343909): c ( ) , (3), (6) Cho X, Y la hai axit cacboxylic don clnrc, no, mach clnrc t 2x + y = 0,2 + , (2) Giai M ( ) va (2) duce x = , va y = , BTNT " C " : ncoz + nNa2C03 b et = nNa2C03 thu dUQ'C => ncoz + 0, I = 0, => ncoz = , mol => V = , 2 , = , lit Dap an B Cau : Phurrng phap: Vi�t cac PTHH tu xac dinh duce cac ch�t X, Y, Z, T tuong (mg Hurmg d�n giai: 10 2NH3 + C02 cao,p cao ) (NH2)2CO (X) + H20 (NH2)2CO (X) + 2H20 -* (NH4)2C03 (Y) (NH4)2CQ3 (Y) + 2HC1 -* 2NH4Cl + H20 + C02 (Z) (NH4)2CQ3 (Y) + N a O H -* Na2C03 + 2NH3 (T) + 2H20 Dap an B Cau : Hurmg d�n giai: - Lap luan tim X: + X kh6ng tan mroc nen loai Na, Ca + X tan HCl nen loai Ag, Cu + X tan dung dich HNQ3 dijc nguoi nen loai Al, Fe => X la Zn - Lap luan tim Y: + Y kh6ng tan NaOH nen loai Al, Na, Ca, Zn + Y kh6ng tan HCl nen loai Fe + Y tan dung dich AgNQ3 nen loai Ag => Y la Cu Dap an A Cau : Phurrng phap: Tinh theo PTHH: - Khi cho FeCb tac dung voi KOH du: FeCb + K O H -* Fe(OH)2J + 3KC1 - Khi cho FeCb tac dung voi AgNQ3 du: Fe2+ + A g + -* Fe3+ + Ag Ag+ + c - -* AgCl Hurrng d�n giai: t t - Khi cho FeCb tac dung voi KOH du: FeCb + 3KOH � Fe(OH)2J + 3KC1 => nFe(OH)2 = , : 90 = , mol => nr-cu = 0, mol => nFe2+ = 0, mol Va ncJ- = 0,3 mol - Khi cho FeCb tac dung voi AgNQ3 du: Fe2+ + A g + � Fe3+ + Ag 0,15 � Ag+ 0,15 t + Cl: � AgCl 0,3 � => m t k6ttua = 0,3 ffiAg + ffiAgCI = 0, + , , = , gam Dap an C Cau : Phuong phap: Dua vao ly thuyet v� an mon dien h6a Hurmg d�n giai: Ch.it tan X la FeSQ4 vi nho FeSQ4 vao xay phan (mg: Z n + FeSQ4 � ZnSQ4 + Fe Fe barn vao la Zn tao cap dien ClJC Zn - Fe cung nhung dung dich dien l i n e n c6 xay SlJ an rnon dien h6a nen khien cho bot thoat nhieu va nhanh hon Dap an B Cau : Phurrng phap: Do phan nguyen t6 cua phan I giong voi phan II nen luong C02 thu duce d6t chung la nhu => ncoz ( d6t phfm II) = ? Mat khac, este duoc tao boi axit no don chirc va axit no don chirc nen d6t chay ta lu6n c6: nH20 = ncoz = ? => IDH20 = ? Hurmg d�n giai: Do phan nguyen t6 cua phan I giong voi phan II nen luong C02 thu duce d6t chung la nhu => ncoz (d6t ph&n II)= 0, mol Mat khac, este duoc tao boi axit no don chirc va axit no don chirc nen d6t chay ta lu6n c6: nH20 = ncoz = , mol => IDH20 = , gam Dap an C Cau : Hurrng d�n giai: - Vinyl axetat (CH3CQOCH=CH2): CH3CHO + [O] � CH3COOH Nhu vay oxi h6a A thu dUQ'C B thoa man d� bai - Metyl fomat (HCOOCH3): HCOOH (B) + CH30H (A) CH30H + [ ] � HCOOH + H20 Nhu vay oxi h6a A thu dUQ'C B thoa man d� bai - Etyl axetat (CH3COOC2Hs): C2HsOH + 2[0] � CH3COOH + H20 Nhu vay oxi h6a A thu dUQ'C B thoa man d� bai - Isopropyl propionat (CH3-CH2-COOCH(CH3)-CH3): Ir , ° CH3-CH2-COOCH(CH3)-CH3 + H20 CH3-CH(OH)-CH3 + [O] � CH3-CO-CH3 Nhu vay oxi h6a (A) kh6ng thu dUQ'C (B) => kh6ng thoa man Dap an D Cau : Phuong phap: Tinh theo PTHH: 3CnH2n+1NH2 + 3H20 + A l C b -+ 3CnH2n+1NH3Cl + Al(OH)3 Hurrng dfin giai: nAJ(OH)3 = , : 78 = , mol Dat c6ng thirc cua amin la CnH2n+ 1NH2 PTHH: 3CnH2n+1NH2 + 3H20 + AlCb -+ 3CnH2n+1NH3Cl + Al(OH)3 Theo PTHH: n amin = 3nAJ(OH)3 = , mol => M amin = , : , = 45 => 14n + = 45 => n = Vay amin la C2HsNH2 Dap an A Cau : Hurrng dfin giai: Ta dung H20 va HCl: * DungH20: - Nh6m : Khong tan h�t nuoc => CaC03 va CaS04.2H20 - Nh6m : Tan h�t mroc => Na2C03, Na2S04 * Dung HCl cho vao m6i nh6m: -Nh6m : + Xu�t hien => CaCQ3 + Khong co => CaS04.2H20 -Nh6m 2: + Xu�t hien => Na2C03 + Khong co => Na2S04 Dap an A Cau 2 : Hurrng d�n giai: X co tinh t�y mau, chong moc va la nguyen nhan gay rmra axit => X la S02 Dap an C Cau : Phuong phap: Dua vao phuong phap diSu ch� Al cong nghiep Hurmg d�n giai: Trong cong nghiep nguoi ta diSu ch� nhom bing each dien phan n6ng chay hop ch�t Ab03 (thanh phan chinh cua quang boxit tu nhien): dpnc 4Al + 302 2Ab03 Dap an A Cau : Phurrng phap: d l 70°C thi ancol bi tach nuoc tao anken tuong (mg (nh6m -OH se tach cung nguyen tu H cua C ben canh) Hurrng d�n giai: CH -CH CH3-CH=CH-CH3 (cis) -CH-CH I OH vay co dong phan co ths tao Dap an B Cau : Phuong phap: Ly thuyet vS cacbohidrat Hurrng d�n giai: (a) sai, monosaccarit khong bi thuy phan (b) dung (c) dung, vi moi tnrong kiem fructozo c6 th� chuyen h6a glucozo ( d) dung, vi glucozo c6 chira nh6m -CHO vay c6 t�t ca phat bieu dung Dap an B Cau : Phurrng phap: Trong pin dien h6a, dien cue nao c6 tinh khir manh hon bi an rnon tnroc Hurrng d�n giai: Trong pin dien h6a, di�n cue nao c6 tinh khir manh hon bi an mon tnroc Tinh klnr: Zn > Fe > Ni > Sn > Pb > Cu Nhu vay c6 cap kim loai ma Fe bi an mon truce l a : Fe-Pb, Fe-Sn, Fe-Ni, Fe-Cu Dap an B Cau : Hurmg d�n giai: - X chi lam d6i mau CuSQ4 khan mau xanh chung to d6t X chi thu duce H20 => X chira H, khong chira C - Y chi tao k�t tua trang binh Ca(OH)2 => Y chira C, khong chira H - Z tao hien tuong ca hai binh => Z chira ca C, H - T khong tao hien tuong gi => T khong chira C, H A sai, vi X khong chira C B sai, vi Y khong chira H C sai, vi Z c6 th� chira C, H, D dung, T khong chira C nen chic chin T khong phai ch�t hiru ca Dap an D Cau : Phurrng phap: - Do phan irng tao san pham khir la S02 nen x chira Fe c6 s6 oxi h6a trung gian - Thanh phan cua san pham chi chira cac nguyen t6 Fe, S, 0, H nen X chira Fe va nguyen t6 S, => Cac hop ch�t c6 th� c6 cua X Hurrng d�n giai: - Do phan irng tao san pham khir la S02 nen x chira Fe c6 s6 oxi h6a trung gian - Thanh phan cua san pham chi chira cac nguyen t6 Fe, S, 0, H nen X clnra Fe va nguyen t6 S, => X c6 th� l a : FeO, Fe3Q4, FeS, FeS2 Dap an A Cau : Hurrng d�n giai: - Viec ngarn l a v a than cay hexan la phurrng phap chi�t xuit - Dun va ngung tu dS thu h6i hexan la phurrng phap chung dt - Cho ch�t long vao cot siic ki va cho cac dung m6i chay qua la phurrng phap siic ki Nhu vay phirong phap kh6ng duce SU dung la phirong phap chung dt 16i cuon hoi mroc Dap an D Cau : Phurrng phap: Ly thuyet v� polime Hurrng d�n giai: Cac polime la san pham cua phan irng trung ngung l a : (3) nilon-7 (4) poli(etylen terephtalat) (5) nilon-6,6 Cac polime lai duoc di�u ch� bing phan (mg trung hop Dap an D Cau : Hurrng d�n giai: ncos = , mol; nH20 = 0,29 mol Do E c6 phan (mg trang girong nen X la HCOOH Gia sir h6n hop E chira: HCOOH (x mol); RCOOH (y mol) va HCOO-R'-OOCR (z mol) (R, R' la cac g6c hidrocacbon no) Ta c6: z = ncoz - nH20 = 0,03 mol ( ) - Khi E tac dung voi AgN03/NH3 du: nAg = 2x + 2z = , / (2) - Khi d6t chay E: BTKL: m02 = mco2 + IDH20 - ID E = , 4 + , - , = , gam => n02 = , 3 mol BTNT " O " : no(E) = 2nc02 + nH20 - 2n02 = , + 0,29 - , 3 = 0,26 mol => no(E) = 2x + 2y + 4z = 0,26 (3) Tu ( ) (2) (3) => x = , ; y = 0,02; z = 0,03 Dat lai c6ng thirc cua cac ch�t E: HCOOH (0,05); CnH2n02 (0,02) va CmH2m-204 (0,03) ID E = , + , ( n + ) + , ( m + ) = , => 2n + 3m = 27 c6 nghiern (m = 7, n = 3) thoa man => E chira HCOOH ( , ) ; C2HsCOOH (0,02) va HCOOC-C2H4-QQCCilis (0,03) tat nhat! - Cho E tac dung voi 0, mol NaOH thi chit rin gom: HCOONa ( , + , = , ) C2HsCOONa ( , + , = , ) NaOH du: , - , - , - , = 0,02 => m ch:ltriln = , + , + , = 1 , gam Dap an B Cau : Phuong phap: H6n hop gom cac chit beo no (CnHzn-406) va axit no (CmH2m02) nen ta c6: ncoz (do axit) - nH20 (do axil)= ncoz (do este) - nH20 (do este) = 2neste => Inco2 - Inmo = 2neste => neste = ? Ta c6: Jl Glixerol = n este => m glixerol = ? Hurmg d�n giai: H6n hop gom cac chit beo no (CnHzn-406) va axit no (CmH2m02) nen ta c6: ncoz (do axit) - nH20 (do axit) = ncoz (do este) - nH20 (do este) = 2neste => Inco2 - Inmo = 2neste => neste = ( , - 23,3)/2 = 0, mol Ta c6: Jl Glixerol = n este = 0, mol => m glixerol = 0, = 9,2 gam Dap an A Cau 3 : Phurrng phap: X, y la peptit duce tao tu cac a-amino axit no, mach chira nh6m -NH2 va nh6m -COOH nen ta quy d6i E thanh: CONH, CH2, H20 (voi s6 mol H20 bing s6 mol cua peptit) Hurrng d�n giai: X, y la peptit duce tao tu cac a-amino axit no, mach chira nh6m -NH2 va nh6m -COOH nen ta quy d6i E thanh: CONH, CH2, H20 (voi s6 mol H20 bing s6 mol cua peptit) nNaOH = 2nNa2C03 = 0,4 mol Sa d6 bai toan: Na C O NH : 0, C0 CH2 : x 0,2 {COON a : 0, BTC E 3: _+_N_aO_H�Muoi NH2 : 0, CQ2 : x + , } _ + _ o + 65,6(g) BTH �H { H 0:0,l CH :x m(g) mc02 + m nz o = , => 44(x+0,2) + ( x + 0,4) = , => x = 0,8 0:x+0,4 => m = , + , + , = 44,4 gam => l , l m = 67,044 gam mE = , + , + 0, = 30,2 gam *D6t , gam E ( , mol): CONH + 0, 75 02 -+ C02 + 0,5H20 + 0,5N2 0,4 -+ 0,3 CH2 + , -+ C02 + H20 , -+ 1,2 => n o ( d t g a m x ) = 0,3 + , = , mol Nhu vay ta c6 ti l � : D6t , gam X dn , mol 02 67,044 g a m -+ , 3 mol g�n nh�t voi , mol Dap an C Cau : Hurmg d�n giai: - Do Z lam v§.n due dung dich Ca(OH)2 nen Z la C02 hoac S02 => Loai D - Thi nghiern cho Z tac dung voi ch�t rin Y => Loai C (vi ca ch�t ban d�u d�u la ch�t rin, kh6ng c6 khi) => Loai B (vi cac ch�t ban d�u la ch�t rin phan (mg voi ch�t long, kh6ng c6 khi) Dap an A Cau : Hurrng d�n giai: Sai, nSu ma thuy phan m6i tnrong axit ta thu duce axit va ancol Dung Dung, glucozo lam nhat mau mroc Br2, fructozo kh6ng lam nhat mau mroc Br2 Sai, chung d�u c6 c6ng thirc t6ng quat la (C6H100s)n nhung s6 mit xich cua xenlulozo Ion hon r�t nhieu so voi tinh bot nen chung kh6ng la dong phan cua Sai, ca hai ch�t d�u kh6ng lam d6i mau quy tim Dung Sai, ta nilon-6 duce di�u chS bing phirong phap trung ngung vay c6 t�t ca phat bieu dung Dap an A Cau : Phuong phap: Luon HCl du % so voi Itron Truy c�p trang Tuyensinh247.com de hoc Toan - Ly- HCl chi phan (mg voi Fe3Q4 theo PTHH: Fe3Q4 + H C -+ FeCb + 2FeCb + 4H20 => nFe304 = nHCI pu/8 = ? => mo, Do Cu du nen sau phan (mg tao muoi Fe2+ Xac dinh phan cua dd Y Khi cho AgNQ3 du vao binh thi chu y c6 ca Cu Bao toan electron tim duoc s6 mol Ag BTNT Cl tim duce s6 mol AgCl Tu tinh dUQ'C khoi hrong k�t tua thu Hurrng d�n giai: nnci D�t nnci pu da dUQ'C dung = 0, 05 mol = x mol Luong HCl du % so voi hrong dn phan (mg nen ta c6: nnci dii dung = nnci pu + nnci du hay , = x + % x = 0,05 => x = 0,04 mol HCl chi phan (mg voi Fe3Q4 theo PTHH: Fe3Q4 + H C -+ FeCb + 2FeCb + 4H20 => nFe304 = nnci pu/8 = 0,005 mol => mo, = mx - ffiFe304 = 4,68 - , 0 = , gam => ncu = , 5 mol Do Cu du nen sau phan (mg tao muoi Fe2+ Fe + : 0, ( B T N T : Fe) Cu + Dung dich Y gom: H + : 0,01 cr : o, BTDT => ncu2+(dd => ncu d u = ncu Y) bd - 05 = (no - 2nFe2+ - nH+)/2 = (0,05 - , - , ) / = , 0 mol ncu2+(dd Y) = , 5 - , 0 = , mol Khi cho AgNQ3 du vao binh phan (mg (chu y binh c6 ca Cu): nNo = nH+/4 = 0,0025 mol QT cho e QT nhan e F e + -+ Fe3+ + l e A g + + l e +» Ag C u ++ Cu2+ + 2e N+s + e -+ N+2 B T e : nFe2+ + 2ncu = nAg + 3nNo => , + , = nAg + , 0 => nAg = , mol Nhu vay k�t tua gom: Ag (0, mol) va AgCl (0,05 mol) => m k6ttua = , + , , = , gam Dap an B Cau : Phurrng phap: - Thi nghiern : m mu6i = ffiFe(N03)3 = ? Quy d6i m6i phan thanh: Fe (0, mol) va O (x mol) BTe cho thi nghiem : 3nFe = 2no + 3nNo => ( ) (�n x va V) - Thi nghiern : +: y +HCl 24,15(g) Fe + :0,165-y +H {Fe:0,165 O : x {Fe BTDT er : 0, 495 - Y Kh5i hrong ch�t tan: m ch&t t an = mFe2+ + mFe3+ + moi, => y = ? => nFe2+ Va nFe3+ BTe cho thi nghiern : 2nFe2+ + 3nFe3+ = 2no + 2nH2 => (2) (�n x va V) Giai ( ) va (2) duoc: x, V Hurrng d�n giai: - Thi nghiern : m mu6i = mFe(N03)3 = , : 242 = , mol Quy d6i m6i phan thanh: Fe (0, mol) va O (x mol) BTe cho thi nghiem : 3nFe = 2no + 3nNo => , = 2x + ( l , V / 2 , ) ( ) - Thi nghiern : +: y +HCl 24,15(g) Fe + :0,165-y {Fe:0,165 O : x {Fe BTDT er : +H 0, 495 - Y Kh5i hrong ch�t tan: m ch&ttan = mFe2+ + mFe3+ + mo => 56y + , ( , - y) = 24, => y = 0,075 => nFe2+ = 0,075 mol; nFe3+ = 0,09 mol BTe cho thi nghiem : 2nFe2++ 3nFe3+= 2no + 2nH2 => , + , = 2x + 2.(V/22,4) (2) Giai ( ) va (2) duoc: x = 0, va V = 0,672 vay v = 0,612 lit Dap an D Cau : Phurrng phap: Bao toan nguyen t6, bao toan dien tich, bao toan khoi hrong Hurrng d�n giai: Do h6n hop sau phan (mg c6 chira H2 nen NQ3- hSt, dung dich Z gom cac muoi: (NH4)2SQ4 DS dang tinh duoc s6 mol cua Al va Ab03 l&n hrot la 0, mol va 0,03 mol Ab(SQ4)3, Na2S04, Sa d6 phan (mg: Al + · 7,65(g)hhx{Al:0,17 Al20 : }+{H2S04 } � d d Z 0, 03 23 ' Na+ NH/ NaN03 so 24 *Khi cho BaCb du vao Z : nsoaz = nBaS04 = 93,2 : 3 = 0,4 mol *Cho z tac dung voi t6i da NaOH: nNaOH = 4nAJ3+ + nNH4+ => , = , + nNH4+ => nNH4+ = , mol BTDT cho dung dich Z : nNa+ = 2nso42- - 3nAJ3+ - nNH4+ = , - , - , = 0,095 mol => nNaN03 = 0,095 mol Nhu vay ta c6: Al + · 23 : 0, 7,65(g)hhX } {H2SO : 0, } Na+ : 0, 095 �ddZ + {Al A l Q : 0,03 ' NaN0 3: 0,095 + Kh i T ( , m o l H J + H NH / : 0,015 so," o,4 BTNT "H": nH20 = (2nH2so4 - 4nNH4+ - n m ) : = (2.0,4 - , - , ) : = , 5 mol B TKL: m T = mx + mazsoa + mNaN03 - mz - mH20 = 7,65 + , + , - ( , + , + , + , ) - , 5 = , g a m = , gam Dap an C Cau : Phurrng phap: m y = mKL + mo(Y) => mo(Y) = ? => no(Y) = ? Khi cho Y tac dung voi NaOH chi c6 Ab03 phan (mg: Ab03 + 2NaOH -+ 2NaA102 + H20 => nAJ203 = 0,5nNaOH = ? => no(A.1203) = 3nAJ203 = ? Mat khac, cho h6n hop Y { Ab03, oxit sit, CuO} tac dung voi H2 va CO thi chi c6 cac oxit sit va CuO => nnz.co = no pu = no(Y) - no(A.1203) = ? Hurrng d�n giai: m y = mKL + mo(Y) => mo(Y) = , - , = 6,26 gam => no(Y) = , mol Khi cho Y tac dung voi NaOH chi c6 Ab03 phan (mg: Ab03 + 2NaOH -+ 2NaA102 + H20 => nA12m = 0,5nNaOH = 0,05 mol => no(Al203) = 3nA12m = , mol bi klnr: Mat khac, cho h6n hop Y { Ab03, oxit sit, CuO} tac dung voi H2 va CO thi chi c6 cac oxit sit va CuO => nnz.co = nopu = no(Y) - no(Al203) = , - , = , mol => V = , 2 , = 5,404 lit Dap an D Cau : Hurmg d�n giai: Sai, lien k�t Si02 la O=Si=O Dung Dung Dung, tinh axit HF < HCl < HBr < HI Dung, vi phan darn amoni chira NH/ c6 tinh axit Dung Dung vay c6 phat bi�u dung Dap an A bi klnr: ... + , 1 = , gam (thoa man) - Phuong an C : L o a i vi san pham cua phan irng thuy phan kh6ng co phan irng trang guong Truy c�p trang Tuyensinh247.com de hoc Toan - Ly- - Phuong an D : HCOOC6H4CH3... clnrc, chia A hai phan bang Ph�n I bi d6t chay hoan toan th�y tao 2,24 lit C02 ( dktc ) Ph�n II duce este hoa tan hoan toan va vira du thu duoc este Khi d6t chay h�t luong este thi luong mroc sinh... tan hoan toan dung dich Y gom H2S04 va NaN03, thu duce dung dich Z chi chira rnuoi trung hoa va m gam h6n hop T (trong T co , mol H2) Cho dung dich BaCb du vao Z dSn cac phan irng xay hoan toan,