Nghiên cứu ứng dụng senxơ áp suất và lưu lượng để xác định nhanh tình trạng kỹ thuật của hệ thống thuỷ lực

NGHIEN CUtJ UNG DUNG SENXO AP SUAT VA LU^U LUONG DE XAC DINH NHANH TINH TRANG KY THUAT CUA HE THONG THUY LUC Ho Viet Hen Bg mdn Chi tgo mdy-Hgc viin KTQS Tom tdt: Bdo cdo di cap tai cdc phuong dn xdc dinh tinh trgng ky thudt ciia he thdng nhdm phuc vu cong tdc sira chua vd bdo dudng hi thdng thiiy luc; xdy dung w dd nguyen ly cdu tgo ciia thiit bi kiim tra nhanh hi thdng thuy lire; sa mgch thiet ke; xdy dung phdn mini thu thdp vd xu ly kit qud do; phirong dn ddu ndi thiit bi vai hi thdng thiiy hrcdi kiim tra ccic didng sd Pmax, AP, Q,„„x vd dong thai cd hai thong w P, Q cua hi thong; kit qud thir nghiem thiit bi Abstract: This report mention the plans for determining the technical conditions, for the repair work and maintenance the hydraulic system; construction principle diagram composed of rapid testing equipment hydraulic system; implement the plan design cmd manufacture equipment; circidt diagram design, construction of software to collect and process measurement results; the project for connecting devices to the hydraulic system to check the parameters Pmax, ^ , Qmax ond simultaneously both parameters P, Q of the system; test results and equipment I DAT VAN DE De bdo dudng, siia chira he thdng thuy lyc tren cdc thiet bj nhu tdu thuyen, xe ca gidi ta cd the dua chiing ve cdc tram sira chiia de kidm tra hodc su dung cdc stand di ddng de kiem tra tai hien trudng nhung deu cdn phdi thdo rdi cdc linh kien thiiy lyc de kiem tra Cdc phuang dn tren deu gay lang phf md thidt bj chua den ban bdo dudng hodc bdng hdc chua ndng Ddi vdi he thdng thiiy lyc dang boat ddng nhung thdng sd ky thudt khdng ddm bao ta cd the kiem tra tai hidn trudng bdng thiet bj (kidm tra nhanh) ddu ndi tryc tidp vdo he thdng de kidm tra Vdi phuang dn kilm tra nhanh ta cd the dugc cdc thdng sd chfnh ciia he thuy lyc dang cdn boat ddng dd la dp suat P, luu lugng Q Cdn ciir vdo cdc thdng sd ky thudt dugc, ta cd till chdn dodn dugc tinh trang thilt bj, xdc djnh dugc vj tri, tinh trang hdng hdc cua thiet bj vd dya vdo cdc thdng tin dk dua dugc phuang dn sira chiia chfnh xdc, lam gidm nhe cdng viec khdo sat cua ngudi sua chiia Bdo cdo ndy de cap den viec iing dung senxo dp sudt vd luu lugng dk chi tao thilt bj kilm tra nhanh he thdng thiiy lyc n NOI DUNG Sff nguyen ly So dd nguyen ly cua thilt bj kilm tra nhanh he thdng thiiy lyc dugc trinh bay tren hinh gdm cd cym chfnh: cym thuy lyc; cum do, hien thj sd vd cum dilu khiln Cdc thdng tin cua he thdng thuy lyc nhu luu lugng Q, dp lyc P dugc ldy qua cdc bd cdm biln, sau xii ly cdc tfn hieu qua bd bii tfn liieu cdc thdng sd se dugc hiln thj tren bd hien thj Cum thdy luc bao gdm cdc van phan phdi, van tilt luu, van mdt chilu vd cdc ddu ndi ghep Nd cd nhiem vy thay ddi dudng ddn ddng ddu vd dilu chinh gid trj cdc thdng sd dp sudt va luu lugng qud trinh kilm tra tuong irng vdi tfn hieu dilu khiln cua cum dilu khiln D I cho cum ggn nhe, tdt cd cdc van dugc ga len mdt dl van dugc ehl tao thay cho cdc dng ddn ddu tir cdc van din vdi Cdc ddu ndi thuy lyc vdi ben ngodi (he thdng cdn kilm tra)"dugc ldp cdc cut noi nhanh 1dm cho vide ldp rdp trd nen nhanh chdng vd chfnh xdc 455 CK" (; 111 dill: l;2.') Klio]) iu")i nhanh Van klirta nga dp l|;c cao Bp luu lifi/ng dp sual \;i I' Van an toin Van ph.ln phdi Hinh So d^ nguyen ly thiet bj kiem tra ca d^ng hq thong thuy lyc Cum vd hien thi ^d bao gdm cdc senxo, cdc bg chuyen ddi A-D vd mdn hinh hiln thj cdc thdng sd luu lugn§, dp suat vd nhidt dg Cdc senxo thu nhan cdc tfn higu can do, sau chiing dugc chuyen ddi thdnh cdc tfn hieu di?n vd gid trj se dugc chuyen ddi vd hien thj tren mdn hinh hien thj tuong img Cum diiu khiin bao gdm cdc thiet bj: PLC; cdc role, bien the Cym cd chiic nang dieu khien cym thuy lyc va cum Cdc phfm dieu khien dudi dang cac cdng tdc ddng md ddng didn dieu khidn cdc van dien tir va cdc senxo Nguyen ly hoat dgng Tdch ddng ddu tai vj tri cdn bdng cdch ddu them dng mem d hai dau tach, ndi dng mem vdo ddu ndi vd qua cdc khdp ndi nhanh Nhu vay, ve nguyen ly ddng dau chay qua thiet bj vd se quay trd lai he thdng thuy lyc Sau thiet bj da dugc ket ndi vdi he thdng thuy luc ta se khdi ddng he thdng thuy lyc Ban ddu chua tien hdnh do, ddng ddu vao cira P va qua cua T ciia van phan phdi de trd ve he thdng thiiy lyc (bode vdo thiing) a) Do dp sudt Ddu tidn dat van an loan d miic thap, cd tfn hieu cdn dp suat Pma.x, he thdng van hoat dgng chi cho phep P he cdn Ddng dau se qua van 3, bg va van phan phdi 7, dudng P thdng qua cira B (V3 hoat dgng) nhung cira B bjt nen dp suat he thdng cd va ddu se qua van (V| boat ddng) theo dudn^ xd quay lai he thdng thuy lyc Dilu chinh ngudng an loan van tdng vd dp sudt he tdng ddn len tir nhd din Idn ddn vd P dat tdi gid trj cyc dai ma he thdng cdn cd thi dat dugc thi dimg lai (hodc he thdng ty dimg) Dem so sdnh dp sudt dugc Pdo vdi dp sudt cdn dat cua he thdn§ Phi cdn Nlu Pdo^^ Pht nhu vay he thdng cd dp sudt dat yeu cdu, nguge lai dp sudt cua he thdng khdng dat yeu cdu tai vj tri kiem tra b) Do luu lugng Khi cd tfn hieu cdn luu lugng Q, he thdng van hoat dgng chi cho phep Qmax, ddu se qua van 3, bg vd van phan phdi hoat dgng cho dudng P qua cua A (V2 boat dgng) qua van tilt luu (md cyc dai) quay vl he thong thiiy lyc Nlu Q^o > Qh nhu vay he thdng du luu lugng tai yj tri kiem tra, nguge lai he thdng thilu luu lugng c) Kiem tra tdng hgp cdc thdng sd dp suit va luu lugng Trong qud trinh 1dm viec, he thdng thuy lyc cd thi lam viec khdng dat dugc cdng sudt nhu thiet ke ban ddu Vide kiem tra tdng hgp bd thdng sd dp sudt va luu lugng cho phep xdc djnh dugc cdng sudt he thdng tai vi trf kilm tra: N=(P.Q)/a; KW