Appendix A Solutions l o tlie kkcrcises 468 Solution 2.2 form I T is canonical as it 11, tvhcrrlinimllni nuniber of energy s t m w (integrators) BJ setting the cocflicients CIO = 0.5; ( t l = 0; a = -3; CI i = I; ho L 0; 112 = 0.1 ailcl h-, = we fiad the block diagrams slioxn in Figs 2.1 H l l d ~olutio 2.3 ~ Solution 2.4 a) Block diagram b) A c.a~ionic.;tlform is found by interchanging the left, a n d right sides arid using a cosiiiiioii differrntiator It does riot liave to fulfil1 any c~onditionras dif€erentiators with tlic saint input signals have the same outpiit sigii;t Is Solution 2.5 a) 'I'hc stitte-qxwe representation is given by z 100 2J = [ 100 -100 ]