494 Appendix A Solutions to the Exercise8 Solution 9.1% a) dx (t) - = -[E(f d".c(t) = -[6(t 1' dt df T +T ) 'LE(t) t E(t *T ) - 2S(1) + b(t - Y-)] I 0 I Tj] olution 10.1 a) 20 log 10 =- 20 d R b) 80 dB r) ill3 d) -34 dR c ) dB S o ~ ~ ~ t 10 ion Kut iUote: ?'he formnla I/ = 10 log -c m also bc used to calculate the dmplifiration p,,, directly Gom (,he power ratio It gives tile sariie resiilt as above Solution 10.3 v ~~agxiitmie = 20 log I I T ( J W ) I = GO CIB-20 log Jm ci13,