486 c) Appendix A Solutions to the Exercises sr - -31 ' , (0 - ) =- -3 ~ o l u t 8.3 ~ o ~ a) ,ra(t) = ~ ( t-)C(C - 1) -t ~ (- t2) - xi ( -l)"(f = k=O Dc h3 i-i'(L(t) = A =.o (-1)%(t - k ) ( - l ) % ( i- k ) = k=O t I,) q(t) = E(t) &(I) qt) ' = = t ' t - E { t - 2) t 1- - +E(t) 2 E(t k -1 t h(t) - "E(1) v ' k -1 4) - = c(t) ' - X-)