Tài liệu Physics exercises solution: Chapter 37 pptx

... This is the kind of conflict resolution that happens when one person has power over another and exercises it. It amounts to the boss saying, ‘‘OK, we have had our discussion, and now I will make ... that the person having the influence has the ability to inflict 9618$$ $CH4 09-06-02 14:59:23 PS CHAPTER 4 Human Resources Management H uman resources management is required to make the most effi...

Ngày tải lên: 24/12/2013, 12:16

... the PMI Board of Directors held their quarterly board meeting in New Orleans. The chapter hosted the board for a chapter meeting, and for the program they invited a panel of disaster and emergency ... events of rolling the die are considered to be mutually exclusive. 9618$$ $CH5 09-06-02 14:59 :37 PS 161Risk Management that we will accept. The point at which the line is drawn is the poi...

Ngày tải lên: 24/12/2013, 12:16

Ngày tải lên: 20/01/2014, 22:20

... 0 t in Eq. (37. 6), so ,s33.8γ 0  tt as in part (a). c) 9 1000.2)800.0()s33.8( c m, which is the distance x found in part (a). 37. 17: Eq. (37. 18): 22 1 cu utx x     Eq. (37. 19): 22 1 ...  . )()( 1 1 )( 222 2 t c x ctxcutcux cc u x cuxtcutx            37. 62: a) From Eq. (37. 37), J.304 )sm1000.3( )sm10(3.00 kg)0.90( 8 3 8 3 2 1 28 44 2 4 2   ...

Ngày tải lên: 17/01/2014, 04:20

... αraa soand .sm180.0 2 a sorad,b) 3 π θ       .sm377.0m0.300rad3srad600.02 222 rad  πrωa The tangential acceleration is still ,sm180.0 2 and so on     .sm418.0sm377.0sm180.0 2 2 2 2 2 a c) tan 22 rad since,sm775.0and,sm754.0,120ofanglean ...  s.m01.1revrad2rev/s0.430 2 m750.0         πrωv d) Combining equations (9.14) and (9.15),  .sm46.3 m))rev)(0 .375 rad2sr...

Ngày tải lên: 21/12/2013, 03:15

... period data. In a circular orbit,   2 2 Ror , vT T R v  Thus  2 d)s40086,d)(137sm10(12 10 2 )ds 86,400d 137) (sm1036( 33 Randm,1078.6R ,   βα m.1026.2 10  Now find the sum of the ... y.248c) m.104.55m)1050.4)(010.01( 1212  T Note: to obtain the numerical results given in this chapter, the following numerical values of certain physical quantities have been used; kg.109...

Ngày tải lên: 21/12/2013, 03:15

... as ., 2 1 1 2 1 2 1 1 2 γγ V V p p V V T T                    K.298)32(K)350(atm,27.2)32(atm)00.4(,b) K.267)32K)(350(atm,04.2)32atm)(00.4(,) 5 2 5 7 3 2 3 5 22 5 7 22 3 5   Tpγ Tpγa 19 .37: a) b) From Eq. (19.25), )C(40.0K)molJ(12.47mol)(0.450  TnCW V J.224 WWQU flow.heat

Ngày tải lên: 21/12/2013, 03:16

...  J.1090.8 K)K)(25.0kgJ4190(K)K)(5.0kgJ2100(kgJ10334kg)80.1( 5 3   b) J.1 037. 3 5 40.2 J1008.8 || 5 C   K Q W c)  || that (noteJ101.14J108.08J1 037. 3|||| H 655 CH QQWQ ).)1(|| 1 C K Q  20.13: a) J.215J335J550|||| CH  QQ b) K .378 J)550JK)(335620(|)|||( HCHC  ... J.2600J6400J9000 J9000 J2600  20.3: a) %.0.23230.0 100,16 370 0  b) J.12,400J3700J100...

Ngày tải lên: 21/12/2013, 03:16

...        s/)s(/H/ RL units of time. 30.28: a) πf LC ω 2 1  .H1 037. 2 )F1018.4()106.1(4 1 4 1 3 1226222       Cf L b) F.1067.3 )H1 037. 2()1040.5(4 1 4 1 11 3252 min 22 max       Lf C 30.56: ... s.1032.3 2 1 ln )2(120 H115.0 2 1 ln 2 2 1 4 )/(2                    R L t e tLR 30.23: a) A.250.0 240 V60 0    R I  b) A. 137. 0A)250.0( )s...

Ngày tải lên: 17/01/2014, 04:20