... for i := 0 to m do Li,0 := 0 for j := 0 to n do L0,j := 0 len := 0 answer := <0,0> for i := 1 to m do for j := 1 to n do if Ai ≠ Bj then Li,j := 0 ... SUBSEQUENCE(A,m,B,n) for i := 0 to m do Li,0 := 0 for j := 0 to n do L0,j := 0 for i := 1 to m do for j := 1 to n do if Ai = Bj then Li,j := 1 + Li-1,j-1 ... then:mi, j = 0, if i = j, andmi, j = MINi ≤ k < j { mi,k + mk+1,j + ri-1rkrj }, if i < j. The algorithm: for i := 1 to n do mi,i := 0 for length := 1 to n-1 do for i := ...