... objects. Listing 16- 2: Reading the Number of Anchors <HTML> <HEAD> Note 305 Chapter 16 ✦ The Document Object <TITLE>document.anchors Property</TITLE> <SCRIPT LANGUAGE=" ;JavaScript& quot;> function ... take JavaScript. Review the document object’s place within the JavaScript object hierarchy. Figure 16- 1 clearly shows that the document object is a...
Ngày tải lên: 10/12/2013, 15:15
... ways in which JavaScript enables scripters to manipulate strings. Much of the syntax you see in this chapter is identical to that of the Java programming language. Because the scope of JavaScript ... window 26 26 CHAPTER ✦ ✦ ✦ ✦ In This Chapter How to parse and work with text Performing search- and-replace operations Scripted alternatives to text formatting ✦ ✦ ✦ ✦ 546 Part III ✦ J...
Ngày tải lên: 21/12/2013, 05:17
Tài liệu Javascript bible_ Chapter 29 pdf
... spreadsheet. In JavaScript, arrays are limited to a table holding one column of data, with as many rows as needed to hold your data. As you have seen in many chapters in Part III, a JavaScript- enabled ... applications (Chapter 48) on the CD-ROM, I show you an extended version of this usage in a page that lets users search a small table of data for a match 29 29 CHAPTER ✦ ✦ ✦ ✦ In This...
Ngày tải lên: 21/12/2013, 05:17
Tài liệu Javascript bible_ Chapter 30 pdf
... that power to JavaScript. Most of the benefit of JavaScript regular expressions accrues to those who script their CGI programs with LiveWire on Enterprise Server 3 or later. The JavaScript version ... accuracy. Helping the procedure in JavaScript regular expressions is the string.replace() method that has been added to the language with JavaScript 1.2 (see Chapter 26). The method r...
Ngày tải lên: 21/12/2013, 05:17
Tài liệu Javascript bible_ Chapter 33 pdf
... key, 33 33 CHAPTER ✦ ✦ ✦ ✦ In This Chapter Event support in different browser generations How to retrieve information from an event The many ways to assign event handlers ✦ ✦ ✦ ✦ 694 Part III ✦ JavaScript ... follows: 687 Chapter 33 ✦ The Event Object document.forms[0].age.onchange = new Function(“event”, “document.forms[0].age”) Or, if the script is written in a <SCRIPT LANGUAGE=...
Ngày tải lên: 21/12/2013, 05:17
Tài liệu Javascript bible_ Chapter 48 pdf
... of the HTML coming in with the document. 48 48 CHAPTER ✦ ✦ ✦ ✦ In This Chapter Serverless data collection lookup Data-entry validation ✦ ✦ ✦ ✦ 12 JavaScript Applications The kind of data I’m talking ... say you can’t let your JavaScript- enhanced document act as a front end to data files of other types on your server. In fact, Chapter 51 presents an application that uses JavaScript...
Ngày tải lên: 24/01/2014, 10:20
Tài liệu Physics exercises_solution: Chapter 04 pdf
... speed. c) N.1028.2)m/s1050.2)(kg1011.9( 162 1431 maF 4.15: .N1094.2)m/s80.9)(m/s12)(N2400()/( 322 gawmaF 4 .16: .m/s0.22)m/s80.9( 2.71 160 / 22 g w F gw F m F a 4.17: ... so N4532)s/m80.9s/m6.50)(kg0.75()( 22 gamF . As a fraction of his weight, this force is 16. 61 g a mg F (keeping an extra figure in the intermediate calculation of...
Ngày tải lên: 10/12/2013, 12:15
Tài liệu Physics exercises_solution: Chapter 14 pdf
... m680.0)1000.1106.13)(m0500.0()( 33 wmmw ρρhh The volume of water is 33424 cm816m108 .16) m10m)(12.0(0.680A hV 14 .16: a) Gauge pressure is the excess pressure above atmospheric pressure. The ... Pa.1 016. 3m250.0sm80.9mkg1000Pa706 323 14.10: a) The pressure used to find the area is the gauge pressure, and so the total area is 2 3 3 cm805 )Pa10205( )N105...
Ngày tải lên: 10/12/2013, 12:15
Tài liệu Physics exercises_solution: Chapter 15 pdf
... pulley, and the speed of a transverse wave on the string is s.m3 .16 )mkg0550.0( )sm80.9)(kg50.1( 2 μ F v b) m.136.0)Hz120()sm3 .16( fv c) The speed is proportional to the square root ... no part of the string except for ,2Lx oscillates with a single frequency. 15.45: a) Hz.0.16m,00.32 )m50.1(2 )sm0.48( 2 11 L v fL b) Hz.0.483m,00.13 1213 ff c) Hz.0.644m,7...
Ngày tải lên: 10/12/2013, 12:15
Tài liệu Physics exercises_solution: Chapter 16 ppt
... unbearable. 16. 4: The values from Example 16. 8 are Hz,1000Pa,1 016. 3 4 fB m.102.1 8 A Using Example 16. 5, ,sm295sm344 293K K 216 v so the pressure amplitude of this wave is Pa).1 016. 3( 2 4 max ... amount of energy. 16. 16: From Eq. (16. 13), ,2 2 max BvpI and from Eq. (19.21), . 2 Bv Using Eq. (16. 7) to eliminate .22, 2 max 2 max ρBpBpρBIv Us...
Ngày tải lên: 10/12/2013, 12:15