... BI111BI1 2 2BI10HT0BI1I 4, 545 I = 2, 273 22 I 1 ,29 3I = 0, 647 22 I 1,0 14 I = 0,507 22 ΣΣ==−= =−−= =−1 2 0HT 2 BI1I III = a + a + 2 22 13 13 = 2, 273 + (-0, 647 ) - 0,507 22 22 = -1, 320 - j2, 529 ... – K26 Trang 24 00BI2I 3 ,25 2I = 1, 626 22 Σ−= =−1 20 2 BI2I III = a + a + 2 22 13 13 = 2, 273 + (-0, 647 ) -1, 626 22 22 = -2, 43 9 - j2, 529 3,513jjΣ ΣΣ−− −+=g ggIBI4 ... KT – K26 Trang 27 N(1,1) 8,916 0 0 0, 9 24 N(1) 9,013 0 0 0, 823 N(3) 2, 9 24 2, 9 24 0 0 N(1,1) 2, 853 3,513 0 2, 700N 2 N(1) 2, 821 3,6590 2, 025 N(3) 2, 9 24 -2, 9 24 0 0 N(1,1) 2, 853...