Geophysics lecture chapter 4 seismology
Geophysics lecture chapter 4 seismology
... using Eq 4. 49 and Eq 4. 38, Eq 4. 50 (the equation of motion) becomes : ω2Φ = ω Ψ = −α2 ∇ · u −β ∇ × u We thus easily get : (4. 51) (4. 52) CHAPTER SEISMOLOGY 152 (A) (B) Figure by MIT OCW Figure 4. 3: ... rotational component of the displacement field by comparing Eq 4. 36 and 4. 42 It is often much easier to solve the wave equations (4. 41) and (4. 43) than to solve the equation o...
lecture chapter 4 frequency domain processing
... of filtering f in the spatial domain with the Sobel mask process in the frequency domain Obtain Frequency Domain Filters from Spatial Filters Obtain Frequency Domain Filters from Spatial Filters ... 'FontSize', 14) subplot(2, 2, 2);imshow(F);title('Fourier tranform fft2',… 'FontSize', 14) subplot(2, 2, [3 4] ); imshow(F0);title('Centered spectrum: ifft2',… 'FontSize', 14) Filt...
Geophysics lecture chapter 1 the earth in the solar system
... Pb 204 Pb � = 4.46 (1. 36) 16 CHAPTER THE EARTH IN THE SOLAR SYSTEM The age information is contained in the slope, M , using only isotopes of Pb The value of 235 U/238 U is 1/ 137.88, and this ratio ... (1. 1) in terms of the mass of the sun and doing so yields L = mr2 ω = (GMs )1/ 2 mr1/2 (1. 6) By integrating (1. 6) over all the planets we find that while the...
Geophysics lecture chapter 2 the earths gravitational field
... (2. 48) g(λ) = = = = GM sin2 λ − (1 + 2f sin2 λ) − 3J2 − m(1 − sin2 λ) a 2 GM (1 + J2 − m) + 2f − J2 + m sin2 λ a 2 2f − (9 /2) J2 + m GM (1 + J2 − m) + sin2 λ a2 + (3 /2) J2 − m GM (2. 53) (1 + J2 ... sin2 λ g = GM 3GJ2 M a2 − a2 (1 − f sin2 λ )2 a4 (1 − f sin2 λ)4 − aω (1 − f sin2 λ) cos2 λ sin2 λ − 2 (2. 52) 2. 2 GRAVITATIONAL POTENTIAL DUE TO NEARLY SPHERICAL BODY49 or, with th...
Geophysics lecture chapter 3 the magnetic field of the earth
... all of opposite sign than those of the main field This indicates a weakening of the dipole field From the numbers in CHAPTER THE MAGNETIC FIELD OF THE EARTH 98 Table 7.1 of Stacey and eq (3. 43) ... solution of the vector diffusion equation is z z H = H0 e− δ ei(ωt− δ ) (3. 65) CHAPTER THE MAGNETIC FIELD OF THE EARTH 104 with δ= ωσµ0 (3. 66) the sk...
Geophysics lecture chapter 5 geodynamics
... change in volume dρ (5. 53) Substitution of (5. 52) and (5. 53) in (5. 51) and using (5. 48) gives the AdamsWilliamson equation: dρ =− dr � ρ κS � ρGm(r) ρGm(r) =− r2 Φr2 (5. 54) 5. 6 THE UPPER MANTLE ... −k (5. 14) with ∂ erf(η) ∂η = ∂ √ ∂η π �η ∂ √ π ∂η �η e−u du = 2 e−u du = √ e−η π (5. 15) so that q = −k (Tm − Ts ) −η2 √ e πκt (5. 16) 204 CHAPTER Age (Ma) GEODYNAMICS 100 Depth (km) 3...
Data Mining Classification: Basic Concepts, Decision Trees, and Model Evaluation Lecture Notes for Chapter 4 Introduction to Data Mining pptx
... same data! 10 © Tan,Steinbach, Kumar Introduction to Data Mining Decision Tree Classification Task Decision Tree © Tan,Steinbach, Kumar Introduction to Data Mining Apply Model to Test Data Test Data ... P(C2) = 4/ 6 Error = – max (2/6, 4/ 6) = – 4/ 6 = 1/3 Introduction to Data Mining 43 Comparison among Splitting Criteria For a 2-class problem: © Tan...
ECE CS 372 introduction to computer networks lecture 1 chapter 4
... block 11 0 010 00 00 010 111 00 010 000 00000000 200.23 .16 .0/20 Organization Organization Organization 11 0 010 00 00 010 111 00 010 000 00000000 11 0 010 00 00 010 111 00 010 010 00000000 11 0 010 00 00 010 111 00 010 100 ... interface 223 .1. 1 .1 223 .1. 1.2 223 .1. 1 .4 223 .1. 1.3 223 .1. 2 .1 223 .1. 2.9 223 .1. 3.27 223 .1. 2.2 223 .1. 3.2 223 .1. 3 .1 223 .1. 1 .1 = 11 011...
Chapter 4: Getting Images into and out of Photoshop
... Dodge and Burn tools The digital fountain of youth At the end of Chapter 5, I show an example of using the Dodge tool to fade wrinkles without removing them completely Photoshop, being a complex and ... again, and repeat a number of times to create a series of paw prints marching into the distance Figure 8- 14: The many faces of transformations The mask-related selecti...
Tài liệu động cơ FORD 6.4L P1- Chapter 4
... diesel particulate filter reads a constant value while the engine is running P 244 C X P 244 D X X REGEN X P 245 3 X KO P 245 4 X Diesel Particulate Filter Differential Pressure Sensor Circuit Low This ... fulcrum plates #1,2,7,8 per steps 4- 6 If #8 intake pushrod shows cam lift, this is the #4 firing position Torque only fulcrum plates #3 ,4, 5,6 per steps 4- 6 Step 4: Partially run dow...
Mechanisms and Mechanical Devices Sourcebook - Chapter 4
... mesh with every lobe on gear 4, and T3/T4 = L3/L4 = 2/3, where T3 and T4 are the numbers of teeth on gears and T1 and T2 will denote the numbers of teeth on gears and 98 and S = ∆θ 3/θ30 Hence θ30(1 ... bottom of a tooth well and is in a position to prevent counter-rotation Sclater Chapter 5/3/01 10 :44 AM Page 97 ODD SHAPES IN PLANETARY GIVE SMOOTH STOP AND GO This interm...
Bài giảng marketing quốc tế CHAPTER 4
... sản phẩm mà nhóm khách hàng đònh mua đòa bàn đònh khoảng thời gian với môi trường chương trình marketing đònh Làm để đánh giá dự báo nhu cầu? Căn vào: * Ý kiến: Chuyên gia, khách hàng, nhân viên ... DN nhỏ, thành lập, vốn yếu * Chuyên biệt hóa sản phẩm, phân phối,…để thích hợp với khách hàng 14 PHÂN TÍCH CẠNH TRANH • Mục tiêu đối thủ cạnh tranh gì? • • • • • • • • Họ tìm kiếm thò trường?
Máy đào HuynDai R170W-9 (Phần 2) - Chapter 4
... S82 2-0 140 00 - CR-29 - Travel forward relay - - CR-30 - Travel reverse relay - - CR-35 - Power relay - - CR-36 - Preheat relay - - CR -4 5 - ECM power relay - - CR -4 6 - Fuel warmer relay - - CR -4 7 - ... relay - - CR-62 - Breaker relay - - CR-66 - Parking relay - - CR-78 - Head lamp power...
Máy xúc lất HuynDai HL760 - Chapter 4
... Resistance 24V 10W normal : 1.2Ω Room lamp 24V 10W Work lamp, Room lamp, Numbaer plate lamp CL-1 CL-6 CL-1 CL-21 CL-32 CL-22 CL-35 CL-5 CL-21 CL-5 CL-22 CL-33 CL-23 CL-6 CL-23 CL- 34 7-5 3 Part name ... pin 1~2) 0Ω(for pin 3 ~4) ∞Ω(for pin 3~5) Relay (5 pin) 24V 20A CR-2 CR-7 CR-38 CR-60 CR-3 CR-26 CR-55 CR-63 CR -4 CR-36 CR-58 CR-79 Hydraulic temperature C - CD-1 Speaker 4 20W Check...
Lập trình hệ điều hành Chapter 4
... C có hai thành phần x Vấn đề xảy ra: Giả sử lớp A có thành phần x Trong lớp B có thành phần x Xây dựng lớp C kế thừa từ lớp A B Khi truy cập thành phần x C chương trình dịch thành phần ... sở trình tự thực tuân theo trình tự kế thừa Object Oriented Programing– Information Systems Department 16 Hàm khởi tạo hàm huỷ b Hàm huỷ Hàm huỷ lớp sở không kế thừa Các hàm huỷ thi hành theo...
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