PRINCIPLES OF COMPUTER ARCHITECTURE phần 1 pdf
... base 16 digit in binary. In general, k bits are needed to Binary (base 2) 0 1 10 11 10 0 10 1 11 0 11 1 10 00 10 01 1 010 10 11 110 0 11 01 111 0 11 11 Octal (base 8) 0 1 2 3 4 5 6 7 10 11 12 13 14 15 16 17 Decimal (base ... AND OUTPUT 311 8 .1 S IMPLE BUS ARCHITECTURES 312 8 .1. 1 Bus Structure, Protocol, and Control 313 8 .1. 2 Bus Clocking 314 8 .1. 3 The S...
Ngày tải lên: 14/08/2014, 20:21
... 00000 011 3096: 10 0 010 10 10 0000 01 011 00000 000000 01 310 0: 10 0000 01 110 00 011 11 100000 0000 010 0 310 4: 10 0 010 10 10 0000 01 011 00000 000000 01 310 8: 000 011 11 0 011 111 1 11 111 111 11 111 111 311 2: 10 000000 10 0000 01 ... 10 0000 01 110 00000 0000 011 1 311 6: 10 0000 01 110 00 011 11 100000 0000 010 0 312 0: 00000000 00000000 00000000 00000000...
Ngày tải lên: 14/08/2014, 20:21
... Systems 99 Management of Input and Output 99 Processes and Scheduling 10 1 Threads 10 2 Synchronization 10 3 Semaphores 10 6 Monitors 10 8 Deadlock 11 1 Scheduling 11 4 Memory Management 11 6 Memory Management ... Trojan Horses 17 5 Hackers 17 6 Can Computers Kill? 17 7 Summary 17 8 Review Questions 17 9 APPENDIX Answers to Review Questions 18 0 Index 217 CONTENTS vii SCHAUM’...
Ngày tải lên: 12/08/2014, 21:22
Schaum’s Outline Series OF Principles of Computer Science phần 9 pdf
... base -10 numbers to base-2: 37 470 12 20 17 99 10 010 1 11 1 010 110 10 011 00 010 0 10 0 01 110 0 011 3.6 Convert the following base-2 numbers to base -10 : 0000 011 1 7 10 1 010 10 17 0 0 011 10 01 57 010 1 010 1 85 0 011 0 011 51 3.7 ... represented? a 32,767 b 010 0 010 00 010 0000 c 11 111 111 111 011 00 d -32,768 ANSWERS TO REVIEW QUESTIONS 18 5 18 0 Answers to Revie...
Ngày tải lên: 12/08/2014, 21:22
PRINCIPLES OF COMPUTER ARCHITECTURE phần 2 doc
... multiplier 1 +1 Add Subtract 11 11 00000 0 011 10 010 00 ( 14 × 1) 10 (14 × 2) 10 1 00 0 0 0 011 10 01 1 11 111 000000 0 011 10 01 1 11 1 0000 0 011 0 0 0 0 0 0 0 0 0 0 0 0( 14 × 4) 10 (14 × 8) 10 ( 14 × 16 ) 10 (14 ... x 1 (2 − x 1 b) = 1. 010 010 1 (10 − (1. 010 010 1)( .10 110 11) ) = 1. 011 0 010 110 010 010 111 01. We iterate again, obtaining our t...
Ngày tải lên: 14/08/2014, 20:21
PRINCIPLES OF COMPUTER ARCHITECTURE phần 3 pps
... place. Example usage: sethi 0x304F15, %r1 Meaning: Set the high 22 bits of %r1 to (304F15) 16 , and set the low 10 bits to zero. Object code: 00000 011 0 011 0000 010 011 110 0 010 1 01 Instruction: andcc Description: ... 3e1b 1c60 3eb1 00f0 0000 00 01 000b 0000 000e 0003 0000 0004 010 0 0008 0006 000c 0002 00 01 0007 0005 00 01 011 0 0008 0000 001d 00 01 00 01 0000 0005 2ab7 012...
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PRINCIPLES OF COMPUTER ARCHITECTURE phần 4 pptx
... 0 010 1 010 011 010 10 10 1 011 11 1 011 110 1 11 111 110 11 111 111 000 011 11 1 010 1 010 11 111 111 00 010 1 01 110 1 010 1 0 010 1 010 11 111 1 01 111 111 11 011 110 00 011 010 01 0 010 10 01 011 111 11 1000 010 0 11 10 011 1 Figure 5 -11 The ... 10 0 011 01 011 0 011 0 10 1 010 10 0 010 1 011 011 010 10 11 010 1 01 0 010 1 010 10 110 011 00000000 011 0 011 0 10 1 010...
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PRINCIPLES OF COMPUTER ARCHITECTURE phần 5 ppsx
... # 0 1 2 3 4 5 6 7 1 0 1 0 1 0 0 1 00 xx 01 xx 11 xx xx 10 Disk address Page frame 010 010 111 00 11 1 011 10 010 10 110 010 111 000 010 011 11 010 111 0 010 1 10 10 011 10 01 0 011 010 110 0 010 100 010 11 Figure 7-22 A page table for a virtual ... slot 0 1 2 3 012 3 010 0 0000 11 00 11 10 0 1 2 3 012 3 0000 10 11 1000 10 10 0 1 2 3 012 3 011 1 0 011...
Ngày tải lên: 14/08/2014, 20:21
PRINCIPLES OF COMPUTER ARCHITECTURE phần 6 pot
... blocks 11 05 11 27 2234 ab.c 1 10 8 3952 212 0 11 0 11 1 12 5 . . . . . . 11 3 257 . . . Creation Date Last Modified Owner Protec- tions 11 /14 /93 11 /14 /93 16 RWX by 10 :30:57 19 :30:57 Owner 8 /18 /93 1/ 21/ 94 20 RX - All 16 :03 :12 ... entering data from maps, pho- 99 00 01 02 03 04 05 06 07 08 09 10 11 12 13 14 15 16 17 18 F E D C B A Z QWE R T Y U I OP ASDFG...
Ngày tải lên: 14/08/2014, 20:21
PRINCIPLES OF COMPUTER ARCHITECTURE phần 7 potx
... transmitted frame T(x) = M(x) + R(x) gets corrupted dur- 11 010 110 110 000 10 011 11 000 010 10 10 011 ⊕ 10 011 10 011 ⊕ 1 10 011 ⊕ 010 10 10 011 ⊕ 11 10 0 1 1 0 0 G(x), of degree n = 4 M(x) n = 4 zeros Bitwise exclusive ... transmitted: 1 1 1 1 1 1 1 1 0 0 0 0 0 0 0 0 0 0 Code 0 0 1 0 1 1 0 0 1 P 0 0 0 0 0 0 0 0 0 Character A B C D E F G H Checksum 0 0 0 0...
Ngày tải lên: 14/08/2014, 20:21