VHDL Programming by Example phần 1 ppsx

VHDL Programming by Example phần 1 ppsx

VHDL Programming by Example phần 1 ppsx

... Functions 11 3 Resolution Functions 11 9 Procedures 13 3 Packages 13 5 Package Declaration 13 6 Deferred Constants 13 6 Subprogram Declaration 13 7 Package Body 13 8 Chapter 6 Predefined Attributes 14 3 Value ... Attributes 14 4 Value Type Attributes 14 4 Value Array Attributes 14 7 Value Block Attributes 14 9 Function Kind Attributes 15 1 Function Type Attributes 15 1 Function...

Ngày tải lên: 14/08/2014, 00:21

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giáo trình Java By Example phần 1 ppsx

giáo trình Java By Example phần 1 ppsx

... information, address Que Corporation, 2 01 W. 10 3rd Street, Indianapolis, IN 46290. You may reach Que's direct sales line by calling 1- 800-428-53 31. ISBN: 0-7897-0 814 -0 http://www.ngohaianh.info To ... Credits Java By Example Copyright© 19 96 by Que® Corporation All rights reserved. Printed in the United States of America. No part of this book may be used or reproduced...

Ngày tải lên: 22/07/2014, 16:21

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Linux Socket Programming by Example PHẦN 1 pot

Linux Socket Programming by Example PHẦN 1 pot

... unix 1 [ ] STREAM … 549 - @00000023 14 : unix 1 [ ] STREAM 10 32 662/01lst 01 15: unix 1 [ ] STREAM 10 31 662/01lst 01 16: unix 1 [ ] STREAM … 793 - /dev/log 17 : unix 1 [ ] STREAM … 582 - /dev/log 18 : ... 1 [ ] STREAM … 406 - @00000 019 9: unix 1 [ ] STREAM … 490 - @0000001f 10 : unix 1 [ ] STREAM … 518 - @00000020 11 : unix 0 [ ] STREAM … 11 7 - @00000 011 12 : u...

Ngày tải lên: 12/08/2014, 21:20

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Linux Socket Programming by Example PHẦN 10 ppsx

Linux Socket Programming by Example PHẦN 10 ppsx

... 2008900 RHAT 213 .500 11 /26 /19 99 1: 00PM +44.562 18 4.000 219 .938 18 1.000 2296600 COB 8. 312 11 /24 /19 99 1: 00PM +1. 188 0.000 8.375 7. 312 316 300 ATYT 10 .375 11 /26 /19 99 12 :59PM +0.438 10 .250 10 .375 10 .12 5 80800 This ... 11 /26 /19 99 1: 01PM -0 .18 8 79.688 79.688 78.938 3 917 00 MOT 11 9.0 31 11/ 26 /19 99 1: 48PM +2.094 11 8.562 12 0.688 11 7.750 1...

Ngày tải lên: 12/08/2014, 21:20

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VHDL Programming by Example phần 2 pps

VHDL Programming by Example phần 2 pps

... 0; IF (a = 1 ) THEN muxval <= muxval + 1; END IF; IF (b = 1 ) THEN muxval <= muxval + 2; END IF; CASE muxval IS WHEN 0 => q <= I0 AFTER 10 ns; WHEN 1 => q <= I1 AFTER 10 ns; WHEN ... ARRAY(0 TO 1) OF BIT; VARIABLE bit_vec : vectype; . . CASE bit_vec IS WHEN “00” => RETURN 0; WHEN “ 01 => RETURN 1; WHEN 10 ” => RETURN 2; WHEN 11 ” => RETURN 3; END CASE;...

Ngày tải lên: 14/08/2014, 00:21

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VHDL Programming by Example phần 3 pptx

VHDL Programming by Example phần 3 pptx

... ‘0’), ( ( ‘0’, ‘0’, ‘0’, 1 ), ( ( ‘0’, ‘0’, 1 , ‘0’), ( ( ‘0’, ‘0’, 1 , 1 ), ( ( ‘0’, 1 , ‘0’, ‘0’), ( ( ‘0’, 1 , ‘0’, 1 ), ( ( ‘0’, 1 , 1 , ‘0’), ( ( ‘0’, 1 , 1 , 1 ) ); BEGIN ASSERT addr ... line 9 result := result + 1; line 10 END IF; END LOOP; RETURN result; line 11 END vector_to_int; BEGIN O1 <= vector_to_int(I1); line 12 END behave; Line 1 of the example declares the array...

Ngày tải lên: 14/08/2014, 00:21

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VHDL Programming by Example phần 4 ppt

VHDL Programming by Example phần 4 ppt

... ’0’, 01 ’0’), 0z (’x’, 1x ’0’, 10 1 , 11 ’x’), 1z (’x’, zx ’0’, z0 ’x’, z1 ’x’)); zz CONSTANT andmd : t_4valmd := ((’x’, xx ’0’, x0 ’x’, x1 ’x’), xz (Notice this example (’0’, 0x is a multidimensional ’0’, ... example (’0’, 0x is a multidimensional ’0’, 00 array.) ’0’, 01 ’0’), 0z (’x’, 1x ’0’, 10 1 , 11 ’x’), 1z (’x’, zx ’0’, z0 ’x’, z1 ’x’)); zz END p_4val; The two c...

Ngày tải lên: 14/08/2014, 00:21

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VHDL Programming by Example phần 5 potx

VHDL Programming by Example phần 5 potx

... ARRAY(t_nine_val) OF BIT; CONSTANT nine_2_bit : t_nine_val_conv := (‘0’, — Z0 1 , — Z1 1 , — ZX ‘0’, — R0 1 , — R1 19 1 Configurations to map the delays back to the model. Modifying the architecture ... generated: 10 20 50 16 #A <— hex input 1_ 2_3 <— underscores ignored 87 52 <— second argument ignored The output from the input file would look like this: 10 0 400 2500 1...

Ngày tải lên: 14/08/2014, 00:21

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VHDL Programming by Example phần 6 doc

VHDL Programming by Example phần 6 doc

... ; signal q2, q1: std_logic ; begin q2_XMPLR : FDSR1 port map ( Q=>q2, D=>q1, CP=>clk); q1_XMPLR : FDSR1 port map ( Q=>q1, D=>din, CP=>clk); dout_XMPLR_XMPLR : MU21S port map ( ... Delay Loading Delay Wire Delay A1 B1 C1 Figure 9-7 Delay Effects Used in Delay Model. Chapter Ten 252 c a d b out out in [1] in [0] in [1] in [0] Figure 10 -1 Model Implementation. Simple Gat...

Ngày tải lên: 14/08/2014, 00:21

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