Introduction to Algorithms Second Edition Instructor’s Manual 2nd phần 5 potx
Introduction to Algorithms Second Edition Instructor’s Manual 2nd phần 5 potx
... O(h) time, analogous to the changes we made for persistence in insertion. But to do so without using parent pointers we need to walk down the tree to the node to be deleted, to build up a stack ... keys are not distinct, because in order to Þnd the path to the node to delete—a particular node with a given key—we have to make some changes to how we store things in the tre...
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Introduction to Algorithms Second Edition Instructor’s Manual 2nd phần 8 potx
... A. We have to traverse B to update representative pointers anyway, so we can just make the last element of B point to the second element of A. Solution to Exercise 21.3-3 You need to Þnd a sequence ... edge it visits to the cycle C, which is then added to the Euler tour T , when we return from a call to VISIT(u), all edges entering or leaving vertex u have been added to th...
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Introduction to Algorithms Second Edition Instructor’s Manual 2nd phần 10 potx
... 25. 1-3, 25- 8 Exercise 25. 1 -5, 25- 8 Exercise 25. 1-10, 25- 9 Exercise 25. 2-4, 25- 11 Exercise 25. 2-6, 25- 12 Exercise 25. 3-4, 25- 13 Exercise 25. 3-6, 25- 13 Exercise 26.1-4, 26- 15 Exercise 26.1-6, 26-16 Exercise ... 14-13 Exercise 14.3-6, 14-13 Exercise 14.3-7, 14-14 Exercise 15. 1 -5, 15- 19 Exercise 15. 2-4, 15- 19 Exercise 15. 3-1, 15- 20 Exercise 15. 4-4, 15- 21 Exercise 16.1-2,...
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Introduction to Algorithms Second Edition Instructor’s Manual 2nd phần 1 pptx
... put in the “cost” and “times” columns later.] Example: 123 456 52 4613 123 456 254 613 123 456 2 456 13 123 456 2 456 13 123 456 2 456 13 123 456 2 4 5 61 3 j jj jj [Read this Þgure row by row. Each part shows ... Structures Lecture Notes 14-1 Solutions 14-9 Preface This document is an instructor’s manual to accompany Introduction to Algorithms, Second Edition, by Thom...
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Introduction to Algorithms Second Edition Instructor’s Manual 2nd phần 2 pps
... be. Solutions for Chapter 5: Probabilistic Analysis and Randomized Algorithms 5- 13 Although these probabilities add to 1, none are equal to 1/6. Solution to Exercise 5. 3-4 PERMUTE-BY-CYCLIC chooses ... cn,so we guess O(n log 1/α n) = O(n lg n). Solutions for Chapter 5: Probabilistic Analysis and Randomized Algorithms 5- 9 Solution to Exercise 5. 2-1 Since HIRE-ASSISTANT al...
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Introduction to Algorithms Second Edition Instructor’s Manual 2nd phần 3 docx
... B .5- 3), # of internal nodes = # of leaves − 1. Lecture Notes for Chapter 7: Quicksort 7-3 816403 95 p,j ri 816403 95 prj 186403 95 p,i rj 186403 95 p,i rj 1864 03 95 prji 18640 3 95 prji 13640 8 95 prji 13640 ... overview [The treatment in the second edition differs from that of the Þrst edition. We use a different partitioning method—known as “Lomuto partitioning”—in the secon...
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Introduction to Algorithms Second Edition Instructor’s Manual 2nd phần 4 pot
... pointer) to the new slot, and updating the pointer in the slot that pointed to j to point to the new slot. Then insert the new element in the now-empty slot as usual. To update the pointer to j , ... lists. If we want to delete elements, it’s better to use doubly linked lists.] • Slot j contains a pointer to the head of the list of all stored elements that hash to j [or t...
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Introduction to Algorithms Second Edition Instructor’s Manual 2nd phần 6 pps
... Programming a 1,1 e 1 enter e 2 a 2,1 a 1,2 a 2,2 t 1,1 t 2,1 t 1,2 t 2,2 a 1,3 a 2,3 t 1,3 t 2,3 a 1,4 a 2,4 t 1,4 t 2,4 a 1 ,5 a 2 ,5 x 1 x 2 exit S 1,1 S 2,1 S 1,2 S 2,2 S 1,3 S 2,3 S 1,4 S 2,4 S 1 ,5 S 2 ,5 2 4 7 8 2 2 9 3 1 5 348 3 13 22 6 45 6 Automobile factory with two assembly lines. • Each ... row-major order, i.e., row-by-row from top to bottom, and left to right within...
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Introduction to Algorithms Second Edition Instructor’s Manual 2nd phần 7 ppsx
... to go to get to 1 or 1/4, starting from 1/2, rate of increase of differs. • For α to go from 1/ 2to1 ,num increases from size /2tosize, for a total increase of size /2. increases from 0 to size. ... sorting A and B into monotoni- cally increasing order works as well. Lecture Notes for Chapter 16: Greedy Algorithms 16-3 Solution to S ij is (solution to S ik ) ∪ { a k } ∪ (s...
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Introduction to Algorithms Second Edition Instructor’s Manual 2nd phần 9 pdf
... weight 8: 1 24 35 minimum spanning tree 1 24 35 second- best minimum spanning tree 1 24 35 second- best minimum spanning tree b. Since any spanning tree has exactly | V | − 1 edges, any second- best ... + E) to compute G . • O(VE) to run BELLMAN-FORD. • (E) to compute w. • O(V 2 lg V +VE) to run Dijkstra’s algorithm | V | times (using Fibonacci heap). • (V 2 ) to compu...
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