Information Theory, Inference, and Learning Algorithms phần 2 ppt
Information Theory, Inference, and Learning Algorithms phần 2 ppt
... exercise 3 .2 (p.47). The probability of the data given each hy- pothesis is: P (D |A) = 3 20 1 20 2 20 1 20 3 20 1 20 1 20 = 18 20 7 ; (3. 32) P (D |B) = 2 20 2 20 2 20 2 20 2 20 1 20 2 20 = 64 20 7 ; ... Exercise 5 .20 . [2 ] Is the ternary code {00, 0 12, 0110, 01 12, 100, 20 1, 21 2, 22 } uniquely decodeable? Exercise 5 .21 . [3, p.106] Make Huffman cod...
Ngày tải lên: 13/08/2014, 18:20
Information Theory, Inference, and Learning Algorithms phần 6 pptx
... parameters ±0.11.] 22 .6 Solutions Solution to exercise 22 .5 (p.3 02) . Figure 22 .10 shows a contour plot of the 0 1 2 3 54 0 1 2 3 5 4 Figure 22 .10. The likelihood as a function of µ 1 and µ 2 . likelihood ... probability 0000000 0. 027 55 62 0 .25 0001011 0.0001458 0.0013 0010111 0.0013 122 0.0 12 0011100 0.0030618 0. 027 0100110 0.00 022 68 0.0 020 0101101 0.00009 72 0...
Ngày tải lên: 13/08/2014, 18:20
Information Theory, Inference, and Learning Algorithms phần 1 ppsx
... = K N K 2 −N 2 −N N N /2 N /2 r=−N /2 e −r 2 /2 2 2 −N N N /2 √ 2 σ, (1.41) where σ = N/4, from which equation (1.40) follows. The distinction between N /2 and N /2 is not important ... links. 34 2 — Probability, Entropy, and Inference revealing a binary variable whose probability distribution is { 1 / 2, 1 / 2} . This revelation has an entropy...
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Information Theory, Inference, and Learning Algorithms phần 3 pdf
... = −xα −∞ dy 1 √ 2 σ 2 e − y 2 2σ 2 = Φ − xα σ . (9.53) Random coding Solution to exercise 9 .20 (p.156). The probability that S = 24 people whose birthdays are drawn at random from A = 365 ... |x) is the same for each value of x: H(Y |x =0) is H 2 (0.15), and H(Y |x =1) is H 2 (0.15). So I(X; Y ) = H(Y ) −H(Y |X) = H 2 (0 .22 ) − H 2 (0.15) = 0.76 − 0.61 = 0.15 bits. (...
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Information Theory, Inference, and Learning Algorithms phần 4 potx
... links. 13 .2: Obsession with distance 20 7 w A(w) 0 1 5 12 8 30 9 20 10 72 11 120 12 100 13 180 14 24 0 15 27 2 16 345 17 300 18 20 0 19 120 20 36 Total 20 48 0 50 100 150 20 0 25 0 300 350 0 5 8 10 15 20 25 ... exp(−(y −x) 2 /2 2 )/ √ 2 σ 2 and set the derivative to zero: dy P (y |x) ln P (y |x) P (y) − λx 2 − µ = 0 (11.39) ⇒ dy exp(−(y −x) 2 /2 2 ) √ 2...
Ngày tải lên: 13/08/2014, 18:20
Information Theory, Inference, and Learning Algorithms phần 5 ppsx
... equilibrium [σ 2 (t + 1) = σ 2 (t)] then the factor in (19 .2) is α(1 + β /2) 1 /2 / √ 2 = 2 (π + 2) 0. 62. Defining this constant to be η ≡ 2/ (π + 2) , we conclude that, under sex and natural selection, ... below 1/β 1 /2 to above 1/β 1 /2 . The data variance is indicated by the ellipse. r 1 (x) = exp(−β(x 1 − m) 2 /2) exp(−β(x 1 − m) 2 /2) + exp(−β(x 1 + m) 2 /2)...
Ngày tải lên: 13/08/2014, 18:20
Information Theory, Inference, and Learning Algorithms phần 7 ppsx
... 4096 (a) -2 -1.5 -1 -0.5 0 2 2.5 3 3.5 4 4.5 5 Energy -2 -1.5 -1 -0.5 0 2 2.5 3 3.5 4 4.5 5 (b) 0.08 0.1 0. 12 0.14 0.16 0.18 0 .2 0 .22 0 .24 0 .26 0 .28 2 2.5 3 3.5 4 4.5 5 sd of Energy 0.015 0. 02 0. 025 0.03 0.035 0.04 0.045 0.05 2 ... for links. 414 32 — Exact Monte Carlo Sampling 0 50 100 150 20 0 25 0 0 5 10 15 20 0 50 100 150 20 0 25 0 0 5 10 15 20 0 50 100...
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Information Theory, Inference, and Learning Algorithms phần 8 docx
... thus computes P (r ≤ 3 |n = 12, H 0 ) = 3 r=0 n r 1 / 2 n = 12 0 + 12 1 + 12 2 + 12 3 1 / 2 12 = 0.07, (37 .27 ) and reports ‘at the significance level of 5%, there is not ... θ could either be 29 or 28 , and both possibilities are equally likely (if the prior probabilities of 28 and 29 were equal). The posterior probability of θ is 50% on 29 an...
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Information Theory, Inference, and Learning Algorithms phần 9 pdf
... exp − (x−x ) 2 2(0.35) 2 −3.0 −1.0 1.0 3.0 5.0 x −4.0 2. 0 0.0 2. 0 4.0 t −3.0 −1.0 1.0 3.0 5.0 x −4.0 2. 0 0.0 2. 0 4.0 6.0 t (c) 2 exp − sin 2 (π(x−x )/3.0) 2( 0.5) 2 (d) 2 exp − (x−x ) 2 2(1.5) 2 + ... links. 5 42 45 — Gaussian Processes −3.0 −1.0 1.0 3.0 5.0 x 2. 0 −1.0 0.0 1.0 2. 0 3.0 t −3.0 −1.0 1.0 3.0 5.0 x −4.0 2. 0 0.0 2. 0 4.0 t (a) 2...
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Information Theory, Inference, and Learning Algorithms phần 10 ppsx
... cyclic codes N 7 21 73 27 3 1057 4161 M 4 10 28 82 244 730 K 3 11 45 191 813 3431 d 4 6 10 18 34 66 k 3 5 9 17 33 65 0.0001 0.001 0.01 0.1 1 1.5 2 2.5 3 3.5 4 Gallager (27 3, 82) DSC (27 3, 82) Figure 47.18. ... 1s and 900 0s 2 266 10 80 Number of electrons in universe 2 200 1.6×10 60 2 190 10 57 Number of electrons in solar system 2 171 3×10 51 Number of electrons in the ea...
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