Failure Analysis Case Studies II Episode 5 pps
Failure Analysis Case Studies II Episode 5 pps
... Meetings, Paper
No.
8,
1987.
1043-1 054 .
assessment of actual failures.
TWI
Research Members Report 51 2/19 95, June 19 95.
Failure Analysis Case Studies
N
D.R.H.
Jones (Editor)
0
2001 ...
C,
cu
j=O
1
2 3
i=O
i=2
i=3
i=4
1.118
1.4 05
3.891
8.328
-0.179
-20.370
5. 902
21.8 95
-0.339 0.130
-9. 057 3.032
23.217 -7 .55 5
-
36.992 12.676
134
Second...
Failure Analysis Case Studies II Episode 3 pps
...
101
164.8
162.2
163.74
1 65. 13
162.24
164.10
166.73
Heat
of
fusion
(mJ mg-')
53 .48
54 . 85
53 .18
50 .11
49.21
50 .96
48.69
maxima at about 1 65 C. However, there are differences ... together.
*Corresponding
author.
Tel.:
01908
653 271;
fax:
01908
653 858 .
Reprinted
from
Engineering Failure Analysis
6
(4),
197-214
(1999)
59
components having...
Failure Analysis Case Studies II Episode 13 ppsx
...
Region
111
Fe
35. 3 27.0 24.6 36.0 80.7 75. 8 92.6 96.3
Cu
56 .6 63.7 65. 1
55 .4 14.6
18 .5 4.4 1
.o
AI
4.6 5. 6 5. 5 4.9 1.2
1.8
0.2
0.4
Mn
1.0 1.1 1.2
1
.O
0 .5
0.8
0.3
0.4
Cr ... Laboratory,
5. Widner,
R.
L.
and Wolfe,
J.
O.,
Merul Progress, April 1968, pp. 52 -59 .
51 3.
130-1 34.
Wright Research and Development Center,
OH
454 33- 653 3, pp. 206,...
Failure Analysis Case Studies II Episode 1 pot
...
HV
~TS
(MW
k,
(MPa)
0
350 1120 700
10 360 1 152 720
17 .5 3 75 1200 750
22 .5
400
1280 800
Case 880 2816 1760
measured hardness at the centre is HV
350 ,
which agrees well with the ... it is not to involve frame bending
FAILURE ANALYSIS
CASE
STUDIES I1
A sourcebook
of
case studies selected
from
the pages
of
Engineering Failure Analysis
1997- 1999...
Failure Analysis Case Studies II Episode 2 docx
...
6
(a)
~~
9
40-140
1 65 5 75
10+30
90-130 62
250 0
11+27 75- 150
35
55 00
11+ 25 85- 1 45 1 35 7 85
12
95- 140
46
3800
12 +50
65
50
3400
6.9
3.8
1.4
3.9
2 .5
3.0
where
Ay
=
pipe ...
Fig.
4.
DCP
sounding
data.
Failure Analysis
Case
Studies
II
D.R.H.
Jones (Editor)
0
2001
Elsevier
Science
Ltd.
All
rights
reserved
45
Torsion...
Failure Analysis Case Studies II Episode 4 pdf
...
d
=
2700mm
=
2.7m
p
=
154 0
kgm-3
g
=
9.81 m
s-2
ozul
=
2 .54 Nmm-’
=
2 .54 ~ 106Nm-*
The equation for
s
becomes
2.7 x 154 0 x 9.81
x
h
2 x
2 .54
x
106
S=
1.82~
=
1.46~ ... Figs
5
and
6.
Longitudinals starboard
of
centre girder
(numbering from centre girder)
1 Brittle fracture
2
Brittle fracture
3
Brittle fracture
4 Brittle fracture
Failure An...
Failure Analysis Case Studies II Episode 6 docx
... Failure Analysis Case Studies
II
D.R.H. Jones (Editor)
0
200
1
Elsevier Science Ltd.
All
rights reserved
1 85
FATIGUE FAILURE OF THE DE HAVILLAND COMET ... the wall thickness. Taking
D
as ca 45 mm and
t
as 2 .5 mm together with the value ofp as 25 psi, then the hoop stress is thus
about 2 25 psi or about 1 .55
MN
m-*, a relatively benign stress ...
0.01 0.01...
Failure Analysis Case Studies II Episode 7 ppt
...
4
5
6
Mean
156 7
50 2 2310 130 42
191
1732
630 2420 143 52 200
1780
58 3 2169
147
48
1
80
2024 57 5 2288 168 48
189
1970
620 2222 163 51
184
158 2
6 25 2 156 131 52 179
1776 58 9 ...
(pa)
(pa)
(MPa) (MPa)
SI
1328 16 85
I10
I40
s2
1408
1628
I17
1 35
53 152 4
1602
126 133
s4 1 452
159 7
121
132
s5
1386 154 0
1 15
128
Trip
1
-
57
-...
Failure Analysis Case Studies II Episode 8 ppt
...
Fatigue bend stress
(MW
15
30
45
60
75
90
1 05
120
1 35
150
I 65
180
1 95
210
2 25
240
255
270
2 85
19
38
58
17
96
1 15
1 35
154
173
192
212
23
1
250
269
289
308
327 ... stress
Cycles to failure
(Ib) (MPa)
~
15
30
45
60
75
90
1 05
120
1 35
150
1 65
180
1 95
210
2 25
240
255
270
2 85
23
47
70
93...
Failure Analysis Case Studies II Episode 9 potx
... 14
16
PH
Fig. AI.
Zn02
1-
h
5.
c.
e
0-+.
Zn(0H)j
passivation
-+
.
corrosion
zn2+
-
-
.
._
corrosion
-I
-
Zn
immunity
IIIIIIIII
-2
0
2 4
6
8
10 12 14
16
PH ...
ions can be estimated from Eqn
(5) .
The ionic mass of CI- is 35, and the molar mass of NaCl is
58 .
The 250 ppm of C1- is therefore equivalent to (58 / 35)
x
250 =414ppm of NaC1. The ioni...