... x x 2. Giải bpt : 1 2 1 2 3 2 12 0 x x x 3. Tính tích phân 4 2 2 0 cos sin I x x dx Câu III: Cho hình chóp đều S.ABCD có cạnh bằng a, cạnh bên SA bằng 2 a . a/ ... trình 2 1 0 x x trên tập số phức 2. Theo chương trình nâng cao : Cõu IV.b 1. Viết PT mp đi qua A(3,1,-1), B (2, -1,4) và vuông góc với mặt phẳng ( ) : 2x – y + 3z + 4 =0...
Ngày tải lên: 30/03/2014, 23:20
Ngày tải lên: 10/07/2014, 22:21
lubricants and hydraulic fluids Episode 2 Episode 10 pptx
... Mobilgear 1 629 Lock and -28 .8 to 37.7 Lubriplate 2 Weeks Stainless None Lubriplate Lubricating Dam No. 12, ( -20 to 100) 124 2 Gun steel 124 2 Brush Eng. IA Almasol 607 SAE 90, yearly Lock and -28 .8 to ... Good IL ( -20 to 120 ) Copper Coat Manual SHC 22 0 Gun Mobilith Gun in cold Gear Grease SHC 22 0 temperature. Marmet, -28 .8 to 43.3 Chesterton Kendall L- Monthly WV ( -20 to 110) 7...
Ngày tải lên: 12/08/2014, 16:20
MODELLING OF MECHANICAL SYSTEM VOLUME 2 Episode 4 pptx
... GS ∂Y s ∂x 2 + ∂Z s ∂x 2 dx + 1 2 L 0 GJ T ∂ψ x ∂x 2 + EI z ∂ 2 Y b ∂x 2 2 + EI y ∂ 2 Z b ∂x 2 2 dx [3 .2] The kinetic energy E κ is: E κ = 1 2 L 0 ρS{ ˙ X 2 + ( ˙ Y s + ˙ Y b ) 2 + ( ˙ Z s + ˙ Z b ) 2 }dx + 1 2 L 0 ρ(J ˙ ψ 2 x + I y ˙ ψ 2 y + ... ES ∂X ∂x − a /2 −a /2 Eaz ∂ 2 Z ∂x 2 dz − αEa a /2 −a /2 ...
Ngày tải lên: 13/08/2014, 05:22
MODELLING OF MECHANICAL SYSTEM VOLUME 2 Episode 5 pptx
... get: ℓ n 0 Es ∂X ∂x 2 dx + ℓ n 0 EI ∂ 2 Z ∂x 2 2 dx ≃ E n S n ℓ n 0 ∂X n ∂x 2 2 dx +E n I n ℓ n 0 ∂ 2 Z n ∂x 2 2 dx =[X I Z I Z ′ I X J Z k Z ′ J ] K 11 K 12 K 13 K 14 K 15 K 16 K 21 K 22 K 23 K 24 K 25 K 26 K 31 K 32 K 33 K 34 K 35 K 36 K 41 K 42 K 43 K 44 K 45 K 46 K 51 K 52 K 53 K 54 K 55 K 56 K 61 K 62 K 63 K...
Ngày tải lên: 13/08/2014, 05:22
Castings 2 Episode 1 potx
... porosity 22 2 7.6 Growth of shrinkage pores 22 6 7.7 Final forms of shrinkage porosity 22 7 8. Linear contraction 23 2 8.1 Uniform contraction 23 2 8 .2 Non-uniform contraction (distortion) 23 7 8.3 ... Blowholes 20 0 7. Solidi$cation shrinkage 20 5 7.1 General shrinkage behaviour 20 5 7 .2 Solidification shrinkage 20 6 7.3 Feeding criteria 21 0 7.4 Feeding - the f...
Ngày tải lên: 13/08/2014, 08:21
Castings 2 Episode 2 docx
... the drop, 2yL. Hence pgh2L /2 = 2yL 5 giving h = 2( y/pg)’l2 (2. 2) Assuming that h = 2r approximately, and eliminating r from Equation 2. 1 we have (2. 3) Figure 2. 16 Balance ... 12. 8 0.50 AI 23 85 0.914 12. 5 0.50 Mg 159 0 0.559 12. 0 0.48 Fe 7 015 1.8 72 10.4 0.45 Ni 7905 1.778 9.6 0.43 cu 8000 1 .28 5 8.1 0.40 Zn 6575 0.7 82 7.0 0.37...
Ngày tải lên: 13/08/2014, 08:21
Castings 2 Episode 3 pot
... the film was pearlitic, indicating that some carbon 42 Castings Figure 2. 26 shows various situations where confluence problems occur in castings. Such locations have been shown to be predictable ... effect is illustrated schematically in Figure 2. 4 I. Such a room-temperature fracture surface is seen in Figure 2. 42 for an Al4.5Cu alloy (Mi 20 00) in which the fracture su...
Ngày tải lên: 13/08/2014, 08:21