REAL-TIME SYSTEMS DESIGN AND ANALYSIS phần 3 docx

... Ceiling S 1 τ 1 ,τ 2 P(τ 1 ) S 2 τ 1 ,τ 2 ,τ 3 P(τ 1 ) S 3 τ 3 P(τ 3 ) S 4 τ 2 ,τ 3 P(τ 2 ) t 1 t 2 t 3 t 1 t 2 t 3 t 4 t 5 t 6 t 7 t 8 Acquire S 2 Attempt t 0 Acquire S 1 Acquire S 1 Acquire S 1 Acquire S 2 Figure 3. 18 Illustration ... at t 6 and lets τ 3 execute to completion at t 7 .Taskτ 3 is then allowed to lock S 1 , and subsequently S 2 ,and completes at t 8 ....

Ngày tải lên: 13/08/2014, 08:20

... evolved, particularly for real-time systems, that provide various approaches to addressing the real-time communication and synchronization problem (e.g., [Douglass 03; Schmidt00]). 5.5 .3 Object-Oriented Design Using ... Approach [3] ::m VehicleTrafficStandard[1] 1.4 .3. m IntersectionController::m Approach [3] ::m VehicleTrafficStandard[0] 1.4.4. m IntersectionController::m Approach...

Ngày tải lên: 13/08/2014, 08:20

... 500 500 .35 22075.50 105. 83 21.15 25 21750. 43 1000 1000.26 21964.14 2 13. 71 21 .37 21. 23 0.11 2 .33 53 26 21799.76 1000 1000.17 220 13. 21 2 13. 45 21 .34 27 21771.48 1000 1000.81 219 83. 71 212. 23 21.21 28 ... 1.066 32 21917. 83 2000 2000.51 2 234 4.12 426.29 21 .31 33 21956.1 2000 2000.05 2 238 0.74 424.64 21. 23 34 22179.94 2000 2000.76 22607.11 427.17 21 .35 35 21554.21 20...

Ngày tải lên: 06/08/2014, 13:22

... Languages / 33 3 6.4.4 Object-Oriented versus Procedural Languages / 33 4 6.5 Brief Survey of Languages / 33 6 6.5.1 Ada 95 / 33 6 6.5.2 C / 33 7 6.5 .3 C++ / 33 8 6.5.4 C# / 33 9 2 1 BASIC REAL-TIME CONCEPTS this ... 32 4 6 .3. 2 Call-by-Value and Call-by-Reference / 32 4 6 .3. 3 Global Variables / 32 5 6 .3. 4 Recursion / 32 5 6 .3. 5 Dynamic Memory Allocation / 32 5 6 .3....

Ngày tải lên: 13/08/2014, 08:20

... applications, including image processing, avionics systems, and medical systems, and the real-time design issues are the same for them as they are for most other systems. 44 2 HARDWARE CONSIDERATIONS FFFFFFFF FFFFFF00 FFFFFE00 FFC00000 DMA Memory-mapped ... including the Pentium,  use this instruction format. 2 .3. 3 .3 3-Address Form The 3- address instruction is of the form:...

Ngày tải lên: 13/08/2014, 08:20

... complex diagrams. 4.5 STRUCTURED ANALYSIS AND DESIGN Methods for structured analysis and structured design (SASD) have evolved over almost 30 years and are widely used in real-time applications, probably ... A and then B. (c) τ 3 = (4, 4, 3; [B;1][C;1]), where the task executes for one time unit, then requests the resource B and then C. 3. 4 MEMORY MANAGEMENT 137 M ∈...

Ngày tải lên: 13/08/2014, 08:20

... of vehicle travel. 1 .3. 30 Vehicle Presence Detector See Occupancy Loop. 1 .3. 31 WAN Wide Area Network. 1.4 References 1. 10 base-T Ethernet (IEEE 802 .3) 2. SNMP (RFC 1157) 3. ‘‘DEVELOPMENT OF AN ... outstanding commercial software. Real-time engineers know that their systems are frequently subject to changes in hardware, algorithms, and even application. Therefore these systems...

Ngày tải lên: 13/08/2014, 08:20

... Defaults 3. 3.1.1, Table 14 (10) 3. 3. 13. 3, Figure 37 Critical Error – Alarm 3. 3.1.1, Table 14 (11) 3. 3. 13. 3, Figure 37 Critical Error – Reset 3. 3.1.1, Table 14 (12) 3. 3. 13. 3, Figure 37 , Figure 36 Write ... Log 3. 3.1.1, Table 14 ( 13) 3. 3.1.4, Figur e 13 Set Phase 3. 3.1.1, Table 14 (14) 3. 3.1.4, Figur e 13 Get Phase 3. 3.1.1, Table 14 (15) 3. 3.1.4, Figur e 1...

Ngày tải lên: 13/08/2014, 08:20

... = 4,λ = 38 0, and µ = 16.5; then p = (38 0/16.5) 4 /4! 1 + (38 0/16.5) + (38 0/16.5) 2 /2 + (38 0/16.5) 3 /3! + (38 0/16.5) 4 /4! = 0. 834 This means there is a potential for time overloading 83. 4% of ... 0.0 539 91. Recalculation of the buffer size now yields B(0.0 539 91) =  0.0 539 91 0 [p(t) − c(t)] dt = 10,000  0.0 539 91 0 [t −1/4t] dt = 10,000 (3/ 4)  0.0 539 91 0 tdt = 10,0...

Ngày tải lên: 13/08/2014, 08:20

... analyzer as follows: Location (hex) Opcode (hex) Instruction 435 6 232 1 STORE R2, R1 435 7 4701 1000 LOAD R1, 1000 435 9 2401 FC32 . . . 464B 630 0 2000 JUMP 2000 402 8 ENGINEERING CONSIDERATIONS Now consider ... = 0.4 (% design modified) + 0. 03 (% code modified) + 0 .3 (% integration modified) (8.14) For new components A = 100. On the other hand, if all of the code is design modified,...

Ngày tải lên: 13/08/2014, 08:20