product design development 4 pptx
... requirements ETM 551 Product Design and Development -Lecture 4 1 Product Design & Development Product Specifications ETM 551 Product Design and Development -Lecture 4 29 Perceptual Mapping ... 551 Product Design and Development -Lecture 4 4 Product specifications • Other names for product specifications’ – Product requirements – Technical specification...
Ngày tải lên: 13/08/2014, 05:21
product design development 1 pptx
... the production, sale,and delivery of a product 1 Product Design & Development and New Products Management 6 Who ‘owns’ the problem • Marketing • Design • Manufacturing 13 Products vs. development ... Eppinger 3 Introduction • Definition of Product and Product Development (PD) • Characteristics of a Successful Product Development • Who design and develops products...
Ngày tải lên: 13/08/2014, 05:21
south east asia development 4 pptx
... government expenditures 0.00 10.00 20.00 30.00 40 .00 50.00 60.00 197019711972197319 741 9751976197719781979198019811982198319 841 985 Source: Woo et al Table A12 (Development exp as % of total exp, total ... gov't spending by sector 0.00 0.50 1.00 1.50 2.00 2.50 3.00 3.50 4. 00 4. 50 197019711972197319 741 9751976197719781979198019811982198319 841 985 Source: Woo et al Table A12 $U...
Ngày tải lên: 12/07/2014, 12:20
... 0.35/0 .40 0.75/1.00 0 .40 /0.70 0 .40 /0.60 0.15/0.25 – 8 640 0.38/0 .43 0.75/1.00 0 .40 /0.70 0 .40 /0.60 0.15/0.25 – 8 642 0 .40 /0 .45 0.75/1.00 0 .40 /0.70 0 .40 /0.60 0.15/0.25 – 8 645 0 .43 /0 .48 0.75/1.00 0 .40 /0.70 ... 0.80/1.10 0.15/0.25 – 41 40 0.38/0 .43 0.75/1.00 – 0.80/1.10 0.15/0.25 – 41 42 0 .40 /0 .45 0.75/1.00 – 0.80/1.10 0.15/0.25 – 41 45 0 .43 /0 .48 0.75/1.00 – 0.80/...
Ngày tải lên: 10/08/2014, 19:20
... UNS Federal (QQ-A-596) (QQ-A-601) Former ASTM (B26) (B108) Former SAE (J453c) Military (MIL-A-21180) 201.0 2 04. 0 208.0 213.0 222.0 242 .0 295.0 296.0 308.0 319.0 328.0 332.0 333.0 336.0 3 54. 0 355.0 C355.0 356.0 A356.0 357.0 A357.0 359.0 44 3.0 B 443 .0 A 444 .0 512.0 513.0 5 14. 0 520.0 535.0 705.0 707.0 710.0 711.0 712.0 713.0 771.0 850.0 851.0 852.0 — — 108 C113 122 142 195 B295.0 A...
Ngày tải lên: 10/08/2014, 19:20
Handbook of Materials for Product Design Part 4 doc
... also used. Equipment is costly. 02Kissell Page 149 Wednesday, May 23, 2001 9:52 AM 2.165 Nondirectional textured M40 M41 M42 M43 M 44 M45 M46 M47 M4X Unspecified Extra fine matte Fine matte Medium ... TABLE 2 .47 Rivet Specifications Alloy and temper Specification number Grade or code 1100-F MIL-R-56 74 A 2017-T4 MIL-R-56 74 D 2117-T4 MIL-R-56 74 AD 20 24- T4 MIL-R-56 74 DD 5056-H32 MIL-R-...
Ngày tải lên: 10/08/2014, 19:20
Handbook of Materials for Product Design Part 14 pptx
... sulfide Polystyrene Polysulfone Polytetrafluoroethylene Polyvinyl chloride Silicone Aluminum Copper 47 35 45 47 16 46 46 31 43 40 39 38 33 41 18 39 24 ≈ 500 ≈ 1000 TABLE 12.3 Surface Tension of Common Adhesives ... should be designed to avoid loading the rivet in tension. Generally, a hole 1/ 64 in. (0 .4 mm) larger than the rivet shank is satisfactory for composite...
Ngày tải lên: 10/08/2014, 19:20
Plastics Engineered Product Design Part 4 potx
... 5/3 84 1/8 Uniformly distributed Both clamped Midspan 1/3 84 I/8 Concentrated at midspan Both simply supported Midspan 1 /48 1 /4 Concentrated at midspan Both clamped Midspan 1/192 1 /4 Concentrated ... (12,600 and 4, 500 psi), respectively. The corres- ponding loads on rods made with resins B and C are 237 and 223 MPa ( 34, 400 and 32,375 lb), respectively. :*I>! ~...
Ngày tải lên: 12/08/2014, 01:22
Plastics Product Design Part 4 ppt
... - v120,) E22 1 e, = - 6, G (2 -42 ) (2 -43 ) (2 -44 ) (2 -45 ) (2 -46 ) Substituting Eq. 2-35, 2-36, and 2-37 into 2 -44 , 2 -45 , and 2 -46 results in, e, = - (cos2 6- v12 sin2 ... = E22 1 e, = - (sin @cos 6)ol G (2 -47 ) (2 -48 ) (2 -49 ) Finally, substituting Eqs. 2 -47 , 2 -48 , and 2 -49 and 2 -41 , 2 -42 , and 2 -43 into Eqs. 2-29,2...
Ngày tải lên: 12/08/2014, 01:22
Plastics Product Design Part 6 pptx
... 85 64 51 43 32 21 192 128 96 77 64 48 32 2 24 149 112 90 75 56 37 256 171 128 102 85 64 43 288 192 144 115 96 72 48 320 213 160 128 107 80 53 3 84 256 192 1 54 128 96 64 41 6 ... 7000)/2] i5.000 x 0.1 501 = 6, 840 I b C, = [(2330 + 1850)/2] [4. 200 x 0.051 = 44 0 Ib - Total C = 7,280 (4- 3) 200 Plastics Engineered Product Design Re...
Ngày tải lên: 12/08/2014, 01:22