Electromagnetic Waves and Antennas combined - Chapter 10 pdf

... quantities Z 0 and γ from Z sc and Z oc . 10. 10 The wave impedances of a 100 -meter long short- and open-circuited segment of a lossy transmission line were measured to be Z sc = 68.45 +128.13j ohm and Z oc = ... as the RG-58/U. Home cable-TV uses 7 5- cables, such as the RG-59/U or RG-6/U. The thin ethernet computer network, known as 10base-2, uses RG-58/U or RG-58A/U, which is...

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... have a 1 = 1 and a 2 = 0, correspond- ing to α 1 = 0 and α 2 =∞. Typical values of the attenuations for commercially available polaroids are of the order of a 1 = 0.9 and a 2 = 10 −2 ,or0.9 dB and 40 ... appropriate linear combinations. For example, we define the right-polarized (forward-moving) and left-polarized (backward- moving) waves for the {E + ,H + } case: E R+ = 1 2  E...

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... 1.38, and the right graph, the case n H = 2, n L = 1.38. 0 10 20 30 40 50 60 70 80 90 0 0.5 1 1.5 2 omnidirectional band θ a (degrees) F 1 , F 2 TE and TM bandwidths TM band TE band 0 10 20 ... = sqrt((r(1)^2*(1-r(2)*r(3))^2 - (r(2)-r(3))^2)/(4*r(2)*r(3)*(1-r(1)^2))); de2 = acos(c); G2 = (r(2)+r(3)*exp (-2 *j*de2))/(1 + r(2)*r(3)*exp (-2 *j*de2)); de1 = (angle(G2) - pi...

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... that: σ = Ne 2 mγ = ( 8.4 × 10 28 )(1.6 × 10 −19 ) 2 (9.1 × 10 −31 )(4.1 × 10 13 ) = 5.8 × 10 7 Siemens/m where we used e = 1.6 × 10 −19 , m = 9.1 × 10 −31 , γ = 4.1 × 10 13 . The plasma frequency of ... plane waves propagating in dielectrics, conductors, and birefringent me- dia, (b) guided waves propagating in hollow waveguides, transmission lines, and optical fibers,...

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... other. Examples of such waves are the evanescent waves in total internal reflection, various guided-wave problems, such as surface waves, leaky waves, and traveling-wave antennas. The most famous ... forward-moving) E (z)= A( ˆ x +j ˆ y)e −jkz (left-polarized, forward-moving) E (z)= A( ˆ x −j ˆ y )e jkz (left-polarized, backward-moving) E (z)= A( ˆ x +j ˆ y )e jkz (right-polarized, b...

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... (180 km/hr) veloc- ity resolution at a 3-GHz carrier frequency, would require B = 5 MHz and T = 1 msec, resulting in the large time-bandwidth product of BT = 5000. Such large time-bandwidth products ... quadrature weights and points h = - wp^2 * tf * J1over(wp*sqrt(x.^2 - tf^2)) .* exp(j*w0*(t(i)-x)); Ez(i) = exp(j*w0*(t(i)-tf)) + w’*h; % exact output Es(i) = exp(j*w0*t(i)-j*k0*tf...

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... half-wave, (c) layer-1 is quarter- and layer-2 half-wave, and (d) layer-1 is half- and layer-2 quarter-wave. Show that the reflection coefficient at interface-1 is given by the following expressions ... (5.2.3) and (5.2.4). 5.3. Reflected and Transmitted Power 159 5.3 Reflected and Transmitted Power For waves propagating in the z-direction, the time-averaged Poynting vector has only...

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... Structures r= -0 .100 0 -0 .2000 -0 .4000 0.5000 A= 1.0000 1.0000 1.0000 1.0000 -0 .100 0 -0 .1200 -0 .2000 0 -0 .0640 -0 .100 0 0 0 -0 .0500000 B= -0 .100 0 -0 .2000 -0 .4000 0.5000 -0 .1880 -0 .3600 0.5000 0 -0 .3500 0.5000 ... as bandstop or bandpass filters. Quarter-wave phase-shifted fiber Bragg gratings act as narrow-band transmission filters a...

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... as p-polarization, π-polarization, or TM po- larization, the electric fields lie on the plane of incidence and the magnetic fields are Fig. 7.1.1 Oblique incidence for TM- and TE-polarized waves. 7.1. ... θ  B = k x k  z = k k  = √  √   Example 7 .10. 1: For the data of the air-water interface of Example 7.9.1, we calculate the fol- lowing Zenneck wavenumbers at 1 GHz and 100 MHz...

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... the values quoted in Table 9.6.1 for the C-band and X-band waveguides, WR-159 and WR-90.  Example 9.8.2: WR-159 Waveguide. Consider the C-band WR-159 air-filled waveguide whose characteristics ... microwave band. name a b f c f min f max band P α WR- 510 5 .10 2.55 1.16 1.45 2.20 L 9MW 0.007 WR-284 2.84 1 .34 2.08 2.60 3.95 S 2.7 MW 0.019 WR-159 1.59 0.795 3.71 4.64 7.05 C 0.9 MW 0.043...

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