... published in 19 84 ISBN 978-3-540-77506-5 DOI 10 .10 07/978-3-540-778 01- 1 e-ISBN 978-3-540-778 01- 1 Scientific Computation ISSN 14 34-8322 Library of Congress Control Number: 2007942575 © 2008, 19 84 Springer-Verlag ... seemed at first glance, for several reasons: 1. The first version of Numerical Methods for Nonlinear Variational Problems was, in fact, part of a set of m...
Ngày tải lên: 12/08/2014, 16:21
... = 1 in (2.9)). The proof of this regularity result will be given in the following simple case: L(v) = [ fv dx, f e L 2 (Q), (2 .10 ) T-OonQ. (2 .11 ) Before proving that (2 .10 ), (2 .11 ) ... - u) dx. (2 .16 ) By (2 .13 ) and (2 .16 ), we obtain E Vu £ • V(Au £ ) dx > s \ fAu s dx, so that, \u. • v(A«.) dx > f Au, dx. (2 .17 ) By Green's formula, (2 .17...
Ngày tải lên: 27/06/2014, 18:20
Numerical Methods for Ordinary Dierential Equations Episode 1 docx
... examples 10 3 16 NUMERICAL METHODS FOR ORDINARY DIFFERENTIAL EQUATIONS λ y 1 y 2 y 3 y λ x 0 0.2 0.5 1 2 5 10 20 50 10 2 10 3 10 4 0 10 −5 10 −4 10 −3 10 −2 10 1 0.5 1. 0 −0.0 10 4 −0.2 10 4 −0.4 10 4 −0.6 10 4 −0.8 10 4 1. 0 10 4 Figure ... device 11 1 246 Starting methods 11 2 247 Numerical examples 11 3 25 Taylor Series Methods 11 4 250 Intr...
Ngày tải lên: 13/08/2014, 05:21
Numerical_Methods for Nonlinear Variable Problems Episode 2 pot
... = 1 in (2.9)). The proof of this regularity result will be given in the following simple case: L(v) = [ fv dx, f e L 2 (Q), (2 .10 ) T-OonQ. (2 .11 ) Before proving that (2 .10 ), (2 .11 ) ... in G.L.T. [1] , [2], [3]. For the approximation of the EVI of the first kind by finite element methods, we also refer the reader to Falk [1] , Strang [1] , Mosco and Strang [1] , Ciarl...
Ngày tải lên: 12/08/2014, 16:21
Numerical_Methods for Nonlinear Variable Problems Episode 7 pptx
... {££ +1 , xt +i } from {u™ + *, \//% +1 }; in fact this is (5.88) with v/, = < +1 , <t> h = < +1 ; (ii) problem(5.99)toobtain{z^ +1 , ^ +1 }from{u^ +1 , ^ +1 },{^ +1 , ^ +1 }; (iii) ... (5 .10 1) T ™ +1 = 0™ +1 + y m +1 T^, (5 .10 2) m = m 4- 1 go to (5.96). It is clear that each iteration of algorithm (5.93)-(5 .10 2) requires the...
Ngày tải lên: 12/08/2014, 16:21
Numerical_Methods for Nonlinear Variable Problems Episode 10 potx
... obtain r" +1 = r"- p n Aw n . If r" +1 = 0, then x" + 1 = x = A" *b; if r" + * # 0, then compute x n +1 ,r" +1 ,g n +1 ,w n +1 by £& (42 91) (4.292) (4.293) g » +1 ... (4 .11 1) X satisfies (4.47), (4 .11 2) p e (L OO (Q)) /V , V • p = 0 (in the distribution sense). (4 .11 3) 348 App. I A Brief Introduction to Linear Variational...
Ngày tải lên: 12/08/2014, 16:21
Numerical_Methods for Nonlinear Variable Problems Episode 11 pdf
... compli- cated problems (in fluid mechanics, semiconductor simulations, etc.). 6 Numerical Experiments 411 Figure 6 .13 . Triangulation 3~* (e = 1( T 3 , 8 = rc/3). Figure 6 .14 . Triangulation 9~\ (e = 10 " 5 , ... (4.209), (4. 310 ), respectively. We should easily prove that the approximate problem (4. 319 ) has a unique solution if (4. 311 )-(4. 313 ) hold. EXERCISE 4 .12 . Pro...
Ngày tải lên: 12/08/2014, 16:21
Numerical_Methods for Nonlinear Variable Problems Episode 12 pps
... 13 9, 14 0, 15 0, 15 2, 16 5, 16 6, 16 8, 17 0, 17 4, 17 6, 17 7, 17 8, 18 4, 18 5, 18 6, 18 7, 18 8, 19 1, 19 3, 19 4, 19 5, 208, 209, 211 , 214 , 219 , 2 21, 244, 245, 246, 248, 249, 250, 2 51, 253, 254, 259, 266, ... 98, 10 2, 10 4, 15 0, 17 0, 19 1, 19 4, 211 , 269, 292, 293, 444, 452 Varga, R. S. 41, 12 8, 14 0, 14 8, 15 8, 2 01, 384, 440, 452 Wags...
Ngày tải lên: 12/08/2014, 16:21
Numerical Methods for Ordinary Dierential Equations Episode 2 docx
... y n 1 − 1 2 y 2 n 1 +1, y 0 =0, (13 4a) y n = y n 1 − 1 2 y 2 n 1 +1, y 0 =4, (13 4b) y n = y n 1 − y 2 n 1 +2,y 0 = 3 2 , (13 4c) y n = y n 1 2 + 1 y n 1 ,y 0 = 10 0, (13 4d) y n = y n 1 y n−2 +2 y n 1 + ... comprising (12 4d), (12 4e), (12 4f) has been reduced, first to an index 1 formulation (12 4d), (12 4e), (12 4h), and then to an ordinary differential equation system (1...
Ngày tải lên: 13/08/2014, 05:21
Numerical Methods for Ordinary Dierential Equations Episode 5 docx
... is 000 − 529 3375 3904 3375 4232 3375 14 72 3375 18 9 92 00 15 2 25 − 12 7 25 − 419 10 0 − 11 18 575 3375 515 2 25 16 8 0 10 19 96 − 1 552 3375 515 2 25 16 8 0 10 19 96 − 1 552 000 10 00 0 01 0000 000 0 010 . For ... 10 −5 4.58854 82 8 −9 1. 02365 × 10 −5 4.78350 13 7 8 10 2 .15 123 × 10 −6 4.75845 228 8...
Ngày tải lên: 13/08/2014, 05:21