... modulus, 106 psi 0° 262.2 177 .6 7. 00 271 .5 181.3 7. 11 251.9 173 .8 6.85 219.6 181.8 6 .78 224.2 1 87. 9 6.82 216.1 170 .6 6 .75 193.2 165.0 6.95 196 .7 173 .8 7. 18 198.2 154 .7 6.80 Bearing ultimate stress, ... at 4% elong. ksi 0° 77 .3 20.5 80.9 21.5 74 .8 19.1 68.8 17. 7 71 .4 19 .7 65.3 17. 2 53.6 17. 0 54.6 18.5 52.1 15.8 Interlaminar shear ultimate stress, ksi 0°...
Ngày tải lên: 10/08/2014, 19:20
... 17.1 0. 98 3. 98 0.25 1.25 3 .89 14.1 Nitrile rubber (39% ACN) 5.1 14.0 0.72 3.45 0. 18 1.07 5.60 22.1 Polychloroprene (CR-G) 2.96 9.97 0 .88 3.50 19.2 55 .8 SBR (23% styrene) 17.3 41.5 12 .8 34.0 ... processing parameters for Hytrel, and for a number of other materials in this chapter, can be found on the producers’ Internet home pages. * Hytrel is a registered trademark of...
Ngày tải lên: 10/08/2014, 19:20
Handbook of Materials for Product Design Part 11 pps
... mathe- matical design of the tapering cross-sectional profile of the trough which, in combination with the incline of the top of the trough, assures that the volume flow of glass over the pipe is uniform ... furnace off to cool overnight. On an industrial scale, a continuous belt lehr is often employed for annealing. One of the several suggested heat treatment schedules for th...
Ngày tải lên: 10/08/2014, 19:20
Handbook of Materials for Product Design Part 16 pps
... Method for Determination of Coefficient of Linear Ther- mal Expansion of Plastics D3386 Test Method for Determination of Coefficient of Linear Ther- mal Expansion of Electrical Insulating Materials ... Testing of Materials 13.31 D0790 Test Method for Flexural Properties of Plastics D0882 Test Method for Tensile Properties of Thin Plastics D0952 Test Method for Bo...
Ngày tải lên: 10/08/2014, 19:20
Handbook of Materials for Product Design Part 18 ppsx
... common reinforcement configuration 5.49 compacting 5.58 component design phase 5.40 curing 5.57 damage tolerance 5.85 design allowables 5.38 design needs 5.40 drilling 5.74 effects of absorbed ... Micromechanics 5.33 Midplane symmetry 5.80 MIL -Handbook- 5 5.36 MIL -Handbook- 17B 5.38 MIL-STD-810 5.96 Modulus of elasticity 2.41 2.84 steel 2.86 Modulus of rigidity 2....
Ngày tải lên: 10/08/2014, 19:20
Modern Plastics Handbook 2011 Part 7 ppsx
... Books, Boston, 1 972 , p. 222. 114. Strong, A. B., Plastics, p. 295. 115. Ibid., pp. 2962 97. 116. Petrotheneđ Polyolefins, p. 84. 1 17. Berins, M. L., Plastics Engineering Handbook, p. 1 17. 118. Wire ... Monitor Cavity Filling Pressure,” ANTEC’ 97, 19 97, p. 3659. 172 . Mueller, N., private correspondence, 1999. 173 . C-Mold Design Guide, p. 144. 174 . Belofsky, H., Plastics: Pro...
Ngày tải lên: 11/08/2014, 16:22
Plastics Engineered Product Design Part 2 ppsx
... have 22 Plastics Engineered Product Design on. The chemical structure and nature of plastics have a significant relationship both to properties and the ways they can bc processed, designed, ... to produce openings without side action movements f PARTING LINE SIDE MEW OF PART PARTING LINE. 32 Plastics Engineered Product Design Pressure is ofken involv...
Ngày tải lên: 12/08/2014, 01:21
Plastics Engineered Product Design Part 9 pps
... coefficients on the composite optimum design? as design variables for the multilayered-filamentary composite? composite optimum design? 31 8 Plastics Engineered Product Design conductive coatings ... appropriate to 3 14 Plastics Engineered Product Design Missile in flight includes the use of plastics 330 Plastics Engineered Product Design _u_I...
Ngày tải lên: 12/08/2014, 01:22
Plastics Engineered Product Design Part 12 ppsx
... one of the broad product headings gets one into the listings of the individual companies themselves, where, if available, one can 448 Plastics Engineered Product Design - 12. Eliminate ... processes Materials Primary equipment Mold design Process controls Auxiliary equipment Troubleshooting Testing 420 Plastics Engineered Product Design metalworking perm...
Ngày tải lên: 12/08/2014, 01:22
Plastics Product Design Part 2 pdf
... Polytetrafluoroethylene 116 130 175 21 5 26 0 26 0 400 330 24 0 26 6 347 41 9 500 500 755 626 The T, is dependent on the processing pressure and the time under heat, particularly during a slow ... going from the product design through production. Examples of potential cost reductions include. (1) redesign product with thinner walls to reduce production cos...
Ngày tải lên: 12/08/2014, 01:22
Plastics Product Design Part 3 doc
... 2,500 2.160 2.400 2.510 116 104 100 Nylon 6 Glass beads 30 1,250 0.140 0 .32 0 0 .36 8 8 93 391 34 0 5,000 0.290 0.650 0.750 862 38 5 33 3 Reinforcement Strain (%) hours (I@ psi) hours carbon ... 6/10 Ferrite 83 2,500 0.4 63 0.507 0.568 540 4 93 440 5,000 0. 638 0. 732 0.952 784 6 83 525 Polypropylene Carbon powder 2,500 1.100 1.140 1.970 114 87 63 5,000 6. 230 6.9...
Ngày tải lên: 12/08/2014, 01:22
Plastics Product Design Part 4 ppt
... - v120,) E22 1 e, = - 6, G (2 -42 ) (2 -43 ) (2 -44 ) (2 -45 ) (2 -46 ) Substituting Eq. 2-35, 2-36, and 2-37 into 2 -44 , 2 -45 , and 2 -46 results in, e, = - (cos2 6- v12 sin2 ... = E22 1 e, = - (sin @cos 6)ol G (2 -47 ) (2 -48 ) (2 -49 ) Finally, substituting Eqs. 2 -47 , 2 -48 , and 2 -49 and 2 -41 , 2 -42 , and 2 -43 into Eqs. 2-29,2...
Ngày tải lên: 12/08/2014, 01:22
Plastics Product Design Part 5 potx
... b-b 1 0.2 x 5 x 106 0.2 85 0.2 85 x IO6 1 150 psi 131 5 psi 0.2 x 5 x 106 + 0.1 x 3 x 106 0.2 x 5 x 106 + 0.1 x 3 x 106 0.2 85 0.1 35 0.2 15 0.3 65 0.326 x IO6 ... 3,100 3,000 2,400 19,300 1,200 1,400 3,100 2 ,50 0 2,800 55 69 61 72 82 62 30 35 25 70 2 .5 12 12 5 20 12 6 a a 75 75 60 5. 4 60 90 600...
Ngày tải lên: 12/08/2014, 01:22
Plastics Product Design Part 7 pps
... 1, 070 1,325 1, 575 1,800 2,500 3,200 1.50 2.50 4.44 6.25 8.06 9. 87 12.56 16.00 20.06 24.50 28 .75 32 .75 44.81 56.50 1.60 2.63 4.62 6.56 8.48 10.35 13.18 16.80 21. 07 25 .73 ... 6800 441 0 640 2910 460 510 1 070 a60 1800 9640 4420 1650 1 570 1060 21 200 59000 11.5 7. 5 1.1 4.9 0.8 0.9 1.5 3.0 16.3 7. 5 2.8 2 .7 1.8 35.9 100.0...
Ngày tải lên: 12/08/2014, 01:22