Handbook of Small Electric Motors MAZ Part 1 pptx

... (Secs. 1. 13, 2 .1, 2.9, 2 .11 , 3 .10 to 3 .12 , 4.3, 4.6 to 4.8, 5 .1 to 5.3, 6 .1, 6.4, 7 .1 to 7.4, and 8 .1 to 8.3) xii CONTRIBUTORS This handbook is dedicated to my wife, Luci Yeadon, who took most of ... Cutler-Hammer (Sec. 10 .6) Leon Jackson LDJ Electronics (Sec. 3 .19 ) Dan Jones Incremotion Associates (Secs. 5 .1. 3, 10 .12 , and 10 .13 ) Douglas W. Jones University of...

Ngày tải lên: 11/08/2014, 07:23

... (emf): constant, 4 .11 5 defined, 1. 80 1. 81, 1. 86 in three-phase motors, 10 .11 2 10 .11 3 trapezoidal versus sinusoidal drives, 10 .12 2 10 .12 4 in two-phase motors, 10 .98 10 .99, 10 .10 1 10 .10 2 Back iron, 5 .13 , 5.40 Back-iron ... electromechanical: conservation of, 1. 10, 1. 12 1. 15, 1. 91 1. 96 equations for, 1. 10 1. 15 unit conversions, 1. 4 Energy-coenergy appli...

Ngày tải lên: 11/08/2014, 07:23

... 11 .22 flat patterns 11 .12 11 .14 forming methods 11 .1 galvanized coating 11 .3 gauges of 11 .1 11 .7 hot-rolled applications 11 .2 machinery for fabricating 11 .4 ... nonferrous 11 .3 oblique cone 11 .28 oblique pyramid 11 .26 punching methods 11 .10 stiffening parts of 11 . 21 11 .24 transition piec...

Ngày tải lên: 11/08/2014, 07:23

... / 1. 1 1. 2. Definition of Terms / 1. 6 1. 3. Estimating the Permeance of Probable Flux Paths / 1. 21 1.4. Electromechanical Forces and Torques / 1. 32 1. 5. Magnetic Materials / 1. 43 1. 6. Losses / 1. 52 1. 7. ... / 1. 78 1. 12. Moving-Coil Actuator Static and Dynamic (Motion) Analysis / 1. 83 1. 13. Electromagnetic Forces / 1. 89 1. 14. Energy Approach (Energy-Coenerg...

Ngày tải lên: 11/08/2014, 07:23

... here. ᏼ 11 =µ 0 =µ 0 (1. 157) < r 11 <+h (1. 158) l 11 =πr 11 (1. 159) dv 11 = 4πr 2 11 dr 11 (1. 160) dᏼ 11 =µ 0 =µ 0 (1. 1 61) ᏼ 11 =µ 0 ͵ g/2 + h g/2 dr 11 (1. 162) ᏼ 11 = 0.32µ 0 h (1. 163) Total ... (Figs. 1. 9 and 1. 10) ᏼ 4 =µ 0 ln ΂ 1 + 2 ΃ (1. 1 31) h ᎏ g w ᎏ π wt ᎏ g 1 ᎏ π πr 2 11 dr 11 ᎏ π 2 r 2 11 dv 11 ᎏ l 2 11 1 ᎏ 4 g ᎏ 2 g...

Ngày tải lên: 11/08/2014, 07:23

... are: P 1 = K 1 f 2 1 + K 2 f 1 W (2 .18 ) P 2 = K 1 f 2 2 + K 2 f 2 W (2 .19 ) From Eqs. (2 .11 ) and (2 .12 ), K 1 = (2.20) K 2 = (2. 21) The eddy loss, in watts, for frequency f 1 is: P e = K 1 f 2 1 = ... Kilolines/in 2 density 1 T = 6.452 10 4 lines/in 2 1 G = 6.452 lines/in 2 1 kline/in 2 = 0 .15 5 kG 1 T = 10 4 G 1 kline/in 2 = 1. 55 10 −2 T Magnetic H...

Ngày tải lên: 11/08/2014, 07:23

... 0.00 01 0.00 015 +0.0000 +0.0000 0–30 −0.0002 −0.0002 9 0.000050 0.000050 +0.0000 +0.0000 0 18 0.000050 0.00 01 −0.00 01 −0.00 01 +0.0000 +0.0000 > ;18 –30 −0.00 01 −0.00 015 Source: Courtesy of NMB ... MACHINING 3.4 .1 Shaft Materials Most motor manufacturers use SAE 10 45 in either cold-rolled or hot-rolled steel (CRS or HRS). Other materials include sulfurized SAE 11 17, SAE...

Ngày tải lên: 11/08/2014, 07:23

... of the SEG1 section needs to be calculated. For the triangle TR1, at the bottom of the slot, the angle is half of the tooth pitch angle: θ TR1 = (4 .13 1) The length of the base of TR1 is L TR1 = ... (4 .13 2) The angle within TR1 that the arc of radius R as sweeps is θ as = 90°−θ TR1 (4 .13 3) The area of triangle TR1 is A TR1 = (4 .13 4) The area of the slot SEG2 which is in...

Ngày tải lên: 11/08/2014, 07:23

... pole 6 21 — — — 911 1 ⁄2 ——— 12 22 41 — — 15 1 2 1 ⁄2 11 1 ⁄4 —— 18 2 3 2 1 1 ⁄2 61 — 21 1 3 1 ⁄2 11 3 ⁄4 NP* X — 242442NPX 81 27 1 4 1 ⁄2 12 1 ⁄4 31 1 ⁄2 11 1 ⁄8 30 2 5 2 2 1 ⁄2 NP X 2 1 1 ⁄4 33 1 5 1 ⁄2 ... 0.966 12 4 Integral 1 1-4 30 1 1.000 1. 000 1. 000 12 2 Variable 1 (average) 1- 8 /1- 6 30 2 0.966 1. 000 0.966 15 4 Fractional...

Ngày tải lên: 11/08/2014, 07:23

... +φ S ) ΅· I b ᎏ 2 N b ᎏ 2 I a ᎏ 2 N a ᎏ 2 1 ᎏ ͙2 ෆ 1 ᎏ ͙2 ෆ N S ᎏ 2 1 ᎏ 2 1 ᎏ 2 1 ᎏ 2 1 ᎏ 2 N S ᎏ 2 1 ᎏ 2 1 ᎏ 2 1 ᎏ 2 1 ᎏ 2 N S ᎏ 2 1 ᎏ 2 1 ᎏ 2 N S ᎏ 2 1 ᎏ 2 1 ᎏ 2 N S ᎏ 2 N S ᎏ 2 N S ᎏ 2 N S ᎏ 2 6 .12 CHAPTER SIX 3. ... INDUCTION MOTORS 6. 21 E m = E fm + E bm = Z f I fm + Z b I bm (6 .11 9) and E a = jaE fm − jaE bm = jaZ f I fm − jaZ b I bm (6 .12 0) Substitu...

Ngày tải lên: 11/08/2014, 07:23